Answer:
Q<K so N2(g) +3H2(g) → 2NH3(g)
Explanation:
Step 1: Data given
For the balanced equation N2(g)+3H2(g)⇌2NH3(g) We have the following data:
⇒ Reaction quotient Q = 3.56 *10^-4
Where Q is defined as Q = [NH3]^2/{[N2]*[H2]^3]
⇒ Equilibrium constant K = 6.02 * 10^-2
If we compare Q and K, there are 3 options
⇒ Q > K : The reaction favors the reactants. This means that in the Q equation, the ratio of the concentration or pressure of the products) to the concentration or pressure of the reactants is larger than that for K.
This means that more products are present than there would be at equilibrium.
Following Le chatelier's principle reactions always tend toward equilibrium, this means the reaction will produce more reactants from the excess products, and will therefore cause the system to shift to the LEFT.
Doing this, it will allow the system to reach equilibrium.
⇒ Q = K : The reaction is already at equilibrium. There is no tendency to form more reactants or more products at this point. No side is favored and no shift will occur.
⇒ Q < K : The reaction favors the products. The ratio of products to reactants is less than that for the system at equilibrium—the concentration or the pressure of the reactants is greater than the concentration or pressure of the products.
Following Le chatelier's principle reactions always tend toward equilibrium, the system shifts to the RIGHT to make more products.
In this case K > Q since 6.02*10^-2 > 3.56*10^-4
This means that forward reaction will be favored or the reaction will shift to the right
N2(g) +3H2(g) → 2NH3(g)
As a result, the reaction will consume nitrogen gas (N2) and hydrogen gas (H2), and produce more ammonia (NH3).
The reaction will proceed in this direction until equilibrium is established
The reaction quotient (Q) is less than the equilibrium constant (K), indicating that the forward reaction is favored. Therefore, the reaction shifts towards the production of more ammonia (NH3) to achieve equilibrium.
Explanation:The reaction quotient (Q) and the equilibrium constant (K) are critical in determining the direction of a chemical reaction. In this scenario, the reaction of nitrogen and hydrogen to generate ammonia is considered. The reaction quotient Q is 3.56×10-4, while the equilibrium constant K is 6.02×10-2.
In situations where Q < K, the reaction progresses in the forward direction to reach equilibrium, meaning the formation of ammonia (NH3) is favored. On the other hand, if Q > K, the reaction would proceed in the reverse direction, favoring the formation of nitrogen and hydrogen. Therefore, given Q is less than K in this case, the reaction will shift toward the production of ammonia to establish equilibrium.
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A base a. causes phenolphthalein indicator to change from colorless to pink. b. donates a proton in a proton transfer reaction. c. accepts electrons in an electron transfer reaction. d. produces hydrogen ions in solution. e. does none of the above.
Answer: a. causes phelophtalein indicator to change from colorless to pink
Explanation:
Phenolphtalein is an indicator, which means it can visually change when given certain circumstances.
Phenolphtalein turns fuchsia when exposed to basic substances, especially above a pH of 8.2, due to ionization, which changes the structure of the indicator.
The periodic table is composed of _________ and __________.
A. periods and rows
B. groups and columns
C. molecules and groups
D. groups and periods
Answer:
D. groups and periods
Explanation:
In groups the elements have the same electronic configuration in the last electronic shell and we expect that they will have similar chemical properties.
In periods the electronic configuration is increasing with one electron as we proceed from left to right and so the chemical properties will vary significantly.
The compound Lead(II) Nitrate reacts with potassium Iodide.
a) Write the balanced chemical equation. Highlight the ions that form the precipitate in yellow and the spectator ions in pink.
b) Write the net ionic equation (remember: this only includes the ions forming the precipitate it does not include spectator ions).
Answer:
a) Pb(NO3)2 + 2KI ⇒ PbI2 + 2K(NO3)
ion that form the precipitate = Pb2+ and I-
Spectator ions = NO3. and K+
b) Pb 2+ + 2 I- ⇒ PbI2
Explanation:
The balanced chemical equation for the reaction of Lead(II) Nitrate and potassium iodide is 2 KI(aq) + Pb(NO3)2(aq) → 2 KNO3(aq) + PbI2(s). The precipitate forming ions are Pb2+ and I-, leading to the net ionic equation: Pb2+(aq) + 2I-(aq) → PbI2(s). The spectator ions are NO3- and K+.
