PLEASE HELP WITH THIS I HAVE NO IDEA HOW TO SOLVE!!!!
PLEASE DON"T IGNORE THIS ONE
PLEASE HELLLP
consider the following graph of a quadratic function. Write the euqation for the quadratic function in standard form.
The graphs y-intercept is 7 and vertex is (-3,-2)
Answers
.. y = a*(x +3)^2 -2
.. = ax^2 +6ax +9a -2
You require the y-intercept to be 7. So, for x=0, you have
.. 9a -2 = 7
.. 9a = 9
.. a = 1
The equation you seek is
.. y = x^2 +6x +7
Related Questions
The perimeter of an airplane ticket is 32 centimeters. The area is 60 square centimeters. What are the dimensions of the ticket
Answers
For this case what you should know is that the perimeter of the rectangle is given by:
P = 2w + 2l
The area of the rectangle is given by:
A = w * l
In both cases:
w: width
l: long
We have the following system of equations:
32 = 2w + 2l
60 = w * l
Solving the system we obtain:
The dimensions of the ticket are:
(10 cm) * (6 cm)
Answer:
the dimensions of the ticket are:
(10 cm) * (6 cm)
Note: see attached image for system solution
Find the total surface area of the triangular pyramid. Each of the faces (sides) has an area of 50.5 square inches.
Answers
A triangular pyramid (also called tetrahedron) is a polyhedron whose surface is formed by a base that is a triangle and triangular lateral faces that converge in a vertex that is called apex (or apex of the pyramid).
It will be composed, therefore, by 4 faces, the triangular base and three lateral triangles that converge at the vertex.
Thus, the surface area is:
As = 4 * (50.5) = 202 in ^ 2
Answer:
The total surface area of the triangular pyramid is:
202 in ^ 2
Let f(x)=x2+14x+48. What are the zeros of the function? Enter your answers in the boxes.
Answers
[tex] x^{2} +14x+48=(x+6)(x+8)[/tex]
Since we are trying to find the zeroes of the function, we are going to set each one of our factored binomial equal to zero and solve for x:
[tex]x+6=0[/tex]
[tex]x=-6[/tex]
and
[tex]x+8=0[/tex]
[tex]x=-8[/tex]
We can conclude that the zeroes of the function [tex]f(x)= x^{2} +14x+48[/tex] are [tex]x=-6[/tex] and [tex]x=-8[/tex].
Answer:x= -6 and -8
Step-by-step explanation: I took the test
PLEASE HELP ASAP! THANKS!
RANDOM ANSWERS WILL BE MODERATED!
Answers
https://brainly.com/question/9006279
PLEASE HELP
7.05a
1. Find the first six terms of the sequence.
a1 = -6, an = 4 • an-1
A) 0, 4, -24, -20, -16, -12
B) -24, -96, -384, -1536, -6144, -24,576
C) -6, -24, -20, -16, -12, -8
D) -6, -24, -96, -384, -1536, -6144
2. Find an equation for the nth term of the arithmetic sequence.
-15, -6, 3, 12, ...
A) an = -15 + 9(n + 1)
B) an = -15 x 9(n - 1)
C) an = -15 + 9(n + 2)
D) an = -15 + 9(n - 1)
3. Find an equation for the nth term of the arithmetic sequence.
a14 = -33, a15 = 9
A) an = -579 + 42(n + 1)
B) an = -579 + 42(n - 1)
C) an = -579 - 42(n + 1)
D) an = -579 - 42(n - 1)
4. Determine whether the sequence converges or diverges. If it converges, give the limit.
48, 8, four divided by three , two divided by nine , ...
A) Converges; two hundred and eighty eight divided by five
B) Converges; 0
C) Diverges
D) Converges; -12432
5. Find an equation for the nth term of the sequence.
-3, -12, -48, -192, ...
A) an = 4 • -3n + 1
B) an = -3 • 4n - 1
C) an = -3 • 4n
D) an = 4 • -3n
6. Find an equation for the nth term of a geometric sequence where the second and fifth terms are -21 and 567, respectively.
A) an = 7 • (-3)n + 1
B) an = 7 • 3n - 1
C) an = 7 • (-3)n - 1
D) an = 7 • 3n
7. Write the sum using summation notation, assuming the suggested pattern continues.
5 - 15 + 45 - 135 + ...
