The finishing time for cyclists in a race are normally distributed with an unknown population mean and standard deviation. If a random sample of 25 cyclists is taken to estimate the mean finishing time, what t-score should be used to find a 98% confidence interval estimate for the population mean?

Answer:

[tex]\sin x + \sqrt{1-\sin^2x}[/tex]

Step-by-step explanation:

Given: sin x + cos x

To change the given trigonometry expression in term of sine only.

Trigonometry identity:-

Expression: [tex]\sin x+\cos x[/tex]

We get rid of cos x from expression and write as sine form.

Expression: [tex]\sin x + \sqrt{1-\sin^2x}[/tex]        [tex]\because \cos x=\sqrt{1-\sin^2x}[/tex]

Hence, The final expression is only sine function.

Answer:

1) Base - 5

2) Base - 1.2

3) Base - [tex]\frac{1}{3}[/tex]

Step-by-step explanation:

To find : Write the base number for each expression ?

Solution :

Base number is defined as the number written in exponent form [tex]a^n[/tex]

which tells you to multiply a by itself, so a is the base of power n.

1) [tex]5^{12}[/tex]

In number [tex]5^{12}[/tex] the base is 5 as the power is 12.

2) [tex]1.2^{2}[/tex]

In number [tex]1.2^{2}[/tex] the base is 1.2 as the power is 2.

3) [tex](\frac{1}{3})^{2}[/tex]

In number  [tex](\frac{1}{3})^{2}[/tex] the base is [tex]\frac{1}{3}[/tex] as the power is 4.

The base number for 5^12 is 5, for 1.2^2 is 1.095, and for (1/3)^4 is 0.577.

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Answer:

The age of this sample is 13,417 years.

Step-by-step explanation:

The amount of carbon 14 present in a sample after t years is given by the following equation:

[tex]C(t) = C_{0}e^{-0.00012t}[/tex]

Estimate the age of a sample of wood discoverd by a arecheologist if the carbon level in the sampleis only 20% of it orginal carbon 14 level.

The problem asks us to find the value of t when

[tex]C(t) = 0.2C_{0}[/tex]

So:

[tex]C(t) = C_{0}e^{-0.00012t}[/tex]

[tex]0.2C_{0} = C_{0}e^{-0.00012t}[/tex]

[tex]e^{-0.00012t} = \frac{0.2C_{0}}{C_{0}}[/tex]

[tex]e^{-0.00012t} = 0.2[/tex]

[tex]ln e^{-0.00012t} = ln 0.2[/tex]

[tex]-0.00012t = -1.61[/tex]

[tex]0.00012t = 1.61[/tex]

[tex]t = \frac{1.61}{0.00012}[/tex]

[tex]t = 13,416.7[/tex]

The age of this sample is 13,417 years.

Answer:

1880 milliliter (mL) = 3.97 pints (pts)

Step-by-step explanation:

This problem can be solved as a rule of three problem.

In a rule of three problem, the first step is identifying the measures and how they are related, if their relationship is direct of inverse.

When the relationship between the measures is direct, as the value of one measure increases, the value of the other measure is going to increase too.

When the relationship between the measures is inverse, as the value of one measure increases, the value of the other measure will decrease.

Unit conversion problems, like this one, is an example of a direct relationship between measures.

1 milliliter (mL) is equal to 0.002 pints. How many pints are 1880 milliliter (mL)? We have the following rule of three

1 mL - 0.002 pints

1880 mL - x pints

x = 1880*0.002

x = 3.97 pints

There are 3.97 pints in 1880 milliliters.

Answer:

1) [tex]7 x 10^{15} J[/tex]

2) [tex]40.5[/tex] days

Step-by-step explanation:

1) First of all we use [tex]1MJ=1x10^{6}J[/tex] so the total energy will be [tex]7x10^{9} kg * 1x10^{6} \frac{J}{kg} =7x10^{15}J[/tex].

2)Then we use [tex]1W=1\frac{J}{s}[/tex] and [tex]Time=\frac{7 x 10^{15} J }{2x10^{9}J/s} =3.5x10^{6}s[/tex] or [tex]3.5x10^{6}s*\frac{1h}{3600s}*\frac{1day}{24h} =40.5 days[/tex]

Answer:

[tex]26^{39}[/tex] is greater.

Step-by-step explanation:

Given numbers,

[tex]26^{39}\text{ and }39^{26}[/tex]

∵ HCF ( 26, 39 ) = 13,

That is, we need to make both numbers with the exponent 13.

