Help me find the andwer.

d=discount tickets

f=full price tickets

d=f+180  (180 more full price tickets than discount tickets)

f+d=240

Answer:

b is the answer

Step-by-step explanation:

f + d = 240

f - d = 180

$12 per ticket divide 48 and 4 then if u want multipy 4x12=48

We are required to find the cost of 5 movie tickets

The Cost of 5 movie tickets is $60

Given:

Cost of 4 movie tickets = $48

Cost of each movie tickets = Cost of 4 movie tickets ÷ 4

= $48 ÷ 4

= $12

So,

Cost of 5 movie tickets = Cost of each movie tickets × 5

= $12 × 5

= $60

Therefore, the Cost of 5 movie tickets is $60

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The formula for arc length is:

s= r∅

Given that ∅= 7π/4

and r= 5

Therefore, arc length s= 7π/4 *5 = 35π/4

Answer:  The required arc length will be 27.5 units.

Step-by-step explanation:  We are given to find the arc length with the following information :

[tex]\theta=\dfrac{7\pi}{4},~~~\textup{radius},~r=5.[/tex]

We know that the length of an arc with angle subtended at the center α and radius of the circle r units is given by

[tex]\ell=r\alpha.[/tex]

Therefore, the required arc length will be

[tex]\ell=r\theta=5\times\dfrac{7\pi}{4}=\dfrac{35}{4}\times \dfrac{22}{7}=\dfrac{5\times 11}{2}=\dfrac{55}{2}=27.5.[/tex]

Thus, the required arc length will be 27.5 units.

Answer:  A. 10

Step-by-step explanation:

because its the right answer

The equation of a hyperbola is x^2/24^2 - y^2/ (10)^2= 1.

We have given that, The equation x^2/24^2 - y^2/ (b)^2= 1 represents a hyperbola centered at the origin with a directrix of x = 576/26.

We have to find the value of b.

[tex]\frac{(x-h)^2}{a^2} -\frac{(y-k)^2}{b^2} =1[/tex]

We have given that,

[tex]x^2/24^2 - y^2/ (b)^2= 1 \implies \frac{(x-0)^2}{24} -\frac{(y-0)^2}{b^2} =1[/tex]

a=24,h=0 and k=0

Now equation of the directrix

x=a^2/c...(1)

and we know x=576/26...(2)

Therefore from 1 and 2 we get

24^2/c=576/26.

isolate the c so we get,

C=26

C= center of focii

[tex]c=\sqrt{a^2+b^2} \\c^2=a^2+b^2\\b^2=c^2-a^2\\b=10[/tex]

So we get the value of b is 10.

Therefore the equation of a hyperbola is x^2/24^2 - y^2/ (10)^2= 1.

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Let f(n) represent the number of bottles in the store on n-th week.

When n=0, f(n)=250.

Then  40% of the bottles were sold, this means that were sold 250·0.4=f(n)·0.4. The amount of bottles left is 250-250·0.4=f(n)-f(n)·0.4=f(n)·0.6.

If 48 new bottles arrived in shipments, then the amount of bottles became

f(n)·0.6+48=f(n+1).

Since n>0, then

f(n)=f(n-1)·0.6+48.

Answer: correct choice is A.

Option: A is the correct answer.

         A:    f(n) = f(n − 1) ⋅ 0.6 + 48, n > 0    

It is given that:

A store had 250 bottles of water.

Each week, 40% of the bottles were sold and 48 new bottles arrived in shipments.

This means that the number of bottles that will be present in the store after 40% of the bottles will be sold at a particular week= 100%-40%=60% plus 48 new arrival

This means that each time the number of bottles in the store will be 60% of the bottles that were sold previous week plus 48.

        Hence, if f(n-1) represent the number of bottle in the (n-1)th week then the number of bottles in the nth week will be represented by:

                     [tex]f(n)=60\%\ of\ f(n-1)+48\\\\i.e.\\\\f(n)=0.6\cdot f(n-1)+48[/tex]

the answer to your question is...

She should buy 5 boxes because if she bought 4 then she would have 8 without a box

There would be 60 pages in the book totally because you would set 40/x=2/3 and solve for x.

40/x=2/3

2x=120

x=60

Final answer:

The student read [tex]\frac{2}{3}[/tex] of a book, equivalent to 40 pages. By setting up a proportion and solving for the total number of pages, it's determined that the book has 60 pages in total.

Explanation:

The student asked a question related to proportion which falls under the category of Mathematics. They read 40 pages, and this is [tex]\frac{2}{3}[/tex] of the book. To find out the total number of pages in the book, we set up a proportion.

Let the total number of pages in the book be x. According to the given information, [tex]\frac{2}{3}[/tex] of the book is 40 pages. Therefore, we can write this as a proportion:

[tex]\frac{2}{3} = \frac{40}{x}[/tex]
[tex]x = 40*\frac{3}{2}[/tex]
x = 60

The book has 60 pages.

