Answer: 120
Step-by-step explanation:
The total number of digits from 1 to 9 = 10
The number of digits from less than 5 (0,1,2,3,4)=5
Since repetition is not allowed so we use Permutations , then the number of 3-digit different codes will be formed :-
[tex]^5P_3=\dfrac{5!}{(5-3)!}=\dfrac{5\times4\times3\times2!}{2!}=5\times4\times3=60[/tex]
The number of digits from greater than 4 (5,6,7,8,9)=5
Similarly, Number of 3-digit different codes will be formed :-
[tex]^5P_3=60[/tex]
Hence, the required number of 3-digit different codes = 60+60=120
Why is a graph that’s symmetric with respect of X-axis is not the graph of function.
Answer:
Because every “x” value has two “y” values.
Step-by-step explanation:
In the graph of a function every value of x has one and only one value of y. So, if we draw a straight line which is parallel to y-axis and it cuts the graph in only one point, this graph will correspond to a function.
Show that if a, b e Z, then a^2 - 4b =/ 2
Step-by-step explanation:
Proposition If a, b [tex]\in[/tex] [tex]\mathbb{Z}[/tex], then [tex]a^{2}-4b \neq2[/tex]
You can prove this proposition by contradiction, you assume that the statement is not true, and then show that the consequences of this are not possible.
Suppose the proposition If a, b [tex]\in[/tex] [tex]\mathbb{Z}[/tex], then [tex]a^{2}-4b \neq2[/tex] is false. Thus there exist integers If a, b [tex]\in[/tex] [tex]\mathbb{Z}[/tex] for which [tex]a^{2}-4b=2[/tex]
From this equation you get [tex]a^{2}=4b+2=2(2b+1)[/tex] so [tex]a^{2}[/tex] is even. Since [tex]a^{2}[/tex] is even, a is even, this means [tex]a=2d[/tex] for some integer d. Next put [tex]a=2d[/tex] into [tex]a^{2}-4b=2[/tex]. You get [tex] (2d)^{2}-4b=2[/tex] so [tex]4(d)^{2}-4b=2[/tex]. Dividing by 2, you get [tex]2(d)^{2}-2b=1[/tex]. Therefore [tex]2((d)^{2}-b)=1 [/tex], and since [tex](d)^{2}-b[/tex] [tex]\in[/tex] [tex]\mathbb{Z}[/tex], it follows that 1 is even.
And that is the contradiction because 1 is not even. In other words, we were wrong to assume the proposition was false. Thus the proposition is true.
a cell phone tower that is 150 ft tall sits on a mountain that
is 1200 ft above sea level. what is the angle of depression from
the top of the tower to a cell user 5 miles away and 400 ft above
sea level?
Answer:
angle of elevation will be [tex]2.14^o.[/tex]
Step-by-step explanation:
Given,
height of tower = 150 ft
height of tower = 1200 ft
So, total height of peak of tower = 1200 + 150
= 1350 ft
distance of user from cell tower = 5 miles
= 5 x 5280 feet
= 26,400 feet
Since the height of user from sea level = 400 ft
so, height of peak of tower with respect to user = 1350 - 400 ft
= 950 ft
If the angle of depression is assumed as [tex]\theta[/tex], then we can write
[tex]tan\theta\ =\ \dfrac{\textrm{height of peak of tower w.r.t user}}{\textrm{distance of user from tower}}[/tex]
[tex]=>\ tan\theta\ =\ \dfrac{950}{26400}[/tex]
[tex]=>\ tan\theta\ =\ 0.374[/tex]
[tex]=>\ \theta\ =\ 2.14^o[/tex]
So, the angle of elevation will be [tex]2.14^o.[/tex]
Purchase likelihood 18 dash 34 35 dash 44 45 dash 54 55 plus Total More likely 223 373 384 404 1384 Less likely 26 7 26 13 72 Neither more nor less likely 285 210 169 113 777 Total 534 590 579 530 2233 (a) What is the probability that a randomly selected individual is 35 to 44 years of age, given the individual is neither more nor less likely to buy a product emphasized as "Made in our country"? The probability is approximately 0.270 0.270. (Round to three decimal places as needed.) (b) What is the probability that a randomly selected individual is neither more nor less likely to buy a product emphasized as "Made in our country," given the individual is 35 to 44 years of age? The probability is approximately nothing. (Round to three decimal places as needed.)
Answer:
(a) 0.270 . . . . as you know
(b) 0.356
Step-by-step explanation:
(a) p(35-44 | neither) = (35-44 & neither)/(neither total) = 210/777 ≈ 0.270
__
(b) p(neither | 35-44) = (neither & 35-44)/(35-44 total) = 210/590 ≈ 0.356
Find the period and amplitude of the function. y-2sin 6x Give the exact values, not decimal approximations. Period: 2 Amplitude:
Answer:
Amplitude=2
Period=[tex]\frac{\pi}{3}[/tex]
Step-by-step explanation:
We are given that [tex]y=2sin6x[/tex]
We have to find the value of period and amplitude of the given function
We know that [tex]y=a sin(bx+c)+d [/tex]
Where a= Amplitude of function
Period of sin function =[tex]\frac{2\pi}{\mid b \mid}[/tex]
Comparing with the given function
Amplitude=2
Period=[tex]\frac{2\pi}{6}=\frac{\pi}{3}[/tex]
Hence, period of given function=[tex]\frac{\pi}{3}[/tex]
Amplitude=2
Find the error with this proof and explain how it mat be corrected in order to clearly prove the equation.
Prove that if m is an odd integer, then m2 is odd.
