Answers
A. y=(x-2)^2-4
1. As you can see in the figure attached, the red parabola has the function f(x)=x^2. This is the patern function. By definition, which is the most basic function of the quadratics functions.
2. The blue parabola is shifted 2 units at x axis and 4 units in the -y axis. Therefore, the correct function that represents this parabola is the function of the option A.
3. If you want to verify it, you can give values to x and plot each point on a graph.
Related Questions
What percent of 7 is 2?
Answers
What are the values of the variable in 37=30-x^2
Answers
x^2 = -7
Then the values of x are
x = ±√-7
x = -i√7 or i√7 . . . . . . where i = √-1
how many problems must be answered correctly on a math test with 60 problems to get a score of 85%
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Answer: 51 problems.
Hey can you please help me posted picture of question
Answers
So, the correct statement will be:
To change the shape of a function you need to stretch or compress it.
Thus, option C is the correct answer.
hey can you please help me posted picture of question
Answers
So x-value of F(x) will be the y-value of its inverse.
And y-value of F(x) will be the x-value of its inverse.
So, (-3, 7) on F(x) will be translated to (7, -3) on its inverse.
Thus, the correct answer is option A
Mr Walton ordered 12 pizzas,for the art class celebration one fourth of the pizza had only mushrooms. how many of the pizza has only mushrooms
Answers
So your answer is 3 pizzas
x−18 , if x<18. Please help asap!
Answers
So that would be x - 18 < 0.
Hope this helps.
If x < 18 then you can subtract both sides by 18 and you would get x - 18 < 18 - 18 = 0
So that would be x - 18 < 0.
Hope this helps.
simplify the expression (-5)2. -10 10 -25 25
Answers
_____
There are an even number of negative factors, so the result is positive.
Round off 1563385 to the nearest million?
Answers
Look at the millions place. 1 is in the millions place.
Now look at the number to the right of 1.
Since it is 5 or greater, round 1 up to 2.
Change all the numbers after 1 to 0.
1,563,385 rounded to the nearest million is 2,000,000.
To round 1,563,385 to the nearest million, we look at the hundred-thousands digit (5), and since it's 5 or greater, we round up to 2,000,000.
To round off 1,563,385 to the nearest million, look at the hundred-thousands digit, which is 5 in this case.
If it is 5 or greater, we round up; if it is less than 5, we round down.
Since our hundred-thousands digit is 5, we round up, so 1,563,385 rounded to the nearest million is 2,000,000.
37% of a certain country's voters think that it is too easy to vote in their country. you randomly select 12 likely voters. find the probability that the number of likely voters who think that it is too easy to vote is (a) exactly three, (b) at least four, (c) less than eight.
Answers
The probability that the number of likely voters who think that it is too easy to vote is:
a) exactly three = 0.17422
(b) at least 4 = 0.70533
(c) less than eight = 0.96406
How to use binomial probability theorem?
The general formula for binomial probability theorem is:
P(X = x) = ⁿCₓ * pˣ * (1 - p)⁽ⁿ ⁻ ˣ⁾
Where:
n = 12
p = 0.37
(a) exactly three,
P(x = 3) = ¹²C₃ * 0.37³ * 0.93⁹
= 0.17422
(b) at least 4,
P(4 ≤ x ≤ 12) = P(4) + P(5) + P(6) + P(7) + P(8) + P(9) + P(10) + P(11) + P(12)
= 0.70533
(c) less than eight.
P(x < 8) = P(0) + P(1) + P(2) + P(3) + P(4) + P(5) + P(6) + P(7)
= 0.96406
the snowfall in year 1 was 2.03 meters .the snowfall in year 2 was 1.6 meters .how many total meters of snow fell in years 1 and 2
Answers
2.03
+1.60
3.63
It is important to line up your decimal points because when you are adding anything, you must add units that are the same. Lining up the decimal points puts the units in order automatically!
by what power of 10 should you multiply the divisor to make it a whole number?