A) summation of five times three to the power of the quantity n plus one from n equals zero to infinity
B) summation of five times negative three to the power of n from n equals zero to infinity
C) summation of five times three to the power of n from n equals zero to infinity
D) summation of five times negative three to the power of the quantity n plus one from n equals zero to infinity
8. Write the sum using summation notation, assuming the suggested pattern continues.
-9 - 3 + 3 + 9 + ... + 81
A) summation of the quantity negative nine plus six n from n equals zero to fifteen
B) summation of negative fifty four times n from n equals zero to fifteen
C) summation of negative fifty four times n from n equals zero to infinity
D) summation of the quantity negative nine plus six n from n equals zero to infinity
9. Write the sum using summation notation, assuming the suggested pattern continues.
64 + 81 + 100 + 121 + ... + n2 + ...
A) summation of n squared from n equals eight to infinity
B) summation of n minus one squared from n equals eight to infinity
C) summation of n squared from n equals nine to infinity
D) summation of n plus one squared from n equals eight to infinity
10. Find the sum of the arithmetic sequence.
17, 19, 21, 23, ..., 35
A) 260
B) 179
C) 37
D) 160
11. Find the sum of the geometric sequence.
1, one divided by two, one divided by four, one divided by eight, one divided by sixteen
A) one divided by twelve
B) 93
C) negative one divided by forty eight
D) thirty one divided by sixteen
12. An auditorium has 30 rows with 10 seats in the first row, 12 in the second row, 14 in the third row, and so forth. How many seats are in the auditorium?
A) 1170
B) 735
C) 1230
D) 600
13. Use mathematical induction to prove the statement is true for all positive integers n.
The integer n3 + 2n is divisible by 3 for every positive integer n.
14. A certain species of tree grows an average of 3.8 cm per week. Write an equation for the sequence that represents the weekly height of this tree in centimeters if the measurements begin when the tree is 5 meters tall.
Answers
Since this exceeds the limit and I had to delete the last questions and I copied all the answers to a file that is attache. See the attachment with all the answers.
1) Question 1. Find the first six terms of the sequence: a1 = -6, an = 4 • an-1
Answer: option D) -6, -24, -96, -384, -1536, -6144
Explanation:
A(1) = - 6
A(n) = 4 * A(n-1)
n A(n)
1 - 6
2 4 * (-6) = - 24
3 4 * (-24) = - 96
4 4 * (-96) = - 384
5 4 * (-384) = - 1536
6 4 * ( -1536) = -6144
So, the first six terms are: -6, - 24, - 96, - 384, - 1536, - 6144.
2) Question 2: Find an equation for the nth term of the arithmetic sequence.
-15, -6, 3, 12, ...
Answer: option D) - 15 + 9(n - 1)
Explanation:
1. find the difference between the consecutive terms:
-6 - (-15) = -6 + 15 = 9
3 - (-6) = 3 + 6 = 9
12 - 3 = 9
So, the difference is 9, and you can find any term adding 9 to the previous.
2. Since the first term is - 15, you have:
First term, A1 = - 15 + 9(0) = - 15
Second term, A2 = - 15 + 9(1) = - 6
Third term, A3 = -15 + 9(2) = - 15 + 18 = 3
Fourth term, A4 = - 15 + 9(3) = - 15 + 27 = 12
3. So, the general formula is An = - 15 + 9 (n - 1), which is the option D)
3) Question 3. Find an equation for the nth term of the arithmetic sequence A14 = - 33, A15 = 9.
Answer: option B) An = - 579 + 42(n - 1)
Explanation:
1) Find the difference: 9 - (-33) = 9 + 33 = 42
2) A15 = A1 + 42 * (15 - 1)
=> A1 = A15 - 42(15 - 1)
A1 = A15 - 42(14)
A1 = 9 - 588 = - 579
Therefore, the formula es An = - 579 + 42(n - 1)
4) Question 4. Determine whether the sequence converges or diverges. If it converges, give the limit.
48, 8, 4/3, 2/9, ...
Answer: the sequence converges to 288/5
Explanation:
That is a geometric sequence.
The ratio is 1/6: 8/48 = 1/6; (4/3) / 8 = 4/24 = 1/6; (2/9)/(4/3) = 6/36 = 1/6.
The convergence criterium is that if |ratio| < 1 then the series, this is the sum of all the terms, converge to: A1 / (1 - ratio)
Then the limit 48 / (1 - 1/6) = 48 / (5/6) = 48*6 / 5 = 288/5
5) Question 5. Find an equation for the nth term of the sequence.
-3, -12, - 48, -192
Answer: - 3 * (4)^(n-1)
Explanation: clearly any term (from the second) is the previous term multiplied by 4.
The first term is -3
The second term is -3(4) = - 12
The third term is -3(4)(4)= - 48
The fourth term is - 3 (4)(4)(4) = - 192
So, the general formula for the nth term is -3 * 4^ (n-1)
6) Question 6. Find an equation for the nth term of a geometric sequence where the second and fifth terms are -21 and 567, respectively.