Explanation:When Lead(II) Nitrate reacts with potassium iodide, the balanced chemical equation becomes:
2 KI(aq) + Pb(NO3)2(aq) → 2 KNO3(aq) + PbI2(s)
The ions that form the precipitate in this reaction are Pb2+ from Lead(II) Nitrate and I- from Potassium Iodide. This results in the formation of Lead(II) Iodide, a yellow precipitate. The spectator ions, which do not participate in the formation of the precipitate, are NO3- from Lead(II) Nitrate and K+ from Potassium Iodide.
The net ionic equation therefore only includes the ions that form the precipitate, which are Pb2+ and I-. It becomes:
Pb2+(aq) + 2I-(aq) → PbI2(s).
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In a double replacement reaction, the ions of two compounds exchange places in an aqueous solution to form to new compounds. true or false
Answer:
The answer to your question is below: True
Explanation:
A double displacement reaction (replacement) is a reaction is which ions are interchanged to forms new compounds. Most of the times one of the products precipitates.
The general equation of this kind of reactions are:
AB + CD ⇒ AD + CB
This is an example of this kind of reactions:
AgNO3 + NaCl → AgCl + NaNO3
The given statement about the double displacement reaction has been true.
In the chemical reaction, the compounds have been dissociated into ions in the aqueous solution. The highly reactive ion will form the bond by displacing the less reactive ion. This type of reaction has been termed the single displacement reaction.
However, when there has been an exchange of the ions of two compounds in the aqueous solution, resulting in a new compound the reaction has been termed a double displacement reaction.
The reaction can be expressed as:
AX + BY [tex]\rightarrow[/tex] AB +XY
Thus, the given statement about the double displacement reaction has been true.
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Which of the following explains the VSEPR geometry of an ammonia molecule?
It is tetrahedral because there are four bonded pairs around nitrogen.
It is trigonal pyramidal because there are four bonded pairs around nitrogen.
It is tetrahedral because there are three bonded pairs and one lone pair around nitrogen.
It is trigonal pyramidal because there are three bonded pairs and one lone pair around nitrogen.
Answer:
The answer to your question is: the lasr one.
Explanation:
Ammonia = NH₃
It is tetrahedral because there are four bonded pairs around nitrogen. This option is wrong, ammonia, does not have four bonds only has 3.
It is trigonal pyramidal because there are four bonded pairs around nitrogen. This option is wrong because ammonia does not have 4 bonds.
It is tetrahedral because there are three bonded pairs and one lone pair around nitrogen. A tetrahedral has 4 bonds not only three, this option is wrong.
It is trigonal pyramidal because there are three bonded pairs and one lone pair around nitrogen. This option is right, it has three bonded pairs and one lone pair around nitrogen so it is a trigonal pyramidal.
The statement that explains the VSEPR geometry of an ammonia molecule is ; ( D ) It is trigonal pyramidal because there are three bonded pairs and one lone pair around nitrogen.
Ammonia ( NH₃ ) has a characteristic strong offensive smell and absence of water in its formation. It is very harmful when exposed to the environment. Ammonia has 3 bonded pairs and a single unpaired electron around nitrogen atom.
The Lewis structure of ammonia depicts a trigonal pyramidal structure because of the bonding of 3 hydrogen atoms to the Nitrogen atom and a lone pair
Hence we can conclude that VSEPR geometry of an ammonia molecule is that it is trigonal pyramidal because there are three bonded pairs and one lone pair around nitrogen.
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Vanillin (used to flavor vanilla ice cream and other foods) is the substance whose aroma the human nose detects in the smallest amount. The threshold limit is 2.0 × 10−11 g per liter of air. If the current price of 50.0 g of vanillin is $115, determine the cost to supply enough vanillin so that the aroma could be detected in a large aircraft hangar with a volume of 5.47 × 107 ft3.
Answer:
[tex]\boxed{\text{\$0.07}}[/tex]
Explanation:
1. Convert cubic feet to litres
[tex]V =5.47 \times 10^{7} \text{ ft}^{3} \times \dfrac{\text{28.32 L}}{\text{1 ft}^{3}} = 1.549 \times 10^{9}\text{ L}[/tex]
2. Calculate the mass of vanillin
[tex]m = 1.549 \times 10^{9}\text{ L} \times \dfrac{2.0 \times 10^{-11}\text{ g}}{\text{1 L}} = \text{0.030 98 g}[/tex]
3. Calculate the cost of the vanillin
[tex]\text{Cost} = \text{0.03098 g} \times \dfrac{\textbf{\$115 }}{\text{50.0 g}} = \text{\$0.07}\\\text{The cost of the vanillin is $\boxed{\textbf{\$0.07}}$}[/tex]
The cost of the Vanillin is $0.07.
What is vanillin used for?
it is utilized in flavorings, foods, perfumes, and pharmaceuticals. Vanillin is used as a chemical intermediate in the manufacture of several essential pills and different merchandise. Human publicity to vanillin is through dermal contact with perfumes and ingestion of meal products that consist of vanillin as a flavor additive.