Proposed proof: Assume m is an odd integer. By definition of odd integer, m=2k+1, for some integer k.
This means that (2k + 1)^2 = 4k^2 + 1, so m is odd.
Answer:
Step-by-step explanation:
It is true that for any given odd integer, square of that integer will also be odd.
i.e if [tex]m[/tex] is and odd integer then [tex]m^{2}[/tex] is also odd.
In the given proof the expansion for [tex](2k + 1)^{2}[/tex] is incorrect.
By definition we know,
[tex](a+b)^{2} = a^{2} + b^{2} + 2ab[/tex]
∴ [tex](2k + 1)^{2} = (2k)^{2} + 1^{2} + 2(2k)(1)\\(2k + 1)^{2} = 4k^{2} + 1 + 4k[/tex]
Now, we know [tex]4k^{2}[/tex] and [tex]4k[/tex] will be even values
∴[tex]4k^{2} + 1 + 4k[/tex] will be odd
hence [tex](2k + 1)^{2}[/tex] will be odd, which means [tex]m^{2}[/tex] will be odd.
The error in the proof is in the expansion of the square of an odd integer. The correct expansion is 4k² + 4k + 1, and adding 1 to an even number 4k² + 4k results in an odd number, proving that m² is odd when m is an odd integer.
The proposed proof has a mistake in expanding the square of an odd integer. The correct expansion of (2k + 1)² is 4k² + 4k + 1, not 4k² + 1 as stated in the proof. To correct the proof:
Assume that m is an odd integer.By definition, m can be written as 2k + 1, where k is an integer.Squaring m yields (2k + 1)² = 4k² + 4k + 1.The expression 4k² + 4k is clearly even since it's divisible by 2.Adding 1 to an even number results in an odd number. Hence, m² is odd.How many rows of 10 make 50
Answer:
5 rows.
Step-by-step explanation:
Imagine having 10 in each row. If you had 5 rows that means you have 5 groups of 10.
Answer:
Step-by-step explanation:
10 goes into 50, 5 times. I know this because if you multiply 10x5 it gives you 50!
A diver's elevation is -5 feet relative to sea level. A
school of fish is swimming at an elevation of -12 feet.
What is the difference in elevation between the diver
and the school of fish?
Answer:
-7 feet
Step-by-step explanation:
To find the difference in elevation between the diver and the school fish SUBTRACT the elevation of the diver from that of the fish
i.e. difference in elevation = -12 - (-5)
= -12 + 5
= -7 feet
Final answer:
The difference in elevation between the diver at -5 feet and the school of fish at -12 feet is 7 feet, calculated by taking the absolute value of their elevations' difference.
Explanation:
The question asks for the difference in elevation between a diver and a school of fish, with the diver at -5 feet and the fish at -12 feet relative to sea level. To find the difference in elevation, you subtract the diver's elevation from the fish's elevation.
Here is the calculation:
School of fish elevation: -12 feetDiver's elevation: -5 feetDifference in elevation: |-12 - (-5)| = |-12 + 5| = |-7| = 7 feetThe absolute value is used because we are interested in the positive difference in elevation, which is the distance between the two elevations regardless of direction.
Therefore, the difference in elevation between the diver and the school of fish is 7 feet.
Describe the differences between a histogram and a stem-and-leaf display. Check All That Apply A stem-and-leaf display describes the individual observations. A stem-and-leaf display describes the individual observations. A histogram describes the individual observations. A histogram describes the individual observations. A histogram has slightly more information than a stem-and-leaf. A histogram has slightly more information than a stem-and-leaf. A stem-and-leaf display has slightly more information than a histogram.
Answer:
Step-by-step explanation:
A steam and leaf plot is the arrangement of numerical data into different groups with place value. For eg, 17,20,21 is shown as
stem leaf
1 7
2 0,1
A histogram is a bar chart that described frequency distribution.
A stem and leaf plot displays more information than a histogram.
Hence we have the correct answers are:
A stem-and-leaf display describes the individual observations.
A stem-and-leaf display has slightly more information than a histogram.
A stem-and-leaf display provides detailed individual data points and their distribution, while a histogram offers aggregated data into bins, showing the overall data distribution without individual details.
The differences between a histogram and a stem-and-leaf display are significant in how they present data. A stem-and-leaf display retains the individual data values and is beneficial for small datasets, showing the exact values and the frequency of data for each "stem" which provides a clear view of the distribution shape. On the contrary, a histogram groups data into contiguous bins, providing a visual representation of data distribution, showing the spread and most frequent values but without detailing individual data points. Therefore, a stem-and-leaf display has slightly more information than a histogram because it describes individual observations, unlike a histogram that aggregates data into bins.
A lawyer researched the average number of years served by 45 different justices on the Supreme Court. The average number of years served was 13.8 years with a standard deviation of 7.3 years. What is the 95% confidence interval estimate for the average number of years served by all Supreme Court justices? Place your limits, rounded to 1 decimal place, in the blanks. Place you lower limit in the first blank.