Answer: An =7 * (-3)^(n-1)
Explanation:
1) The fith term is the second term * (ratio)^3: A5 = A3 * (r)^3
2) A5 = 567, A2 = - 21 => r^3 = A5 / A2 = - 567 / 21 = - 27
=> r = ∛(-27) = - 3
3) So the first term is A1 = A2 / r = -21 / -3 = 7
4) The general formula is
An =7 * (-3)^(n-1)
7) Question 7. Write the sum using summation notation, assuming the suggested pattern continues.
5 - 15 + 45 - 135 + ...
Answer: option B) summation of five times negative three to the power of n from n equals zero to infinity
Explanation:
5 = 5
-15 = 5 (-3)
45 = 5(-3)^2
-135 = 5(-3)^3
=> 5 + 5(-3) + 5(-3)^2 + 5(-3)^3+....
Using the summation notation that is:
∞
∑ (5)(-3)^n
n=0
Which means summation of five times negative three to the power of n from n equals zero to infinity
8) Question 8. Write the sum using summation notation, assuming the suggested pattern continues.
-9 - 3 + 3 + 9 + ... + 81
Answer: option A) summation of the quantity negative nine plus six n from n equals zero to fifteen
Explanation:
Find the difference:
-3 - (-9) = - 3 + 9 = 6
3 - (-3) = 3 + 3 = 6
9 - 3 = 6
First term: - 9
Second term: - 9 + 6(1)
Third term: - 9 + 6(2)
nth term = - 9 + (n -1)
Summation = [- 9] + [- 9 + 6(1) + [-9 + 6(2)] + [-9 + 6(3) ]+ .... [-9 + 6(15) ]
Using summation notation:
15
∑ [-9 + 6n]
n=0
which means summation of the quantity negative nine plus six n from n equals zero to fifteen.
9) Question 9. Write the sum using summation notation, assuming the suggested pattern continues.
64 + 81 + 100 + 121 + ... + n2 + ...
Answer: A) summation of n squared from n equals eight to infinity
Explanation:
64 = 8^2
81 = 9^2
100 = 10^2
121 = 11^2
n^2
=>
∞
∑ n^2
n=8
which means summation of n squared from n equals eight to infinity
10) Question 10. Find the sum of the arithmetic sequence.
17, 19, 21, 23, ..., 35
Answer: 260
Explanation:
The difference is 2:
The sum is: 17 + 19 + 21 + 23 + 25 + 27 + 29 + 31 + 33 + 35.
You can use the formula for the sum of an arithmetic sequence:
(A1 + An) * n / 2 = (17 + 35)*10/2 = 260
11) Question 11. Find the sum of the geometric sequence.
1, 1/2, 1/4, 1/8, 1/16
Answer: option D) 31/16
Explanation:
You can either sum the 5 terms or use the formula for the partial sum of a geometric sequence.
The formula is: Sum = A * ( 1 - r^n) / (1 - r)
Here A = 1, r = 1/2, and n = 5 => Sum = 1 * (1 - (1/2)^5 ) / (1 - 1/2) =
= [ 1 - 1/32] / [1/2] = [31/32] / [1/2] = 31 / 16
Find the number of real number solutions for the equation. x2 – 18 = 0
cannot be determined
1
0
2
Answers
For this case, the first thing you should do is rewrite the expression:
x ^ 2 - 18 = 0
x ^ 2 = 18
The solutions for this case are:
x1 = root (18)
x2 = -raiz (18)
Therefore the answer is:
2 solutions of real numbers.
Answer:
2
Answer:
The number of real roots is 2.
Step-by-step explanation:
Given,
[tex]x^2 -18 = 0[/tex]
We will find the number of roots by Descartes' rule of signs.
Let,
[tex]f(x)=x^2-18[/tex]
Since,
[tex]f(x) = + x^2 - 18[/tex]
That is, the change in the sign shows, the given polynomial has one positive real root.
Now, by putting x = - x,
[tex]f(-x)=(-x)^2- 18 = x^2 - 18[/tex]
[tex]\implies f(-x) = + x^2 - 18[/tex]
That is, the change in the sign shows, the given polynomial has one negative real root.
We know that, given polynomial has degree 2,
⇒ It only has 2 roots one is positive real and another is negative real,
⇒ f(x) having 2 real roots.
Find two consecutive whole numbers that 101 lies between
Answers
We can see here that the two consecutive whole numbers that 101 lies between are 100 and 102.
