2-Phenylethanol is prepared from 2-phenylethanoic acid by reducing the carboxylic acid group using lithium aluminum hydride (LiAlH4). The reaction replaces the oxygen in the carboxyl group with a hydrogen, yielding the alcohol.
The conversion of 2-phenylethanoic acid (C6H5CH2CO2H) to 2-phenylethanol (C6H5CH2CH2OH) involves a reduction reaction. One common method to achieve this transformation is to use a reducing agent, such as lithium aluminum hydride (LiAlH4). Here's the reaction:
[tex]\[ \text{C}_6\text{H}_5\text{CH}_2\text{CO}_2\text{H} + \text{LiAlH}_4 \rightarrow \text{C}_6\text{H}_5\text{CH}_2\text{CH}_2\text{OH} + \text{LiAl(OH)}_4 \][/tex]
In this equation:
- C6H5CH2CO2H represents 2-phenylethanoic acid.
- LiAlH4 is lithium aluminum hydride, a powerful reducing agent.
- C6H5CH2CH2OH represents 2-phenylethanol.
- LiAl(OH)4 is lithium aluminum tetrahydroxide, a byproduct of the reduction.
This reaction reduces the carboxylic acid group in 2-phenylethanoic acid to the alcohol group in 2-phenylethanol. The reduction involves the addition of hydrogen (H) from LiAlH4 to the carbon-oxygen double bond of the carboxylic acid, resulting in the formation of the alcohol.
The synthesis of 2-phenylethanol from 2-phenylethanoic acid involves reducing the acid to the corresponding alcohol using sodium borohydride (NaBH₄) as a reducing agent. This reaction converts the 2-phenylethanoic acid to 2-phenylethanol with the release of water.
The preparation of 2-phenylethanol (C₆H₅CH₂CH₂OH) from 2-phenylethanoic acid (C₆H₅CH₂CO₂H) can be carried out through the following steps:
Reduction of 2-phenylethanoic acid to 2-phenylethanol: This reaction involves the conversion of the acid to the corresponding alcohol. Sodium borohydride (NaBH₄) can be used as a reducing agent.2-phenylethanoic acid is reduced to 2-phenylethanol using sodium borohydride:
C₆H₅CH₂CO₂H + 4[H] → C₆H₅CH₂CH₂OH + H₂O
In this reaction, sodium borohydride (NaBH₄) serves as the source of hydrogen (H).
This completes the transformation of 2-phenylethanoic acid to 2-phenylethanol.
A student is given two metal cubes that look similar. the first had an edge length of 1.05 cm and a mass of 14.32 g, while the other had an edge length of 2.66 cm and a mass of 215.3 g. how can the student determine if these two cubes of metal are the same material using only the given data?
The value densities of cube-1 and cube-2 are not at all similar which means that both the cubes are made up of different materials.
Explanation:
Mass and volume are extensive properties of the matter which change with change in the size of matter. But density is an intensive property of a matter which is independent of the size and shape of the matter.The density of the matter is given by:[tex]Density=\frac{Mass}{Volume}[/tex]
So one can compare of values of densities of two unknowns to determine whether both are materials the same or not.Given:
Two different cubes, one with an edge length of 1.05 cm and mass of 14.32 g, and the other cube have an edge length of 2.66 cm and mass of 215.3 g.
To find:
Whether two cubes are of the same material or not.
Solution:
The edge length of the cube-1 = l = 1.05 cm
The volume of cube-1 =v
[tex]v=l^3=(1.05 cm)^3=1.16 cm^3[/tex]
Th mass of cube-1 = m = 14.32 g
The density of the cube-1 =d
[tex]d=\frac{m}{v}\\d=\frac{14.32 g}{1.16 cm^3}=12.3 g/cm^3[/tex]
The edge length of the cube-2 = l' = 2,66 cm
The volume first cube-2 =v'
[tex]v'=l'^3=(2.66 cm)^3=18.8 cm^3[/tex]
Th mass of cube-2 = m = 215.3g
The density of the cube-2 =d'
[tex]d'=\frac{m'}{v'}\\d'=\frac{215.3g}{ 18.8cm^3}=11.4g/cm^3[/tex]
The value density of cube-1 is different from that of cube-2, not at all similar which means that both the cubes are made up of different materials.
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Commercial grade hcl solutions are typically 39.0% (by mass) hcl in water. determine the molarity of the hcl, if the solution has a density of 1.20 g/ml.
