The prefix mili-means a thousand
so a kilo -gram is a thousand of a liter
1 kilogram = 1,000 grams
how many kilograms is 1,216 grams?

The molecules in a gas move faster than in a liquid.

Answer: The answer is A

Explanation: I know this because I just did the USA test-prep

Hello!

To find the number of moles in the given amount of aluminum, we need to know the mass of one mole of aluminum, and divide that by the given amount of aluminum.

One mole of aluminum is equal to about 27 grams. With that, we can divide it by the given amount of aluminum.

198.5 grams / 27 grams ≈ 7.35185185

According the number of significant figures, there are about 7.4 moles of aluminum in 189.5 grams of aluminum.

Most of these questions relate to the Doppler Effect - how the frequency of sound and light waves changes depending on whether the source is moving towards or away from the observer. Moving toward an observer leads to higher frequencies and a 'blue shift' while moving away leads to lower frequencies and a 'red shift'.

1. As an object moves towards another object the sound waves bunch up. True. This is a representation of the Doppler Effect where the frequency appears to change when a source of sound is moving relative to the observer.

2. As an object moves toward another object the sound waves have a lower frequency. False. As the object moves closer, the sound waves will have a higher frequency.

3. As an object moves toward another object the sound waves have a lower frequency. False as explained in the question.

4. Faster sources moving towards an object have a higher pitch than slower-moving sources. True. Faster moving sources will cause the sound waves to bunch up leading to higher frequency and hence greater pitch.

5. An object moving away will have a lower pitch. True. The pitch will appear to be lower as the sound waves are spread out.

6. Lower shows differences in frequency as color. This sentence is not clear enough to provide an accurate response.

7. An object moving away to be blue-shifted. False. An object moving away shows a red shift; a blue shift occurs when an object is moving toward the observer.

8. Is a star that shows as blue-shifted moving toward the observer. True. The blue shift indicates that a cosmos object is moving towards us.

9. Faster-moving objects show MORE shifts in frequency. True. The frequency of light waves will change more noticeably with faster-moving objects due to the Doppler effect.

10. Galaxies appear to be redshifted from observing on Earth. Is this because they are moving towards the earth? False. Galaxies are moving away from the Earth which is why they appear redshifted.

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Hey there!:

Temperature in kelvin : 45 + 273 => 318 K

Number of moles H2:

p * V = n * R * T

4.46 * 0.579 = n * 0.082 * 318

2.58234 = n * 26.076

n = 2.58234 / 26.076

n = 0.09903 moles of H2O

Given the reaction:

XeF6(s) + 3 H2(g) → Xe(g) + 6 HF(g)

Molar  mass XeF6 = 245.3 g/mol

0.09903 mol H2O *  ( 1 mol XeF6 / 3 mol H2 ) * 245.3

= 8.09 g of XeF6

Hope that helps

Explanation: For evaluating the combined gas law, we use four laws:

Charles' Law: Volume of a gas is directly proportional to the Temperature at Constant Pressure.

                           [tex]V\propto T[/tex]      (at constant Pressure)

Boyle's Law: Volume of a gas is inversely proportional to the Pressure of a gas at constant Temperature.

                           [tex]V\propto \frac{1}{P}[/tex]   (at constant Temperature)

Gay-Lussac's Law: Pressure of the gas is directly proportional to the Temperature at constant Volume.                                                                  

                           [tex]P\propto T[/tex]      (at constant Volume)

Avogadro's Law: Volume of gas is directly proportional to the number of moles of gas at constant Pressure and constant Temperature.

