The diagram shows the layers of the Sun. Which labels correctly identify the layers most closely associated with gamma rays and visible light?
Z: Gamma rays
X: Visible light
X: Gamma rays
Z: Visible light
Z: Gamma rays
Y: Visible light
Y: Gamma rays
Z: Visible light
Answers
X - Visible Light
Gamma rays are heavily produced in the core of the sun but are diluted before they reach the surface (Z). And the surface is the only thing the human eye can see (X).
Answer:
Z: Gamma rays
X: Visible light
Explanation:
A close look at the diagram attach shows the core of the sun and then the external surface.
Gamma rays are intricately associated with the nuclear reactions that go on in the core of the sun that makes it to produce light. Hence Z must refer to gamma rays emitted in these nuclear processes at the core of the sun.
Visible light is given out by the sun and seen externally. Hence X is visible light.
Related Questions
If the spectrum of a star is blue shifted, which way is the star moving?
Answers
When you look at yourself in a pocket mirror and then hold the mirror farther away, you see less of yourself more of yourself the same of yourself?
Answers
Find the amount of work done in vertically lifting a steel beam of mass 600. kg at uniform speed through a distance of 38.0 m.
Answers
[tex]W=mg \Delta h[/tex]
where
m is the mass of the steel beam
g is the gravitational acceleration
[tex]\Delta h[/tex] is the variation of height of the object
In this problem, m=600 kg and [tex]\Delta h=38.0 m[/tex], therefore the work done to lift the object is
[tex]W=(600 kg)(9.81 m/s^2)(38.0 m)=2.24 \cdot 10^5 J[/tex]
From the calculations, we can see that the work done in the gravitational field is 228000J
What is work done?The work done in a gravitational field depends on the height of the body hence we have;
Work done = mgh
m = 600 kg
g = 10 m/s^2
h = 38 m
Hence
W = 600 kg * 10 m/s^2 * 38 m = 228000J
Learn more about work done:https://brainly.com/question/13662169?
#SPJ5
What total distance will a sound wave travel in air in 3.00 seconds at stp?
Answers
[tex]v=331.2 m/s[/tex]
The sound wave moves by uniform motion, so we can use the basic relationship between space, time and velocity:
[tex]S=vt[/tex]
where S is the distance covered by the sound wave in a time t. In our problem, t=3.00 s, therefore the distance covered by the sound wave is
[tex]S=vt=(331.2 m/s)(3.00 s)=993.6 m[/tex]
What is the biggest star in our solar system?
Answers
which direction will the magnetometer read for earth’s magnetic field when the satellite passes over earths equator ?
Answers
A magnetometer over the Earth's equator will detect Earth's magnetic field as a horizontal line pointing northward. As one moves west along the equator, the detected orientation of the magnetic field by the magnetometer remains constant due to the parallel nature of the magnetic field lines at this latitude.
Explanation:When a satellite equipped with a magnetometer passes directly over the Earth's equator, the primary direction the magnetometer will read for the Earth's magnetic field is horizontal and points towards the magnetic north pole. Since we are assuming the Earth's magnetic north is aligned with the geographic north pole, the magnetometer reading will be directed northward, perpendicular to the equator.
As the student or satellite moves west along the equator, the orientation of the magnetic field detected by the compass or magnetometer would not significantly change. This is because at the equator, the Earth's magnetic field lines are parallel to the Earth's surface, resulting in a compass needle aligning horizontally and pointing towards the north pole. Even while travelling, this horizontal alignment remains constant all along the equator.
Remember, magnetic field lines around a magnetic source, like Earth, follow a path from the magnetic north pole to the magnetic south pole. Also, a compass needle aligns itself with the local magnetic field lines. At the equator, these lines are parallel to the ground, dictating the needle's orientation.
A 1.00 kg object is attached to a horizontal spring. the spring is initially stretched by 0.500 m, and the object is released from rest there. it proceeds to move without friction. the next time the speed of the object is zero is 0.100 s later. what is the maximum speed of the object?
