can someone tell me how to evalaute 6!

91/7= 13

13 portraits in 1 week

13x4=52

52 portraits in 4 weeks

To estimate the value of y when x = 14 using exponential regression, we first find the equation that best fits the data, and then substitute x = 14 into it. The estimated value of y when x = 14 is approximately 223.7.

To find the value of y when x = 14 using exponential regression, we need to first find the equation that best fits the data. We can do this by using a graphing calculator or software that can perform exponential regression. Once we have the equation, we can substitute x = 14 into it to find the estimated value of y.

The exponential regression equation that best fits the data is [tex]y = 4 \times 2.0487^x.[/tex] Plugging in x = 14 into this equation gives us  [tex]y = 4 \times 2.0487^{14} = 223.7.[/tex]

Therefore, the estimated value of y when x = 14 is approximately 223.7.

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To estimate the value of y when x = 14 using exponential regression, we first need to find the exponential equation that best fits the given data points. The estimated value of y when x = 14 is approximately D. 223.7.

To estimate the value of y when x = 14 using exponential regression, we first need to find the exponential equation that best fits the given data points.

We can do this by using a graphing calculator or a statistical software. Once we have the equation, we can substitute x = 14 into the equation to find the estimated value of y.

Using the given data points, the exponential regression equation that best fits the data is y = 3.6841 * (1.5693)^x. Substituting x = 14 into the equation, we get: y = 3.6841 * (1.5693)^14 ≈ 223.7.

Therefore, the estimated value of y when x = 14 is approximately 223.7. Therefore, the correct answer is D. 223.7.

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Since there's a negative in front of the parenthesis, it switches the values inside. So that it's -2h+18=7h. h = 2

when rounded to the tenths place it would be 9.3

m = [tex]\frac{5}{6}[/tex] , y - 7 = [tex]\frac{5}{6}[/tex] ( x - 12), y = [tex]\frac{5}{6}[/tex] x - 3

(a) calculate the slope using the gradient formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (- 6, - 8) and (x₂, y₂) = (12, 7)

m = [tex]\frac{7+8}{12+6}[/tex] = [tex]\frac{15}{18}[/tex] = [tex]\frac{5}{6}[/tex]

(b) the equation of a line in point-slope form is

y - b = m(x - a )

where m is the slope and (a, b) a point on the line

using m = [tex]\frac{5}{6}[/tex] and (a , b) = (12, 7 )

y - 7 = [tex]\frac{5}{6}[/tex] (x - 12)

(c) the equation of a line in slope-intercept form is

y = mx + c ( m is the slope and c the y-intercept )

rearrange (b ) into this form

y - 7 = [tex]\frac{5}{6}[/tex] - 10

y = [tex]\frac{5}{6}[/tex] x - 3

You did everything right all the way up to one small thing at the end.  When you moved the decimal to the left and made 10.35 into 1.035, you would need to make the exponent an 11.  Raising the exponent will show that you have moved the decimal more than the original problem started with.  

Hope this helps?

In the second to the last step (10.35 x 10¹⁰), you moved the decimal of 10.35 one place to the left but you did not balance it by moving 10¹⁰ one place to the right. FYI: Moving the exponent one place to the right means to add one to the exponent.

The correct answer: 1.035 x 10¹¹

Final answer:

To create an alloy with 4.9 lb of zinc based on the nickel to zinc ratio of 2:7, about 1.4 pounds of nickel is required.

Explanation:

To determine how many pounds of nickel have to be used to create an alloy that contains 4.9 lb of zinc, we must first understand the given ratio of nickel to zinc to copper in the alloy, which is 2:7:9. Since zinc's ratio is 7 and we have 4.9 lb of it, we can calculate the amount of nickel by setting up a proportion.

We use the proportion 2/7 = x/4.9, where x represents the pounds of nickel. By cross-multiplying and solving for x, we get x = (2 * 4.9) / 7, which simplifies to x = 9.8 / 7. This gives us the result x ≈ 1.4 lb.

Therefore, to create an alloy with 4.9 lb of zinc, approximately 1.4 pounds of nickel are needed.