[tex]26^{39}=((13\times 2)^3)^{13}=(13^3\times 2^3)^{13}=(13^3\times 8)^{13}=(13^2\times 104)^{13}[/tex]

[tex](\because (a)^{mn}=(a^m)^n\text{ and }(ab)^m=a^m.a^n)[/tex]

[tex]39^{26}=((13\times 3)^2)^{13}=(13^2\times 3^2)^{13}=(13^2\times 9)^{13}[/tex]

Since,

[tex]13^2\times 104>13^2\times 9[/tex]

[tex]\implies (13^2\times 104)^{13} > (13^2\times 9)^{13}[/tex]

[tex]\implies 26^{39} > 39^{26}[/tex]

Answer:

Step-by-step explanation:

Estimated because there is no number that can go into 5 and 8 evenly

Answer:

The proposition: The sum of two odd numbers is an even number is true.

Step-by-step explanation:

A proof by contradiction is a proof technique that is based on this principle:

To prove a statement P is true, we begin by assuming P false and show that this leads to a contradiction; something that always false.

Facts that we need:

Proposition. The sum of two odd numbers is an even number

Proof. Suppose this proposition is false in this case we assume that the sum of two odd numbers is not even. (That would mean that there are two odd numbers out there in the world somewhere that'll give us an odd number when we add them.)

Let a, b be odd numbers. Then there exist numbers m, n, such that a = 2m + 1, b = 2n + 1 .Thus a + b = (2m + 1) + (2n + 1) = 2(m + n + 1) which is even. This contradicts the assumption that the sum of two odd numbers is not even.

To determine the number of subsets that can be formed from a set containing eleven elements, we use the formula [tex]2^n,[/tex] yielding [tex]2^11[/tex] = 2048 possible subsets.

The question is about finding the number of subsets that can be formed from a set containing eleven elements. To determine this, we employ the principle that for any set with n elements, the number of possible subsets is 2n. This includes both the empty set and the set itself as subsets.

Therefore, for a set with 11 elements, the number of possible subsets is 211 = 2048. This calculation reveals that one can form 2048 different subsets from a set of eleven elements. This includes all possible combinations of elements within the set, ranging from choosing no elements (the empty set) to choosing all eleven elements (the set itself).

Answer: I don't know if you wanted to write sin(4x) or [tex]sin^{4} (x)[/tex] , but here we go:

ok, sin(4x) = sin(2x + 2x), and we know that:

sin (a + b) = sin(a)*cos(b) + sin(b)*cos(a)

then sin (2x + 2x) = sin(2x)*cos(2x) + cos(2x)*sin(2x) = 2cos(2x)*sin(2x)

So 2*cos(2x)*sin(2x) is equivalent of sin(4x)

If you writed [tex]sin^{4} (x)[/tex] then:

[tex]sin^{4} (x) = sin^{2} (x)*sin^{2} (x)[/tex]

and using that: [tex]sins^{2} (x) = \frac{1-cos(2x)}{2}[/tex]

we have: [tex]sin^{2} (x)*sin^{2} (x) = \frac{(1-cos(2x))*(1-cos(2x))}{4} = \frac{1-2cos(2x) + cos^{2}(2x) }{4}[/tex]

and using that: [tex]cos^{2} (x) = \frac{1 + cos(2x)}{2}[/tex]

[tex]\frac{1-2cos(2x) + cos^{2}(2x) }{4} = \frac{1-2cos(2x) + \frac{1+cos(4x)}{2} }{4}[/tex]

You can keep simplifying it, but there is your representation of [tex]sin^{4} (x)[/tex]  that does not contain powers of trigonometric functions greater than 1.

To write an equivalent expression for sin(4x) without powers of trigonometric functions greater than 1, use the trigonometric identity sin(2x) = 2sin(x)cos(x). Apply this identity twice to get 4sin(x)cos(x)(cos^2(x) - sin^2(x)).

To write an equivalent expression for sin(4x) that does not contain powers of trigonometric functions greater than 1, we can use the trigonometric identity sin(2x) = 2sin(x)cos(x). By applying this identity twice, we get:

Therefore, an equivalent expression for sin(4x) that does not contain powers of trigonometric functions greater than 1 is 4sin(x)cos(x)(cos^2(x) - sin^2(x)).

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Answer: D. 2.5

Step-by-step explanation:

Given : Line segment DF is dilated from the origin to create line segment D’F’ at D' (0, 10) and F' (7.5, 5).

The original coordinates for line segment DF are D(0, 4) and F(3, 2).

We know that the scale factor(k) is the ratio of the coordinates of the image points and the original points.