0.82÷6.232
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1. A line passes through the ordered pairs (7,2) and (5,4). What is the slope? please show work
2. A sphere has a diameter od 20 cm. What would be the volume of sphere?
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since the sphere has a diameter of 20, its radius is half that, or 10.
[tex]\bf \textit{volume of a sphere}\\\\ V=\cfrac{4\pi r^3}{3}~~ \begin{cases} r=radius\\ -----\\ r=10 \end{cases}\implies V=\cfrac{4\pi (10)^3}{3}[/tex]
Patrick's favorite shade of purple paint is made with 4 ounces of blue paint for every 3ounces of red paint.
Which of the following paint mixtures will create the same shade of purple?
Choose 2 answer
Blue : 4x2=8
Red : 3x2=6
Blue :4x5=20
Red:3x5=15
The following mixtures will create Patrick's favorite shade of purple:
:8ounces of blue paint mixed with 6ounces of red paint
:20 ounces of blue paint mixed with 15 ounces of red paint
Answers
Blue:red=4:3
The mixtures that will create the same shade of purple is:
a] 8ounces of blue paint mixed with 6ounces of red paint
because the ratio of blue to red is 4:3
and
b] 20 ounces of blue paint mixed with 15 ounces of red paint
because the ratio of blue to red is 4:3
Answer:
actually its b and d
Step-by-step explanation:
according to khan academy
Which polynomial represents the difference below?
Answers
Correct answer is B.
The difference between given two polynomials is [tex](- x^{2} + 12x + 3)[/tex].
What is a polynomial?"A polynomial is an expression consisting of indeterminates and coefficients, that involves only the operations of addition, subtraction, multiplication, and non-negative integer exponentiation of variables."
Given two polynomials are [tex](5x^{2} + 9x + 3)[/tex] and [tex](6x^{2} - 3x)[/tex].
Therefore, the difference between these two polynomials
[tex]= (5x^{2} + 9x + 3) - (6x^{2} - 3x)\\= (5x^{2} - 6x^{2}) + (9x + 3x) + 3\\= - x^{2} + 12x + 3[/tex]
Learn more about polynomial here:
https://brainly.com/question/21610884
#SPJ3
340 students went to the first dance but only 306 went to the second. What is the percent decrease in the attendance from the first to the second dance
Answers
340 - 306 = 34
divide that by the number of students that went to the first dance:
34 / 340 = 0.1 = 10% decrease
Percentage decreased = 34/340 x 100 = 10%
Answer: 10%
if a circle has a radius of 13 and a sector defined by a 7.4 degree arc, what is the area, in cm2, of the sector? round your answer to the nearest tenth.
Answers
A = (S '/ S) * (pi) * (r ^ 2)
Where,
S '/ S = relation of arcs
r: radius of the circle
Substituting values we have:
A = (7.4/360) * (3.14) * (13 ^ 2)
A = 10.9080111
Rounding off we have:
A = 10.9 cm^2
Answer:
the area of sector is:
A = 10.9 cm^2
A piece of cardboard has two circles punched out of it. What is the approximate area of the remaining cardboard? Use 3.14 for pie and round to the nearest whole number.
227 cm2
246 cm2
258 cm2
276 cm2
Answers
we know that
[the approximate area of the remaining cardboard]=(area of rectangle) - 2(area of circle)
area of rectangle=14 cm* 18 cm------> 252 cm²
area of a circle=pi*r²
r=2/1----> 1 cm
area=pi*1²-----> 3.14 cm²
[the approximate area of the remaining cardboard]=252- 2*3.14
=245.72-------> 246 cm²
the answer is
246 cm²
Anna plans a business model to compete with two video stores, where she hopes to draw in customers from one store but not lose money on the deal. Movie Mania charges a subscription fee of $30 and an additional $5 per movie, x. Movie Time charges a subscription fee of $25 and an additional $6 per movie, x. Based on this information, which system of inequalities could be used to determine how many movies need to be rented for a customer on Anna’s plan, y, to pay her more than they would at Movie Time, but less than they would at Movie Mania?