Charity donated by Tillman = $3540

Number of employees who donated = 118

Contribution of Tillman = 40%

Let the average contribution of employees be = x

Then the amount contributed by employees = 118x

Then contribution of Tillman = [tex]\frac{40}{100}\times118x[/tex]

As Tillman donated 3540 , then

[tex]3540=\frac{40}{100}\times118x[/tex]

[tex]3540=47.20x[/tex]

[tex]x=75[/tex]

Hence, average contribution by each employee is $75.

Option C is correct.

Answer:

$75

Tillman's donation = .40(total employees' donations)

$3540 = .40x

x = 8850

8850

118

= $75 for each employeeep explanation:

$75

Tillman's donation = .40(total employees' donations)

$3540 = .40x

x = 8850

8850

118

= $75 for each employee

We are given side length of a cube = (3x+2y).

Volume is given by formula [tex]V=s^3[/tex], where s is the side of cube.

We have s = (3x+2y).

Plugging s = (3x+2y) in formula now.

We get,

[tex]V=(3x+2y)^3[/tex]

Expanding by applying formula [tex](a+b)^3=(a)^3 + 3a^2b+3b^2a+(b)^3.[/tex]

[tex](3x+2y)^3 =(3x)^3+3(3x)^2(2y)+3(2y)^2(3x)+(2y)^3[/tex]

[tex](3x+2y)^3 = 27x^3+54x^2y+36xy^2+8y^3[/tex]

Answer:

D

The side length, s, of a cube is 3x + 2y. If V = s3, what is the volume of the cube?

3x3 + 18x2y + 36xy2 + 8y3

27x3 + 54x2y + 18xy2 + 2y3

27x3 + 18x2y + 12xy2 + 2y3

27x3 + 54x2y + 36xy2 + 8y3

if x can be 2-5 and y can be 1-6, c=3(5)+4(6)

which would turn out to be c=39

The maximum value of C will be equal to 39.

It is defined as the relation between two variables, if we plot the graph of the linear equation we will get a straight line.

Given constraints are:-

x  ≥   2

x  ≤   5

y  ≥   1

y  ≤  6

Here maximum value of x = 5 and for y = 6

Putting the maximum values of x and y to calculate the maximum value of C.

C  =  3x  +  4y

C  = ( 3 x 5 )  +  (  4  x  6 )

C  =  15  +  24

C   =  39

Therefore the maximum value of C will be equal to 39.

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Since you are solving for a, you want to have a on one side of the equation and the other terms on another side of the equation. It would be easiest to have all the terms with a on the left side of the equation, so that is what we will do.

Subtract 9a from both sides to get a on the left side of the equation.

5 + 5a = -5

Subtract 5 from both sides of the equation to isolate the term with a.

5a = -10

Divide both sides of the equation by 5 to solve for a.

a = -2

The result to the equation is a = -2.

To break for a in the equation 5 + 14a = 9a - 5, we can start by simplifying both sides of the equation.

Adding 5 to both sides

5 + 14a + 5 = 9a - 5 + 5

10 + 14a = 9a

Next, we can insulate the variable a by abating 9a from both sides

14a - 9a + 10 = 9a - 9a

5a + 10 = 0

To break for a, we'll abate 10 from both sides

5a + 10 - 10 = 0 - 10

5a = -10

Eventually, we divide both sides by 5 to break for a

5a/ 5 = -10/ 5

a = -2

Thus, the result to the equation is a = -2.

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Answer:

3050

Step-by-step explanation:

Answer:

The first and third one

Step-by-step explanation:

Answer:

[tex]\frac{7y^{2} +9x}{4}[/tex] and 6y²+5x

Step-by-step explanation:

Polynomials are algebraic expressions involving one, or even more than one variables raised to any power summing each other. Generally speaking, in other words an one variable Polynomial is

[tex]a_{0}+a_{1} x+a_{2} x^{2}...a_{n} x^{n}[/tex]

So a multivariate polynomial expression are [tex]\frac{7y^{2} +9x}{4}[/tex] and 6y²+ 5x.

Because in the other options:

We have a Radical of an Irrational number[tex]\sqrt{3} =3^{\frac{1}{3}}[/tex] times x (2nd option) what does not configure a polynomial.