Answer: [tex]11.7<\mu<15.9[/tex]
Step-by-step explanation:
Given : Significance level : [tex]\alpha:1-0.95=0.05[/tex]
Sample size : n=45
Critical value : [tex]z_{\alpha/2}=1.96[/tex]
Sample mean : [tex]\overline{x}=13.8\text{ years}[/tex]
Standard deviation : [tex]\sigma=7.3\text{ years}[/tex]
The confidence interval for population mean is given by :-
[tex]\overline{x}\pm z_{\alpha/2}\dfrac{\sigma}{\sqrt{n}}\\\\=13.8\pm(1.96)\dfrac{7.3}{\sqrt{45}}\\\\\approx13.8\pm2.1\\\\=(13.8-2.1,\ 13.8-2.1)=(11.7,\ 15.9)[/tex]
Hence, the 95% confidence interval estimate for the average number of years served by all Supreme Court justices is [tex]11.7<\mu<15.9[/tex]
Twenty girls (ages 9-10) competed in the 50-meter freestyle event at a local swim meet. The mean time was 43.70 seconds with a standard deviation of 8.07 seconds. The median time was 40.15 with an IQR of 4.98 seconds. Without looking at a graphical display, what shape would you expect the distribution of swim times to have?
The distribution of swim times from the data given would most likely be right-skewed, as the mean is larger than the median and the Interquartile Range (IQR) suggests the data is concentrated towards the middle.
Explanation:From the given data about the 50-meter freestyle event, one can deduce probable distribution shape of the swim times. Notably, the mean of 43.70 seconds significantly exceeds the median of 40.15 seconds. This fact suggests a possible right skewed distribution, with longer swim times occurring less frequently but affecting the mean more strongly due to their higher values. It's called right-skewed because the 'tail' of the distribution curve extends more towards the right.
We can also examine the Interquartile Range (IQR), which measures spread in the middle 50% of the data. This is found by subtracting the lower quartile (first 25% of data) from the upper quartile (last 25% of data). An IQR of 4.98 seconds signifies much of the data is bunched in the middle of the distribution rather than at the ends, reinforcing the notion of a skewed distribution.
Thus, without a graphical representation, the swim times would be expected to exhibit a right-skewed distribution, presenting a positive skewness in the data.
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The expected shape of the distribution of swim times would be right-skewed.
To determine the expected shape of the distribution, we compare the mean and median of the swim times:
- The mean time is 43.70 seconds, which is greater than the median time of 40.15 seconds.
- The standard deviation is 8.07 seconds, which is relatively large compared to the mean, indicating a wide spread of times.
- The interquartile range (IQR) is 4.98 seconds, which is relatively small compared to the standard deviation, suggesting that the middle 50% of the data is more tightly clustered.
In a perfectly symmetric distribution, the mean and median would be equal. However, when the mean is greater than the median, it suggests that there are some outliers or a longer tail on the right side of the distribution, pulling the mean up. The relatively large standard deviation in comparison to the IQR reinforces this idea, as it indicates there are some times that are significantly higher than the majority of the times, which are more closely packed around the median.
After calculating the sample size needed to estimate a population proportion to within 0.05, you have been told that the maximum allowable error (E) must be reduced to just 0.025. If the original calculation led to a sample size of 1000, the sample size will now have to be
Answer: 40000
Step-by-step explanation:
The formula to find the sample size is given by :-
[tex]n=p(1-p)(\dfrac{z_{\alpha/2}}{E})^2[/tex], where p is the prior estimate of the population proportion.
Here we can see that the sample size is inversely proportion withe square of margin of error.
i.e. [tex]n\ \alpha\ \dfrac{1}{E^2}[/tex]
By the equation inverse variation, we have
[tex]n_1E_1^2=n_2E_2^2[/tex]
Given : [tex]E_1=0.05[/tex] [tex]n_1=1000[/tex]
[tex]E_2=0.025[/tex]
Then, we have
[tex](1000)(0.05)^2=n_2(0.025)^2\\\\\Rightarrow\ 2.5=0.000625n_2\\\\\Rightarrow\ n_2=\dfrac{2.5}{0.000625}=4000[/tex]
Hence, the sample size will now have to be 4000.
The new sample size will have to be approximately 4000.
The formula to calculate the sample size (n) needed to estimate a population proportion with a given maximum allowable error (E) and confidence level (usually 95% or 1.96 standard deviations for a two-tailed test) is given by:
[tex]\[ n = \left(\frac{z \times \sigma}{E}\right)^2 \][/tex]
Given that the original maximum allowable error was 0.05 and the sample size calculated was 1000, we can set up the equation:
[tex]\[ 1000 = \left(\frac{1.96 \times 0.5}{0.05}\right)^2 \][/tex]
Now, we want to find the new sample size when the maximum allowable error is reduced to 0.025. The new sample size can be calculated by:
[tex]\[ n_{new} = \left(\frac{z \times \sigma}{E_{new}}\right)^2 \][/tex]
Since \( z \) and[tex]\( \sigma \)[/tex] remain constant, and only \( E \) changes, the relationship between the original sample size and the new sample size is inversely proportional to the square of the ratio of the original error to the new error:
[tex]\[ n_{new} = n_{old} \times \left(\frac{E_{old}}{E_{new}}\right)^2 \] \[ n_{new} = 1000 \times \left(\frac{0.05}{0.025}\right)^2 \] \[ n_{new} = 1000 \times \left(\frac{0.05}{0.025}\right)^2 \] \[ n_{new} = 1000 \times \left(2\right)^2 \] \[ n_{new} = 1000 \times 4 \] \[ n_{new} = 4000 \][/tex]
Therefore, the new sample size will have to be approximately 4000 to reduce the maximum allowable error to 0.025."
Mr Barkley has a box of books. He says the number of books in the box is divisible by 2,3,4,5 and 6. How many books could be in the box? Add another factor so there is only one possible solution.
Answer:
The number of books in the box is 60.
Step-by-step explanation:
Since it is given that the number of books in the box is divisible by 2,3,4,5 and 6.
So, the number of books in the box is multiple of these numbers.