Answers
30 + 5x
Movie Time charges a subscription fee of $25 and an additional $6 per movie, x. So the total charges at Movie Time for x movies will be:
25 + 6x
Anna wants her plan to her amount y which is more than Movie Time but Less than Movie Mania. So we can set up the equation as:
Cost at Movie Time < y < Cost at Movie Mania
Using the values, we can write:
25 + 6x < y < 30 + 5x
Using this system of inequalities Anna can determine how many movies need to be rented for a customer on her plan
Answer:D. y<5x+30/x
y>6x+25/x
Step-by-step explanation:
got right on edmentum
hey can you please help me posted picture of question
Answers
y² = 64 -(x -2)²
y² = 64 -(x² -4x +4)
y² = -x² +4x +60
The answer is ...
D. y² = -x² +4x +60
Can someone help me with this problem? please explain.
Answers
You have weight (5.76 pounds) and density (0.08 pounds/in³). The units of volume (in³) are in the denominator of the density, but we want them in the numerator of a number that gives the volume of the brick. At the same time, we want to cancel units of pounds. We can do all that by dividing weight by density.
volume = weight/density
volume = (5.76 pounds)/(0.08 pounds/in³) = (5.76/0.08) in³ = 72 in³
We know the volume of a rectangular prism (brick) is given by the product of its length, width, and height. We now have enough information to find the height.
volume = length*width*height
72 in³ = (8 in)*(2.25 in)*height . . . . . substitute known numbers
72 in³/((8*2.25) in²) = height . . . . . .. solve for height
72/18 in = height = 4 in . . . . . . . . . . . do the arithmetic. (in³)/(in²) = in
The height of the brick is 4 inches.
Please help me with coordinates. IT'S DO IN 3 HOURS
Answers
Get graphs (standard X,Y graphs) and start placein the numbers in the following format (x,y) If they are negative, it will be placed to the left of the graph, if positive to the right of the graph
Value of m varies directly as value of n and n=5 when m=12. What is n when m=18?
Answers
m = 12 & n = 5
m = 6 & n = 2.5 (divided each number by 20)
Now m is a factor of 18. Multiply each number by 3.
Answer: m = 18 & n = 7.5
Assume that the number of watches produced every hour is normally distributed with a mean of 500 and a standard deviation of 100. what is the probability that in a randomly selected hour the number of watches produced is greater than 500
Answers
z=(x-μ)/σ
where:
x=500
μ=500
σ=100
thus
z=(500-500)/200=0
Thus:
P(x>500)=1-P(x<500)=1-P(z<0)=1-0.5=0.5
Answer: 0.5~50%
Answer: 0.5
Step-by-step explanation:
Given : The number of watches produced every hour is normally distributed with a mean of 500 and a standard deviation of 100.
i.e. [tex]\mu = 500\text{ and } \sigma= 100[/tex]
Let x be the number of watches produced every hour.
Then, the probability that in a randomly selected hour the number of watches produced is greater than 500 will be :
[tex]P(x>500)=1-P(x\leq500)\\\\=1-P(\dfrac{x-\mu}{\sigma}\leq\dfrac{500-500}{100})\\\\=1-P(z\leq0)\ \ [\because\ z=\dfrac{x-\mu}{\sigma}]\\\\=1-0.5\ \ [\text{ By z-table}]\\\\=1-0.5=0.5[/tex]
Hence, the probability that in a randomly selected hour the number of watches produced is greater than 500 =0.5.
A brother and a sister are in the same math class. There are 8 boys and 10 girls in the class. One boy and one girl are randomly chosen. What is the probability that the brother and sister are chosen? Write your answer as a fraction in simplest form.
Answers
[tex] |\Omega|=8\cdot10=80\\ |A|=1\\\\ P(A)=\dfrac{1}{80} [/tex]
27 33 34 35 37 39 40 41 54 84,75,90,87,99,91,85,88,76,92,94 median: first quartile: third quartile: interquartile range:
Answers
Final answer:
For the given data, the median is 85, the first quartile is 37, the third quartile is 90.5, the interquartile range (IQR) is 53.5, and the range is 72.