Is vanillin dangerous for your fitness?Vanillin is thought to release numerous substances whilst burnt. these consist of polycyclic fragrant hydrocarbons, that have been classed as human cancer-causing agents through the global corporation for studies on most cancers.
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Please help me!!
What is the volume of a salt crystal measuring 5.44 x 10^-2 m, by 2.5 x 10^-3 m, by 7.9 x 10^-3 m?
please explain how you got your answer.
Thank you so much for your help, I appreciate it. God bless
Answer:
The answer to your question is: Volume = 1.074 x 10⁻⁶ m³
Explanation:
Data
Salt crystal measures 5.44 x 10⁻² m ; 2.5 x 10⁻³ m; 7.9 x 10⁻³ m
From the information I suppose it is a cube, then,
Volume of a cube = length x width x height
Volume = 5.44 x 10⁻² m x 2.5 x 10⁻³ m x 7.9 x 10⁻³ m
Volume = 0.000001074 m³
Volume = 1.074 x 10⁻⁶ m³
The decomposition reaction of CO2(g) to produce carbon and oxygen gas consumes 462 kJ of energy. The energy levels of the products are ________ than the energy level of the reactant, and the heat appears on the _______ side of the equation.
Answer:
higher, left
Explanation:
Given that the reaction consumes 462 kJ of energy. It means that the reaction is a endothermic reaction.
In the energy profile of the endothermic diagrams, The reactants are at a very low level as compared to the products and hence, energy is supplied to overcome this difference.
Hence, The energy levels of products are higher than the energy level of reactant.
Hence, already stated, heat is required by the reaction and thus heat is written to the reactant side which is to the left side of the equation.
WILL CHOOSE BRAINLIEST!!
what are electromagnetic waves!!??
From his experiments, J. J. Thomson concluded that cathode ray particles can move at very fast speeds. cathode ray particles can be moved by electric current atoms contain small positively charged particles that are called protons. atoms contain small negatively charged particles that are called electrons.
True / False.
Answer:
False
Explanation:
J. J. Thomson conducted an experiment which lead to the discovery of negatively charged particles only. He took a discharged tube and passed high voltage current through the gas and noticed that some particles from cathode is being emitted. They are fast moving particles and are deviated in the electrical and the magnetic field.
J. J. Thomson did not conclude anything about the positive charge. Hence, the statement is false.
Oxides are:
A. only formed during incomplete combustion.
B. products formed during combustion.
C. products formed during double replacement reactions.
D. reactants in combustion. brainly
Answer: The correct answer is Option B.
Explanation:
Combustion reaction is defined as the chemical reaction in which a hydrocarbon reacts with oxygen gas to produce carbon dioxide gas and water molecule. The chemical equation for this reaction follows:
[tex]\text{hydrocarbon}+O_2\rightarrow CO_2+H_2O[/tex]
Incomplete combustion is defined as the reaction in which supply of oxygen is limited and carbon monoxide gas is also produced as a product. The chemical equation for this reaction follows:
[tex]\text{hydrocarbon}+O_2\text{(limited)}\rightarrow CO+CO_2+H_2O[/tex]
Single displacement reaction is defined as the reaction in which more reactive element displaces a less reactive element.
[tex]AB+C\rightarrow CB+A[/tex]
Element C is more reactive than element A.
As, we can see that oxides are the products in both complete combustion reaction and incomplete combustion reaction.
Hence, the correct answer is Option B.
Oxides are chemical compounds comprising of oxygen and another element. They're most often formed during combustion, where oxygen reacts with another substance to produce an oxide. One example is the burning of coal which produces carbon dioxide.
Explanation:Oxides are chemical compounds that contain at least one oxygen atom and one other element. Most of the Earth's crust consists of solid oxides, the result of elements being oxidized by the oxygen in the air. Option B, 'Products formed during combustion.' is the most accurate. During combustion, oxygen reacts with a substance, resulting in the production of an oxide. For example, when you burn coal (which is mostly carbon), carbon dioxide (CO2) is one of the products formed.
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Determine the volume of fluid in the graduated cylinder shown.
A. 12.7 mL
B. 12.8 mL
C. 12 .78 mL
D. 12 .88 mL
Answer : The correct option is, (B) 12.8 ml
Explanation :
As we know that for the measurement of the volume of liquid in graduated cylinder are shown by placing the graduated cylinder on the flat surface and then view the height of the liquid in the graduated cylinder with the naked eyes directly level with the liquid.
The liquid will tend to curve downward that means this curve is known as the meniscus.
