carol has only 20p and 10p coins in her purse
she has three times as many 20p coins and 10p coins
if Carol has £4.20 altogether, how many 20p coins does she have

Here are two ways of solving this problem.

Method A. Using fractions.

You will need 3 times as much milk, so you need to multiply 3 by 2 3/4.

First, convert 2 3/4 into an improper fraction.

2 3/4 = 2 + 3/4 = 2/1 + 3/4 = 8/4 + 3/4 = 11/4

Now multiply 11/4 by 3.

3 * 11/4 = 3/1 * 11/4 = 33/4

Now convert 33/4 into a mixed numeral.

33/4 = 8 1/4

Answer: 8 1/4

Method B. Using decimals.

You will need 3 times as much milk, so you need to multiply 3 by 2 3/4.

First, convert 2 3/4 into a decimal number.

2 3/4 = 2.75

Now multiply 2.75 by 3.

3 * 2.75 = 8.25

Now convert 8.25 into a mixed numeral.

8.25 = 8 + 0.25 = 8 + 1/4 = 8 1/4

Answer: 8 1/4

Correct answer is: [tex]8\frac{1}{4}[/tex] cups milk needed if the recipe is tripled.

Solution:-

Given that a recipe calls for [tex]2\frac{3}{4}[/tex] cups of milk.

Let us convert that mixed fraction to proper fraction.

[tex]2\frac{3}{4}=\frac{2*4+3}{4}=\frac{11}{4}[/tex]

If the recipe is tripled, milk also should be tripled.

Hence amount of milk = [tex]3*\frac{11}{4}=\frac{33}{4}=8\frac{1}{4}[/tex]

[tex]2n,2n+2,2n+4\\\\\\2\cdot2n+3(2n+4)=42\\\\4n+6n+12=42\\\\10n=30\\\\n=3\\\\2n=2\cdot3=6\\2n+2=6+2=8\\2n+4=6+4=10[/tex]

6,8,10

'a' and 'b' are placeholders for some numbers. In this case, a = 3 and b = 5. So we'll replace every copy of 'a' with 3 and every copy of 'b' with 5. Afterwards, we use PEMDAS to simplify

4(a+2b) = 4*(3+2*5) = 4*(3+10) = 4*(13) = 52

Answer: 52

(a) What are you being asked to find?

the number of pounds of soil Emmanuel purchased last week

(b) Write an equation to model the problem.

Let x = amount of potting soil Emmanuel bought last week.

2x + 5 = 27

(c) How many pounds of potting soil did Emmanuel buy last week? Show the calculations

2x + 5 = 27

Subtract 5 from both sides.

2x = 22

Divide both sides by 2.

x = 11

Answer: Emmanuel bought 11 lb of potting soil last week.

I'm not sure if you were supposed to add two numbers together to get five? If that's the case the answer would be 5/3. If it's not i'm sorry, I tried.

−2^6 − 6^2 =

-64 - 36 =

-100

[tex]\sqrt{2.4^2+0.7^2}=\sqrt{5.76+0.49}=\sqrt{6.25}=2.5\\\\because\ 2.5^2=6.25[/tex]

Answer:

1,800/6

Step-by-step explanation:

if he has 6 times more songs than his mum & he has 1,800 in total his mum has 1/6 of 1,800 e.g. 1,800/6

No he did not find the right question

no he didn't find the right one

The fourth term of the arithmetic sequence 4, 8, 12, 16, 20, 24, ... is 16, which can be found either by adding the common difference to the third term or by using the formula for the nth term of an arithmetic sequence.

The fourth term of the sequence 4, 8, 12, 16, 20, 24, ... can be determined by looking at the pattern of the sequence. This sequence is an arithmetic sequence, where each term increases by the same amount, which is 4 in this case. To find the fourth term, we can simply add the common difference (4) to the third term (12), which gives us 16. Alternatively, we can use the formula for the nth term of an arithmetic sequence, which is an = a1 + (n - 1)d, where a1 is the first term, d is the common difference, and n is the term number. Using this formula with a1 = 4, d = 4, and n = 4, we again get the fourth term as 16.