Explanation:
The median in a dataset is the middle value when the values are arranged in numerical order. For the given data 27, 33, 34, 35, 37, 39, 40, 41, 54, 75, 84, 75, 90, 87, 99, 91, 85, 88, 76, 92, 94, after arranging them in ascending order, the median (Q2) is the value positioned at the center of the dataset. Since there are 21 values, the median is the 11th value, which is 85. The first quartile (Q1) is the median of the first half (lower half) of the dataset, which is the value in the 5.5th position, so we average the 5th and 6th values to get 37. Similarly, the third quartile (Q3) is the median of the second half (upper half) of the dataset, which would be the average of the 16th and 17th values, yielding 90.5. The interquartile range (IQR) is the difference between the third quartile and the first quartile, so IQR = Q3 - Q1 = 90.5 - 37 = 53.5. The range of the dataset is the difference between the maximum and minimum value which is 99 - 27 = 72.
Hey can you please help me posted picture of question
Answers
F(x)= (x-1)^2+3
First the graph is shifted right by 1 unit which can be expressed as:
(x - 1)²
Next the function is shifted up by 3 units, so the final function can be expressed as:
F(x) = (x - 1)² + 3
So, the correct answer is option B
Name the pattern block used to cover 1 third of the hexagon
Answers
See the attached figure
By sketching a hexagon and dividing it to 3 equal shapes.
we will shading one of the 3 equal shapes.
So, the shaded area is a parallelogram with equal sides which is called rhombus
The correct answer is:
The pattern block used to cover 1 third of the hexagon is rhombus
Factor completely.
3x squared + 2xy - y squared
Answers
[tex]3 x^{2} +2xy- y^{2} \\ \\ 3 x^{2} +3xy-xy- y^{2} \\ \\ 3x(x-y)-y(x-y) \\ \\ (x-y)(3x-y) [/tex]
Which values are outliers?
5.8, 6.1, 4.9, 10.9, 0.8, 6.1, 7.4, 10.2, 1.1, 5.2, 5.9
Select Outlier or Not Outlier for each data point.
Data Outlier Not Outlier
0.8
1.1
10.2
10.9
Answers
The outliers are 0.8, 1.1, 10.2, and 10.9. The rest are not outliers.
A value is typically considered an outlier if it is less than Q1 - 1.5 [tex]\times[/tex] IQR or greater than Q3 + 1.5 [tex]\times[/tex] IQR.
First, we need to arrange the data in ascending order:
0.8, 1.1, 4.9, 5.2, 5.8, 5.9, 6.1, 6.1, 7.4, 10.2, 10.9
Next, we find the first quartile (Q1), which is the median of the first half of the data:
(4.9 + 5.2) / 2 = 5.05
We find the third quartile (Q3), which is the median of the second half of the data:
(6.1 + 7.4) / 2 = 6.75
Now, we calculate the interquartile range (IQR):
IQR = Q3 - Q1 = 6.75 - 5.05 = 1.7
The lower bound for outliers is:
Q1 - 1.5 [tex]\times[/tex] IQR = 5.05 - 1.5 [tex]\times[/tex] 1.7 = 5.05 - 2.55 = 2.5
The upper bound for outliers is:
Q3 + 1.5 [tex]\times[/tex] IQR = 6.75 + 1.5 [tex]\times[/tex] 1.7 = 6.75 + 2.55 = 9.3
Now we can determine which values are outliers:
0.8 is less than the lower bound (2.5), so it is an outlier.
1.1 is less than the lower bound (2.5), so it is an outlier.
10.2 is greater than the upper bound (9.3), so it is an outlier.
10.9 is greater than the upper bound (9.3), so it is an outlier.
The remaining values (4.9, 5.2, 5.8, 5.9, 6.1, 6.1, 7.4) are not outliers as they fall within the range of Q1 - 1.5 [tex]\times[/tex] IQR and Q3 + 1.5 [tex]\times[/tex] IQR.