                          [tex]V\propto n[/tex]      (at constant Pressure and Temperature)

Combining all the four laws, we get

                           [tex]PV\propto nT[/tex]

                            PV=nRT     (Combined Gas Law)

where, R = Gas constant

Now, we need to calculate the pressure, rearranging the terms:

                          [tex]P=\frac{nRT}{V}[/tex]

When an ideal gas at Initial Pressure [tex]P_1[/tex], Volume [tex]V_1[/tex] and Temperature [tex]T_1[/tex] undergoes change in variables to Final pressure [tex]P_2[/tex], Volume [tex]V_2[/tex] and Temperature [tex]T_2[/tex] , we write

                         [tex]\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}[/tex]

                        [tex]P_2=(\frac{P_1V_1}{T_1})(\frac{T_2}{V_2})[/tex]

Answer : The variables in the numerator (a) will be, [tex]P_1,V_1,T_2[/tex] and the variables in the denominator (b) will be, [tex]V_2,T_1[/tex]

Explanation :

The combined gas law has arrived from the combination of the four laws:

1) Boyle's Law : It is defined as the pressure of the gas is inversely proportional to the volume of the gas at constant temperature and the number of moles.

[tex]P\propto \frac{1}{V}[/tex]

2) Charles' Law : It is defined as the volume of the gas is directly proportional to the temperature of the gas at constant pressure and number of moles.

[tex]V\propto T[/tex]

3) Gay-Lussac's Law : It is defined as the pressure of the gas is directly proportional to the temperature of the gas at constant volume and number of moles.

[tex]P\propto T[/tex]

4) Avogadro's Law : It is defined as the volume of the gas is directly proportional to the number of moles of the gas at constant pressure and temperature.

[tex]V\propto n[/tex]

By combining these four laws, we get the combined gas law.

[tex]PV\propto nT\\\\PV=nRT[/tex]

where, R = gas constant

An ideal gas at initial pressure [tex]P_1[/tex], initial volume [tex]V_1[/tex] and initial temperature [tex]T_1[/tex] undergoes changes with the variables to final pressure [tex]P_2[/tex], final volume [tex]V_2[/tex] and final temperature [tex]T_2[/tex].

By rearranging the gas law, we get the final pressure.

[tex]\frac{P_1V_1}{P_2V_2}=\frac{T_1}{T_2}\\\\P_2=\frac{P_1V_1T_2}{V_2T_1}[/tex]

Therefore, the variables in the numerator (a) will be, [tex]P_1,V_1,T_2[/tex] and the variables in the denominator (b) will be, [tex]V_2,T_1[/tex]

Mass of strontium = 88 g

Atomic mass of Sr = 87.62 u

Moles = mass /atomic mass

Moles of Sr =  88 / 87.62 = 1.004

Mass of bromine = 160 g

Atomic mass of Br = 79.904 u

Molar mass of Br₂ = 79.904 x 2 = 159.808 g/mol

Moles = mass /molar mass

Moles of Br₂ =  160 / 159.808 = 1.001

The balanced chemical equation of the reaction between strontium and bromine:

Sr(s) + Br₂(l) = SrBr₂

The molar ratio between Br₂  and SrBr₂ is 1:1

So the moles of SrBr₂ produced from 1.001 moles of Br₂ is 1.001.

Moles = mass /molar mass

Mass = moles x molar mass

Molar mass of SrBr₂ = 247.4280 g/mol

Mass = 1.001 mol x 247.4280 g/mol

Mass = 247.428 g

The mass of strontium bromide produced is 247.428 g.

The Pascal (symbol: Pa) is the SI derived unit of pressure. It is used to quantify internal pressure, stress, Young's modulus and ultimate tensile strength. It is defined as one Newton per square meter. It is named after the French polymath Blaise Pascal.

The Pascal (Pa) or kilo pascal (kPa) as a unit of pressure measurement is widely used throughout the world and has largely replaced the pounds per square inch.

The SI unit of pressure is the Pascal (Pa) and it is derived from the base units of the International System of Units (SI): kilogram (kg), meter (m), and second (s).

The SI unit of pressure is the Pascal (Pa). It is derived from the base units of the International System of Units (SI): kilogram (kg), meter (m), and second (s).

One Pascal is defined as one Newton per square meter (N/m^2). This means that pressure is the force applied per unit area.

For example, if you have a force of 100 Newtons acting on an area of 1 square meter, the pressure would be 100 Pascals.

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Answer:

The correct answers are (1) True (2) London dispersion force (3) one of the option is missing, none of these three is an answer (4) The total number of electrons increases down the group, and this increases the strength of the intermolecular forces (5) London dispersion forces which are always present.