To find two consecutive whole numbers that 101 lies between, we can start by finding the smaller whole number.
Since 101 is greater than 100, the smaller whole number would be 100.
To find the larger whole number, we can add 2 to the smaller whole number:
100 + 2 = 102
Thus, we see here that 100 and 102 are the two consecutive numbers where 101 lies between. As we see above, we see the process of finding the numbers.
Consecutive numbers are numbers that follow each other in order without any gaps and have a difference of 1 between each number. In other words, they are numbers that come one after another in a sequence.
The masses of four planets in a solar system outside the Milky Way are given below. Mass of Planet A: 5.97 × 10 24 kg; Mass of Planet B: 3.30 × 10 23 kg; Mass of Planet C: 1.89 × 10 27 kg; Mass of Planet D: 4.87 × 10 24 kg What is the order of these planets from least to greatest mass?
Planet C; Planet B; Planet D; Planet A Planet C; Planet A; Planet D; Planet B Planet B; Planet D; Planet A; Planet C Planet A; Planet D; Planet B; Planet C\
Answers
Mass of Planet A: 5.97 × 10 24 kg;
Mass of Planet B: 3.30 × 10 23 kg;
Mass of Planet C: 1.89 × 10 27 kg;
Mass of Planet D: 4.87 × 10 24 kg
We observe that according to the scientific notation we have:
3.30 × 10 23 kg <4.87 × 10 24 kg <5.97 × 10 24 kg <1.89 × 10 27 kg
Therefore the order of the planets from lowest to highest mass is:
Planet B, Planet D, Planet A, Planet C
Answer:
Planet B, Planet D, Planet A, Planet C
The order of the planets from least to greatest mass is Planet B, Planet D, Planet A, Planet C.
To determine the order of the planets from least to greatest mass, we need to compare the given masses:
Mass of Planet A: 5.97 × 1024 kg
Mass of Planet B: 3.30 × 1023 kg
Mass of Planet C: 1.89 × 1027 kg
Mass of Planet D: 4.87 × 1024 kg
These masses help us rank the planets:
Planet B: 3.30 × 1023 kg
Planet D: 4.87 × 1024 kg
Planet A: 5.97 × 1024 kg
Planet C: 1.89 × 1027 kg
Therefore, the order of the planets from least to greatest mass is Planet B, Planet D, Planet A, Planet C.
Solve.
x² + 4x + 4 = 18
A x=−4±3√ 2
B x=2±3√ 2
C x=4±9√ 2
D x=−2±3√2
Answers
x² + 4x + 4 = 18
A x=−4±3√ 2
B x=2±3√ 2
C x=4±9√ 2
D x=−2±3√2
[tex]x^2 + 4x + 4 = 18 \\ \\ x^2+4x+4-18= 0 \\ \\ x^2+4x-14=0 \\ \\ x_1_y_2= \dfrac{-b\pm \sqrt{b^2-4ac} }{2a} \qquad a= 1\qquad b= 4\qquad c= -14 \\ \\ \\ x_1_y_2= \dfrac{-4\pm \sqrt{4^2-4(1)(-14)} }{2(1)} \\ \\ \\ x_1_y_2= \dfrac{-4\pm \sqrt{16-(-56)} }{2} \\ \\ \\ x_1_y_2= \dfrac{-4\pm \sqrt{72} }{2} \\ \\ \\ x_1= \dfrac{-4+ \sqrt{72} }{2} \qquad\qquad x_2= \dfrac{-4+ \sqrt{72} }{2}\\ \\ \\ x_1= \dfrac{-4+ \sqrt{2^3*3^2} }{2} \qquad\qquad x_2= \dfrac{-4- \sqrt{2^3*3^2} }{2}[/tex]
[tex] x_1= \dfrac{-4+2*3 \sqrt{2} }{2} \qquad\qquad x_2= \dfrac{-4- 2*3\sqrt{2} }{2} \\ \\ \\ x_1= \dfrac{-4+6 \sqrt{2} }{2} \qquad\qquad x_2= \dfrac{-4- 6\sqrt{2} }{2} \\ \\ \\ x_1= \dfrac{-4}{2} + \dfrac{6 \sqrt{2} }{2} \qquad\qquad x_2= \dfrac{-4}{2}- \dfrac{ 6\sqrt{2} }{2} \\ \\ \\ x_1= -2 + 3 \sqrt{2} \qquad\qquad\quad x_2= -2- 3\sqrt{2} \\ \\ \\ \boxed{x= -2\pm 3\sqrt{2} } \to D) [/tex]
This was the correct answer, I even provided proof from my own test. Hope this helps!
write the polynomial in standard form. Then name the polynomial based on it's degree and number of terms
6 - 12x + 13x^2 - 4x^2
@kewlgeek555
Answers
I can explain if needed
Is it possible to place 158 books on three shelves so that the first shelf has 8 less books than the second and 5 more books than the third shelf?