In the case of colored liquid, we are always read the upper meniscus of the liquid for the measurement.
In the case of colorless liquid, we are always read the lower meniscus of the liquid for the measurement.
In the given image, there are 10 division between the 12 and 13 and the smallest division is, 0.1. So, the volume of liquid will be, 12 ml + 0.8 ml = 12.8 ml.
Hence, the correct option is, (B) 12.8 ml
Please pleas show work I need help please it is confusing me 73. Make the following temp conversion: a. 44.2 degrees C to kelvins c. -20 degrees C to kelvins. 74. Carry out the indicated ten conversion. a.-201 degrees F to kelvin c. 351 degrees to Fahrenheit degrees. 75. Convert the following Fahrenheot temperatures to Celsius degrees. a. a chilly morning in early autumn 45 degrees F c. Temperature in winter when my car won’t start -10 degrees F
Answer:
To convert C to K, just add 273, remember that 0° C is 273 K, so 73.a) is 317.2 K and 73.c) is 253 K. 74.a) Will be, -129, 4 C + 273 = 143.5 F, 74.c) 663.8 F
75.a) 7.2 C , 75.c) -23.3 C
Explanation:
To convert C to F, you can use this, (9/5 * C + 32 ) = F, or back ward, C = (F - 32)* 5/9.
Two containers hold the same radioactive isotope. Container A contains 1000 atoms, and container B contains 500 atoms. which container has greater radioactive decay?The rate of decay of atoms in container A is greater than the rate of decay of atoms in container B.
Answer:
The rate of decay of atoms (half-life) in container B is the same as the rate of decay of atoms (half-life) in container A.
Solutions of sodium carbonate and silver nitrate react to form solid silver carbonate and a solution of sodium nitrate. A solution containing 3.60g of sodium carbonate is mixed with one containing 5.14 of silver nitrate.
1.) How many grams of sodium carbonate are present after the reaction is complete?
2.)How many grams of silver nitrate are present after the reaction is complete?
3.)How many grams of silver carbonate are present after the reaction is complete?
4.) How many grams of sodium nitrate are present after the reaction is complete?
Answer:
1) 2.0 g
2) 0 g
3) 4.17 g
4) 2.57 g
Explanation:
First of all, we need to know the compounds and the reaction. The ion carbonate is [tex]CO3^{-2}[/tex], and the ion nitrate is [tex]NO3^{-}[/tex].
Sodium is in group 1, so it must lose one electron to be stable, and be the cation [tex]Na^{+}[/tex]. Silver has only one electron too, so the cation will be [tex]Ag^{+}[/tex].
To form the chemical compounds, first we put the cation, then the anion, and change their charges without the signal:
Sodium carbonate: Na2CO3
Silver nitrate: AgNO3
Silver carbonate: Ag2CO3
Sodium nitrate: NaNO3
The balanced reaction will be:
Na2CO3 + 2 AgNO3 --> Ag2CO3 + 2 NaNO3
Now, we must check the stoichiometry, which will be 1:2:1:2 (always in number of moles)
The question wants to know the mass value, so we need to know the molar mass of these compounds. Checking the periodic table will see that:
Na = 23 g/mol, C = 12 g/mol, N = 14 g/mol, O = 16 g/mol, Ag = 108 g/mol
So the molar mass of the compounds must be:
Na2CO3 = 106 g/mol (2x23 + 12 + 3x16)
AgNO3 = 170 g/mol (108 + 14 + 3x16)
Ag2CO3 = 276 g/mol (2x108 + 12 + 3x16)
NaNO3 = 85 g/mol
We have a mixture of the reactants, so one probably would be in excess, so, first will need to test. Let's do the stoichiometry calculus using silver nitrate as the limit, so:
1 mol of Na2CO3 ---------- 2 mol of AgNO3
106 g ------------------------------ 2x170 = 340 g
x ------------------------------------ 5.14 g
By a simple direct three rule:
340x = 544.84
x = 1.6 g of Na2CO3
That means that for this reaction, we only need 1.6 g of Na2CO3 to react with 5.14 of AgNO3. How we have 3.60 g of Na2CO3, it is on excess, and all the AgNO3 will be consumed.
