The number of passengers on coaches travelling along 12 popular scenic routes are 29 42 45 39 36 41 38,37.43,35 and 40 find the mean numbres of passengers on coaches

Answer:

Length=8 and width=6

Step-by-step explanation:

The length of the rectangle is 4 less than twice the width, let l stand for length and w for width: l=2w-4

The perimeter is equal to 28 and the formula for the perimeter of a rectangle is 2l+2w: 28=2l+2w

Substitute l into the equation:

28=2(2w-4)+2w

28=4w-8+2w

28=6w-8

36=6w

w=6

Find for l:

l=2w-4

l=2(6)-4

l=12-4

l=8

Answer:

2x^2-9x-5

Step-by-step explanation:

Just multiply

Answer:

2x^2-9x-5

Step-by-step explanataion:

multiply

Answer: [tex]3\frac{1}{2}[/tex]

Multiply

[tex]3.5/1*10/10=35/10[/tex]

Divide each side by 5

[tex]35/10[/tex]  ÷  [tex]5/5=7/2[/tex]

[tex]7/2=3\frac{1}{2}[/tex]

Answer:

[tex] \frac{3.5}{1} \frac{ \times }{ \times } \frac{10}{10} = \frac{35}{10} \\ \frac{35}{10} \frac{ \div }{ \div } \frac{5}{5} \\ = \frac{7}{2} = 3 \frac{1}{2} [/tex]

hope this helps you...

[tex]f(t)=(t-5)u_2(t)-(t-2)u_5(t)[/tex]

The Laplace transform is

[tex]F(s)=\displaystyle\int_0^\infty f(t)e^{-st}\,\mathrm dt=\int_2^\infty(t-5)e^{-st}\,\mathrm dt-\int_5^\infty(t-2)e^{-st}\,\mathrm dt[/tex]

Integrate by parts; in the first integral, take

[tex]u=t-5\implies\mathrm du=\mathrm dt[/tex]

[tex]\mathrm dv=e^{-st}\,\mathrm dt\implies v=-\dfrac{e^{-st}}s[/tex]

[tex]\implies\displaystyle\int_2^\infty(t-5)e^{-st}\,\mathrm dt=-\frac{e^{-st}}s(t-5)\bigg|_2^\infty+\frac1s\int_2^\infty e^{-st}\,\mathrm dt[/tex]

[tex]=-\dfrac{3e^{-2s}}s-\dfrac{e^{-st}}{s^2}\bigg|_2^\infty[/tex]

[tex]=-\dfrac{3e^{-2s}}s+\dfrac{e^{-2s}}{s^2}=-\dfrac{(3s-1)e^{-2s}}{s^2}[/tex]

For the second integral, take

[tex]u=t-2\implies\mathrm du=\mathrm dt[/tex]

[tex]\mathrm dv=e^{-st}\,\mathrm dt\implies v=-\dfrac{e^{-st}}s[/tex]

[tex]\implies\displaystyle\int_5^\infty(t-2)e^{-st}\,\mathrm dt=-\dfrac{(t-2)e^{-st}}s\bigg|_5^\infty+\frac1s\int_5^\infty e^{-st}\,\mathrm dt[/tex]

[tex]=\dfrac{3e^{-5s}}s-\dfrac{e^{-st}}{s^2}\bigg|_5^\infty[/tex]

[tex]=\dfrac{3e^{-5s}}s+\dfrac{e^{-5s}}{s^2}=\dfrac{(3s+1)e^{-5s}}{s^2}[/tex]

So we have

[tex]F(s)=\dfrac{(3s+1)e^{-5s}-(3s-1)e^{-2s}}{s^2}[/tex]

       Equation representing the cups of flour for every teaspoon of yeast will be → c = 2t

          y ∝ x

          y = kx [Here, k = proportionality constant]

It has been given in the question,

"A bread recipe calls for 1 teaspoon of yeast for every 2 cups of flour."

If the number of teaspoons of yeast is represented by 't' and number of cups of flour by 'c',

c = kt

From the given statement,

2 = k × 1

k = 2

    Therefore, equation for the given statement will be → c = 2t

Learn more about the proportional relation here,

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Answer:

22%

Step-by-step explanation:

Answer:

5%

Step-by-step explanation:

There are two ways to solve this

a fast way: 125/2400 which equals approx 0.05208

when you convert this to a percentage it is about 5%

another way is take 2400 has 100% and 125 as x%

so

125/2400 = x/100

cross multiply so

2400x = 12500

then

x= 12500/2400 which simplifies to about

5.208. since this was out of 100 from the start you don't need to convert it to percentage form

Answer:

(a) The point estimate for the population proportion p is 0.34.

(b) The margin of error for the 99% confidence interval of population proportion p is 0.055.