Answers
[tex]T=2 t = 2 \cdot 0.100 s = 0.200 s[/tex]
Which means that the frequency is
[tex]f= \frac{1}{T}= \frac{1}{0.200 s}=5 Hz [/tex]
and the angular frequency is
[tex]\omega=2 \pi f = 2 \pi (5 Hz)=31.4 rad/s[/tex]
In a spring-mass system, the maximum velocity of the object is given by
[tex]v_{max} = A \omega[/tex]
where A is the amplitude of the oscillation. In our problem, the amplitude of the motion corresponds to the initial displacement of the object (A=0.500 m), therefore the maximum velocity is
[tex]v_{max} = A \omega = (0.500 m)(31.4 rad/s)= 15.7 m/s[/tex]
The maximum speed of the object is 15.70 m/s
Given data:
The mass of object attached to horizontal spring is, m = 1.00 kg.
The stretching distance is, x = 0.500 m.
Time interval is, t = 0.100 s.
The linear velocity of spring - mass system is given as,
[tex]v = x \times \omega[/tex]
Here, [tex]\omega[/tex] is an angular speed. Solving as,
[tex]v = x \times (2 \pi f )\\\\v = x \times (\dfrac{2 \pi}{T} )[/tex]
Time period (T) for complete oscillation is, [tex]T = 2t[/tex].
[tex]v = x \times (\dfrac{2 \pi}{ 2 t} )\\v = 0.500 \times (\dfrac{ \pi}{0.100} )\\v =15.70 \;\rm m/s[/tex]
Thus, the maximum speed of the object is 15.70 m/s.
Learn more about the oscillation here:
https://brainly.com/question/15780863?referrer=searchResults
How many coulombs of charge are needed to produce 29.1 mol of solid zinc?
Answers
Zn (2+) + 2e (-) ------> Zn
It can be noted that 1 mole of Zn is produced by 2 Faraday of electricity.
For 29.1 moles,
Total charge required = 2*29.1 = 58.2 F
But, 1F = 96500 C
Then,
Amount of charge required = 96500*58.2 = 5,616,300 C
To produce 29.1 mol of solid zinc, approximately 2801443.5 Coulombs of charge are needed.
Explanation:To calculate the number of coulombs of charge needed to produce 29.1 mol of solid zinc, we need to use Faraday's constant, which is approximately 96485 C/mol.
Charge (in coulombs) = Faraday's constant x number of moles of substance
In this case, Charge = 96485 C/mol x 29.1 mol = 2801443.5 C.
Learn more about Coulombs of charge for producing solid zinc here:https://brainly.com/question/31440253
#SPJ3
"In this lesson, you learned about renewable energy resources and nonrenewable energy resources. Think about the resources discussed in this lesson and select the one that you think is the most effective in all ways. Think about the financial impact, the ability to be renewed, and the effectiveness of the energy that is produced. Write a paragraph describing why the resource you have selected is the most efficient."
I'm thinking wind energy, what else should be in this paragraph?
Answers
This is how hydro energy works:
its is usually built near a waterfall, OK so when the water falls of the cliff of the water fall , it creates a force which helps turn the generator and then it is carried into poles of electricity.
Hope this helps plus i gave u extra point Good luck :)
Rain or snow usually falls on the leeward side of a mountain range true or false
Answers
Answer:
false
Explanation:
The lowest surface temperature yet measured on anybody in the solar system is negative 200 degrees celsius occurring on
Answers
The difference in potential between the cathode and anode of a spark plug is 14700 v. what energy does the electron give up as it passes between the electrodes? answer in units of j.
Answers
[tex]\Delta U = e \Delta V[/tex]
where
e is the electron charge
[tex]\Delta V[/tex] is the potential difference
Plugging numbers into the equation, we find that the electron gives up is
[tex]\Delta U = (1.6 \cdot 10^{-19} C)(14700 V)=2.35 \cdot 10^{-15} J[/tex]
Which kind of star is most likely to spend the longest time on the main sequence?
A.) A low-mass red star
B.)A yellow star like
the sun
C.) a high-mass blue star
D.) a bright white star
Answers
Answer: 1. c . Nebula
2. a. low mass red star
3. d. turn into white dwarfs
4. c. 10 billion years
Explanation:
Which is the best example of a cycle: a turn of a wheel or a slide down a ski slope?