And a Polynomial Quotient with a variable on the denominator, described by:

[tex]P(x)=\frac{Q(x)}{R(x)} \\ P(x)=q(x)*Q(x)+R(x)[/tex]

Like the last option:

[tex]\frac{7x^{2}+8}{4x}[/tex]

Hello!

The function f/g means that that f(x) is written in the numerator and g(x) is written in the denominator because we are dividing the functions f(x) and g(x). (f/g = f(x)/g(x))

f(x)/g(x) is shown as: (3x - 6)/(x - 2).

The function shown above can be factored before we find the domain, since the greatest common factor of the numerator is 3.

f(x)/g(x) = 3(x - 2)/(x - 2)

f(x)/g(x) = 3

The function y = 3 is a horizontal line, so it has a domain of all real numbers.

Therefore, f/g is 3, and its domain is all real numbers, which is choice D.

Final answer:

The quotient of the functions f(x) = 3x - 6 and g(x) = x - 2 is 3. The domain of this quotient function is all real numbers except x = 2.

Explanation:

To find the quotient of the functions f(x) = 3x - 6 and g(x) = x - 2, we divide f(x) by g(x):

f/g = (3x - 6) / (x - 2).

Simplifying the expression:

f/g = 3(x - 2) / (x - 2).

Since (x - 2) is a common factor in both the numerator and the denominator, we can cancel it out as long as x is not equal to 2 (since division by zero is undefined):

f/g = 3; for all x ≠ 2.

Therefore, the quotient of f and g is 3, and the domain of this quotient function is all real numbers except x = 2.

Answer:

A) (3, 12)

Step-by-step explanation:

For such a problem, I like to use a graphing calculator. It shows the answer quickly without a lot of fuss.

_____

If you want to solve this analytically, set the difference in y-values equal to zero and solve the resulting quadratic in the usual way. This will give the x-value at which the y-values are equal. (After we find x, we still need to find y.)

... y - y = 0

... x² -2x +9 -4x = 0

... x² -6x +9 = 0 . . . . . . collect terms. Recognize this as a perfect square.

... (x -3)² = 0

... x = 3 is the solution to this

... y = 4x = 4·3 = 12

The point on each of the given curves is (x, y) = (3, 12). The line is tangent to the parabola there, so there is only one point of intersection.

The line y = 4x and the parabola y = x^2 - 2x + 9 intersect at the point (3, 12).

To find the intersection points of the line y = 4x and the parabola y = x^2 - 2x + 9, we set the two equations equal to each other and solve for x. Hence the equation to solve is 4x = x^2 - 2x + 9. Rearranging this gives the quadratic equation x^2 - 6x + 9 = 0. This factors to (x - 3)^2 = 0, so x = 3 is the only solution, meaning the line and the parabola intersect at x = 3. Substituting x = 3 back into either the line or parabola equation gives y = 12, so the point of intersection is (3, 12).

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The value of f(12) which represents the amount of interest he will receive after 12 months is; $120.

Evidently, the sequence is an arithmetic progression;

As such, we must evaluate the common difference, d as follows;

The first term, a = $10

Therefore; From the nth term formula for an arithmetic progression;

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f(x) + n - shift a graph n units up

f(x) - n - shift a graph n units down

f(x + n) - shift a graph n units left

f(x - n) - shift a graph n units right

-------------------------------------

We have:

[tex]y=\dfrac{1}{x}\to y=\dfrac{1}{x+4}\\\\f(x)=\dfrac{1}{x}\to f(x+4)=\dfrac{1}{x+4}[/tex]

Answer:

 Total weight of the nuts bought by Dan =  5.4 kg

Explanation:

Number of packets of nuts bought by Dan = 24

Weight of each packet of nuts = 225g

 Total weight of the nuts bought by Dan = Number of packets of nuts bought by Dan * Weight of each packet of nuts

    Total weight of the nuts bought by Dan = 24 * 225 = 5400 g = 5400/1000 kg = 5.4 kg

    Total weight of the nuts bought by Dan =  5.4 kg

Answer:

D

Step-by-step explanation:

Start by subtracting 64 from both sides:

[tex]25x^2=225[/tex]

Factor this by taking roots.  Divide both sides by 25 first:

[tex]x^2=9[/tex]

We "undo" a square by taking the square roots of both sides.  Taking the square root leaves the possibilities of both the positive and negative roots of 9.  Therefore, the solutions to this are

[tex]x=\sqrt{3},-\sqrt{3}[/tex]

No! Nadia is not correct, the maximum is actually 4 hours. I know this because

4(9.75h+3)=150          distribute

39h-12=150              get the value h alone by adding 12

39h = 162                 divide both sides by 39

h=4.15

No, Nadia is incorrect, the maximum is actually 4 hours.