Thus we have to find Least Common Multiple (L.C.M.) of these number
L.C.M. of (2,3,4,5,6) = 60
Thus the number of books in the box is multiples of 60 i.e. 60, 120, 180, 240,... etc.
The other factor that can we add in statement so there is only one possible solution is: "The number of books in the box is smallest number divisible by 2,3,4,5 and 6".
Answer:
The number is 60
Step-by-step explanation:
So the first way to solve this would be to multiply the greatest numbers in the sequence, you have 5 and 6, the result is 30, since 30 is not divisible by 4 you need to find the next number that is divisible by 5 and 6, that would be 60, since 60 is divisible by 4, then that is the answer, 60 is the first number that is divisible by 2, 3, 4, 5, and 6.
Using a formula estimate the body surface area of a person whose height is 5 feet and who weighs 120 pounds.
A.
1.52 m2
B.
0.32 m2
C.
1.13 m2
D.
55.9 m2
Answer:
(A) 1.52 m²
Step-by-step explanation:
As per the given data of the question,
Height of a person = 5 feet
As we know that 1 feet = 30.48 cm
∴ Height = 152.4 cm
Weight of a person = 120 pounds
And we know that 1 pound = 0.453592 kg
∴ Weight = 54.4311 kg
The Mosteller formula to calculate body surface area (BSA):
[tex]BSA(m^{2})=\sqrt{\frac{Height (cm)\times Weight(kg)}{3600}}[/tex]
Therefore,
[tex]BSA=\sqrt{\frac{Height (cm)\times Weight(kg)}{3600}}[/tex]
[tex]BSA=\sqrt{\frac{152.4\times 54.4311}{3600}}[/tex]
[tex]BSA= 1.517 m^{2} = 1.52 m^{2}[/tex]
Hence, the body surface area of a person = 1.52 m²
Therefore, option (A) is the correct option.
Which of the following is equivalent to the set {Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday}?
(you may select more than one)
Question 4 options:
{x | x is one of the seven wonders of the ancient world}
{x | x is one of the six nobel prize categories}
{x | x is the number of humans who can breathe unassisted underwater}
{x | x is a letter of the alphabet
{x | x is one of the two lead singers of Van Halen}
{x | x is a day of the week}
Answer:
The answer is: {x | x is a day of the week}
Step-by-step explanation:
The mathematical expression {x | x is a day of the week}, uses set theory notation and can be translated as: The set of all x such that x is a day of the week. Since the original set contains all days of the week, therefore it is equivalent to the expression {x | x is a day of the week}.
Final answer:
The correct equivalent set to { Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday} is {x | x is a day of the week}, as both sets contain the days of the week.
Explanation:
The student has asked which option is equivalent to the set {Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday}. This set represents the seven days of the week. Therefore, the correct option that is equivalent to this set is {x | x is a day of the week}. All other options listed represent different sets with no connection to the days of the week. When comparing sets for equivalence, we look for a one-to-one correspondence between the members of each set, which is only present in the option directly referring to days of the week.
List all element of the following sets
a. { 1/n ∣ n ∈ { 3 , 4 , 5 , 6 } }
b. {x∈Z ∣ x=x+1}
c. {n∈P ∣ n is a factor of 24 }
Answer:
a) The elements are [tex]\frac{1}{3},\frac{1}{4},\frac{1}{5},\frac{1}{6}[/tex]
b) The elements are (-∞ ...-1,0,1,2,..∞).
c) The elements are 2 and 3.
Step-by-step explanation:
To find : List all element of the following sets ?
Solution :
a) [tex]\{\frac{1}{n}| n\in \{ 3 , 4 , 5 , 6 \} \}[/tex]
Here, The function is [tex]f(n)=\frac{1}{n}[/tex]
Where, [tex]n\in \{ 3 , 4 , 5 , 6 \}[/tex]
Substituting the values to get elements,
[tex]f(3)=\frac{1}{3}[/tex]
[tex]f(4)=\frac{1}{4}[/tex]
[tex]f(5)=\frac{1}{5}[/tex]
[tex]f(6)=\frac{1}{6}[/tex]
The elements are [tex]\frac{1}{3},\frac{1}{4},\frac{1}{5},\frac{1}{6}[/tex]
b) [tex]\{x\in \mathbb{Z} | x=x+1\}[/tex]
Here, The function is [tex]f(x)=x+1[/tex]
Where, [tex]x\in \mathbb{Z}[/tex] i.e. integers (..,-2,-1,0,1,2,..)
For x=-2
[tex]f(-2)=-2+1=-1[/tex]
For x=-1
[tex]f(-1)=-1+1=0[/tex]
For x=0
[tex]f(0)=0+1=1[/tex]
For x=1
[tex]f(1)=1+1=2[/tex]
For x=2
[tex]f(2)=2+1=3[/tex]
The elements are (-∞ ...-1,0,1,2,..∞).
c) [tex]\{n\in \mathbb{P}| \text{n is a factor of 24}\}[/tex]
Here, The function is n is a factor of 24.
Where, n is a prime number
Factors of 24 are 1,2,3,4,6,8,12,24.
The prime factor are 2,3.
The elements are 2 and 3.
Use a truth table to verify the first De Morgan law (p ∧ q)’ ≡ p’ ∨ q’.
Answer:
(p ∧ q)’ ≡ p’ ∨ q’
Step-by-step explanation:
First, p and q have just four (4) possibilities, p∧q is true (t) when p and q are both t.
p ∧ q
t t t
t f f
f f t
f f f
next step is getting the opposite
(p∧q)'
f
t
t
t
Then we get p' V q', V is true (t) when the first or the second is true.
p' V q'
f f f
f t t
t t f
t t t
Let's compare them, ≡ is true if the first is equal to the second one.