Then, [tex]k=\dfrac{\text{ y-coordinate of D'}}{\text{y-coordinate of D}}\\\\=\dfrac{10}{4}=\dfrac{5}{2}=2.5[/tex]

Hence, the scale factor was line segment DF dilated by = 2.5

Answer:

The answer to this is 2.5

Step-by-step explanation:

Well 1 i took the test and 2 if you mulitply the otginial coordinates by 2.5 then you will get the new cordiates

Answer:

[tex]x\ =\ \dfrac{21}{5}[/tex]

[tex]y\ =\ \dfrac{3}{5}[/tex]

z = 2

Step-by-step explanation:

Given equations are

x - 2y - z = 2

x + 3y - 2z = 4

-x + 2y + 3z = 2

from the given equations the augmented matrix can be written as

[tex]\left[\begin{array}{ccc}1&-2&-1:2\\1&3&-2:4\\-1&2&3:2\end{array}\right][/tex]

[tex]R_2=>R_2-R_1\ and\ R_3=>R_3+R_1[/tex]

[tex]=\ \left[\begin{array}{ccc}1&-2&-1:2\\0&5&-1:2\\0&0&2:4\end{array}\right][/tex]

[tex]R_2=>\dfrac{R_2}{5}[/tex]

[tex]=\ \left[\begin{array}{ccc}1&-2&-1:2\\0&1&\dfrac{-1}{5}:\dfrac{2}{5}\\0&0&2:4\end{array}\right][/tex]

[tex]R_1=>R_1+2.R_2[/tex]

[tex]=\ \left[\begin{array}{ccc}1&0&-1-\dfrac{2}{5}:2+\dfrac{4}{5}\\\\0&1&\dfrac{-1}{5}:\dfrac{2}{5}\\\\0&0&2:4\end{array}\right][/tex]

[tex]=\ \left[\begin{array}{ccc}1&0&\dfrac{-7}{5}:\dfrac{14}{5}\\\\0&1&\dfrac{-1}{5}:\dfrac{2}{5}\\\\0&0&2:4\end{array}\right][/tex]

[tex]R_3=>\dfrac{R_3}{2}[/tex]

[tex]=\ \left[\begin{array}{ccc}1&0&\dfrac{-7}{5}:\dfrac{14}{5}\\\\0&1&\dfrac{-1}{5}:\dfrac{2}{5}\\\\0&0&1:2\end{array}\right][/tex]

[tex]R_1=>R_1+\dfrac{7}{5}R_3\ and\ R_2+\dfrac{1}{5}R_3[/tex]

[tex]=\ \left[\begin{array}{ccc}1&0&0:\dfrac{14}{5}+\dfrac{7}{5}\\\\0&1&0:\dfrac{2}{5}+\dfrac{1}{5}\\\\0&0&1:2\end{array}\right][/tex]

So, from the above augmented matrix, we can write

[tex]x\ =\ \dfrac{21}{5}[/tex]

[tex]y\ =\ \dfrac{3}{5}[/tex]

z = 2

Answer:

As consequence of the Taylor theorem with integral remainder we have that

[tex]f(x) = f(a) + f'(a)(x-a) + \frac{f''(a)}{2!}(x-a)^2 + \cdots + \frac{f^{(n)}(a)}{n!}(x-a)^n + \int^a_x f^{(n+1)}(t)\frac{(x-t)^n}{n!}dt[/tex]

If we ask that [tex]f[/tex] has continuous [tex](n+1)[/tex]th derivative we can apply the mean value theorem for integrals. Then, there exists [tex]c[/tex] between [tex]a[/tex] and [tex]x[/tex] such that

[tex] \int^a_x f^{(n+1)}(t)\frac{(x-t)^k}{n!}dt = \frac{f^{(n+1)}(c)}{n!} \int^a_x (x-t)^n d t = \frac{f^{(n+1)}(c)}{n!} \frac{(x-t)^{n+1}}{n+1}\Big|_a^x[/tex]

Hence,

[tex] \int^a_x f^{(n+1)}(t)\frac{(x-t)^k}{n!}d t = \frac{f^{(n+1)}(c)}{n!} \frac{(x-t)^{(n+1)}}{n+1} = \frac{f^{(n+1)}(c)}{(n+1)!}(x-a)^{n+1} .[/tex]

Thus,

[tex] \int^a_x f^{(n+1)}(t)\frac{(x-t)^k}{n!}d t = \frac{f^{(n+1)}(c)}{(n+1)!}(x-a)^{n+1} [/tex]

and the Taylor theorem with Lagrange remainder is

[tex] f(x) = f(a) + f'(a)(x-a) + \frac{f''(a)}{2!}(x-a)^2 + \cdots + \frac{f^{(n)}(a)}{n!}(x-a)^n + \frac{f^{(n+1)}(c)}{(n+1)!}(x-a)^{n+1}[/tex].