Answer:
12.82 mol/L the molarity of the HCl.
Explanation:
Suppose in 100 grams of 39.0% (by mass) HCl in water.
Volume of solution = V
Density of the solution = d = 1.20 g/mL
Mass = Density × Volume
[tex]V=\frac{M}{d}=\frac{100 g}{1.20 g/mL}=83.33 mL = 0.08333 L[/tex]
Mass of HCl = 39.0% of 100 grams= [tex]\frac{39}{100}\times 100g=39 g[/tex]
Moles of HCl = [tex]\frac{39 g}{36.5 g/mol}=1.0685 mol[/tex]
[tex]Molarity=\frac{\text{Moles of compound}}{\text{Volume of solution (L)}}[/tex]
The molarity of the HCl = M
[tex]M=\frac{1.0685 mol}{0.0833 L}=12.82 mol/L[/tex]
12.82 mol/L the molarity of the HCl.
Answer:
The commercial grade of HCl solution having a density of 1.20 g/ml has the molarity of 12.8 M.
Explanation:
Let's take the volume of solution to be 1000 ml.
Mass of HCl = [tex]\rm density\;\times\;volume[/tex]
Mass = [tex]\rm 1.20\;\times\;1000[/tex]
Mass of HCl = 1200 g.
In 39 % of HCl,
mass of HCl = [tex]\rm 39\;\times\;1200[/tex]
mass of HCl = 468 grams.
Molarity = [tex]\rm \frac{moles}{Liter}[/tex]
Molarity = [tex]\rm \frac{468}{36.5}\;\times\;\frac{1}{liters}[/tex]
Moalrity = 12.8 moles/liter
Molarity of 39% HCl with a density of 1.20 g/ml is 12.8 M.
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What products are formed from monochlorination of (2r)−2−bromobutane at c1 and c4? draw the products using skeletal structures?
Scientists often investigate alternative explanations for the data and observations presented, even once a hypothesis has been tested and supported through an experiment. This investigation of alternative explanations ...
Answer:
Strengthens the evidence and support for a scientific theory.
Explanation:
Hello,
Scientific method provides a compelling tool scientists use to both develop and demonstrate new theories. As it involves both the observation and experimentation towards a specific subject of matter, it turns out convenient to consider alternative explanations substantiating such subject of matter in light of obtaining a more precise explanation for it. In such a way, this investigation of alternative explanations strengthens the evidence and support for a scientific theory.
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The reaction of 0.779 g K with O2 forms 1.417 g potassium superoxide, a substance used in self-contained breathing devices. Determine the formula for potassium superoxide.
Final answer:
The correct formula for potassium superoxide formed when 0.779 g of potassium reacts with an excess of oxygen to form 1.417 g of the compound is[tex]KO_{2}[/tex]
Explanation:
The formula for potassium superoxide can be determined by considering the mass of potassium reacted and the mass of the resultant compound formed. In this case, 0.779 grams of potassium reacts with oxygen to form 1.417 grams of potassium superoxide. Knowing that the potassium has fully reacted and become part of the potassium superoxide, we can deduce that the difference in mass (1.417 g - 0.779 g = 0.638 g) must be due to the oxygen present in the compound.
The simplest ratio between potassium (K) and oxygen (O) that could form a compound would be a 1:1 ratio, which gives us KO. However, based on the provided information, potassium superoxide has a different stoichiometry where 1 mol of potassium reacts with oxygen to form a compound with the formula [tex]KO_{2}[/tex], which is a superoxide. This means there are two oxygen atoms for every potassium atom in the compound.
Therefore, the correct formula for potassium superoxide, as formed in the reaction with an excess of oxygen, is [tex]KO_{2}[/tex].
Draw the acetal produced when ethanol adds to ethanal.
Explanation:
Acetals are geminal diethers derivatives of aldehyde formed by the addition to equivalent molecules of an alcohol and removal of water.
When ethanol is added to the ethanal in acidic medium:
Ethanal + Ethanol → Hemiacetal
Hemiacetal + Ethanol → Acetal
Acetal produced when ethanol is added to ethanal are given in the image attached.
Write and balance the chemical equation for the reaction between carbon monoxide, co(g), and oxygen to form carbon dioxide, co2(g). use only integers (not fractions) and be sure to include the states of matter.
The balanced chemical equation for the reaction between carbon monoxide (CO) and oxygen (O₂) to form carbon dioxide (CO₂) is 2 CO(g) + O₂(g) → 2 CO₂(g), adhering to the law of conservation of mass.