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so first lets make the denominators the same so that we can divide

1/3 = 2/6

5/6

if you divide johny can make 2 cups of serving and  R 1/5

No it is not a real number

Yes, it is a number. It equals 1,000,000,000,000.

im not 100% sure but im pretty sure it is B

Final answer:

To find dy/dx for y=log(tan(2x)), we can use the chain rule: dy/dx = (2sec²(2x))/tan(2x).

Explanation:

To find dy/dx for y = log(tan(2x)), we can use the chain rule. Let's break it down step by step:

First, we identify the inner function, which is u = tan(2x).

Next, we find the derivative of the inner function with respect to x: du/dx = 2sec²(2x).

Then, we identify the outer function, which is y = log(u).

Finally, we find the derivative of the outer function with respect to u and multiply it by the derivative of the inner function with respect to x: dy/dx = (1/u) * (du/dx) = (2sec²(2x))/tan(2x).

Let the first number be = x

Then other number according to question is

4 less than 5 times the number i.e. 5x-4

Also ,sum of numbers is 32

x+5x-4=32

6x-4=32

Add 4 to both sides

6x-4+4=32+4

6x=36

Divide both sides by 6

x=36/6

x=6

First number =x =6

Other number =5(6)-4 = 30-4 =26

Answer: 26 and 6

Step-by-step explanation: Let's use two variables to represent our two numbers in this problem. Since a variable is a letter that represents any number, we can pick any letters we want to but I will use with x and y.

So if the sum of two numbers is 32, that means x + y = 32.

To solve for two separate variables, we will need two separate equations. So for the second equation, let's read through the second sentence in the problem.

"One of the numbers" that's x, "is" means equals, "4 less than 5 times the other" is not 4 - 3y, it means 5y - 4. The word "less than" switches the order around. So we now have x = 5y - 4.

So to solve this system of equations, let's use substitution. Since x = 5y - 4, we can substitute a 5y - 4 in for x in the first equation to get (5y - 4) + y = 32. Solving from here we get 6y - 4 = 32 by combining like terms. Now we can get rid of that -4 by adding 4 to both sides of the equation to get 6y = 36. Now, we will divide both sides of the equation by 6 in order to isolate y and we end up with y = 6.

To find x, plug 6 back in for y in the second equation to get x = 5 (6) -4 which we can simplify to x = 30 - 4 which simplifies to x = 26.

Therefore, our two numbers in this problem are 26 and 6.

B.  First and Second St appear to be parallel

No.

The value of 2.29 is greater than, not less than, the value 2.129.

2 and 1 are in the same location in each number: the tenths position. 2 is larger than 1 is, and thus 2.29 is larger.

Answer:

Step-by-step explanation:

8.00 to 10.00 yes the relationship is proportional because it is the eniquality between two ratios 8.00 and 10.00

Final answer:

This detailed answer explains the proportional relationship between the cost and retail price of t-shirts in the given data table, provides the equation representing the relationship, and predicts the retail price for a t-shirt costing the store $9.50.

Explanation:

a. Is the relationship proportional? Yes, the relationship is proportional because the ratio between the cost and the retail price remains constant. This can be seen by calculating the cost-to-price ratios for each pair of values. If the ratios are the same, the relationship is proportional.

b. Write an equation that represents the relationship: The equation for the relationship is y = 1.25x + 0.75 where y represents the retail price and x represents the cost to the store.

c. Predict the retail price for a t-shirt that cost the store $9.50: Substituting $9.50 for x in the equation gives us a predicted retail price of $11.88. The store is likely to charge $11.88 for a t-shirt that cost them $9.50.

You will mark down the product $29.37. So it would be 89.00-29.37=59.63

2 6/8 i think hope this helps

The solution of the given expression is n = 8.

Expressions are defined as mathematical statements that have a minimum of two terms containing variables or numbers.

Arithmetic operations can also be specified by subtracting, dividing, and multiplying built-in functions.