Step-by-step explanation:

Answer:

Cost function C(x) == FC + VC*Q

Revenue function R(x) = Px * Q

Profit function P(x) =(Px * Q)-(FC + VC*Q)

P(12000) = -38000 Loss

P(23000) = 28000 profit

Step-by-step explanation:

Total Cost is Fixed cost plus Variable cost multiplied by the produce quantity.  

(a)Cost function

C(x) = FC + vc*Q

Where  

FC=Fixed cost

VC=Variable cost

Q=produce quantity

(b)

Revenue function

R(x) = Px * Q

Where  

Px= Sales Price

Q=produce quantity

(c) Profit function

Profit = Revenue- Total cost

P(x) =(Px * Q)-(FC + vc*Q)

(d) We have to replace in the profit function

at 12,000 units

P(12000) =($20 * 12,000)-($110,000 + $14*12,000)

P(12000) = -38000

at 23,000 units

P(x) =($20 * 23,000)-($110,000 + $14*23,000)

P(23000) = 28000

Step-by-step explanation:

Consider the provided information.

If Fury is the director of SHIELD then Hill and Coulson are SHIELD agents"

For the condition statement [tex]p \rightarrow q[/tex] or equivalent "If p then q"

Part (A) Write the contrapositive.

Here p is Fury is the director of SHIELD, and q is Hill and Coulson are SHIELD agents.

Contrapositive: If Hill and Coulson are not SHIELD agents, then Fury is not the director of SHIELD.

Part (b) Write the converse.

Here p is Fury is the director of SHIELD, and q is Hill and Coulson are SHIELD agents.

Converse: If Hill and Coulson are SHIELD agents, then Fury is the director of SHIELD.

Part (c) Write the inverse.

Here p is Fury is the director of SHIELD, and q is Hill and Coulson are SHIELD agents.

Inverse: If Fury is not the director of SHIELD then Hill and Coulson are not SHIELD agents

Part (D) Write the negation.

Here p is Fury is the director of SHIELD, and q is Hill and Coulson are SHIELD agents.

Negation: Fury is the director of SHIELD and Hill and Coulson are not SHIELD agents"

Step-by-step explanation:

Consider the provided information.

If Fury is the director of SHIELD then Hill and Coulson are SHIELD agents." For the condition statement  or equivalent "If p then q"

The rule for Converse is: Interchange the two statements.

The rule for Inverse is: Negative both statements.

The rule for Contrapositive is: Negative both statements and interchange them.

The rule for Negation is: If p then q" the negation will be: p and not q.

- Part (A) Write the contrapositive.

.Here p is Fury is the director of SHIELD, and q is Hill and Coulson are SHIELD agents.

Contrapositive: If Hill and Coulson are not SHIELD agents, then Fury is not the director of SHIELD.

- Part (b) Write the converse.

 .Here p is Fury is the director of SHIELD, and q is Hill and Coulson are SHIELD agents.

 .Converse: If Hill and Coulson are SHIELD agents, then Fury is the director of SHIELD.

- Part (c) Write the inverse.

 .Here p is Fury is the director of SHIELD, and q is Hill and Coulson are SHIELD agents.

 .Inverse: If Fury is not the director of SHIELD then Hill and Coulson are not SHIELD agents

- Part (D) Write the negation.

 .Here p is Fury is the director of SHIELD, and q is Hill and Coulson are SHIELD agents.

 .Negation: Fury is the director of SHIELD and Hill and Coulson are not SHIELD agents"

There are 11,238,513 ways Powerball tickets can be purchased.

There are 292, 201, 338 ways to win Powerball tickets.

Given

Number of white balls = 69

Number of white balls drawn = 5

Number of red balls = 26

Number of red balls drawn = 1

The combination is the way to select the number of objects from a group.

The formula is used to select the number of the object is;

[tex]\rm = \ ^nC_r \\\\\rm = \dfrac{n!}{(n-r)!r!}[/tex]

Where n is the total number of objects and r is the number of selected objects.

1. How many possible different Powerball tickets can be purchased?

The number of ways Powerball tickets can be purchased is;

[tex]\rm = \ ^{69}C_5\\\\= \dfrac{69!}{(69-5)!. 5!}\\\\= \dfrac{69!}{64!.5!}\\\\= 11238513[/tex]

There are 11,238,513 ways Powerball tickets can be purchased.