Explanation:

Given: An instantaneous dipole occurs when a molecule's moving electrons are briefly more concentrated in one place than another, causing the molecule to become temporarily polarized.

Answer: True

when the electrons moving in a molecule or an atom move towards one end of the molecule or atom the other end has a small positive pole at that time and the end where electrons move has a small negative pole. So, a dipole is formed for that instant.

(2) What type of intermolecular force occurs between all substances?

Answer: London dispersion force

remember from first part how an instantaneous dipole is formed. When a pole is formed at that instant the molecule in neighborhood can interact with the dipole that was formed. The dipole that was formed has a positive pole and a negative pole. If the neighboring molecule is present near positive pole it’s electrons will get attracted to the positive pole of the dipole. This interaction is called London dispersion force. Since every atom or molecule or ion in the universe has electrons, so there is development of instantaneous dipole in each of them and each one of them has London dispersion force acting on them.

(3) When comparing [tex]H_2,\;NH_3,\;O_2,\; \rm{and}\;{CH_4[/tex] which of the following statements is correct?

Answer: one of the option is missing, none of these three is an answer.

(4)The boiling points of diatomic halogens are compared in the table.

Answer: The total number of electrons increases down the group, and this increases the strength of the intermolecular forces.

(5) What is the strongest intermolecular force that occurs between molecules of [tex]CO_2[/tex]?

Answer: London dispersion forces which are always present.

London forces are weakest forces, if other forces would have been present then we would have ignored London forces but since no other forces are present, the only choice is London forces.

[tex]CO_2[/tex] is a non polar molecule, it does not have permanent dipole moment. So there are no chances of dipole-dipole, [tex]CO_2[/tex] doesn’t have a positive or negative charge so even not ionic bond.

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Answer:

The answer is A: the part of the earth and its atmosphere in which living organisms exist or that is capable of supporting life.

Explanation:

i got it on study island and make sure you copy this "the part of the earth and its atmosphere in which living organisms exist or that is capable of supporting life." and do ctrl f and paste and check where your answer is because the answer might be shuffled hope you have a great day!! :)

The part of the earth and its atmosphere in which living organisms exist or that is capable of supporting life. Thus option A is correct.

The atmosphere is a gas that cover the a planet and is present in place by the gravitational force of the planet, the temperature of the atmosphere is low.

The atmosphere is composed of nitrogen (78%), oxygen (21%), argon (0.9%), carbon dioxide (0.04%) and trace gases, variable amount of water vapor are also present .

Carbon dioxide gas is responsible mainly for the greenhouse effect, transparent to the incoming solar radiation but is opaque to the outgoing terrestrial radiation.

Dust particles are  present in the atmosphere, these particles act as hygroscopic nuclei around which water vapor condenses to produce clouds.

Thus option A is correct.

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that would be 2226.109837560 sorry if i'm wrong have a nice day.

The question is incomplete, here is the complete question:

Calculate the standard enthalpy of combustion of sucrose. The standard enthalpy of formation of sucrose is -2226.1 kJ/mol

Answer: The standard enthalpy of combustion of sucrose is -5636.52 kJ

Explanation:

Combustion reaction is defined as the chemical reaction in which a hydrocarbon reacts with oxygen gas to produce carbon dioxide gas and water molecule.

[tex]\text{Hydrocarbon}+O_2\rightarrow CO_2+H_2O[/tex]

Enthalpy change is defined as the difference in enthalpies of all the product and the reactants each multiplied with their respective number of moles. The equation used to calculate enthalpy change is of a reaction is:

[tex]\Delta H^o_{rxn}=\sum [n\times \Delta H_f^o_{(product)}]-\sum [n\times \Delta H_f^o_{(reactant)]}[/tex]

The chemical equation for the combustion of sucrose follows:

[tex]C_{12}H_{22}O_{11}(s)+12O_2(g)\rightarrow 12CO_2(g)+11H_2O(l)[/tex]

The equation for the enthalpy change of the above reaction is:

[tex]\Delta H^o_{rxn}=[(12\times \Delta H_f^o_{(CO_2)})+(11\times \Delta H_f^o_{(H_2O)})]-[(1\times \Delta H_f^o_{(C_{12}H_{22}O_{11})})+(12\times \Delta H_f^o_{(O_2)})][/tex]

We are given:

[tex]\Delta H_f^o_{(H_2O)}=-285.8kJ/mol\\\Delta H_f^o_{(CO_2)}=-393.51kJ/mol\\\Delta H_f^o_{(C_{12}H_{22}O_{11})}=-2226.1kJ/mol\\\Delta H_f^o_{(O_2)}=0kJ/mol[/tex]

Putting values in above equation, we get:

[tex]\Delta H^o_{rxn}=[(12\times (-393.51))+(11\times (-285.8))]-[(1\times (-2226.1))+(12\times (0))]\\\\\Delta H^o_{rxn}=-5636.52kJ[/tex]

Hence, the standard enthalpy of combustion of sucrose is -5636.52 kJ

Because it is just simply bigger a na is way way smaller than a ci.

Ionic radii of cations:

When you form a metal cation, you are removing the outermost electrons and revealing the inner core.  

For example, to form an Na⁺ ion you must remove a 3s electron from an Na atom, exposing the 2s and 2p subshells.

The n = 2 shell is smaller than an n= 3 shell, so an Na⁺ ion is smaller than an Na atom (as in the image below).

Ionic radii of anions:

When you form an anion, you are adding electrons to the outermost shell. These electrons (a) increase the shielding from the nucleus and (b) repel all the other electrons.  

The decreased nuclear attraction and the electronic repulsions cause the electron cloud to expand, so a Cl⁻ ion is larger than a Cl atom.

Hey There!:

Molar mass O2 => 32.0 g/mol

Molar mass Cl2 => 71.0 g/mol

effusion rate α  1 / (√ molar mass )

E Cl2 / E O2 = √ molar mass O2 / √ molar mass Cl2

E Cl2 / E O2 =   ( √ 32.0 ) /  ( √ 71.0 )

=> 0.671

Hope that helps!

Answer: The ratio of rate of effusion of chlorine gas and oxygen gas will be 0.671

Explanation:

To calculate the rate of diffusion of gas, we use Graham's Law.

This law states that the rate of effusion or diffusion of gas is inversely proportional to the square root of the molar mass of the gas. The equation given by this law follows the equation:

[tex]\text{Rate of diffusion}\propto \frac{1}{\sqrt{\text{Molar mass of the gas}}}[/tex]

We are given:

Molar mass of chlorine gas = 71 g/mol

Molar mass of oxygen gas = 32 g/mol

By taking their ratio, we get:

[tex]\frac{Rate_{Cl_2}}{Rate_{O_2}}=\sqrt{\frac{M_{O_2}}{M_{Cl_2}}}[/tex]

[tex]\frac{Rate_{Cl_2}}{Rate_{O_2}}=\sqrt{\frac{32}{71}}\\\\\frac{Rate_{Cl_2}}{Rate_{O_2}}=0.671[/tex]

Hence, the ratio of rate of effusion of chlorine gas and oxygen gas will be 0.671

Hey there!:

1 mole of FeSO4 = 151.8 g/mol

25.0 g change to mole  = 25.0 / 151.8

moles of FeSO4 = 0.165 moles

One mole of any substance has  6.02*10²³ units

0.165 moles to get the number of Fe ( II ) ions :

number of  Fe(II) ion = 0.165 * ( 6.02*10²³ )

number of Fe ( II ) ion = 9.93*10²² units

Answer:

[tex]ions_{Fe^{2+}}=9.90x10^{22}ionsFe^{2+}[/tex]

Explanation:

Hello,

In this case, the following mole-mass relationship, is applied to obtain the ions of iron (II) in 25.0 g of iron (II) sulfate whose molar mass is 152 g/mol:

[tex]ions_{Fe^{2+}}=25.0gFeSO_4*\frac{1molFeSO_4}{152gFeSO_4}*\frac{1molFe^{2+}}{1molFeSO_4}*\frac{6.022x10^{23}ionsFe^{2+}}{1molFe^{2+}} \\ions_{Fe^{2+}}=9.90x10^{22}ionsFe^{2+}[/tex]

Best regards.