Answers
x-----------------> books in the first shelf
y-----------------> books in the second shelf
z-----------------> books in the third shelf
we know that
x+y+z=158-------------> equation (1)
x=y-8---------> y=x+8 -------> equation (2)
x=z+5--------> z=x-5 --------> equation (3)
substitute (2) and (3) in (1)
x+(x+8)+(x-5)=158--------> 3x=155----------> x=51.7
the number of books in the first shelf (x=51.7) is not a whole number
therefore
the answer is
Is not possible to place the amount of 158 books in the amounts indicated in the problem
Yes, it is possible to place 158 books on three shelves with the given conditions. The distribution will be 49 books on the first shelf, 57 books on the second, and 52 books on the third shelf.
To solve this problem, let's use algebra. Let x represent the number of books on the second shelf. According to the given conditions, the first shelf would have x - 8 books, and the third shelf would have x - 5. The total number of books on all three shelves is 158, and the equation representing the total number of books is:
x + (x - 8) + (x - 5) = 158
Combining like terms:
3x - 13 = 158
Adding 13 on both sides:
3x = 171
Dividing both sides by 3:
x = 57
Therefore, the second shelf has 57 books, the first shelf has 49 books (57 - 8), and the third shelf has 52 books (57 - 5).
It is possible to place the books on the three shelves as required, and the answer is yes, with the distribution being 49 books on the first shelf, 57 books on the second, and 52 books on the third.
He first three terms of a geometric sequence are as follows. 10 , 30 , 90 find the next two terms of this sequence.+
Answers
30*3=90
90*3=270
270*3=810
or
10*3^1=30
10*3^2=90
10*3^3=270
10*3^4=810
the next two terms of this sequence are 270 and 810.
The next two terms of the given geometric sequence is 810.
The first three terms of a geometric sequence are 10, 30, 90.
What is a geometric sequence?A geometric sequence is a special type of sequence where the ratio of every two successive terms is a constant. This ratio is known as a common ratio of the geometric sequence.
The formula to find nth term of the geometric sequence is [tex]a_n = ar^{n - 1[/tex].
Where, a = first term of the sequence, r= common ratio and n = number of terms.
Here, the common ratio is 30/10 = 90/30 = 3
Now, [tex]a_4=10\times 3^{4-1}[/tex]
= 10 × 3³
= 270
[tex]a_5=10\times 3^{5-1}[/tex]
= 810
Therefore, the next two terms of the given geometric sequence is 810.
To learn more about the geometric sequence visit:
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Find the volume of the prism. 1,728 cu. in. 864 cu. in. 288 cu. in.
Answers
you multiply 12 by 12 by 12
Volume of cube is given by the formula :
[tex] Volume = a * a * a [/tex]
Where a is edge of the cube.
We are given edge of cube as 12 inches.
Plugging the value of edge in given formula:
[tex] Volume = 12 * 12 * 12 [/tex]
Volume = 1728 cubic inches.
Answer : Volume of cube is 1728 cubic inches.
Volume of cube is given by the formula :
[tex] Volume = a * a * a [/tex]
Where a is edge of the cube.
We are given edge of cube as 12 inches.
Plugging the value of edge in given formula:
[tex] Volume = 12 * 12 * 12 [/tex]
Volume = 1728 cubic inches.
Answer : Volume of cube is 1728 cubic inches.
As cars passed a checkpoint, the following speeds were clocked and recorded. Speed (mph): 55 62 61 54 68 72 59 61 70
What are the minimum, first quartile, median, third quartile, and maximum of the data set? Show your work.
Answers
We have ---- > 55, 62, 61, 54, 68, 72, 59 ,61, 70
In total 9 numbers
step 1
order the numbers from smallest to largest
54,55,59,61,61,62,68,70,72
1) What is the minimum of the data set ?
The lowest number is the minimum------------ > 54
2) What is the median of the data set ?
Find the number that is in the middle
54,55,59,61,61,62,68,70,72
The middle number is 61. That is the median.
Find the middle of each half. Since these numbers are between 2 numbers, you average the numbers (add then divide by 2).
55+59=114/2=57 This is the first quartile.
68+70=138/2=69 This is the third quartile
3) What is the first quartile of the data set ?
the answer is 57
4) What is the third quartile of the data set ?
the answer is 69
5) What is the maximum of the data set ?