2.  How many possible different winning Powerball tickets are there?

A number of ways to win Powerball tickets are there is;

[tex]\rm = \ ^{69}C_5 \times ^{26}C_1\\\\= \dfrac{69!}{(69-5)!. 5!} \times \dfrac{26!}{(26-1)!\times 1!}\\\\= \dfrac{69!}{64!.5!} \times \dfrac{26!}{25!.1!}\\\\= 11238513 \times 26\\\\= 292, 201, 338 ways[/tex]

There are 292, 201, 338 ways to win Powerball tickets.

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The total number of possible different Powerball tickets is 292,201,338, calculated by multiplying 11,238,513 combinations of white balls with the 26 possible red balls. There is only one winning combination for the Powerball jackpot, so there is only one possible winning Powerball ticket.

To calculate the total number of possible different Powerball tickets, we must consider the combination of white balls and the selection of the red Powerball. There are 5 white balls drawn from a set of 69, and this is a combination because the order does not matter. Therefore, the number of combinations of white balls is calculated using the combination formula C(n, k) = n! / (k!(n-k)!), where n is the total number of balls to choose from and k is the number of balls chosen. So, the calculation is C(69, 5) = 69! / (5!(69-5)!) = 11,238,513 combinations of white balls.

For the red Powerball, there is 1 ball drawn from a set of 26, and since there is only one ball, there are 26 possible outcomes. To find the total number of possible Powerball tickets, multiply the number of white ball combinations by the number of possible red balls: 11,238,513 × 26 = 292,201,338 possible Powerball tickets.

For part b, considering that there is only one winning combination, there is just one possible winning Powerball ticket.

Answer:

The function is a parabola described by: [tex]y = 1 +\frac{(x-2)^{2}}{8}[/tex]

Step-by-step explanation:

Since a directrix and a focus are given, then we know that they are talking about a parabola.

We know that the distance from any point in a parabola (x, y), to the focus is exactly the same as the distance to the directrix. Therefore, in order to find the required equation, first we will compute the distance from an arbitrary point on the parabola (x, y) to the focus (2, 1):

[tex]d_{pf} = \sqrt{(x-2)^2+(y-1)^2}[/tex]

Next, we will find the distance from an arbitrary point on the parabola (x, y) to the directrix (y= -3). Since we have an horizontal directrix, the distance is easily calculated as:

[tex]d_{pd}=y-(-3)=y+3[/tex]

Finally, we equate the distances in order to find the parabola equation:

[tex]\sqrt{(x-2)^2+(y-1)^2}=y+3[/tex]

[tex](x-2)^2+(y-1)^2=(y+3)^2[/tex]

[tex](x-2)^{2} +y^{2}-2y+1=y^{2}+6y+9[/tex]

[tex](x-2)^{2}-8=8y[/tex]

[tex]y = \frac{(x-2)^{2}}{8}-1[/tex]

Answer:  We should dispense 60 tablets.

Step-by-step explanation:

Given : A patient is to receive 2 tablets po ACHS for 30 days.

i.e. Dose for each day = 2 tablets

Number of days = 30

If a patient takes 2 tablets each day , then the number of tablets he require for 30 days will be :-

[tex]2\times30=60[/tex]   [Multiply 2 and 30]

Therefore, the number of tablets we should dispense = 60

For this case we propose a rule of three:

110.2 million -------------> 100%

x --------------------------------------> 17.7%

Where the variable "x" represents the number of households (in millions) that watched the finals of a popular reality series.

[tex]x =  \frac {17.7 * 110.2} {100}\\x = \frac {1950.54} {100}\\x = 19.5054[/tex]

Thus, a total of 19.5054 million homes watched the finals of a popular reality series.

Answer:

19.5054 million homes watched the finals of a popular reality series.

Final answer:

The expected value of the winnings on a $8 bet placed on a red number in European roulette is -$1.945, indicating an average loss.

Explanation:

The question concerns the expected value of winnings on a $8 bet placed on red in European roulette. In European roulette, there are 18 red numbers, 18 black numbers, and 1 green number (0), totaling 37 numbers. A bet on red will win if the ball lands on any of the red numbers. When betting $8 on red, the player will either win $8 or lose $8, since the payoff for winning is 1:1.

To calculate the expected value, we consider the probability of winning, P(Win), and the probability of losing, P(Lose). The probability of landing on red (and wining) is 18/37, and the probability of not landing on red (and losing) is 19/37 (which includes the 18 black and 1 green).