Divide $62.50 by 5, and your answer will be $12.50 per ticket.

The interval you use when finding the rate of change of a proportional relationship does matter because the behavior of the relationship could vary within different intervals. To illustrate this, consider a proportional relationship where y is directly proportional to x. If we calculate the rate of change for different intervals, we might get different results. Therefore, it is important to specify the interval when finding the rate of change to accurately represent the behavior of the relationship within that interval.

The interval you use when finding the rate of change of a proportional relationship does matter. The rate of change represents how a quantity changes with respect to another quantity. If you use different intervals, you may get different rates of change because the behavior of the relationship could vary within different intervals. Let me provide an example to illustrate this:

Suppose we have a proportional relationship where y is directly proportional to x:

y = kx

If we calculate the rate of change for different intervals, we might get different results. For example, if we consider the interval from x = 1 to x = 5, the rate of change would be (y2 - y1) / (x2 - x1) = (5k - k) / (5 - 1) = 4k / 4 = k. However, if we consider the interval from x = 3 to x = 7, the rate of change would be (y2 - y1) / (x2 - x1) = (7k - 3k) / (7 - 3) = 4k / 4 = k. In both cases, the rate of change is the same within each interval, but it may differ between intervals.

Therefore, it is important to specify the interval when finding the rate of change of a proportional relationship to accurately represent the behavior of the relationship within that interval.

Note the equal sign. What you do to one side, you do to the other.

First, combine like terms

-7x + -7x = -14x

-14x = 84

Isolate the x. Divide -14 from both sides

(-14x)/-14 = (84)/-14

x = 84/-14

Divide

x = -6

-6 is your answer for x

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~Rise Above the Ordinary, Senpai

the answer is -16 sooooo brainliest plzz

The diagonals of a rectangle are congruent. That means that their lengths are equal. One diagonal is AC, and the other diagonal is BD. AC must equal BD. We set their lengths equal and solve for x.

3(x - 2) = x + 18

Distribute the 3 on the left side.

3x - 6 = x + 18

Subtract x from both sides; add 6 to both sides.

2x = 24

Divide both sides by 2.

x = 12

Now that we know x = 12, we replace x with 12 in BD = x + 18 to find the length of BD.

BD = x + 18 = 12 + 18 = 30

Since the diagonals are congruent, the length of AC is also 30.

Answer:   AC = 30;  BD = 30

The length of the diagonals of the rectangle are AB = 30 and BD = 30

A 4-sided flat shape with straight sides where all interior angles are right angles (90°). Also, the opposite sides are parallel and of equal length.

Given that, ABCD is a rectangle and its diagonals are  AC= 3(x-2) and BD=x+18

According to the property of a rectangle,

Diagonals of a rectangle are equal.

Therefore, AC = BD

3(x-2) = x+18

3x-6 = x+18

2x = 24

x = 12

AC = 3(12-10) = 30

BD = 12+18 = 30

Hence, the diagonals of the rectangle are AB = 30 and BD = 30

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#SPJ2

1. 0.48

2.8.48

3.124

4.29

5.530

6.1056

12.2 jlasjajlsajlajlzwljdazdazwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwww

Answer:

12.2

Step-by-step explanation:i did the work and got 12.2

Since 18 people withdrew 100 dollars each, that would be 18 multiply by 100 which is 1800

100 + 10m = 15m

5m = 100

m=20 movies

20 is the amount of movies to make it cost the same.

To find the number of movies at which the cost of both movie clubs would be the same, you set the cost equations for both clubs equal to each other and solve for the number of movies, m. The result is m=20.

The subject here is essentially figuring out where the total cost of each movie club is equal. In this case, we can define two equations representing the total costs of each movie club. For the first club, which charges a $100 membership fee and $10 per movie, that equation is C1 = 100 + 10m . For the second club, which charges no membership fee but $15 per movie, the equation is C2 = 15m. Setting these two equations equal to each other gives us 100 + 10m = 15m. Solving for m (the number of movies) we subtract 10m from both sides to get 100 = 5m, then divide both sides by 5, to find that m = 20.

Therefore, if you plan to buy 20 or more movies in a year, the first club would be more cost effective. If you plan to buy less than 20 movies, the second club would be the better option.

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[tex]f(x)=\dfrac{x}{2}-3,\ g(x)=3x^2+x-6\\\\(f+g)(x)=f(x)+g(x)=\left(\dfrac{x}{2}-3\right)+(3x^2+x-6)=\dfrac{1}{2}x-3+3x^2+x-6\\\\=3x^2+1\dfrac{1}{2}x-9[/tex]

[tex]Answer:\ \boxed{B.\ 3x^2+\dfrac{3}{2}x-9}}[/tex]

An equivalent ratio of 64:60 is 16:15.