The highest is the maximum------------ > 72
Answer:
Minimum = 54
Maximum = 72
Median = 61
First quartile = 57
Third quartile = 69
Step-by-step explanation:
Data : 55 62 61 54 68 72 59 61 70
Arrange the data is ascending order
54 , 55, 59, 61,61 ,62 , 68,70 ,72
So, minimum = 54
Maximum = 72
Median is the mid value .
There are nine observations.
So, 5th observation is the median
So, Median = 61
First quartile = It is the median of data of the left side data of the median .
Left side data : 54 , 55, 59, 61
There are four observations
Median = [tex]\frac{\frac{n}{2}th+(\frac{n}{2}+1)th}{2}[/tex]
Median = [tex]\frac{\frac{4}{2}th+(\frac{4}{2}+1)th}{2}[/tex]
Median = [tex]\frac{2th+3rd}{2}[/tex]
Median = [tex]\frac{55+59}{2}[/tex]
Median = [tex]57[/tex]
First quartile = 57
Third quartile = It is the median of data of the right side data of the median .
Right side data : 62 , 68,70 ,72
There are four observations
Median = [tex]\frac{\frac{n}{2}th+(\frac{n}{2}+1)th}{2}[/tex]
Median = [tex]\frac{\frac{4}{2}th+(\frac{4}{2}+1)th}{2}[/tex]
Median = [tex]\frac{2th+3rd}{2}[/tex]
Median = [tex]\frac{68+70}{2}[/tex]
Median = [tex]69[/tex]
Third quartile = 69
Hence minimum is 54 , maximum is 72 ,median is 61 , first quartile is 57 and third quartile is 69
In the diagram, KL = , LM = , and MN = . What is the perimeter of isosceles trapezoid KLMN? units units + units + units
Answers
The Perimeter of the isosceles trapezoid KLMN given the dimensions is;
3√2 + 2√5
How to find the Perimeter of a Quadrilateral?We re given the lengths of the isosceles trapezoid KLMN as;
KL = 2√2; LM = √5; MN = √2
We don't have the length of KN but we have the coordinates as;
K(-2, -4) and N(-1, -2)
Length of KN = √[(-2 - (-4))² + (-1 - (-2))]
Length of KN = √5
Thus;
Perimeter = 2√2 + √5 + √2 + √5
Perimeter = 3√2 + 2√5
Read more about Quadrilateral Perimeter at; https://brainly.com/question/24571594
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Need help on questions 1, and 2 please
Answers
2. All translations are considered rigid motion. The locations of points on the figure do not change relative to one another.
What is 7,433,654 rounded to the nearest 10,000
Answers
Here is your answer:
The proper answer for this question is "7,430,000".
3 is less than 5 which means it doesn't round up one.
Your answer is 7,430,000!
If you need anymore help feel free to ask me!
Hope this helps!
What is the following difference? 11 square root 45 - 4 square root 5
Answers
= 11√(9 * 5) - 4√5
= (11 · √9 · √5) - 4√5
= (11 · 3 · √5) - 4√5
= (11 * 3)√5 - 4√5
= 33√5 - 4√5
= (33-4)√5
= 29√5
Answer:
[tex]29\sqrt{5}.[/tex]
Step-by-step explanation:
The difference is
[tex]11\sqrt{45}-4\sqrt{5}[/tex]
To simplify let's try to covert [tex]\sqrt{45}[/tex] in terms of [tex]\sqrt{5}[/tex]:
45 = 9*5, then [tex]\sqrt{45} = \sqrt{9*5} = \sqrt{9}\sqrt{5} = 3\sqrt{5}[/tex]. So,
[tex]11\sqrt{45}-4\sqrt{5} = 11(3\sqrt{5})-4\sqrt{5} = 33\sqrt{5} -4\sqrt{5} = 29\sqrt{5}.[/tex]
Bernadette is at the turtle tank. There are 32 green (g) and yellow (y) turtles in the tank. There are 3 times as many yellow turtles as green turtles. Using the guess and check method, determine how many yellow turtles are in the tank.
Answers
Answer:
24
Step-by-step explanation:
The turtle tank has 24 yellow turtles, computed using the guess and check method.
What is the guess and check method?The guess and check method is the process of guessing a solution to the given conditions that will be satisfying all the conditions.
How to solve the question?In the question, we are informed that Bernadette is at the turtle tank, which has 32 green and yellow turtles in the tank. We are also informed that there are 3 times as many yellow turtles as green turtles.