The expected value is calculated as follows:

EV = (amount won × P(Win)) + (amount lost × P(Lose))

EV = ($8 × 18/37) + (-$8 × 19/37)

EV = $2.16 + (-$4.11)

EV = -$1.95

Rounded to three decimal places, the expected value is -$1.945.

Thus, if you were to place a $8 bet on red in European roulette, you would expect to lose, on average, $1.945 per game, as the expected value is negative.

Answer: Our required probability is 0.406.

Step-by-step explanation:

Since we have given that

Probability of selecting an adult over 40 years of age with cancer = 0.05

Probability of a doctor correctly diagnosing a person with cancer as having the disease = 0.78

Probability of incorrectly diagnosing a person without cancer as having the disease = 0.06

Let A be the given event i.e. adult over 40 years of age with cancer. P(A) = 0.05.

So, P(A')=1-0.05 = 0.95

Let C be the event that having cancer.

P(C|A)=0.78

P(C|A')=0.06

So, using the Bayes theorem, we get that

[tex]P(A|C)=\dfrac{P(A).P(C|A)}{P(A).P(C|A)+P(A')P(C|A')}\\\\P(A|C)=\dfrac{0.78\times 0.05}{0.78\times 0.05+0.06\times 0.95}\\\\P(A|C)=0.406[/tex]

Hence, our required probability is 0.406.

Answer:

(a) 0.48, (b) 0.625, (c) 0.1923

Step-by-step explanation:

First define

Probability a person is a democrat: P(D) = 0.4

Probability a person is a republican: P(R) = 0.6

Probability a person support the measure given that the person is a democrat: P(SM | D) = 0.75

Probability a person support the measure given that the person is a republican: P(SM | R) = 0.3

Now for the Theorem of total probabilities we have

(a) P(SM) = P(SM | D)P(D)+P(SM | R)P(R) = (0.75)(0.4)+(0.3)(0.6) = 0.48

and for the Bayes' Formula we have

(b) P(D | SM) = P(SM | D)P(D)/[P(SM | D)P(D)+P(SM | R)P(R)] = (0.75)(0.4)/0.48 = 0.625

Now let SMc be the complement of support the measure, i.e.,

P(SMc | D) = 0.25 : Probability a person does not support the measure given that the person is a democrat

P(SMc | R) = 0.7: Probability a person does not support the measure given that the person is a republican,

and also for the Bayes' Formula we have

(c) P(D | SMc) = P(SMc | D)P(D)/[P(SMc | D)P(D)+P(SMc | R)P(R)] = (0.25)(0.4)/[(0.25)(0.4)+(0.7)(0.6)] = 0.1/(0.52)=0.1923

Final answer:

This detailed answer covers the calculation of probabilities regarding support for gun control based on political affiliation in a certain town in the United States.

Explanation:

a) To find the probability that a randomly selected resident supports the measure, we calculate as follows: P(support) = P(support|Democrat) ∗ P(Democrat) + P(support|Republican) ∗ P(Republican) = 0.75 ∗ 0.40 + 0.30 ∗ 0.60 = 0.45 + 0.18 = 0.63.

b) The probability that a supporter is a Democrat can be found using Bayes' theorem: P(Democrat|support) = P(support|Democrat) ∗ P(Democrat) / P(support) = 0.75 ∗ 0.40 / 0.63 = 0.4762.

c) To find the probability that a non-supporter is a Democrat: P(Democrat|non-support) = P(non-support|Democrat) ∗ P(Democrat) / P(non-support) = 0.25 ∗ 0.40 / (1 - 0.63) = 0.1.

Answer:

time = 28 years

Step-by-step explanation:

Given,

principal amount = $10,000

rate = 4%

total amount = $30,000

According to compound interest formula

[tex]A\ =\ P(1+r)^t[/tex]

where, A = total amount

            P = principal amount

            r = rate

            t = time in years

so, from the question we can write,

[tex]30000\ =\ 10000(1+0.04)^t[/tex]

[tex]=>\ \dfrac{30000}{10000}\ =\ (1+0.04)^t[/tex]

[tex]=>\ 3\ =\ (1.04)^t[/tex]

by taking log on both sides, we will get

=> log3 = t.log(1.04)

[tex]=>\ t\ =\ \dfrac{log3}{log1.04}[/tex]

=> t = 28.01

So, the time taken to get the amount from 10000 to 30000 is 28 years.