(p∧q)' ≡ (p' V q')
f f
t t
t t
t t
Both are true, so
(p ∧ q)’ ≡ p’ ∨ q’
A swimmer bounces straight up from a diving board and falls feet first into a pool. She starts with a velocity of 4.00 m/s, and her takeoff point is 1.20 m above the pool. (a) How long are her feet in the air? .3 Incorrect: Your answer is incorrect. s (b) What is her highest point above the board? m (c) What is her velocity when her feet hit the water? m/s
The height of the swimmer's feet in the air at time [tex]t[/tex] is given according to
[tex]y=1.20\,\mathrm m+\left(4.00\dfrac{\rm m}{\rm s}\right)t-\dfrac g2t^2[/tex]
where [tex]g[/tex] is the magnitude of the acceleration due to gravity (taken here to be 9.80 m/s^2).
a. Solve for [tex]t[/tex] when [tex]y=0[/tex]:
[tex]1.20\,\mathrm m+\left(4.00\dfrac{\rm m}{\rm s}\right)t-\dfrac g2t^2=0\implies\boxed{t=1.05\,\mathrm s}[/tex]
(The other solution is negative; ignore it)
b. At her highest point [tex]y_{\rm max}[/tex], the swimmer has zero velocity, so
[tex]-\left(4.00\dfrac{\rm m}{\rm s}\right)^2=-2g(y_{\rm max}-1.20\,\mathrm m)\implies\boxed{y_{\rm max}=2.02\,\mathrm m}[/tex]
c. Her velocity at time [tex]t[/tex] is
[tex]v=4.00\dfrac{\rm m}{\rm s}-gt[/tex]
After 1.05 s in the air, her velocity will be
[tex]v=4.00\dfrac{\rm m}{\rm s}-g(1.05\,\mathrm s)\implies\boxed{v=-6.29\dfrac{\rm m}{\rm s}}[/tex]
The swimmer's feet are in the air for approximately 0.816 seconds. Her highest point above the diving board is approximately .43 m. She hits the water with a velocity of approximately -8.00 m/s.
Explanation:To answer these questions, we need to use physics equations that describe motion. The swimmer's motion can be broken down into two parts - the upward motion and the downward motion. Let's discuss each with respect to the provided variables.
(a) How long are her feet in the air?
To calculate the time, we can use the equation of motion given by: t = (v_f - v_i)/g where v_f is the final velocity (which is 0 at the highest point), v_i is the initial velocity (4.00 m/s), and g is the acceleration due to gravity (approx -9.81m/s²). The time taken for the upwards journey is: t = (0 - 4)/-9.81 ≈ 0.408 seconds. Since motion up and motion down take the same amount of time, we double this to get the total time: 2*0.408 = 0.816 seconds.
(b) What is her highest point above the board?
Let's use the equation h = v_i * t + 0.5*g*t², where h is the height, t is the time (0.408 seconds), g is the gravity (-9.81 m/s²), and v_i is the initial velocity (4.00 m/s). The highest point above the board is: h = 4*0.408 + 0.5*-9.81* (0.408)² = 1.63 m above the water surface or .43 m above the diving board.
(c) What is her velocity when her feet hit the water?
Here, we can repurpose the equation v_f = v_i + g*t. Notice that the time here is the total time her feet were in the air (0.816 seconds). Using these values we get: v_f = 0 + (-9.81 * 0.816) = -8.00 m/s. She hits the water at a speed of 8.00 m/s.
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What is the probability of selecting an ace of diamonds from a deck of cards?
5/52
1/52
4/52
1/13
The numbers 2, 4, 6, and 8 are a set of four consecutive even numbers. Suppose the sum of five consecutive numbers is 320. What is the smallest of the five numbers?
The smallest of five consecutive numbers, whose sum equals 320, is 62. This is determined by setting up an equation where the sum of these numbers equals 320, then solving for the smallest number 'n'.
Explanation:The subject at hand involves understanding patterns within consecutive numbers (numbers that follow each other in order, without gaps). In the given example of four consecutive even numbers 2, 4, 6 and 8, we see that the difference between them is constantly 2.
When it comes to the sum of five consecutive numbers equating to 320, let's presume the first (and smallest) number is 'n'. Therefore, the consecutive numbers would be n, (n+1), (n+2), (n+3) and (n+4). Their sum ought to total 320, so we write the expression n + (n+1) + (n+2) + (n+3) + (n+4) = 320. By simplifying, we receive 5n+10 = 320.
Further simplifying, we subtract 10 from both sides to afford: 5n = 310. Divide 310 by 5 to isolate 'n', which results in 'n' equals 62. Consequently, the smallest of the five consecutive numbers is 62.
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An amount of $15,000 is invested in a fund that has a return of
6%. How much money is invested in a fund with a 4% return if the
total return on both investments is $1380?
Answer:
$12000 should be invested in a fund with a 4% return.
Step-by-step explanation:
Consider the provided information.
An amount of $15,000 is invested in a fund that has a return of 6%.
We need to calculate how much money is invested in a fund with a 4% return if the total return on both investments is $1380.
Let $x should be invested in a fund with a 4% return.