To get an equivalent ratio, you are going to simplify it like you would a fraction. An equivalent ratio would be 32:30. Then, just keep dividing both sides by the same number until both sides can't be divided by the same number. i.e. 9:6 -> 3:2 Both sides were divided by three.

4x + 5y = 2(x + 3y)

4x + 5y = 2x + 6y   distributed 2 on the right side

2x + 5y = 6y           subtracted 2x from both sides

2x = y                      subtracted 5y from both sides

         if y = 2x

then 17(y) = 17(2x)

          17y = 34x

Answer: 34x

We know:

[tex]LCM(a,\ b)=\dfrac{ab}{GCF(a,\ b)}[/tex]

We have

[tex]GCF(a,\ b)=2,\ LCM(a,\ b)=20,\ a\leq12,\ b\leq12[/tex]

Substitute:

[tex]20=\dfrac{ab}{2}\qquad|\cdot2\\\\ab=40[/tex]

[tex]40=1\cdot40=2\cdot20=4\cdot10=5\cdot8[/tex]

Only 4 and 10 meet the requirements of the question.

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40 and 1 NOT, because 40 > 12

20 and 2 NOT, because 20 > 12

5 and 8 NOT because GCF(5, 8) = 1

The numbers are 4 and 10 or 5 and 8.

The relation is given as,

                 [tex]LCM*GCF=m*n[/tex]

Where m and n are two numbers.

Given that,  [tex]GCF=2,LCM=20[/tex]

Substitute values in above relation.

              [tex]m*n=2*20=40[/tex]

Since, both numbers less than or equal to 12.

We observed that,

              [tex]4*10=40\\\\5*8=40\\[/tex]

The numbers are 4 and 10 or 5 and 8.

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Lets put Monday as 'm'

Monday: m

Tuesday: 2m

Wednesday 2m-6

The Three Days: 5m-6

Final Answer: 5m-6=19

Answer:

Amplitude

Step-by-step explanation:

I just had this question and got it right

Answer: [tex]a=\frac{k}{9b+4}[/tex]

Step-by-step explanation:

↓↓↓↓↓↓↓↓↓↓↓↓↓↓

First, flip the equation.

[tex]9ab+4a=k[/tex]

Next, factor out variable a.

[tex]a(9b+4)=k[/tex]

Then, divide by 9b+4 from both sides.

[tex]\frac{a(9b+4)}{9b+4}=\frac{k}{9b+4}[/tex]

[tex]=a\frac{k}{9b+4}[/tex]

Hope this helps!

Thank you for posting your question at here on brainly.

-Charlie

Answer:

The value of a is [tex]a=\frac{K}{4+9b}[/tex].

Step-by-step explanation:

The given equation is

[tex]K=4a+9ab[/tex]

We have to solve the above equation  for a. So, we need to isolate the variable a.

Taking out a from the left side.

[tex]K=a(4+9b)[/tex]

Divide both sides by 4+9b to get the value of a.

[tex]\frac{K}{4+9b}=\frac{a(4+9b)}{4+9b}[/tex]

Cancel out the common factors from numerator and denominator.

[tex]\frac{K}{4+9b}=a[/tex]

Therefore the value of a is [tex]a=\frac{K}{4+9b}[/tex].

A monomial is a polynomial which has only one term. For example, the polynomial [tex]5x+2y^{2}[/tex], has two terms: [tex]5x[/tex] and [tex]2y^{2}[/tex]. The combination of these two terms would be classified as a binomial. However, each individual term is classified as a monomial.

Answer:

ΔSTR is similar to ΔRTQ

Step-by-step explanation:

Given QRS is a right angled triangle. we have to find the similarity statement ΔSTR ~ Δ__

Let ∠S=x

In ΔSTR, by angle sum property

∠S+∠STR+∠SRT=180°

⇒ ∠SRT=90°-x

In ΔSRQ, by angle sum property

∠S+∠R+∠Q=180°

⇒ ∠Q=90°-x

In ΔSTR and ΔRTQ

∠SRT=∠Q=90°-x     (proved above)

∠STR=∠RTQ           (each 90°)

RT=RT                      (common)

Hence, by AAS rule ΔSTR≅ΔRTQ

∴ ΔSTR is similar to ΔRTQ

Option 4 is correct.

Answer:

RTQ

Step-by-step explanation:

Let ∠S=a, In ΔSTR, using angle sum property, we have

∠S+∠STR+∠SRT=180°

⇒ ∠SRT=90°-a

Again In ΔSRQ, using angle sum property, we have

∠S+∠R+∠Q=180°

⇒ ∠Q=90°-a

Now, In ΔSTR and ΔRTQ

∠SRT=∠Q=90°-a    (proved above)

∠STR=∠RTQ              (each 90°)

 RT=RT                      (common)

Hence, by AAS rule,

ΔSTR≅ΔRTQ

Thus,  ΔSTR is similar to ΔRTQ

Option 4 is correct.

Lines L and M are parallel

m<2 = 38° (corresponding angles are equal)