By the binomial theorem we know that

[tex]1 = (.4 + .6)^8 \\ = {8 \choose 0} (.4)^{8} (.6)^{0} + {8 \choose 1} (.4)^{7} (.6)^{1} +{8 \choose 2} (.4)^{6} (.6)^{2} + {8 \choose 3} (.4)^{5} (.6)^{3} + {8 \choose 4} (.4)^{4} (.6)^{4} \\ + \quad {8 \choose 5} (.4)^{3} (.6)^{5} + {8 \choose 6} (.4)^{2} (.6)^{6} + {8 \choose 7} (.4)^{1} (.6)^{7} + {8 \choose 8} (.4)^{0} (.6)^{8}[/tex]

The probability that exactly 5 of 8 support the incumbent is the term

 [tex]{8 \choose 5} (.4)^{3} (.6)^{5}[/tex]

So at least five of eight support is the sum of this term and beyond,

[tex]p={8 \choose 5} (.4)^{3} (.6)^{5} + {8 \choose 6} (.4)^{2} (.6)^{6} + {8 \choose 7} (.4)^{1} (.6)^{7} + {8 \choose 8} (.4)^{0} (.6)^{8}[/tex]

No particularly easy way of calculating that except popping it into Wolfram Alpha which reports

[tex]p = \dfrac{ 46413}{78125}[/tex]

Shouldn't half the terms work out to .6 ?  Interestingly it's not exactly .6 but pretty close at .594.

The total probability of at least five residents supporting the candidate, denoted as P(X≥5), is calculated by summing the probabilities of exactly five, six, seven, and eight residents supporting the candidate.

To find the probability of at least five out of eight randomly selected residents supporting the incumbent candidate when 60% of the community supports them, calculate and sum the binomial probabilities for exactly five to eight residents supporting the candidate.

The student is asking for the probability of at least five out of eight randomly selected community members supporting the incumbent candidate, given that 60% of the eligible voting residents support the candidate. This is a binomial probability problem because each selection is a Bernoulli trial with only two possible outcomes (support or do not support) and the probability of a resident supporting the candidate is constant (60%).

To calculate this probability, we will sum the probabilities of exactly five, six, seven, and eight residents supporting the candidate:

Calculate the probability of exactly 5 residents supporting the candidate using the binomial probability formula: P(X = 5) = (8 choose 5) * (0.6)^5 * (0.4)^3.

Repeat the process for P(X = 6), P(X = 7), and P(X = 8).

Finally, sum these probabilities to get the total probability of at least five residents supporting the candidate: P(X \\u2265 5) = P(X = 5) + P(X = 6) + P(X = 7) + P(X = 8).

This sum provides the required probability.

Answer:

This is the reduced row-echelon form

[tex]\left[\begin{array}{cccccc}1&-2&0&0&3&5\\0&0&1&0&2&-3\\0&0&0&1&-4&7\end{array}\right][/tex]

from the augmented matrix

[tex]\left[\begin{array}{cccccc}1&-2&3&2&1&10\\2&-4&8&3&10&7\\3&-6&10&6&5&27\end{array}\right][/tex]

Step-by-step explanation:

To transform an augmented matrix to the reduced row-echelon form we need to follow this steps:

1. Write the system of equations as an augmented matrix.

The augmented matrix for a system of equations is a matrix of numbers in which each row represents the constants from one equation (both the coefficients and the constant on the other side of the equal sign) and each column represents all the coefficients for a single variable.

[tex]\left[\begin{array}{cccccc}1&-2&3&2&1&10\\2&-4&8&3&10&7\\3&-6&10&6&5&27\end{array}\right][/tex]

2. Make zeros in column 1 except the entry at row 1, column 1 (this is the pivot entry). Subtract row 1 multiplied by 2 from row 2 [tex]\left(R_2=R_2-\left(2\right)R_1\right)[/tex]

[tex]\left[\begin{array}{cccccc}1&-2&3&2&1&10\\0&0&2&-1&8&-13\\3&-6&10&6&5&27\end{array}\right][/tex]

3. Subtract row 1 multiplied by 3 from row 3 [tex]\left(R_3=R_3-\left(3\right)R_1\right)[/tex]

[tex]\left[\begin{array}{cccccc}1&-2&3&2&1&10\\0&0&2&-1&8&-13\\0&0&1&0&2&-3\end{array}\right][/tex]

4. Since element at row 2 and column 2 (pivot element) equals 0, we need to swap rows. Find the first non-zero element in the column 2 under the pivot entry. As can be seen, there are no such entries. So, move to the next column. Make zeros in column 3 except the entry at row 2, column 3 (pivot entry). Divide row 2 by 2 [tex]\left(R_2=\frac{R_2}{2}\right)[/tex]