Answers
Final answer:
The best example of a cycle is a turn of a wheel, as it involves a repetitive motion that returns to its starting point, unlike a slide down a ski slope which is a linear motion.
Explanation:
When discussing the concept of a cycle, a turn of a wheel is the best example, as it involves a repetitive motion that returns to its starting point. As the wheel turns, each point on its circumference moves in a circular motion and eventually comes back to where it began, completing one cycle. This represents a continuous, recurring sequence over time and is often depicted in physics and other sciences when explaining rotational motions.
In contrast, a slide down a ski slope is a linear motion that does not inherently return to its starting point, thus not forming a cycle. While one may cycle up and down the slope repeatedly, the slide itself is not cyclical.
For instance, Bug B on a spinning wheel demonstrates this concept of a cycle perfectly as it continuously moves in a circle.
The periodic table lists all the compounds on Earth.
True or False?
Answers
Bettina spoke into a microphone during the school play to increase the sound of her voice so the audience could hear her speak. The loudness of Bettina’s voice was changed by what type of energy?
Answers
C.) Electric Energy
The diagram shows a charge moving into an electric field. The charge will most likely leave the electric field near which letter?
Answers
In fact, the electric field lines goes from a positive charge to a negative charge. This means that a positive charge would move in the same direction of the field lines, while a negative charge would move in the opposite direction of the field lines. In this problem, we have a negative charge, which is deflected downward (in the opposite direction of the field lines), so it will leave the electric field near position Y.
Answer:
Y
Explanation:
next to Y
________ describes the unique sound quality or tone color of a sound.
Answers
A humming bird feeder is tied by a rope to a tree branch. You notice that in a gentle breeze, the feeder moves back and forth 15 times in 1 minute. How long is the rope?
Answers
a proton is moving horizontally at 7.9 x 10^5 m/s. It passes through a vertical magnetic field that points downward. In which direction is the proton deflected by the magnetic field? A. up B. to the right of its velocity C. down D. to the left of its velocity
Answers
First, Its magnitude is proportional to the magnitude of the charge.
Second, the magnitude of the force is also proportional
Third, the magnetic force depends on the particle’s
velocity.
Fourth, we find by experiment that the magnetic force [tex]\vec{F}[/tex] does not have the same direction as the magnetic field [tex]\vec{F}[/tex] but instead is always perpendicular to both [tex]\vec{B}[/tex] and the velocity [tex]\vec{v}[/tex]
So, in a mathematical language this is given by:
[tex]\vec{F}=q\vec{v} \times \vec{B}[/tex]
So, this is a cross product. Therefore, applying the Right-hand rule:
The answer is:
D. to the left of its velocity.
Explaining this in other words:
"The force [tex]\vec{F}[/tex] is directed into the plane of the paper, so this is the direction of the proton"
The maximum gauge pressure in a hydraulic lift is 18.0 atm what is the largest size vehicle
Answers
The maximum gauge pressure in a hydraulic lift is 18.0 atm, the largest size vehicle (in terms of weight) that the hydraulic lift can lift is approximately 112,336.84 kg.
We must weigh the weight of the vehicle and the pressure imposed by the lift to find the largest size vehicle that can be lifted by a hydraulic lift with a maximum gauge pressure of 18.0 atm.
r = d / 2
r = 28.0 cm / 2
r = 14.0 cm
r = 0.14 m
A = π *[tex]r^2[/tex]
A = π * [tex](0.14 m)^2[/tex]
A ≈ 0.0616 [tex]m^2[/tex]
1 atm = 101,325 Pa
18.0 atm = 18.0 * 101,325 Pa
≈ 1,823,850 Pa
Substituting the values into the formula:
Force = (1,823,850) * (0.0616) ≈ 112,336.84 N
Now, we can calculate the weight (W) of the largest vehicle that can be lifted using the formula:
Weight = Force
Thus, the largest size vehicle (in terms of weight) that the hydraulic lift can lift is 112,336.84 kg.