Answer: Option (c) is the correct answer.

Explanation:

In liquids, molecules are held by slightly less strong intermolecular forces of attraction as compared to solids.

Hence, molecules of a liquid are able to slide past each other as they have more kinetic energy than the molecules of a solid.

As a result, liquids are able to occupy the shape of container in which they are placed. Also, liquids have fixed volume but no fixed shape.

Thus, we can conclude that liquids have a variable shape and a fixed volume.

Answer:

variable, fixed

Explanation:

I think the answer is B because Sound travels about 1,500 m/s underwater, and sound travels about 332 m/s in air. Sound underwater travels faster and longer in water. The particles are more tightly packed together, so sounds travel faster through water.

Final answer:

A protein is best described as a polymer made up of 20 or more amino acid monomers, with proteins varying greatly in size and function.

Explanation:

The correct statement that best describes a protein is (D) a polymer made up of 20 or more amino-acid monomers. Proteins are essential biomolecules within living organisms, made from building blocks known as amino acids, which are connected by peptide bonds forming long chains. There are 20 standard amino acids that can combine in various sequences to form a vast array of proteins, each with unique functions and properties. These proteins can be as small as a few dozen amino acids to several thousand in the larger proteins.

Yes, it is possible to combine the same two elements to form two different compounds. An example is carbon dioxide CO2 and carbon monoxide CO. This is because two elements can form different types of bond and end up with different compounds.

There is a limited number of elements but a large number of compounds because of the above reason.

Yes, two different compounds can be made from the same two elements by altering their atomic ratios. Despite having fewer than 120 elements, innumerable compounds exist due to various ways elements can combine and bond.

A. This is because different compounds can be created by changing the ratio of atoms of each element. For instance, depending on the number of oxygen atoms bonded to each carbon atom, carbon and oxygen can combine to form carbon monoxide (CO) or carbon dioxide (CO₂).

B. The reason for this is that elements can combine in a variety of ways, resulting in a wide range of compounds with distinct properties. For example, even if two elements form a compound in the same ratio, they can combine in different ratios to form entirely different compounds.

Factors influencing compound formation

The balanced chemical equation for the given reaction:

NaHCO₃ + HCl --> NaCl + H₂O + CO₂

Given, mass of NaHCO₃ = 0.05 g

Molar mass of NaHCO₃ = 84.007 g/mol

Moles = mass/molar mass

Moles of NaHCO₃ = 0.05 g/84.007 g/mol

Moles of NaHCO₃ = 6.0 x 10⁻⁴

Given, mass of HCl = 0.05 g

Molar mass of HCl = 36.46 g/mol

Moles of HCl = 0.05 g/ 36.46 g/mol

Moles of HCl = 1.4 x 10⁻³

Since NaHCO3 has the least number of moles, it is the limiting reagent.

As per the balanced equation the molar ratio between NaHCO₃ : CO₂ is 1:1

Therefore, moles of CO₂ = 6.0 x 10⁻⁴

Molar mass of CO₂ = 44 g/mol

Mass = moles x molar mass

Mass of CO₂ =  6.0 x 10⁻⁴ mol x 44 g/mol = 0.0264 g

Mass of carbon dioxide gas produced = 0.0264 g

The correct answer is option (B) [Ne]3s¹3p⁶.

The electron configuration of Cl is [Ne]3s²3p⁵ in the ground state.

The electron configuration of Cl is [Ne]3s¹3p⁶ in the excited state.

In the excited state one electron from the 2s orbital jumps to the 2p orbital. As a result the 2p orbital becomes completely filled with 6 electrons and the 2s orbital is partially filled with only 1 electron. To be completely filled a p and a s orbital can have a maximum of 6 and 2 electrons respectively.

Thus [Ne]3s¹3p⁶ electron configuration correspond to an atom with an electron in an excited state.