[tex]\left[\begin{array}{cccccc}1&-2&3&2&1&10\\0&0&1&-1/2&4&-13/2\\0&0&1&0&2&-3\end{array}\right][/tex]

5. Subtract row 2 multiplied by 3 from row 1 [tex]\left(R_1=R_1-\left(3\right)R_2\right)[/tex]

[tex]\left[\begin{array}{cccccc}1&-2&0&7/2&-11&59/2\\0&0&1&-1/2&4&-13/2\\0&0&1&0&2&-3\end{array}\right][/tex]

6. Subtract row 2 from row 3 [tex]\left(R_3=R_3-R_2\right)[/tex]

[tex]\left[\begin{array}{cccccc}1&-2&0&7/2&-11&59/2\\0&0&1&-1/2&4&-13/2\\0&0&0&1/2&-2&7/2\end{array}\right][/tex]

7. Make zeros in column 4 except the entry at row 3, column 4 (pivot entry). Subtract row 3 multiplied by 7 from row 1 [tex]\left(R_1=R_1-\left(7\right)R_3\right)[/tex]

[tex]\left[\begin{array}{cccccc}1&-2&0&0&3&5\\0&0&1&-1/2&4&-13/2\\0&0&0&1/2&-2&7/2\end{array}\right][/tex]

8. Add row 3 to row 2 [tex]\left(R_2=R_2+R_3\righ)[/tex]

[tex]\left[\begin{array}{cccccc}1&-2&0&0&3&5\\0&0&1&0&2&-3\\0&0&0&1/2&-2&7/2\end{array}\right][/tex]

9. Multiply row 3 by 2 [tex]\left(R_3=\left(2\right)R_3\right)[/tex]

[tex]\left[\begin{array}{cccccc}1&-2&0&0&3&5\\0&0&1&0&2&-3\\0&0&0&1&-4&7\end{array}\right][/tex]

Answer:

(a) 65

(b) -26

(c) 54.6

(d) -54.6

Step-by-step explanation:

(a) [tex]f(5)=8(5)+5(5)=40+25=65[/tex]

(b) [tex]f(-2)=8(-2)+5(-2)=-16-10=-26[/tex]

(c) [tex]f(4.2)=8(4.2)+5(4.2)=33.6+21=54.6[/tex]

(d) [tex]f(-4.2)=8(-4.2)+5(-4.2)=-33.6-21=-54.6[/tex]

Answer:

The rate is 4.9%.

Step-by-step explanation:

The compound interest formula is :

[tex]A=p(1+\frac{r}{n})^{nt}[/tex]

A = 73677.48

p = 73377.34

r = ?

n = 12

t = 1/12

Putting the values in formula we get;

[tex]73677.48=73377.34(1+\frac{r}{12})^{12*1/12}[/tex]

=> [tex]73677.48=73377.34(1+\frac{r}{12})^{1}[/tex]

=> [tex]\frac{73677.48}{73377.34} =(1+\frac{r}{12})[/tex]

=> [tex]1.004090=(\frac{12+r}{12})[/tex]

=> [tex]12.04908=12+r[/tex]

=> [tex]r = 12.04908-12[/tex]

r = 0.04908

or r = 4.9%

Therefore, the interest rate is 4.9%.

Final answer:

Explaining how to calculate the interest rate for an investment question.

Explanation:

To find the interest rate, subtract the initial amount from the final amount: $73,677.48 - $73,377.34 = $300.14. This represents the interest earned in one month.

Next, calculate the interest rate using the formula we get the :

Interest Rate = (Interest Earned / Initial Amount) x 100%.

Plugging in the values: Interest Rate = ($300.14 / $73,377.34) x 100% ≈ 0.409% or 0.4% to the nearest tenth.

Answer:

i think the answer is 1,000

Step-by-step explanation:

Before the piper increased his volume, there were approximately 2530 rats. The final total (6578 rats), represents a 160 percent increase over this original amount.

The question is asking about the original number of rats before a 160 percent increase. In this scenario, you must remember that 6578 rats is equal to the original number of rats plus an extra 160 percent of the original number. Hence, 6578 rats signifies 260% of the original quantity of rats because inherently 100% represents the original quantity. To find the original number of rats, we'd divide the final quantity by 2.6. So, the original number of rats would be calculated by: 6578 ÷ 2.6 = 2530 rats approximately. Therefore, before the piper increased his volume, there were approximately 2530 rats.

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