use the drop down means to classify the elements as alkali metals alkaline eather metals or transition metals

Answer:

Mass of toddler = 12.5 kg

Explanation:

 The potential energy of a body is given by the expression, PE = mgh, where m is the mass of the body, g is the acceleration due to gravity value and h is the height of the body.

 Potential energy = 187.5 J

 Height = 1.5 m

 Substituting

     187.5 = m * 10 * 1.5

     m = 12.5 kg

So mass of toddler = 12.5 kg

The kinetic energy of the roller coaster at the bottom of the hill is 1800 joules, which is indeed twice the kinetic energy at the top of the hill (450 joules). This confirms the statement that the car has joules of kinetic energy at the bottom of the hill, which is twice its kinetic energy at the top.

The kinetic energy of the roller coaster at the bottom of the hill is twice its kinetic energy at the top of the hill.

To find the kinetic energy (KE) of the roller coaster, we use the formula:

[tex]\[ KE = \frac{1}{2}mv^2 \][/tex]

where [tex]\( m \)[/tex] is the mass of the object and [tex]\( v \)[/tex] is its velocity.

Given that the mass [tex]\( m \)[/tex] of the roller coaster car is 100 kilograms, and its speed [tex]\( v \)[/tex] at the top of the hill is 3 meters/second, we can calculate the kinetic energy at the top of the hill as follows:

[tex]\[ KE_{top} = \frac{1}{2} \times 100 \text{ kg} \times (3 \text{ m/s})^2 \] \[ KE_{top} = \frac{1}{2} \times 100 \text{ kg} \times 9 \text{ m}^2/\text{s}^2 \] \[ KE_{top} = 50 \text{ kg} \times 9 \text{ m}^2/\text{s}^2 \] \[ KE_{top} = 450 \text{ J} \][/tex]

Since the speed of the roller coaster car doubles at the bottom of the hill, its new speed [tex]\( v_{bottom} \)[/tex] is:

[tex]\[ v_{bottom} = 2 \times 3 \text{ m/s} = 6 \text{ m/s} \][/tex]

The kinetic energy at the bottom of the hill is:

[tex]\[ KE_{bottom} = \frac{1}{2} \times 100 \text{ kg} \times (6 \text{ m/s})^2 \] \[ KE_{bottom} = \frac{1}{2} \times 100 \text{ kg} \times 36 \text{ m}^2/\text{s}^2 \] \[ KE_{bottom} = 50 \text{ kg} \times 36 \text{ m}^2/\text{s}^2 \] \[ KE_{bottom} = 1800 \text{ J} \][/tex]

Therefore, the kinetic energy of the roller coaster at the bottom of the hill is 1800 joules, which is indeed twice the kinetic energy at the top of the hill (450 joules). This confirms the statement that the car has joules of kinetic energy at the bottom of the hill, which is twice its kinetic energy at the top.

Average speed is defined as ratio of total distance covered and  total time

now we will have

[tex]d_1 = 4 km[/tex]

[tex]t_1 = 32 min[/tex]

[tex]d_2 = 2 km[/tex]

[tex]t_2 = 22 min[/tex]

[tex]d_3 = 1 km[/tex]

[tex]t_3 = 16 min[/tex]

now total distance moved is

[tex]d = d_1 + d_2 + d_3[/tex]

[tex]d = 4 + 2 + 1 = 7 km[/tex]

total time is given as

[tex]t = 32 min + 22 min + 16 min[/tex]

[tex]t = 70 min[/tex]

now average speed is given as

[tex]v_{avg} = \frac{d}{t}[/tex]

[tex]v_{avg} = \frac{7}{70} = 0.1 km/min[/tex]

so its average speed is 0.1 km per minute

Answer:

[tex]0.1 \ km/min[/tex]

Explanation:

We know speed , s is given by [tex]s=\dfrac{distance}{time}.[/tex]

NOW,

Average speed , S is given by:

[tex]S=\dfrac{total \ distance\ covered}{total\ time \ taken }[/tex].   .....eqn 1.

Total distance covered , [tex]D=4+2+1 \ km=7 \ km[/tex].

Total time taken, [tex]T=32+22+16\ min=70 \ min.[/tex]

Putting these values in equation 1.