For more details regarding gauge pressure, visit:
https://brainly.com/question/30698101
#SPJ6
Your question seems incomplete, the probable complete question is:
The maximum gauge pressure in a hydraulic lift is 18.0 atm what is the largest size vehicle "What is the largest size vehicle (kg) it can lift if the diameter of the output line is 28.0 cm? "
Serena is a research student who has conducted an experiment on the discoloration of marble. Read about Serena’s experiment. Then identify two flaws in her experiment’s design.Serena sees an article about the Taj Mahal, a medieval marble monument in India. She reads that the white monument is beginning to turn a dull yellow-brown. Serena admires the Taj Mahal and is eager to learn what might be causing the yellowing. She formulates a hypothesis that the yellow-brown tinge may be caused by air pollution from black carbon, brown carbon, or methane, combined with wind erosion.To test her hypothesis, she decides to study the effects of these air pollutants and wind on white marble. She finds three identical pieces of white marble and exposes one of them to air containing black carbon, one to air with brown carbon, and one to air with methane. She also places a fan on two of the samples, varying the speed of the air stream in regular intervals. After a few days, the marble samples begin changing color, becoming grayish. Serena learns that air pollution caused the discoloration. However, she is not sure how it became gray instead of yellow and what exactly caused the discoloration.
Answers
Serena's experiment has flaws including the absence of a control group and the failure to isolate variables, which makes it difficult to determine the exact cause of the marble discoloration.
Two flaws in Serena's experiment design:
Lack of Control Group: Serena should have had a control group of white marble exposed to clean air to compare the discoloration caused by pollutants accurately.
Insufficient Variables: Serena only considered air pollutants and wind speed as factors, neglecting other variables like humidity, temperature, or types of pollutants.
Two flaws in Serena's experiment design are evident: the lack of a control group and the lack of variable isolation. A control group is necessary to compare changes in marble coloration without any exposure to pollutants. Without this, it is impossible to ascertain if the discoloration is solely due to the pollutant exposure or if there are other environmental factors at play.
Furthermore, Serena exposed some marble samples to both air pollutants and varying wind speeds without having a sample with a constant wind speed. This means that the specific effects of each air pollutant could not be isolated, as the wind variation could have contributed to the discoloration. For a better understanding of the pollutants' effects, each variable (pollutant and wind speed) should be tested independently.
What is the force on an electron in a CRT when it’s moving at 2.5 × 105 meters/second perpendicular to a magnetic field of 1.5 teslas? The charge for an electron is -1.6 × 10-19 coulombs.
Answers
The force on an electron moving perpendicular to a magnetic field of 1.5 teslas at 2.5 × 10⁵ meters/second is calculated to be -6.0 × 10⁻¹⁴ newtons, using the formula F = qvB.
Explanation:The force on an electron moving perpendicular to a magnetic field can be calculated using the Lorentz force equation, which states that the magnetic force (F) exerted on a moving charge in a magnetic field is the product of the charge (q), its velocity (v), and the magnetic field strength (B), and is given by F = qvB when the velocity is perpendicular to the magnetic field. In this case, the electron has a charge of -1.6 × 10-19 coulombs, is moving at a velocity of 2.5 × 105 meters/second, and the magnetic field strength is 1.5 teslas.
Therefore, to calculate the force on the electron:
F = qvBF = (-1.6 × 10-19 C)(2.5 × 105 m/s)(1.5 T)F = -6.0 × 10-14 newtonsNote that the negative sign indicates the force direction according to Fleming's left-hand rule, opposite to the conventional current direction.
Using the Lorentz force equation, the force on an electron moving at 2.5 x 10^5 m/s perpendicular to a 1.5 T magnetic field with a charge of -1.6 x 10^-19 C is calculated to be -6.0 x 10^-14 N. The negative sign represents the direction opposite to the magnetic field.
Explanation:The force on an electron in a CRT (Cathode-Ray Tube) when it's moving perpendicular to a magnetic field can be determined by using the Lorentz force equation for magnetic force, which is F = qvBsin(\u03b8), where F is the force, q is the charge, v is the velocity of the particle, B is the magnetic field strength, and \u03b8 is the angle between the velocity and the magnetic field. In this case, the electron is moving perpendicular to the field, so \u03b8 = 90 degrees, and sin(90) = 1. Substituting the given values:
F = (-1.6 \u00d7 10^{-19} C)(2.5 \u00d7 10^{5} m/s)(1.5 T)
Since sin(90) = 1, the equation simplifies to:
F = (-1.6 \u00d7 10^{-19} C)(2.5 \u00d7 10^{5} m/s)(1.5 T)
After calculating, the magnetic force acting on the electron is:
F = -6.0 \u00d7 10^{-14} N
The negative sign indicates the direction of the force is opposite to the direction of the magnetic field, following Fleming's left-hand rule for the direction of magnetic force on a moving charge.