The above information can be written as:
[tex]1380=15000\times 6\%+x\times 4\%[/tex]
[tex]1380=15000\times \frac{6}{100}+x\times \frac{4}{100}[/tex]
[tex]1380=150\times6+x\times 0.04[/tex]
[tex]1380-900=0.04x\\480=0.04x\\x=12000[/tex]
Hence, $12000 should be invested in a fund with a 4% return.
prove that |a| < b if and only if -b < a < b
Answer:
Since,
[tex]|x|=\left\{\begin{matrix}x &\text{ if } x \geq 0 \\ -x &\text{ if } x < 0\end{matrix}\right.[/tex]
Here, the given equation is,
|a| < b
Case 1 : if a ≥ 0,
|a| < b ⇒ a < b
Case 2 : If a < 0,
|a| < b ⇒ -a < b ⇒ a > - b
( Since, when we multiply both sides of inequality by negative number then the sign of inequality is reversed. )
|a| < b ⇒ a < b or a > - b ⇒ -b < a < b
Conversely,
If -b < a < b
⇒ a < b or a > - b
⇒ a < b or -a < b
⇒ |a| < b
Hence, proved..
least to greatest
-4/5, -5/4, -4.5, -0.54, -5, -0.4
Answer:
[tex]-5[/tex], [tex]-4.5[/tex], [tex]-\frac{5}{4}[/tex], [tex]-\frac{4}{5}[/tex], [tex]-0.54[/tex] and [tex]-0.4[/tex].
Step-by-step explanation:
We are asked to write the given numbers from least to greatest.
-4/5, -5/4, -4.5, -0.54, -5, -0.4
We know that the more negative number has least value.
Let us convert each number into decimal.
[tex]-\frac{4}{5}=-0.8[/tex]
[tex]-\frac{5}{4}=-1.25[/tex]
We can see that -5 is most negative, so it will be least.
Order from more negative to less negative:
[tex]-5[/tex], [tex]-4.5[/tex], [tex]-1.25[/tex], [tex]-0.8[/tex], [tex]-0.54[/tex] and [tex]-0.4[/tex].
Therefore, the least to greatest numbers would be [tex]-5[/tex], [tex]-4.5[/tex], [tex]-\frac{5}{4}[/tex], [tex]-\frac{4}{5}[/tex], [tex]-0.54[/tex] and [tex]-0.4[/tex].
Let a,b,,c and x elements in the group G. In each of the following solve for x in terms of a,b,c, and c.
Solve simultaneously x^2 a=bxc^-1 and acx=xac.
Answer with Step-by-step explanation:
We are given that a, b, c and x are elements in the group G.
We have to find the value of x in terms of a, b and c.
a.[tex]x^2a=bxc^{-1}[/tex]
[tex]x^2ac=bxc^{-1}c=bx[/tex]
[tex]x^{-1}x^2ac=x^{-1}bx=b[/tex] ([tex]x^{-1}bx=b[/tex])
[tex]xac=b[/tex]
[tex]xacc^{-1}=bc^{-1}[/tex]
[tex]xa=bc^{-1}[/tex] ([tex]cc^{-1}=[/tex])
[tex]xaa^{-1}=bc^{-1}a^{-1}[/tex]
[tex]x=bc^{-1}a^{-1}[/tex]
b.[tex]acx=xac[/tex]
[tex]acxc^{-1}=xacc^{-1}=xa[/tex] ([tex]cc^{-1}=1,cxc^{-1}=x[/tex])
[tex]axa^{-1}=xaa^{-1}[/tex] ([tex]aa^{-1}=1,axa^{-1}=x[/tex])
[tex]x=x[/tex]
Identity equation
Hence, given equation has infinite solution and satisfied for all values of a and c.
Proof by Contradiction : Show that √ 2 is irrational.
Answer:
[tex]\sqrt2[/tex] is irrational
Step-by-step explanation:
Let us assume that [tex]\sqrt2[/tex] is rational. Thus, it can be expressed in the form of fraction [tex]\frac{x}{y}[/tex], where x and y are co-prime to each other.
[tex]\sqrt2[/tex] = [tex]\frac{x}{y}[/tex]
Squaring both sides,
[tex]2 = \frac{x^2}{y^2}[/tex]
Now, it is clear that x is an even number. So, let us substitute x = 2u
Thus,
[tex]2 = \frac{(2u)^2}{y^2}\\y^2 = 2u^2[/tex]
Thus, [tex]y^2[/tex]is even, which follows the fact that y is also an even number. But this is a contradiction as x and y have a common factor that is 2 but we assumed that the fraction [tex]\frac{x}{y}[/tex] was in lowest form.
Hence, [tex]\sqrt2[/tex] is not a rational number. But [tex]\sqrt2[/tex] is a an irrational number.
Two fair dice are tossed, and the up face on each die is recorded. Find the probability of observing each of the following events. Answer in fraction form or decimal approximation with 4 decimal places: A:{A:{ A 5 does not appear on either die }} B:{B:{ The difference of the numbers is 2 }} C:{C:{ The sum of the numbers is 10 or more }
Step-by-step explanation:
When two dies are tossed, possible outcomes are (1,1) (1,2) ,(1,3) (1,4), (1,5) (1,6),(2,1) (2,2) (2,3) (2,4) (2,5) (2,6), (3,1)(3,2)(3,3)(3,4),(3,5)(3,6)(4,1) (4,2),(4,3)(4,4)(4,5)(4,6)(5,1)(5,2)(5,3)(5,4)(5,5)(5,6)(6,1)(6,2)(6,3)(6,4)(6,5)(6,6)
so the total sample space =36
From de possible outcome, probability of getting a die that five does not appear on either side is given by total outcome of not getting five from either side/sample space
=30/36 = 5/6
And also probability of getting the difference of numbers to be 2 are (3,1)(4,2) (5,3) (6,4) =4outcomes
the probability of getting a difference of 2 is given by outcome/sample space 4/36 = 1/9
probability of getting the summation of two numbers to be equal to or greater than ten are; Outcome/sample space.
the outcome are (4,6) (5,5) (5,6)(6,4)(6,5)and (6,6)= 6outcomes
=6/36 =1/12.