1) The mass of Na2CO3 that remains after the reaction will be the initial less the mass that reacted:
m = 3.6 - 1. 6 = 2.0 g
2) All the AgNO3 reacted, so there isn't a mass present after the reaction.
m = 0 g
3) Now, doing the stoichiometry calculus between AgNO3 and Ag2CO3
2 moles of AgNO3 ------------- 1 mol of Ag2CO3
2x170 g ------------------------------- 276 g
5.14 g --------------------------------- x
By a simple direct three rule:
340x = 1418.64
x = 4.17 g of Ag2CO3
4) Now, doing the stoichiometry calculus between AgNO3 and NaNO3
2 moles of AgNO3 ----------------------- 2 moles of NaNO3
2x170 g ---------------------------------------- 2x85 g
5.14 g ------------------------------------------- x
By a simple direct three rule:
340x = 873.8
x = 2.57 g
2.0 grams of sodium carbonate, 0 gram of silver nitrate, 4.17 grams of silver carbonate and 2.57 grams of sodium nitrate is present after the reaction is complete.
How we calculate no. of grams from moles?We can calculate Number of grams or wanted weight through below expression:
[tex]\[{\rm{n = }}\frac{{\rm{W}}}{{\rm{M}}}\][/tex], where
n = no. of mole
W = given weight
M = molar mass
In the question given balanced chemical reaction is:
[tex]${\rm{N}}{{\rm{a}}_{\rm{2}}}{\rm{C}}{{\rm{O}}_{\rm{3}}}{\rm{ + 2AgN}}{{\rm{O}}_{\rm{3}}} \to {\rm{A}}{{\rm{g}}_{\rm{2}}}{\rm{C}}{{\rm{O}}_{\rm{3}}}{\rm{ + 2NaN}}{{\rm{O}}_{\rm{3}}}$[/tex]
It is clear that mole ratio of reactant and product is 1:2::1:2.
Also mention that, given initial mass of sodium carbonate = 3.60g
And given initial mass of silver nitrate = 5.14g
In the reactant mixture one would be present in the excess quantity and we did stoichiometry calculation by assuming silver nitrate as the limiting reactant, so:
1 mole of Na₂CO₃ ............................. 2 mole of AgNO₃
106 g .............................. 2 × 170 = 340 g
x .............................. 5.14 g
Now by using simple three rule, we can calculate the value of x:
340x = 544.84
x = 1.6 g of Na₂CO₃
(1). Mass of Na₂CO₃ remains after the completion of reaction:
Initial - used = 3.6 - 1.6 = 2.0 g
(2). All the AgNO₃ get consumed by the excess Na₂CO₃, so mass present after completion of reaction is 0 g.
(3). Now again we will do stoichiometry calculation between AgNO₃ and Ag₂CO₃:
2 moles of AgNO₃ ............................ 1 mole of Ag₂CO₃
2 × 170 g ............................. 276 g
5.14 g ............................. x
Now by using simple three rule, we can calculate the value of x:
340x = 1418.64
x = 4.17 g of Ag₂CO₃
(4). Again we will do stoichiometry calculation between AgNO₃ and NaNO₃:
2 moles of AgNO₃ .............................. 2 moles of NaNO₃
2 × 170 g .............................. 2 × 85 g
5.14 g ............................... x
Now by using simple three rule, we can calculate the value of x:
340x = 873.8
x = 2.57 g
Hence, amount of sodium carbonate, silver nitrate, silver carbonate and sodium nitrate is 2.0 g, 0 g, 4.17 g and 2.57 g respectively.
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This problem has been solved!See the answerFrom the information in this chapter on the mass of the proton, the mass of the electron, and the sizes of the nucleus and the atom, calculate the densities of a hydrogen nucleus and a hydrogen atom. (Radius of hydrogen atom is 1 ✕ 10-8 cm.)Can someone please help with this two part question? I have asked twice on here and I am still getting it wrong on my WebAssign-it's the only one I cannot get!.... Thank you in advance!!density of hydrogen nucleus :
The density of a hydrogen nucleus is approximately 1.24 x 10^17 kg/m^3, and the density of a hydrogen atom is approximately 8.38 x 10^16 kg/m^3.
Explanation:To calculate the density of a hydrogen nucleus, we can use the formula for density, which is mass divided by volume. The mass of a proton is approximately 1.67 x 10^-27 kg, and the volume of a sphere can be calculated using the formula V = (4/3)πr^3. Let's assume the radius of a hydrogen nucleus is equal to the diameter of a proton, which is approximately 1.2 fm. Plugging these values into the formula, we can calculate the density of a hydrogen nucleus.
density = mass / volume = 1.67 x 10^-27 kg / ((4/3)π(0.6 x 10^-15 m)^3) = 1.24 x 10^17 kg/m^3
So, the density of a hydrogen nucleus is approximately 1.24 x 10^17 kg/m^3.