We get,

[tex]S=\dfrac{7}{70} \ km/min=0.1\ km/min.[/tex]

answer is C

slope= (y2-y1)/(x2-x1)=(300 km-0km)/(4h-0h)=(300km)/(0 h)=75km/h

v=d/t= 150/2=75

Average velocity is given as the total displacement of an object over a given time interval

Average velocity = total displacement /time interval

consider the time interval t₁ = 0  to t₂ = 4

at t₁ = 0 , d₁ = 0 km

at t₂ = 4 , d₂ = 300 km

Δd = total displacement = d₂ - d₁ = 300 - 0 = 300 km

Δt = time interval = t₂ - t₁ = 4 - 0 = 4 h

average velocity is given as

V = Δd/Δt = 300/4 = 75 km/h

Hence the correct choice is

C) 75 km/hr

Part a)

acceleration is defined as rate of change in velocity

so we can write

[tex]a = \frac{v_f - v_i}{t}[/tex]

here we know that

finally it will stop so vf = 0

initial speed is given as 9m/s

and the time to stop is 0.2 s

[tex]a = \frac{0 - 9}{0.2}[/tex]

[tex]a = -45 m/s^2[/tex]

Part b)

Now by 2nd law of Newton

[tex]F = ma[/tex]

given that

m = 100 kg

a = 45 m/s^2

so now using above equation

[tex]F = 100 * 45[/tex]

[tex]F = 4500 N[/tex]

so it will exert 4500 N force to stop

A. The deceleration of Alex is 45 m/s²

B. The force of impact is 4500 N

From the question given above, the following data were obtained:

a = (v – u) / t

a = (0 – 9) / 0.2

a = –9 / 0.2

a = –45 m/s²

The, negative sign indicate that the Alex is coming to rest.

F = ma

F = 100 × 45

F = 4500 N

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Hi, the answer is A) +2.90%.

The correct answer is constant and positive

The velocity is changing with respect to time at constant rate and we know that the change in velocity is known as acceleration so a constant change in velocity with respect to time will give us a constant acceleration. Similarly the velocity is gradually increasing that is why we will take the acceleration as positive .

Answer: constant and positive

Explanation:

Acceleration is the rate of change of velocity. It can be measured in meter per second square.

[tex]a = \frac{dv}{dt}[/tex]

It can be measured from the slope of velocity - time graph.

In the given velocity vs. time graph, the slope is a straight line in the first quadrant. This means the acceleration is uniform (constant) and positive.

Acceleration from the given graph is:

a = change in velocity /time interval = (5-0)m/s/(5-0)s = 1 m/s².

In a distance versus time graph, the distance is plotted on the y-axis, or vertical axis and the time is plotted on the x-axis (Option B).

In a distance versus time graph, the x-axis, which is the horizontal axis, represents time.

This means that time is plotted along the horizontal axis, and it shows how much time has passed as you move from left to right on the graph. The vertical y-axis represents distance, so the graph illustrates how distance changes over time.

Therefore, the answer is x- axis, represents time.

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Final answer:

Time is plotted on the x-axis of a distance versus time graph because it is the independent variable, while distance is dependent and is plotted on the y-axis.

Explanation:

On a distance versus time graph, time is typically plotted on the x-axis. This is because time is considered an independent variable. When analyzing motion, an object's distance or displacement depends on the elapsed time; hence, distance is plotted on the y-axis. The question mentions other variables like speed and velocity, which are related but represented differently in graphical form. For instance, a velocity vs. time graph has velocity on the y-axis and time on the x-axis, where the slope represents acceleration, and the area under the curve represents displacement. A graph of displacement vs. time would display a straight line if the velocity (v) is constant and time (t) is the independent variable on the x-axis.

Answer:

Nucluas

Explanation:

Given that force applied due to tree on car is 6000 N

and during the stop the acceleration is given as 2 m/s^2.

So here we can say that As per Newton's II law

[tex]F = m*a[/tex]

here F = force on car = 6000 N

a = acceleration of car = 2 m/s^2

now we can plug in all values above in the given equation

[tex]6000 = 2*m[/tex]

[tex]m = 3000 kg[/tex]

So here the mass of the car will be 3000 kg

The mass of the car is 3000 kg.

To calculate the mass of the car, we can use Newton's second law of motion: F = ma.

In this case, the force exerted on the car is 6000 N and the acceleration is 2 m/s².

So, using the formula F = ma, we can rearrange it to solve for mass (m). Therefore, m = F/a = 6000 N / 2 m/s² = 3000 kg.

the answer youre looking for is (C

I think its either sight or its your hands/sensory limbs because it takes babie a while to figure out how to use their hands. i would say speech but it is not a sense. hope this helps!

The least functional sense at birth is vision. Newborn babies have limited visual acuity and are unable to see clearly or focus on objects that are far away. Their vision gradually improves as they grow older.

The least functional sense at birth is vision. Newborn babies have limited visual acuity and are unable to see clearly or focus on objects that are far away. Their visual system is still developing, and it takes a few months for them to develop better visual skills.

Babies are born with the ability to hear, taste, and touch, but their vision is less developed at birth. They can detect light and motion, but their vision gradually improves as they grow older. By about 6 months of age, most babies have developed the ability to see more clearly.

During the early stages of development, babies rely on their other senses, such as touch and hearing, to explore and interact with the world. These senses are more functional at birth compared to vision.

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The answer is C I hope this helps

The correct option is C kg.

The system international ( SI) unit of mass is kilogram.

It is denoted as kg.