The probabilities for the three events are approximately 0.6944, 0.2222, and 0.1667 respectively. These figures were achieved by comparing the number of favorable outcomes to the total number of outcomes when rolling two dice.
Explanation:The subject of this question is probability which involves using numbers for calculation. When you roll two dice, there are 36 possible outcomes.
Event A: The probability that a 5 does not appear on either die can be calculated by subtracting the outcomes where one or both dice show five (11 outcomes) from total outcomes. So the probability is (36-11)/36, or around 0.6944 as a decimal approximation.Event B: The difference of the numbers is 2 happens in 8 cases (3 and 1, 4 and 2, 5 and 3, 6 and 4, 1 and 3, 2 and 4, 3 and 5, 4 and 6). So the probability is 8/36, which simplifies to 2/9 or around 0.2222 in decimal approximation.Event C: The sum of the numbers is 10 or more happens in 6 cases (5 and 5, 6 and 4, 4 and 6, 6 and 5, 5 and 6, 6 and 6). So the probability is 6/36, which simplifies to 1/6 or around 0.1667 in decimal approximation.
Learn more about probability here:
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Solve the system using either Gaussian elimination with back-substitution or Gauss-Jordan elimination. (If there is no solution, enter NO SOLUTION. If there are an infinite number of solutions, set x3 and solve for x1 and x2. x1-3x3 =-5 3x1 X2 2x34 2x1 + 2x2 + x3 = 7 Need Help? Read It Talk to a Tutor Submit Answer Save Progress Practice Another Version 1 points LarLinAlg8 1.2.033 Solve the system using either Gaussian elimination with back-substitution or Gauss-Jordan elimination. (If there is no solution, enter NO SOLUTION. If the system has an infinite number of solutions, express x, x2, and x3 in terms of the parameter t.) My Notes Ask Your Teach 2x1+ 4x1-3x2 + 7x3 = 2 8x1 - 9x2 15x3 12 3x33 (x1, x2, x3) -
Therefore, the solution to the system of equations is:
x=0
y=-3t+4
z=t
We can solve the system of equations using Gaussian elimination with back-substitution. Here's how:
Steps to solve:
1. Eliminate x from the second and fourth equations:
x+y+3z=4
0=0 (2x+5y+15z=20)-(x+2y+6z=8)
3y+9z=12
-x+2y+6z=8
2. Eliminate y from the fourth equation:
x+y+3z=4
0=0
3y+9z=12
3y+9z=12 (3y+9z=12)-(3y+9z=12)
0=0
3. Since the last equation is always true, we can ignore it.
4. Solve the remaining equations:
x+y+3z=4
0=0
3y+9z=12
From the second equation, we know that y=-3z+4. Substituting this into the first equation, we get:
x+(-3z+4)+3z=4
x+4=4
x=0
Now that we know x=0, we can substitute it back into the third equation to solve for z:
3(-3z+4)+9z=12
-9z+12+9z=12
12=12
This equation is always true, so there are infinitely many solutions. We can express x, y, and z in terms of the parameter t as follows:
x=0
y=-3z+4
z=t
Complete Question:
Solve the system using either Gaussian elimination with back-substitution or Gauss-Jordan elimination. (If there is no solution, enter NO SOLUTION. If the system has an infinite number of solutions, express x, y, and z in terms of the parameter t.)
3x + 3y + 9z = 12
x + y + 3z = 4
2x + 5y + 15z = 20
-x + 2y + 6z = 8
(x, y, z) =
On three examinations, you have grades of 85, 78, and 84. There is still a final examination, which counts as one grade In order to get an A your average must be at least 90. If you get 100 on the final, what is your numerical average? (Type an integer or a decimal)
Answer:
The average of the provided grades are 86.75
Step-by-step explanation:
Consider the provided information.
On three examinations, you have grades of 85, 78, and 84. In order to get an A your average must be at least 90.
In the last exam you get 100 marks now calculate the average by using the formula:
[tex]\frac{\text{Sum of observations}}{\text{Number of observations}}[/tex]
[tex]\frac{85+78+84+100}{5}[/tex]
[tex]\frac{347}{5}[/tex]
[tex]86.75[/tex]
86.75 is less than 90 so you will not get A.
The average of the provided grades are 86.75
Find the distance between a point (– 2, 3 – 4) and its image on the plane x+y+z=3 measured parallel to a line
(x + 2)/3 = (2y + 3)/4 = (3z + 4)/5
Answer:
The distance is:
[tex]\displaystyle\frac{3\sqrt{142}}{10}[/tex]
Step-by-step explanation:
We re-write the equation of the line in the format:
[tex]\displaystyle\frac{x+2}{3}=\frac{y+\frac{3}{2}}{2}=\frac{z+\frac{4}{3}}{\frac{5}{3}} [/tex]
Notice we divided the fraction of y by 2/2, and the fraction of z by 3/3.