To calculate the density of a hydrogen atom, we need to know its mass and volume. The mass of an electron is approximately 9.11 x 10^-31 kg, and the volume of a sphere can be calculated using the formula V = (4/3)πr^3. Let's assume the radius of a hydrogen atom is equal to the given value, which is 1 x 10^-8 cm. Plugging these values into the formula, we can calculate the density of a hydrogen atom.
density = mass / volume = 9.11 x 10^-31 kg / ((4/3)π(0.5 x 10^-10 m)^3) = 8.38 x 10^16 kg/m^3
So, the density of a hydrogen atom is approximately 8.38 x 10^16 kg/m^3.
Put the following metric units in order from largest to smallest pL, mL, dL, kL
Thank you for your help! God bless
Answer:
kL, dL, mL, pL
Explanation:
pL stands for picoliters. This is equal to 1 × 10⁻¹² (0.000000000001) liters.
mL stands for milliliters. This is equal to 1 × 10⁻³ (0.001) liters.
dL stands for deciliters. This is equal to 1 × 10⁻¹ (0.1) liters.
kL stands for kiloliters. This is equal to 1 × 10³ (1000) liters.
Certain compound contains 7.3% carbon, 4.5% hydrogen, 36.4% oxygen, and 31.8% nitrogen. It’s reality molecular mass is 176.0. Find its empirical and molecular formula
Answer:
The answer to your question is:
Explanation:
Data
carbon 7.3% = 7.3g
hydrogen 4.5% = 4.5g
oxygen 36.4% = 36.4 g
nitrogen 31.8% = 31.8 g
Now
For carbon
12 g --------------------1 mol
7.3 g ------------- x
x = 7.3/12 = 0.608 mol
For hydrogen
1 g -------------------- 1 mol
4.5 g ------------------ x
x = 4.5 mol
For oxygen
16 g ------------------- 1 mol
36.4 g ---------------- x
x = 2.28 mol
For nitrogen
14 g ---------------- 1 mol
31.8 g --------------- x
x = 2.27 mol
Now divide by the lowest result, the is 0.608 from carbon
carbon 0.608/0.608 = 1
hydrogen 4.5/ 0.608 = 7.4
oxygen 2.28/0.608 = 3.75
nitrogen 2.27/0.608 = 3.73
Empirical formula = CH₇O₄N₄
For a compound with 7.3% carbon, 4.5% hydrogen, 36.4% oxygen, and 31.8% nitrogen, and a molecular mass of 176.0 g/mol, the empirical formula is CH7O4N4, and the molecular formula is CH9O5N5.
To find the empirical and molecular formulas of a compound with 7.3% carbon, 4.5% hydrogen, 36.4% oxygen, and 31.8% nitrogen, we start by assuming a 100g sample. This assumption simplifies the calculation since the percentages can directly translate to grams.
For carbon (C), 7.3 g / 12.01 g/mol = 0.608 moles.For hydrogen (H), 4.5 g / 1.008 g/mol = 4.464 moles.For oxygen (O), 36.4 g / 16.00 g/mol = 2.275 moles.For nitrogen (N), 31.8 g / 14.01 g/mol = 2.270 moles.Next, we find the simplest whole number ratio by dividing each mole value by the smallest mole value calculated, which is for carbon.
The ratio simplifies to C: 1, H: 7, O: 4, and N: 4, giving us an empirical formula of CH7O4N4. The empirical formula mass (EFM) is calculated by summing the masses of all atoms in the empirical formula, which totals to 176 g/mol. Since the empirical formula mass matches the given molecular mass of 176.0 g/mol, the empirical formula CH7O4N4 is also the molecular formula.
To find the molecular formula, we need to compare the molar mass of the empirical formula with the given molar mass (176.0 g/mol) to find the "scaling factor" by which to multiply the empirical formula.
Calculate the molar mass of the empirical formula:
1 × 12.01 + 7 × 1.008 + 4 × 16.00 + 4 × 14.01 = 12.01 + 7.056 + 64.00 + 56.04 = 139.106 g/mol
Calculate the scaling factor:
Scaling factor = Molecular formula mass ÷ Molecular formula mass
Scaling factor = 176.0 ÷ 139.106
Scaling factor ≈ 1.264
Molecular formula: C1 × 1.264 H7 × 1.264 O4 × 1.264 N4 × 1.264
Molecular formula: C1.264 H8.848 O5.056 N5.056
Since we need whole numbers, we'll round these to the nearest whole number: CH7O4N4.
So, the empirical formula of the compound is CH7O4N4 and its molecular formula is CH9O5N5
Determining nitrogen balance in the clinical setting can be very valuable. To determine a client’s state of nitrogen balance, a 24-hour urinary urea nitrogen collection is done. What do you also need to do?