What is a half circle that extends from the north pole to the south pole?
Answers
Researchers have found that the ________ lobes of the brain are more active when we experience positive emotions, while the ________ lobes of the brain are more active when we experience negative emotions.
Answers
Answer:
Researchers have found that the left frontal lobes of the brain are more active when we experience positive emotions, while the right frontal lobes of the brain are more active when we experience negative emotions.
The frontal lobe of the brain has some functions such: movement control, behavior control, high-level mental functions and emotion control.
The frontal lobes of the brain are more active with positive emotions, and the right hemisphere is more active with negative emotions, reflecting their respective roles in emotional processing.
Explanation:Researchers have found that the frontal lobes of the brain are more active when we experience positive emotions, while the right hemisphere is more active when we experience negative emotions. The frontal lobe, involved in reasoning, motor control, emotion, and language, has been linked to the processing of positive emotions and is located in the forward part of the brain, extending back to a central sulcus. In contrast, the right hemisphere is associated with arousal and negative emotions, suggesting a lateralization effect in emotional processing.
Do other planets aside from Saturn have rings?
Answers
What is the potential energy of a 0.5 kg object sitting on a shelf that is 1.5 meters high?
Answers
=0.5 x1.5 x9.7(gravity)=7.275J
Answer:
what is the potential energy of a 5 kg apple that is sitting on a 1.5 m high tree branch
Explanation:
What can you do with the Freudian tools for analysis? You can decode the manifest content in your dreams. You can scrutinize a person's fears. You can protect latent content. You can figure out the non-projected dream content.
Answers
The answer is : you can decode the manifest content in your dreams.
Which element has a full valence shell of electrons
Answers
Helium , Neon , argon, xenon and radon all are noble gases and have full valence shell of electron
What are noble gases ?The noble gases (Group 18) are located in the far right of the periodic table and were previously referred to as the "inert gases" due to the fact that their filled valence shells (octets) make them extremely nonreactive.
The 18th group in the modern periodic table is of noble gases, because their outer most shell is completely filled as it have 8 electrons in the outermost shell , except helium which have 2 electrons in outermost shell ( He have only one shell )
Helium , Neon , argon, xenon and radon all are noble gases and have full valence shell of electron
learn more about noble gases
https://brainly.com/question/11764545?referrer=searchResults
#SPJ2
A car drives over a hilltop that has a radius of curvature 120 m at the top of the hill. at what speed would the car be traveling when it tires just barely lose contact with the road when the car is at the top of the hill?
Answers
V^2 = Rg, where V = maximum speed, R = Radius of curvature, g = gravitational acceleration.
Substituting;
V = Sqrt (Rg) = Sqrt (120*9.81) = 34.31 m/s
The car would be traveling about 122 km/h when its tires just barely lose contact with the road at the top of a hill with a radius of curvature of 120 m.
Explanation:This problem can be solved by using the concept of centripetal force. When the car's tires barely lose contact with the road, the only force acting on it will be the gravitational force. This gravitational force, or the weight of the car, must provide the required centripetal force for the car to stay in circular motion. Hence, we equate centripetal force to the gravitational force. This sets up the equation mg = mv²/r, where m is the mass of the car, g is the acceleration due to gravity, v is the velocity, and r is the radius. Notice that the mass of the car cancels out.
Solving this equation, we calculate the velocity v as √(g×r) = √(9.8×120) ≈ 34 m/s, which is about 122 km/h. Please note that the given figure of 165 km/h seems inconsistent with the radius provided in the question and commonly accepted value for gravity. However, for a steeper curve or a higher banking angle, the speed at which the car loses contact with the road could indeed be higher.
Learn more about Centripetal Force here:https://brainly.com/question/11324711
#SPJ3