In that equation, the director vector of the line is built with the denominators of the equation of the line, thus:
[tex]\displaystyle\vec{v}=\left< 3, 2, \frac{5}{3}\right> [/tex]
Then the parametric equations of the line along that vector and passing through the point (-2, 3, -4) are:
[tex]x=-2+3t\\y=3+2t\\\displaystyle z=-4+\frac{5}{3}t[/tex]
We plug them into the equation of the plane to get the intersection of that line and the plane, since that intersection is the image on the plane of the point (-2, 3, -4) parallel to the given line:
[tex]\displaystyle x+y+z=3\to -2+3t+3+2t-4+\frac{5}{3}t=3[/tex]
Then we solve that equation for t, to get:
[tex]\displaystyle \frac{20}{3}t-3=3\to t=\frac{9}{10}[/tex]
Then plugging that value of t into the parametric equations of the line we get the coordinates of the intersection:
[tex]\displaystyle x=-2+3\left(\frac{9}{10}\right)=\frac{7}{10}\\\displaystyle y=3+2\left(\frac{9}{10}\right)=\frac{24}{5} \\\displaystyle z=-4+\frac{5}{3}\left(\frac{9}{10}\right)=-\frac{5}{2}[/tex]
Then to find the distance we just use the distance formula:
[tex]\displaystyle d=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2+(z_1-z_2)^2}[/tex]
So we get:
[tex]\displaystyle d=\sqrt{\left(-2-\frac{7}{10}\right)^2+\left(3-\frac{24}{5}\right)^2+\left(-4 +\frac{5}{2}\right)^2}=\frac{3\sqrt{142}}{10}[/tex]
A = ( −2 −1 2 −2 2 3 −4 1 3 ) b = ( −1 −1 4 ) x = ( x1 x2 x3 ) (a) (2 pts) Write down the augmented matrix (A|b). (b) (4 pts) Use Gauss-Jordan elimination to find the Reduced Row Echelon Form (RREF) of the augmented matrix. (c) (2 pts) What is the rank of A? What is the rank of (A|b) (d) (2 pts) State whether the system is consistent or inconsistent. State how many solutions the system has; if there is/are a solution/s, write it/them down.
Answer:
The augmented matrix is [tex]\left[\begin{array}{ccc|c}-2&-1&2&-1\\-2&2&3&-1\\-4&1&3&4\end{array}\right][/tex]
The Reduced Row Echelon Form of the augmented matrix is [tex]\left[\begin{array}{cccc}1&0&0&-3\\0&1&0&1\\0&0&1&-3\end{array}\right][/tex]
The rank of matrix (A|B) is 3
The system is consistent and the solutions are [tex]x_{1}= -3, x_{2} = 1, x_{3}= -3[/tex]
Step-by-step explanation:
We have the following information:
[tex]A=\left[\begin{array}{ccc}-2&-1&2\\-2&2&3\\-4&1&3\end{array}\right], X=\left[\begin{array}{c}x_{1}&x_{2}&x_{3}\end{array}\right] and \:B=\left[\begin{array}{c}-1&-1&4\end{array}\right][/tex]
1. The augmented matrix is
We take the matrix A and we add the matrix B we use a vertical line to separate the coefficient entries from the constants.
[tex]\left[\begin{array}{ccc|c}-2&-1&2&-1\\-2&2&3&-1\\-4&1&3&4\end{array}\right][/tex]
2. To transform the augmented matrix to the Reduced Row Echelon Form (RREF) you need to follow these steps:
Row operation 1: multiply the 1st row by -1/2[tex]\left[\begin{array}{cccc}1&1/2&-1&1/2\\-2&2&3&-1\\-4&1&3&4\end{array}\right][/tex]
Row Operation 2: add 2 times the 1st row to the 2nd row[tex]\left[\begin{array}{cccc}1&1/2&-1&1/2\\0&3&1&0\\-4&1&3&4\end{array}\right][/tex]
Row Operation 3: add 4 times the 1st row to the 3rd row[tex]\left[\begin{array}{cccc}1&1/2&-1&1/2\\0&3&1&0\\0&3&-1&6\end{array}\right][/tex]
Row Operation 4: multiply the 2nd row by 1/3[tex]\left[\begin{array}{cccc}1&1/2&-1&1/2\\0&1&1/3&0\\0&3&-1&6\end{array}\right][/tex]
Row Operation 5: add -3 times the 2nd row to the 3rd row[tex]\left[\begin{array}{cccc}1&1/2&-1&1/2\\0&1&1/3&0\\0&0&-2&6\end{array}\right][/tex]
Row Operation 6: multiply the 3rd row by -1/2[tex]\left[\begin{array}{cccc}1&1/2&-1&1/2\\0&1&1/3&0\\0&0&1&-3\end{array}\right][/tex]
Row Operation 7: add -1/3 times the 3rd row to the 2nd row[tex]\left[\begin{array}{cccc}1&1/2&-1&1/2\\0&1&0&1\\0&0&1&-3\end{array}\right][/tex]
Row Operation 8: add 1 times the 3rd row to the 1st row[tex]\left[\begin{array}{cccc}1&1/2&0&-5/2\\0&1&0&1\\0&0&1&-3\end{array}\right][/tex]
Row Operation 9: add -1/2 times the 2nd row to the 1st row[tex]\left[\begin{array}{cccc}1&0&0&-3\\0&1&0&1\\0&0&1&-3\end{array}\right][/tex]
3. What is the rank of (A|B)
To find the rank of a matrix, we simply transform the matrix to its row echelon form and count the number of non-zero rows.
Because the row echelon form of the augmented matrix has three non-zero rows the rank of matrix (A|B) is 3
4. Solutions of the system
This definition is very important: "A system of linear equations is called inconsistent if it has no solutions. A system which has a solution is called consistent"
This system is consistent because from the row echelon form of the augmented matrix we find that the solutions are (the last column of a row echelon form matrix always give you the solution of the system)
[tex]x_{1}= -3, x_{2} = 1, x_{3}= -3[/tex]