(c) The 99% confidence interval of population proportion p is (0.285, 0.395).

Step-by-step explanation:

A point estimate of a parameter (population) is a distinct value used for the estimation the parameter (population). For instance, the sample mean [tex]\bar x[/tex] is a point estimate of the population mean μ.

Similarly, the the point estimate of the population proportion of a characteristic, p is the sample proportion [tex]\hat p[/tex].

The (1 - α)% confidence interval for the population proportion p is:

[tex]CI=\hat p\pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}[/tex]

The margin of error for this interval is:

[tex]MOE= z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}[/tex]

The information provided is:

[tex]\hat p=0.34\\n=500\\(1-\alpha)\%=99\%[/tex]

(a)

Compute the point estimate for the population proportion p as follows:

Point estimate of p = [tex]\hat p[/tex] = 0.34

Thus, the point estimate for the population proportion p is 0.34.

(b)

The critical value of z for 99% confidence level is:

[tex]z={\alpha/2}=z_{0.01/2}=z_{0.005}=2.58[/tex]

*Use a z-table for the value.

Compute the margin of error for the 99% confidence interval of population proportion p as follows:

[tex]MOE= z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}[/tex]

          [tex]=2.58\sqrt{\frac{0.34(1-0.34)}{500}}[/tex]

          [tex]=2.58\times 0.0212\\=0.055[/tex]

Thus, the margin of error for the 99% confidence interval of population proportion p is 0.055.

(c)

Compute the 99% confidence interval of population proportion p as follows:

[tex]CI=\hat p\pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}[/tex]

[tex]CI=\hat p\pm MOE[/tex]

     [tex]=0.34\pm 0.055\\=(0.285, 0.395)[/tex]

Thus, the 99% confidence interval of population proportion p is (0.285, 0.395).

The point estimate for p is 0.34. The margin of error, calculated using a z-score of 2.576, is 0.034. The 99% confidence interval is from 0.306 to 0.374.

This question is about calculating a confidence interval for a proportion using the normal distribution. The best point estimate for p is the sample proportion, p-hat, which is 0.34.

For a 99% confidence interval, we use a z-score of 2.576, which corresponds to the 99% confidence level in a standard normal distribution. The formula for the margin of error (E) is: E = Z * sqrt[(p-hat(1 - p-hat))/n]. Substituting into the formula, E = 2.576 * sqrt[(0.34(1 - 0.34))/500] = 0.034.

The 99% confidence interval for p is calculated by subtracting and adding the margin of error from the point estimate: (p-hat - E, p-hat + E). The 99% confidence interval is (0.34 - 0.034, 0.34 + 0.034) = (0.306, 0.374).

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Answer:

The answer to the last one is regular

Step-by-step explanation:

A polygon is a planar figure defined by a finite number of straight-line segments. The polygon that best describes a stop sign is a regular polygon.

A polygon is a planar figure defined by a finite number of straight-line segments that are joined to form a closed polygonal chain in geometry. A polygon can be defined as a bounded planar region, a bounding circuit, or both.

The polygon that best describes a stop sign is a regular octagon because a stop sign has 8 sides and the length of each side is the same, therefore, the polygon will be a regular polygon.

Thus, the polygon that best describes a stop sign is a regular polygon.

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Answer: C. Taking the square root of both sides of the equation.

Step-by-step explanation:

Answer:

c

Step-by-step explanation:

i got it right

Answer:

21 maybe?

Step-by-step explanation:

if those numbers represent lengths and those lines are the same size, x is 21

Answer: useing the distributive property the method is 4x+8=20

using the reciprocal the method is x+2=5

Step-by-step explanation:

Answer:

Using this method, the equivalent equation is 4x+8=20.

Another method is to use the reciprocal.

Using this method, the equivalent equation is x+2=5.

Step-by-step explanation:

IT IS CORRECT

Answer:

6

Step-by-step explanation:

same size...hope this helps :)))))

Answer: −420x+1073

Step-by-step explanation:

Let's simplify step-by-step.

955−105x(4)+118=955+−420x+118

Combine Like Terms:

=955+−420x+118=(−420x)+(955+118)=−420x+1073

Answer: =−420x+1073

I did it on my calculator and it got 653. The calculator is never wrong.

Answer:

Estimate of the standard error of the mean = 0.38 lb

Step-by-step explanation:

We are given the following in the question:

Sample mean, [tex]\bar{x}[/tex] = 10.87 lb

Sample size, n = 131

Standard deviation, σ = 4.31 lb

We have ti find the estimate of the standard error of the mean.