Answer:
We also need the nitrogen intake
Explanation:
The nitrogen balance is the difference between the nitrogen intake and nitrogen excreted. If this calculation is positive, the body grow; if it is negative, the body is decreased.
In two or more complete sentences explain how to balance the chemical equation and classify its reaction type
Answer:
P4+ 3O2 --->2P2O3
Explanation:
left side:
P=4O=2right side :
P=2O=3to balance:
since there is 4 P at left , thus right side need 4P :P2×2 = 2P2 , now u get 4 P at the right and leftsince at right , P2O3 has been ×2 , O2 now has 6 , thus left side need 6 O too :O2×3= 3O2 , now you get 6 O at the left and rightImportant moleculear discoveries in the 1980s have led researchers to hypothesize theat the original vital orgnaic molecule shaping living things was not what was first thought. What molecule is currently supported as the candidate for the vital molecule for earlly life?
Answer:
RNA
Explanation:
Oparin-Haldane hypothesis says that the life gradually arose from amino acids and then they combining to make the complex polymers.
Miller-Urey experiment provided first evidence that the organic molecules needed for the life could be formed from the inorganic components.
Currently, Scientists support RNA world hypothesis. It suggests that first life was the self-replicating RNA. Thus, RNA is vital molecule for the early life.
State whether or not the following equation is balanced: FeO + Al → Fe + Al2O3
If it is not balanced, explain why and provide the balanced equation.
Answer: 3 FeO + 2 Al -> 3 Fe + Al2O3
Explanation:
In order to verify if it is balanced or not you need to count the element at the left and the right. If they arent the same it isnt balanced.
And to balance the equation (simple method, not using redox) you assign coef 1 to the compound with more number of elements Al2O3 in this case and then you complete the rest
A student measures the volume of a liquid in a graduated cylinder of 250 mL capacity, and finds the volume of the liquid to be 200 mL. The student transfers the liquid to a graduated cylinder with a capacity of 500 mL. What is the volume of the liquid in the 500 mL cylinder?
A. unknown
B. 100 mL
C. 200 mL
D. 500 mL
Answer:
Option C = 200 mL
Explanation:
The volume of liquid remain same because students just transfer the liquid from the graduated cylinder with the capacity 250 mL to the graduated cylinder having the capacity of 500 mL. The volume of the liquid will remain same either it is in the large graduated cylinder or in a small graduated cylinder.
Which of the following characteristics are true about a typical peptide (amide) bond?
The bond is planar.
There is free rotation about the carbonyl carbon and nitrogen bond.
There is substantial double-bond character to this bond.
There is a net negative charge on nitrogen and net positive charge on oxygen.
Answer:
The bond is planar. There is free rotation about the carbonyl carbon and nitrogen bond.
Explanation:
The peptide bond is planar and for this reason there is free rotation about the carbonyl carbon and nitrogen bond. Peptide bonds don't have double-bonds or delocalized electrons in their structure. Both oxygen and nitrogen have a net negative charge on the peptide bonds.
A peptide bond is planar, does not allow free rotation due to its double-bond character, and has no net charge under physiological conditions.
Explanation:The characteristics of a typical peptide (amide) bond are as follows:
The bond is planar. This is because of the resonance or delocalization of the peptide bond.There is not free rotation about the carbonyl carbon and nitrogen bond. This is due to the double-bond character of the peptide bond caused by the resonance.A peptide bond has a double bond character which gives it its planar structure.There is no net charge on either the nitrogen or the oxygen in a peptide bond under physiological circumstances i.e. pH 7.4. So, the last statement that nitrogen has a net negative charge and oxygen has a positive charge is not correct.Learn more about Peptide Bond here:https://brainly.com/question/35560541
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Which half-reaction correctly describes an oxidation?
Answer:
The last reaction is an oxidation:
[tex]Cr_(_s_)~->~Cr^+3_(_a_q_)~+~3e^-[/tex]
Explanation:
For the first half-reaction, we have a strange reduction the charge is not balanced so, it is not a possible reaction. In the second half-reaction we will have a reduction process as such, we have 2 negative charges in both sides and the electrons are placed on the reactive side. For the third half-reaction, we will have strange oxidation because the charge is not balanced, we have a charge of +1 in the left and a charge of -1 in the right, so this is not a possible reaction. For the last half-reaction, we have the production of electrons and the charge is equal on both sides, which is zero.
Finally to remember, Oxidation=production of electrons, Reduction=Consumtion of electrons.
A child with cystic fibrosis has a mutated protein in his cells which does not behave normally. The mutated protein stops chloride ions from leaving the cells. This causes water to be retained in the cell creating thicker fluids. These fluids cause a buildup of mucus which leads to breathing problems. Which cell structure is most likely being negatively affected by the mutated protein?