Each shell can contain only a fixed number of electrons: The first shell can hold up to two electrons, the second shell can hold up to eight (2 + 6) electrons, the third shell can hold up to 18 (2 + 6 + 10) and so on.

A. repeat the investigation several times. You must repeat an experiment to make sure it is valid.

Answer:

the answer is A

Explanation:

Answer:

On the basis of the given information, the dominant allele must be for black fur and the recessive allele must be for white fur.

Explanation:

A variation of a gene, which will generate a certain phenotype, even in the existence of other alleles is known as a dominant allele. On the other hand, a version of a gene that needs to be homozygous when inherited in order to be articulated in the phenotype is known as a recessive allele. The offspring will not express the phenotype of the recessive allele if it is inherited together with a dominant allele, that is, the phenotype of the dominant allele will just be expressed.

When multiplying 2.3 mm by 8.00 mm to find area, how should you report your answer?

A. 18 mm^2

Answer;

-Acceleration: 10 km/h/s east

Explanation;

-The quantity is either a vector or a scalar. Scalars are quantities that are fully described by a magnitude (or numerical value) alone while Vectors are quantities that are fully described by both a magnitude and a direction.

Acceleration is a vector quantity that is defined as the rate at which an object changes its velocity. An object is accelerating if it is changing its velocity.

In this case , a =( v-u)/t ; where a is the acceleration, v is the final velocity, u is the initial velocity and t is time.

      a = (60 - 0)/6

         = 10 km/h/s

Final answer:

In the scenario, the vector quantities are 'acceleration: 10 km/h/s east' and 'velocity: 10 km/h/s east' since they include both magnitude and a direction, unlike the scalar quantities 'speed: 60 km/h' and 'distance: 60 km', which lack direction.

Explanation:

In the provided scenario of a sports car accelerating uniformly, the quantity that represents a vector is acceleration: 10 km/h/s east and velocity: 10 km/h/s east. Both these quantities include both magnitude and direction. In contrast, 'speed: 60 km/h' is a scalar as it only specifies magnitude and does not include direction. Similarly, 'distance: 60 km' is also a scalar quantity because it states how far the car has traveled without a specific direction.

Vector quantities are defined by both magnitude and direction, which is the case with the acceleration and velocity specified 'east' in this scenario. Scalar quantities, such as speed and distance, only have magnitude without any reference to direction.

Scientists use land surface temperature maps to analyze and forecast changes in Earth's climate, studying variables such as glaciers, river levels, tree rings, and greenhouse gases.

Scientists use a land surface temperature map in various ways to analyze and forecast changes in the Earth's climate. One method is by examining previous and present data, such as the dimensions and locations of glaciers, and the levels of lakes, rivers, and oceans. This can reveal patterns related to global warming and other temperature changes.

Another method is by examining the number and condition of annual rings in trees. The thickness and appearance of these rings can provide information about the climate in various eras. A third approach is analysis of greenhouse gases in the atmosphere, which can point to climactic changes over the years.

Scientists also use temperature maps to model weather patterns, incorporating data about pressure (which can be depicted on the same maps) and solar energy. This can be particularly useful for predicting the path and impact of notable weather events like hurricanes. All of these methods contribute to our understanding of the Earth's climate and how it might change in the future.

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to be as exact as i can it is all of them they all work together to make water good.

Answer: Option (A) is true.

Explanation:

In a laboratory, the solutions are prepared in advance so that as and when the need arises they can be easily available. As these solutions are prepared by keeping in mind the correct ratio of concentrations.

Hence, when a person need to fill a test tube with hydrochloric acid then he/she just need to find the bottle of acid and pour the contents into the test tube.

Thus, it can be conclude that the statement is true.

Answer: True

Explanation:

In a laboratory if someone needs a test tube full of hydrochloric acid then it should be directly poured into the test tube.

As required in the experiment or during the experiment, the hydrochloric acid is pored and used in the experiment.

During the time of experiment the concentration of HCl can be adjusted base on the type of experiment.

So, it is true that hydrochloric acid can be poured directly in the test tube from the bottle.