Formula for standard error:

[tex]S.E= \dfrac{\sigma}{\sqrt{n}}[/tex]

Putting values, we get,

[tex]S.E = \dfrac{4.31}{\sqrt{131}} = 0.3766 \approx 0.38[/tex]

0.38 lb is the standard error of the mean.

To make informed decisions based on a statistical study about restaurants, it's critical to understand the goal of the study, how the quality was measured, what the variable of interest was, who the respondents were and how they were selected.

The crucial information that would need to know before acting on the study mentioned in the question includes all of the options provided and more. Let's discuss each option in detail:

A. The goal of the study. This would provide context and help to determine why these specific variables were chosen and measured. Without a clear goal, interpreting findings can be difficult.

B. How the quality of restaurants was measured. It's important to understand how the '29 out of 30' rating was developed - what specific factors led to this score. If the rating system or measurement techniques are flawed, the results could possibly be inaccurate.

C. The variable of interest. It would be necessary to understand what variable is being measured. Is it the food quality, service, ambiance, or some other factor of a restaurant's operation?

D. Who the respondents in the survey were. The demographic and social details of the respondents are also vital. If all respondents are from a certain group (for example, high-income people), results may not be representative for the general public.

E. How the respondents were selected. This would throw light on the methodology and the degree to which the findings can be generalized to the larger population.

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Answer:

35 and 15

Step-by-step explanation:

Process of elimination:

Try 105 and 5 - 105 is way too much and 5 is way too little. We know that they are between 5 and 105.

Try 50 and 10.5 - This is closer, but 50 is still too much and 10.5 is too little. We now know that the two numbers are between 10.5 and 50

Try 30 and 17.5 - This is very close, but now 30 is not enough and 17.5 is too much. We now know that the smaller number is between 10.5 and 17.5 as well as the larger number is between 30 and 50.

Try 40 and 13.125 - This is also very close, but 40 is too much and 13.125 is too little. We now know that the lower number is between 13.125 and 17.5 as well as the larger number is between 30 and 40.

Try 35 and 15 - Success: 35 and 5 make the simplified ratio of 7:3! They also are products of 525!

Final answer:

The two positive numbers with a ratio of 7 to 3 and a product of 525 are found to be 35 and 15, by assigning a constant to the numbers, forming and solving a quadratic equation to find the value of the constant, and then using it to find the two numbers.

Explanation:

To find two positive numbers where their ratio is 7 to 3, and their product is 525, we can assign values x and y to the numbers such that x/y = 7/3, and x*y = 525. We can solve these equations simultaneously to find the values of x and y.

Step-by-step solution:

Therefore, the two numbers are 35 and 15.

Answer:

  4x^2−12x+9

Step-by-step explanation:

The form of a perfect square trinomial is ...

  (a +b)² = a² +2ab +b²

The first and last terms must be positive and perfect squares. The middle term must be twice the product of their roots (possibly with a minus sign).

  x^2 -10x -25 . . . . -25 is not a positive perfect square

  4x^2 -12x +9 . . . . 12x = 2√(4x^2·9) = 2·6x . . . . perfect square

  9x^2 +12x +16 . . . 12x ≠ 2√(9x^2·16) = 2·12x

  16x^2 +16x +1 . . .  16x ≠ 2√(16x^2·1) = 2·4x

At noon, the Shady Farm Milk Company has 10,000 gallons of milk in the queue to be processed given the demand and the processing rate.

The Shady Farm Milk Company can process 7500 gallons of milk per hour. Given that the company operates from 8 a.m. to 6 p.m., this is a total of 10 hours of operation in a day. Therefore, in 10 hours, the company can process 7500 × 10 = 75,000 gallons of milk.

However, the demand for milk is 100,000 gallons over the course of the day. Therefore, by noon, the company has been operating for 4 hours, meaning they can process 7500 × 4 = 30,000 gallons.

The demand over the same 4 hours period (from 8 a.m. to noon) is calculated by dividing the total demand over the entire course of the day (which is evenly spread) by the number of operating hours. Thus: 100,000 / 10 = 10,000 gallons/hour.

Consequently, the demand from 8 a.m. to noon is: 10,000 × 4 = 40,000 gallons. So, the amount of milk in the queue at noon would be the demand minus what the company has processed at that time.

Hence: 40,000 (demand from 8 a.m. to noon) - 30,000 (processed milk from 8 a.m. to noon) = 10,000 gallons. Therefore, at noon, the company has 10,000 gallons of milk in the queue to be processed.

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At noon, there are 20,000 gallons of milk in the queue to be processed.

To find out how many gallons of milk are in the queue to be processed at noon, we first need to calculate how many gallons of milk have been processed by noon.

The company can process milk at a fixed rate of 7500 gallons per hour. From 8 a.m. to noon, there are 4 hours.