Answer:
Explanation:
lung air ways the mucus will clog it up causing asthma hope this helped :P
QUESTION 8
Buffer solutions:
keep the pH of the solution constant even when small amounts of acid or base are added
resist changes in pH when small amounts of acid or base are added
are not used up in buffer reactions and can keep reacting to adjust the pH indefinitely
have no practical uses outside of laboratory conditions
Answer:
B
Explanation:
I would go with B b/c C and D are wrong. The reason C is wrong is that buffers do get used up after a while so it wont be able to react indefinitely to maintain the pH and the reason D is wrong is that there are thousands of uses for buffer ranging from your own human body to thousands and thousands of things.
In my opinion, A is not necessarily wrong because buffer's job is to keep the pH of the solution relatively constant (up to some point), but I think B is still the best answer because it describes the actual function of buffer which is to resist pH.
Final answer:
Buffer solutions resist changes in pH when small amounts of acid or base are added. They protect other molecules from the effects of added acid or base and are critically important in biological systems.
Explanation:
A buffer solution is one which resists changes in pH when small amounts of acid or base are added. Buffer solutions contain both a weak acid and its conjugate base, or a weak base and its conjugate acid. By maintaining a relatively constant pH, buffers protect other molecules in the solution from the effects of added acid or base. These solutions are critically important in biological systems and can be obtained commercially.
How did dmitri mendeleev organize the periodic table
Answer:
According with atomic weight and valences
Explanation:
Mendeleev organized the periodic table according atomic weight because the elements exhibit an apparent periodicity of properties, and the magnitude of the weight determines the character of the element
Which of the following is a precipitation reaction?
a. HCl(aq) + KOH(aq) → KCl(aq) + H2O(l)
b. 2 NaI(aq) + Hg2(NO3)2(aq) → Hg2I2(s) + 2 NaNO3(aq)
c. Zn(s) + 2 AgNO3(aq) → 2 Ag(s) + Zn(NO3)2(aq)
d. KCl(aq) + LiI(aq) → KI(aq) + LiCl(aq)
e. None of the above is a precipitation reaction.
Answer:
B is a precipitation reaction.
Explanation:
This is because a precipitation reaction is when a solid is made from the combination of cations and anions in a solution to create a solid.
[tex]\rm 2 NaI(aq) + Hg_2(NO_3)_2(aq) \rightarrow Hg_2I_2(s) + 2 NaNO_3(aq)[/tex] is a precipitation reaction. Therefore, the correct option is option B.
When two soluble compounds are combined, a precipitation reaction occurs, which is a sort of chemical reaction that creates an insoluble solid known as a precipitate. When two compounds mix to generate an insoluble compound that separates out as a solid from the solution, a precipitation reaction takes place.
The reactants in a precipitation reaction are typically ionic compound-containing aqueous solutions. The ions from the various chemicals may combine in these solutions to generate a complex that is only partially soluble. As a result, a solid precipitate that settles out of the solution is created. [tex]\rm 2 NaI(aq) + Hg_2(NO_3)_2(aq) \rightarrow Hg_2I_2(s) + 2 NaNO_3(aq)[/tex] is a precipitation reaction.
Therefore, the correct option is option B.
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Fermentation has a relatively low atp yield compared to aerobic respiration because
Answer:
Oxidative phosphorylation yields a lot of ATP.
Explanation:
There are two types of respiration:
1. Aerobic respiration
2. Anaerobic respiration
Aerobic respiration
It is the breakdown of glucose molecule in the presence of oxygen to yield large amount of energy. Water and carbon dioxide are also produced as a byproduct.
Glucose + oxygen → carbon dioxide + water + 38ATP
Anaerobic Respiration
It is the breakdown of glucose molecule in the absence of oxygen and produce small amount of energy. Alcohol or lactic acid and carbon dioxide are also produced as byproducts.
Glucose→ lactic acid/alcohol + 2ATP + carbon dioxide
This process use respiratory electron transport chain as electron acceptor instead of oxygen. It is mostly occur in prokaryotes. Its main advantage is that it produce energy (ATP) very quickly as compared to aerobic respiration.
Steps involve in anaerobic respiration are:
Glycolysis
Glycolysis is the first step of both aerobic and anaerobic respiration. It involve the breakdown of one glucose molecule into pyruvate and 2ATP.
Fermentation
The second step of anaerobic respiration is fermentation. It involve the fermentation of pyruvate into lactic acid or alcohol depending upon the organism in which it is taking place. There is no ATP produced, however carbon dioxide is released in this step. Fermentation itself not produced ATP but produce in glycolysis step.