Explanation:The reaction between carbon monoxide (CO) and oxygen (O₂) to form carbon dioxide (CO₂) can be represented by the following balanced chemical equation:
2 CO(g) + O₂(g) → 2 CO₂(g)
In balancing this equation, it is important to ensure that the number of each type of atom on the reactants side is equal to the number on the products side. Here, we have two carbon atoms and two oxygen atoms from the CO molecules and two oxygen atoms from the O₂ molecule, giving us a total of four oxygen atoms on the reactants side, which balance with the four oxygen atoms in the two CO₂ molecules on the right side of the equation.
This reaction demonstrates the law of conservation of mass, where the mass of the reactants equals the mass of the products. In this case, the coefficients used are the smallest possible whole numbers that maintain this balance.
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Consider the reaction a + b c +
d. at biochemical equilibrium (25°c, ph of 7), the concentration of a is 0.2 m, the concentration of b is 0.2 m, the concentration of c is 0.8 m, and the concentration of d is 0.8 m. calculate δg and δg° ′ under these conditions.
Minerals form from bodies of water by the process of _____. precipitation melting cooling condensation
Minerals form from water bodies by the process of [tex]\boxed{{\text{precipitation}}}[/tex].
Further Explanation:
The formation of minerals takes place in several ways. The mineral formation depends on the physical and chemical conditions. These conditions include temperature, pressure, pH, and time.
Precipitation
It is a process by which the dissolved minerals get free from water and as a result deposits are formed. It occurs when dissolved substances come out of water. Minerals form when precipitation takes place in aqueous solutions and from gaseous emissions as in case of volcanic eruptions.
Melting
The process that results in the conversion of any substance from a solid state to the liquid state is known as melting. Another term for this process is fusion.
Cooling
The process of removal of heat by lowering the temperature of any substance is known as cooling.
Condensation
This phase transition occurs when a substance is converted from its gaseous state to the liquid state. Variations in temperature and pressure are done in order to achieve this phase change.
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Answer details:
Grade: Senior School
Chapter: Phase transition
Subject: Chemistry
Keywords: minerals, precipitation, cooling, melting, condensation, pH, temperature, time, pressure, substance, phase transition, gaseous state, liquid state, heat, dissolved minerals, water bodies.
How many grams nano3 add to 500g of h20 prepare solution .5 molal nano3?
dentify the molecule with the highest boiling point.
CHCl3
OF2
NH3
C6H6
Answer: Option (c) is the correct answer.
Explanation:
A molecule which has hydrogen bonding will have the highest boiling point. So, out of the given options only [tex]NH_{3}[/tex] will have hydrogen bonding.
Whereas in [tex]CHCl_{3}[/tex] there will be dipole-dipole interactions and no hydrogen bonding within the molecule.
In [tex]OF_{2}[/tex] and [tex]C_{6}H_{6}[/tex], there will be dipole-dipole interaction in both the molecules.
Thus, we can conclude that [tex]NH_{3}[/tex] will have the highest boiling point.
What is the acid-base equilibrium reaction between ClO– and H2O.
Approximately how many moles of boron make up 1.20 × 10^24 atoms of boron?
A. 7.22 × 10^47 moles
B. 6.02 × 10^23 moles
C. 5.00 moles
D. 1.99 moles
H2+I2= 2HI+3 kcal Based on the reaction given above, as the temperature decreases, the formation of the reactants will: A. decrease B. increase C. remained consistent D. indeterminate
the answer is A: decrease
If kc = 7.04 × 10-2 for the reaction: 2 hbr(g) ⇌h2(g) + br2(g), what is the value of kc for the reaction: 1/2 h2(g) + 1/2 br2 ⇌hbr(g)
The value of Kc for the second reaction is mathematically given as
Kc' = 3.769
What isthe value of Kc for the second reaction?
Question Parameters:
kc = 7.04 × 10-2 for the reaction
2 hbr(g) ⇌h2(g) + br2(g)
1/2 h2(g) + 1/2 br2 ⇌hbr(g)
Generally, the equation for the reaction is mathematically given as
2HBr(g) ⇄ H2(g) + Br2(g)
Therefore
Kc = [H2] [Br2] / [HBr]^2
7.04X10^-2 = [H2][Br] / [HBr]^2
Upon final reaction
Kc' = [HBr] / [H2]^1/2*[Br2]^1/2
Hence
[tex]\sqrt{(1/7.04X10^-2)}= [HBr] / [H2]^1/2*[Br]^1/2}\\\\Kc' = \sqrt{(1/7.04X10^-2)[/tex]
Kc' = 3.769
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Hexanal would be soluble in water? True or false?