Total gallons processed by noon = Rate of processing Time

[tex]\[ = 7500 \, \text{gallons/hour} \times 4 \, \text{hours} = 30000 \, \text{gallons} \][/tex]

Now, we need to find out how many gallons of milk are still in demand by noon. The total demand over the course of the day is 100,000 gallons, and it is spread out uniformly from 8 a.m. to 6 p.m.

This means that by noon, half of the day has passed.

So, the total demand by noon = Total demand / 2

[tex]\[ = \frac{100000}{2} = 50000 \, \text{gallons} \][/tex]

Now, to find out how many gallons are in the queue to be processed at noon, we subtract the gallons already processed from the total demand:

Gallons in the queue at noon = Total demand by noon - Gallons processed by noon

[tex]\[ = 50000 \, \text{gallons} - 30000 \, \text{gallons} = 20000 \, \text{gallons} \][/tex]

So, at noon, there are 20,000 gallons of milk in the queue to be processed.

Answer:

a.

[tex]\text{Sample Space} = \{ CCC,CCW,CWW,WWW,WWC,WCC,WCW,CWC \}[/tex]

b.

(i)  1/2

(ii) 2/3

(iii) 1/6

Step-by-step explanation:

a.

The sample space is the list of all possibilities.

[tex]\text{Sample Space} = \{ CCC,CCW,CWW,WWW,WWC,WCC,WCW,CWC \}[/tex]

b.

(i)

If exactly one answer is correct the favorable outcomes are

CWW , WCW , WWC.

And the probability would be 3/6 = 1/2.

(ii)

If at least two answers are correct then the favorable outcomes are

CCC,CCW,WCC,CWC

and the probability is 4/6 = 2/3.

(iii)

If  no answer is correct, the favorable outcomes are

WWW

and the probability is  1/6.

Answer:

U shape

Step-by-step explanation: look for a U shape and youll have chosen a quadratic function but find the vertex and put them into the format then find the slope

Answer:

1/3

Step-by-step explanation:

You can try it I keep getting 3 so maybe that’s the answer

1/3, because 18.6 / 3 = 6.2

Answer:

The volume is 192.96

Step-by-step explanation:

You multiply length x width x height to find the volume.

Answer:

5.2161,7.5,7.508,7.58

Step-by-step explanation:

Answer:

5.2161; 7.5; 7.508; 7.58

Step-by-step explanation:

-First you will look at the first digit of each number given, obviously 5 is the smallest so it will go first

-Then you will check the following number after the first digit to see which one is smaller of the "7" values. In this case, they all have the number "5" has their second value, so we move on to the third digit.

-Since "7.5" does not have a third digit, it will be the smallest of the number "7" values.

-We then have a remaining of two values, 7.508 and 7.58. Still looking at the third numbers of each of the two, we see "0" and "8," and obviously 0 is smaller than 8, so 7.508 is smaller than 7.58

The interest for 8 years is $2.10

Step-by-step explanation:

Principal amount (p) = $6.57

Rate of interest (r) = 4%

Time (t) = 8 years

Interest = (p x r x t) /100

= (6.57 x 4 x 8) /100

= 210.24/100

= 2.10

The interest for 8 years is $2.10

Answer:

[tex]Z = 1[/tex]

Step-by-step explanation:

Z - score

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

[tex]\mu = 61, \sigma = 4[/tex]

Calculate the Z value for the next car that passes through the checkpoint will be traveling slower than 65 miles per hour.

This is Z when X = 65. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{65 - 61}{4}[/tex]

[tex]Z = 1[/tex]

Answer:

The answer is  D.

Step-by-step explanation:

Step-by-step explanation:

Total books sold = 412

So if there are 103 maths books then biology books should be three times = 103 × 3 = 309

So when we add 103 + 309 = 412

It means the number of biology books is 309 and maths book is 103

Answer:

Check below

Step-by-step explanation:

That's too bad you haven't attached a rectangle.

Here's an example, with the data you've typed in.

1) When we dilate a rectangle we either grows it or shrink it through a scale factor.

Check the first picture below.

The New Dilated Rectangle A'B'C'D' will follow its coordinates, when the Center of Dilation is at its origin(Middle):

[tex]D_{A'B'C'D'}=\frac{1}{2}(x,y)[/tex]

2) But In this question, B is the center of Dilation. So, Since B is the Dilation Point B=B' .  And More importantly:

[tex]\bar{AB}=\frac{1}{2}\bar{A'B'}\\\bar{CD}=\frac{1}{2}\bar{C'D'}\\\bar{AC}=\frac{1}{2}\bar{A'C'}\\\bar{CD}=\frac{1}{2}\bar{C'D'}\\[/tex]

3) So check the pictures below for a better understanding.

Answer:

Pretty sure its B