Assuming the number of green turtles to be g, and the number of yellow turtles to be y, we can write the equation g + y = 32, as the total number of turtles is given to be 32.
Now, we are told that the number of yellow turtles is 3 times the number of yellow turtles.
Thus, we can say that y = 3g.
Substituting this in the equation, we get g + 3g = 32, or, 4g = 32.
We are asked to solve this equation by the guess and check method.
If we guess g to be 7, the equation is not satisfied as we get 28 = 32.
If we guess g to be 9, the equation is not satisfied as we get 36 = 32.
If we guess g to be 8, the equation is satisfied as we get 32 = 32.
Thus, the correct value for g is 8.
Thus, y = 3g = 3*8 = 24.
Thus, the turtle tank has 24 yellow turtles, computed using the guess and check method.
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So I need to add 2 teaspoons of conditioner for every 10 gallons of water in a tank. I have a 2.5-gallon tank, how much conditioner do I need to put in the tank? Please help I don't want my fish to die.
Answers
This is really just a simple equation:
2/10=x/2.5
Now, there are several ways you can really solve this, but i'll give you the basic version. You know for 10 gallons, you need 2 teaspoons. Divide, this means for every 1 teaspoon, you need 5 gallons. This here is a simplification.
Now, in order to get from 5 gallons per 1 teaspoon to 2.5 gallons per X teaspoons, you have to figure out the differences in what you know. 2.5 is half of 5, and what you do to one side of an equation, you do to the other. The first half was divided by half, so divide the second half (1 teaspoon) by half as well.
1/2=.5, AKA half.
2 teaspoons of conditioner for every 10 gallons
For 2.5 gallons, you need .5 teaspoons, or 2.46 ml.
Your answer is .5 teaspoons, basically HALF of a teaspoon.
~Hope this helps!
0.5 teaspoon of conditioner to 2.5 gallon of tank.
What is ratio?Comparing two amounts of the same units and determining the ratio tells us how much of one quantity is in the other. Two categories can be used to categorise ratios. Part to whole ratio is one, and part to part ratio is the other. The part-to-part ratio shows the relationship between two separate entities or groupings.
Given
So, you need 2 teaspoons of conditioner for every 10 gallons of water.
2/10=x/2.5
Now, know for 10 gallons, you need 2 teaspoons. Divide, this means for every 1 teaspoon, you need 5 gallons. This here is a simplification.
x =0.5
2 teaspoons of conditioner for every 10 gallons
For 2.5 gallons, you need .5 teaspoons.
Hence 0.5 teaspoon of conditioner to 2.5 gallon of tank.
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A rectangular room is 6 6 meters longer than it is wide, and its perimeter is 28 28 meters. find the dimension of the room
Answers
We also know that the length is 6 meters longer than the width.
Based on this we can create the following formula to find the dimensions:
28= (w+6)+(w+6)+w+w
Then to solve, it's just simple algebra.
First, combine like terms: 28= w+w+w+w+6+6 28= 4w+12
The next thing we do is isolate the variable by subtracting 12 from each side: 28-12 = 4w+12-12 16= 4w
The next thing we do is divide both sides by the coefficient (4): 16/4 = 4w/4
And this gives us the answer that w=4.
Now to find the dimensions:
We know that the width is equal to 4.
We also know that the length is equal to 6 more than the width. If the width is 4 then the length is 4+6 or 10.
So there you have it, the dimensions of the room would be 4x10.
3 times the complement of an angle is 30 more than the supplement of the original angle. What is the measure of the angle? 15° 30° 60° 90°
Answers
90-x (The complement of the angle)
180-x (The sumplement of the angle)
"x" is the angle that you want to calculate.
2. Then, you have:
3(90-x)+30=180-x
(270-3x)+30=180-x
300-3x=180-x
300-180=-x+3x
120=2x
120/2=x
x=60°
What is the measure of the angle?
The answer is: The measure of the angle is 60°.
(4) Check my work please?
Answers
x/3 = 3/4
x*4 = 3*3
4x = 9
x = 9/4
AC = AD+DC
AC = 4+x
AC = 4+9/4
AC = 16/4 + 9/4
AC = 25/4
AB^2 + BC^2 = AC^2
5^2 + y^2 = (25/4)^2
25 + y^2 = 625/16
y^2 = 625/16 - 25
y^2 = 625/16 - 400/16
y^2 = 225/16
y = sqrt(225/16)
y = 15/4
A system of equations is graphed on a coordinate plane.
Which coordinates are the best estimate of the solution to the system of equations?