Answer:
False.
Explanation:
Hexanal is a non-polar compound while water is a polar solvent.
We have the role "Like dissolves like".
So, hexanal is insoluble in water.
Write the chemical reaction that is responsible for the ph of a buffer which contains nh3 and nh4cl. write the reaction in such a way that is appropriate for a ka.
The pH of a buffer containing NH3 and NH4Cl is determined by the equilibrium between NH4+ and NH3 in water, with the reaction NH4+ (aq) + H2O(l) → H3O+ (aq) + NH3(aq). The reaction demonstrates the action of the ammonium ion as a weak acid, and its Ka is calculated using the Ka = Kw/Kb relationship. The chloride ion does not undergo significant hydrolysis, so it does not affect the pH of the buffer.
Explanation:The chemical reaction responsible for the pH of a buffer containing NH3 (ammonia) and NH4Cl (ammonium chloride) involves the equilibrium between NH4+ and NH3 in water:
NH4+ (aq) + H2O(l) ⇒ H3O+ (aq) + NH3(aq)
This represents the dissociation of the ammonium ion, which is a weak acid, in water to produce hydronium ions (H3O+) and ammonia. Since ammonia is a weak base, the corresponding acid dissociation constant (Ka) can be calculated using the relation Ka = Kw/Kb, where Kw is the ion product of water and Kb is the base dissociation constant of ammonia.
The chloride ion, being the conjugate base of the strong acid hydrochloric acid (HCl), does not undergo significant hydrolysis in water:
Cl-(aq) + H2O(l) → HCl(aq) + OH−(aq)
Since HCl is a strong acid, the equilibrium constant (Ka) for its conjugate base, Cl-, is essentially zero, which means Cl- does not affect the buffer solution's pH appreciably.
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moves river of ice fresh water made of fallen snow snow compressed to ice This is a list of features of a(n) A) glacier. B) ice age. C) iceberg. D) continent.
The answer is A. Glacier
If a propane heater burns 38.95 g C3H8, it consumes 38.95 mol C3H8. 0.8830 mol C3H8. 1 mol C3H8. 44.10 mol C3H8.
Answer:
Option-2 (0.8830 mol C₃H₈) is the correct answer.
Solution:
In statement we are given with the amount of propane gas and are asked to find out the moles for given mass.
As we know mass is related to moles as follow,
Moles = Mass / M.mass ----- (1)
Data Given:
Moles = ??
Mass = 38.95 g
M.mass = (C)3 + (H)8 = (12)3 + (1)8 = 36 + 8 = 44 g/mol
Putting values in equation 1,
Moles = 38.95 g / 44 g/mol
Moles = 0.8854 Moles
Explain why c6h5ch2ch2br is not formed during the radical bromination of c6h5ch2ch3. select the single best answer.
Final answer:
C6H5CH2CH2Br is not formed during the radical bromination of C6H5CH2CH3 because the intermediate benzyl radical, formed at the carbon adjacent to the aromatic ring, is much more stable than the primary radical needed for the other product. Selectivity is due to bromine's preference for stable radicals, supported by Hammond's postulate.
Explanation:
The reason why C6H5CH2CH2Br is not formed during the radical bromination of C6H5CH2CH3 involves the relative stability of the radical intermediate. Radical bromination tends to occur at the position that forms the most stable radical, which for a benzyl compound is the carbon atom directly adjacent to the aromatic ring. The radical formed at this position, a benzyl radical, is highly stabilized by resonance. In contrast, the radical that would be required to form C6H5CH2CH2Br is a primary radical, which is less stable and thus less likely to form. This selectivity is due to the fact that bromine radicals are relatively selective and prefer to abstract hydrogen atoms from positions that lead to more stable radical intermediates. Moreover, Hammond's postulate suggests that since the radical formation with bromine is endothermic, the transition state will more closely resemble the stable radical intermediate, leading to more selective radical formation.
The ph of 0.015 m hno2 (nitrous acid) aqueous solution was measured to be 2.63. what is the value of pka of nitrous acid?
In a molecule of methane (ch4), what type of bond joins the carbon atom to each of the hydrogen atoms?