An equation is an expression that shows the relationship between two or more numbers and variables.

We are given that the equation below can be used to determine the number of hours, h , the 4 friends can rent bikes with $150.

4 (9.75h - 3) = 150

Solving;

4(9.75h+3)=150          

Now distribute

39h-12=150              

To get the value h alone by adding 12;

39h = 162                

Then divide both sides by 39

h=4.15

She have enough money to rent bikes for a maximum of 4 hours.

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Answer:

The statement is false because the conclusion is false.

Step-by-step explanation:

"then it is 0" is the conclusion. This is false because not all integers are 0.

Remark

Usually this is written in very simple terms. You could do it as a proportion, but it might be easier to see if you used Newton's formula twice.

Formula

F = m * a

m = mass, F = force, a = accelerationn

Givens

F1 = 70 N

a1 = 6.5 m/s^2

m = ?

F2 = ??

m = ?

a2 = 8 m/s^2

Step One

Solve for m

F1 = m * a1              Substitute the values

70 = m *  6.5           Divide by 6.5

70/6.5 = m

10.77 kg = m

Step Two

Solve for F2

m = 10.77 kg

a = 8

F2 = ??

F2 = m * a2

F2 = 10.77 * 8

F2 = 86.154

Answer: C rounded to the nearest 1/100

The answer is the first option: Even.

The explanation for this exercise is shown below:

1. By definition, if [tex]f(x)=f(-x)[/tex] the fucntion is even.

2. When the graph is symmetric with respect to the y-axis, it is an even function.

3. As you you can see in the graph attached in the problem, the graph is symmetric about the y-axis. Therefore, you can conclude it is an even function.

Answer: The total amount of bacteria present after [tex]10^3[/tex] hours is [tex]10^{14}[/tex].

Explanation:

It is given that the Strep throat is caused by Streptococcus bacteria. The amount of bacteria multiplies at a rate of 10^13 per 10^2 hrs.

[tex]10^2[/tex] hours = [tex]10^3[/tex] bacteria

The amount of bacteria in one hours is,

[tex]\text{Bacteria}=\frac{10^{13}}{10^2}[/tex]

The amount of bacteria after [tex]10^3[/tex] hours is,

[tex]\text{Bacteria}=\frac{10^{13}}{10^2}\times (10^3)[/tex]

[tex]\text{Bacteria}=10^{13}\times 10[/tex]

[tex]\text{Bacteria}=10^{14}[/tex]

Therefore, the total amount of bacteria present after [tex]10^3[/tex] hours is [tex]10^{14}[/tex].

Answer:  The correct option is  (C) [tex]2x+5y=-15.[/tex]

Step-by-step explanation:  Given that the equation of the line that passes through (-5, -1) and (10, -7) in point-slope form is given by

[tex]y+7=-\dfrac{2}{5}(x-10)~~~~~~~~~~~~~~~~~~~~~~~(i)[/tex]

We are to find the standard form of the equation for the above line.

We know that the STANDARD form of the equation of a line is given by

[tex]ax+by=c,~~~~~\textup{[a and b cannot be zero at the same time]}.[/tex]

From equation (i), we have

[tex]y+7=-\dfrac{2}{5}(x-10)\\\\\Rightarrow 5(y+7)=-2(x-10)\\\\\Rightarrow 5y+35=-2x+20\\\\\Rightarrow 2x+5y=20-35\\\\\Rightarrow 2x+5y=-15.[/tex]

Thus, the required standard form is [tex]2x+5y=-15.[/tex]

Option (C) is CORRECT.

The 8 is in the hundredths place.

Hope this helps & good luck. :)