(6, 0)
(0, 5)
(1, 4)
(1, 5)
Answers
4x+2y = 10
-2(2x+3y = 12) -->
-4x-6y = -24
+4x+2y = 10
----------------
0 + -4y = -14
-4y = -14
-4y/-4 = -14/-4
y = 7/2 = 3.33
4x+2y = 10
4x+2(7/2) = 10
4x+7 = 10
4x = 3
x = 3/4 = 0.75
So the solution is at (0.75, 3.33)
closest is C) (1, 4)
Point E is located at (–5, 2). Point M is the reflection of point E across the y-axis. What is the distance between E and M?
Answers
The distance between E and M is 10 units.
The reflection of point E across the y-axis, point M, is at (5, 2). The distance between these two points is 10 units.
Explanation:In the context of this problem, a reflection of a point across the y-axis inverts the sign of the x-coordinate while leaving the y-coordinate unchanged. Thus, if Point E is located at (-5, 2), the reflection of Point E, or Point M, would be located at (5, 2).
In terms of distance, it is important to remember that distance is always a positive value. Considering the x-coordinates, the distance from E to M is the absolute difference between their x-coordinates, which in this case is |-5 - 5| or 10 units.
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James has $32 and earns $10 per week for his allowance. What is the initial value for the scenario described?
A.10
B.32
C.42
D.320
Answers
This answer is confirmed!
what's the sum or difference
1. 4x^10-9x^10
2. 3y^5-10y^5
@kewlgeek555
Answers
1. -5x^10
Since both terms have an exponent of 5, they can both be subtracted.
2. -7y^5
Same reason as above.
Hope this helps!
A wolf population and compound interest were both used as examples of exponential functions. How easy is it for you to see how these diverse examples relate to exponential functions
Answers
Wolf population and compound interest are exponential functions because both functions are in the form of m x [tex]a^x[/tex] as given below.
What is a function?A function is a relationship between inputs where each input is related to exactly one output.
Example:
f(x) = 2x + 1
f(1) = 2 + 1 = 3
f(2) = 2 x 2 + 1 = 4 + 1 = 5
The outputs of the functions are 3 and 5
The inputs of the function are 1 and 2.
We have,
An exponential function is denoted as f(x) = [tex]a^x[/tex]
Where x is a variable and a is a constant.
Now,
Wolf population:
Suppose the wolf population initially is 10.
It grows double every year.
This means,
The population of wolves after 3 years.
x = 3
P = 10 x 2³ = 10 x 2 x 2 x 2 = 80
P = 10 x 2³ is an exponential function.
Now,
Compound interest:
Principal = 10
Rate = 10% per year
Time = 3
Amount = P [tex](1 + r/n)^{nt}[/tex]
A = 10 [tex](1 + 0.1)^3[/tex]
A = 10 x 1.1³
This is an exponential function.
Thus,
Wolf population and compound interest are exponential functions.
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The answer is (A) I find it very easy to see the relationships and why they are all exponential functions.
To see why a wolf population and compound interest both relate to exponential functions, follow these steps:
1. Understand exponential functions: An exponential function has the form [tex]\( f(t) = a \cdot b^t \)[/tex], where a is the initial amount, b is the growth (or decay) factor, and t is time.
2. Wolf population:
- Suppose a wolf population grows at a constant rate of 5% per year.
- If the initial population is [tex]\( P_0 \)[/tex], the population after t years is [tex]\( P(t) = P_0 \cdot (1.05)^t \)[/tex], showing exponential growth.
3. Compound interest:
- For compound interest, if you invest P dollars at an annual interest rate of r, compounded annually, the amount after t years is [tex]\( A(t) = P \cdot (1 + r)^t \)[/tex], which is also an exponential function.
4. Conclusion:
- Both scenarios involve quantities growing by a constant percentage over time, fitting the exponential model.
Thus, the answer is: A. I find it very easy to see the relationships and why they are all exponential functions.
Complete question:- A wolf population, and compound interest were both used as examples of exponential functions. How easy is it for you to see how these diverse examples relate to exponential functions?
A. I find it very easy to see the relationships and why they are all exponential functions.
B. I have some difficulty seeing the relationships but understand why they are both exponential functions.
C. I don't see the relationships and am not sure why they are both exponential functions.
D. I do not understand what an exponential function is.
Which equation demonstrates the distributive property?
A) 3 (2 + 8) = 3 (8 + 2)
B) 3 (2 + 8) = 3 × 2 + 3 × 8
C) (3 × 2) × 8 = 3 × (2 × 8)
D) 3 × (2 × 8) = 3 × (8 × 2)
Answers
The answer is:
B) 3(2+8) = 3x2 + 3x8
Hope this helps! :)
please help me and explain it