What is the smallest particle of an element that still retains all the properties of the element? a compound a mineral an atom an isotope
The basic building block of chemistry is known as the atom. The smallest particle of an element that still retains all the properties of the element is known as the atom. The correct option is C.
What is an atom?The atom can be considered as the basic building blocks of matter which possess the properties of the chemical element. An atom don't exist independently, instead they form ions and molecules which in turn combine in large numbers to form matter.
An atom is an indivisible particle and it contains the sub-atomic particles like protons, electrons and neutrons. The positively charged particles are called protons, the negatively charged particles are called electrons. The neutrons are chargeless particles.
All atoms of the same element are identical but different elements have different types of atoms. The chemical reactions occur when the atoms are rearranged.
Thus the correct option is C.
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pls help me!!
Which of the following is a large body in space that orbits a star and does not produce its own light?
Moon
Planet
Sun
Universe
What mass of potassium hydroxide is formed when 8.2 g of potassium oxide is added to 1.3 g of water? answer key?
How many neutrons are found in Cr-54
Answer:
30
Explanation:
To find out the neutron number of an element we must first know what the mass value of that element is and the value of the atom number of that element. To find out these values, just look for the element in the periodic table. Once discovered simply subtract the values using the formula:
No. of neutrons = mass - atom number.
In the case of Cr, the mass is 54, while the atom number is 24. So we can find the number of neutrons.
Cr Neutrons = 54-24 = 30
In an experiment, you combine 83.77 g of iron with an excess of sulfur and then heat the mixture to obtain iron(III) sulfide. 2Fe(s) + 3S(s) → Fe2S3(s) What is the theoretical yield, in grams, of iron(III) sulfide?
The theoretical yield of iron (II) sulfide would be 155.92 g
Theoretical yieldIt is the total stoichiometric product from a reaction.
From the equation of the reaction:
2Fe(s) + 3S(s) → Fe2S3(s)
The mole ratio of Fe to Fe2S3 is 2:1
Mole of 83.77 g Fe = 83.77/55.85
= 1.4999 moles
Equivalent mole of Fe2S3 = 1.4999/2
= 0.75 moles
Mass of 0.75 mole Fe2S3 = 0.75 x 207.9
= 155.92 g
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For a particular first-order reaction, it takes 3.0 minutes for the concentration of the reactant to decrease to 25% of its initial value. what is the value for rate constant (in s-1) for the reaction?
For a first-order reaction, the rate constant can be determined using the concentration of the reactant at a given time. In this case, the rate constant is 0.25 s^-1.
Explanation:A first-order reaction is one in which the rate of reaction is directly proportional to the concentration of the reactant. The rate law expression for a first-order reaction is given by rate = k[A], where [A] is the concentration of the reactant and k is the rate constant.
In this case, the concentration of the reactant decreases to 25% of its initial value in 3.0 minutes. We can use this information to determine the rate constant (k).
25% of the initial concentration corresponds to 0.25 times the initial concentration, so the concentration at that time is 0.25[A]. We can substitute this value into the rate law expression and solve for k:
0.25[A] = k[A]
0.25 = k
Therefore, the value for the rate constant (k) for the reaction is 0.25 s-1.
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To find the rate constant (k) for a first-order reaction, we can use the half-life formula. The given information states that it takes 3.0 minutes for the concentration of the reactant to decrease to 25% of its initial value. By substituting these values into the equation, we can find the rate constant.
Explanation:To determine the rate constant (k) for the first-order reaction, we can use the formula for the half-life of a first-order reaction. The half-life is the amount of time it takes for the concentration of the reactant to decrease to half of its initial value. In this case, it takes 3.0 minutes for the concentration to decrease to 25% of its initial value, which is equivalent to one half-life.
The formula for the first-order half-life is: t1/2 = ln(2)/k
Since the concentration decreases to 25% of its initial value after one half-life, we can use this information to solve for k:
25% = (1/2) * 100% = e-kt1/2
ln(1/2) = -k * t1/2
k = -ln(1/2) / t1/2
Substituting the given values, we have:
k = -ln(1/2) / 3.0 minutes
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Which of the following is a part of a land based carbon cycle ?coral reefs
Crab shells
Trees
Whales
Answer:
c
Explanation:
Match the each term with its definition. 1) reaction coordinate a) the higher point on the energy curve 2) δg° b) the plot of the reaction progress as a function of time 3) δg‡ c) the free energy of the reaction