- Subtraction operation: Subtracts the right-hand operand from the left-hand operand.

for example 4 -2 = 2

/ Division operation: Divides left-hand operand by right-hand operand

For example 4/2 = 2

We have been given that expression as :

⇒ 6.4n - 10 = 4.4n + 6

Rearrange the likewise terms in the above expression,

⇒ 6.4n - 4.4n = 6 + 10

Apply the subtraction operation in the terms,

⇒ 2n = 16

⇒ n = 16/2

Apply the division operation in the terms,

⇒ n = 8

Therefore, the solution of the given expression is n = 8.

Learn more about the Expressions here :

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Taking Rhs

1/2 [sin(x+y)+ sin (x-y)]

using sinA + sin B = 2 cos (A+B)/2 cos( A - B)/2

1/2 [ 2 Cos ( x+y+x-y)/2 . Cos (x+y-x+y)/2]

=Cos 2x/2. Cos 2y/2 = Cos x . Cos y

Hence true

To cover one cake, we need approximately 1.33 times the amount of frosting that covers 1/8 of the container.

To find out how much frosting is needed to cover one cake, we need to find the ratio between the amount of frosting and the amount of cake that is covered. We are given that 1/8 of the frosting container covers 1/6 of the cake. To simplify this ratio, we can find a common denominator, which is 24. So, 1/8 of the frosting container is equivalent to 3/24 and 1/6 of the cake is equivalent to 4/24.

Since the ratio is now 3/24 frosting to 4/24 cake, we can say that for every 3 parts of frosting, we need 4 parts of cake. So, if we want to cover one cake, we would need 4/3 times the amount of frosting, which is approximately 1.33 times the amount of frosting needed to cover 1/8 of the container.

Therefore, to cover one cake, we need approximately 1.33 times the amount of frosting that covers 1/8 of the container.

3.6 /4

= (3.6/4) 10

= 36/40

= 0.9

Answer 0.9

Solution: The function [tex]f(x)=x^4+2x^3-5x^2-6x[/tex] is decreasing on [tex](-\infty ,-2.303]\cup [-0.5,1.303][/tex].

Explanation:

The given function is  [tex]f(x)=x^4+2x^3-5x^2-6x[/tex].

differentiate with respect to x.

[tex]f'(x)=4x^3+6x^2-10x-6[/tex]

To find the extreme points put [tex]f'(x)=0[/tex] and find the value of x.

[tex]f'(x)=4x^3+6x^2-10x-6=0[/tex]

[tex]2(2x^3+3x^2-5x-3)=0[/tex]

By hidden trial [tex]\frac{-1}{2}[/tex] is the root of the equation and [tex](x+\frac{1}{2} )[/tex] is factor of the equation.

[tex]2(x+\frac{1}{2} )(2x^2+2x-6)=0\\4(x+\frac{1}{2} )(x^2+x-3)=0\\4(x+\frac{1}{2} )(x+2.303)(x-1.303)=0[/tex]

The extreme points of graph [tex]x=-0.5, -2.303, 1.303[/tex]

The intervals are [tex](-\infty ,-2.303]\cup[-2.303,-0.5]\cup [-0.5,1.303]\cup [1.303,\infty )[/tex].

Put any value from each interval in [tex]f'(x)=4x^3+6x^2-10x-6[/tex].

If the value of [tex]f'(x)>0[/tex], then the function increase on that interval.

If the value of [tex]f'(x)<0[/tex], then the function decrease on that interval.

Since the value [tex]f'(x)<0[/tex] on [tex](-\infty ,-2.303][/tex]. and [tex][-0.5,1.303][/tex], therefore function [tex]f(x)=x^4+2x^3-5x^2-6x[/tex] is decreasing on [tex](-\infty ,-2.303]\cup [-0.5,1.303][/tex].

3x - y=0

5x + 2y=22

Solve the first equation for y

3x - y =0

-y = -3x

so y = 3x

Now plug in y=3x in second equation

5x + 2y=22

5x + 2(3x) =22

5x + 6x = 22

11x = 22

Divide by 11 on both sides

x= 2

Plug in 2  for x and find out y

y = 3x

y = 3(2) = 6

Solution is (2,6)

The graph is attached below to verify the solution

Both lines intersects at (2,6)

so our answer is correct.