As per Newton's II law we can say force applied on an object is product of mass and acceleration

[tex]F = ma[/tex]

given that

Force = 140 N

mass = 32.5 kg

now we can use above formula

[tex]140 = 32.5* a[/tex]

[tex]a = \frac{140}{32.5}[/tex]

[tex]a = 4.31 m/s^2[/tex]

so its acceleration must be 4.31 m/s^2

Answer:

B.0 N

Explanation:

Based on the description of the free-body diagram, there are only two forces acting on the child sitting on the seat:

- The force of gravity, Fg=-100 N, in the downward direction

- The normal reaction of the chair on the child, Fn=100 N, in the upward direction

The two forces have same magnitude but in opposite directions, so the net force (resultant of the two forces) is zero:

[tex]F_{net}=F_n+F_g=100 N-100 N=0 N[/tex]

The new average pressure will be four times the original pressure when the wood is replaced by a sheet with half the diameter, i.e p' = 4p.

The pressure exerted by an object is given by the force applied divided by the area over which it is distributed.

The formula for pressure (p) is (p = F/A).

If the box exerts a pressure (p) on the original round sheet of wood, and the wood is replaced by a sheet with half the diameter, the new area will be (1/4) of the original (since area is proportional to the square of the diameter).

Therefore, the new pressure (p') can be expressed as:

p' = F ÷ (1/4)A = 4p

So, the new average pressure will be four times the original pressure when the wood is replaced by a sheet with half the diameter.

it is the process by which important molecules enter the body cells and waste products are removed from cells.  is why it is important because your body kills off the stuff that's  not supposed to be in it and makes sure all the good cells are  where they're supposed to be

Answer:

 Length of displacement vector = 7.51 m

Explanation:

 Consider east as positive X axis and North as positive Y axis.

 Eric headed 6 meters east, Displacement = 6 i

 Then he headed X meters north, Displacement = X j

 Total displacement = 6 i + X j

  Angle it makes with horizontal axis, θ = tan⁻¹(X/6) = 37°

  X/6 = tan 37

   X = 4.52 m

Total displacement = 6 i + 4.52 j

Magnitude = [tex]\sqrt{6^2+4.52^2} =7.51m[/tex]

 Length of displacement vector = 7.51 m

The answer is A. 7.5.

durability and flexibility

look at you shoelaces they are not hard, don't move like a liquid, or have a high density.

Answer:

Flexibility and durability.

Explanation:

The material of leather and nylon is durable which means it can be used for a long period of time and the material is also flexible means it is not hard. The material which is used in shoe laces can be chosen on the basis of its flexibility and its long lasting nature because costumer do not want to invest on them more than one time or on the basis of easily use.

Therefore, due to the long lasting nature means durability and their flexibility nylon and leather is mostly used in shoe laces.

D.  For any projectile motion, there is a constant downwards acceleration due to gravity at all instances.  This not to be confused with velocity, which changes due to gravity at every moment along the object's path.

speed of first one is given as

[tex]v_1 = 1 mile \: in \: 1 min[/tex]

we also know that

1 mile = 1609 meter

also for time of motion

t = 1 min = 60 s

so in SI units the speed is given as

[tex]v = \frac{1609}{60}[/tex]

[tex]v = 26.82 m/s[/tex]

so 1 mile/min = 26.82 m/s

So here we will say that 1 mile per min is more speed than 20 m/s as we can see that 1 mile / min is 26.82 m/s in SI units after its conversion

Final answer:

Someone traveling at a mile a minute (26.67 m/s) is faster than someone traveling at 20 meters per second.

Explanation:

To determine who is faster between someone traveling a mile a minute and someone traveling at 20 meters per second, we need to convert one of the rates so that both are in the same units. First, let's convert a mile a minute to meters per second. Since one mile is equivalent to 1600 meters, and one minute is equivalent to 60 seconds, if you travel a mile in a minute, you're traveling 1600 meters in 60 seconds. Thus, the conversion is 1600 meters / 60 seconds = 26.67 meters per second.

Now, we compare:

A mile a minute = 26.67 m/s

Someone traveling at 20 m/s

It's clear that 26.67 m/s is faster than 20 m/s. Therefore, someone traveling a mile a minute is faster than someone traveling at 20 m/s.

I think its 60. I think you would subtract 144-84 to get the mass of the vinegar molecule.

Answer:

m = 60 amu

Explanation:

As we know that total mass is always conserved

So here we know that compound is of mass 84 amu initially

after reaction with vinegar molecule the total mass is given as

[tex]M_{total} = M + m[/tex]

here we know that

[tex]M = 84 amu[/tex]

so we will have

[tex]M_{total} = 144 amu[/tex]

so we have

[tex]144 = 84 + m[/tex]

[tex]m = 60 amu[/tex]

The car's (average) acceleration would be

[tex]a=\dfrac{46.1\,\frac{\mathrm m}{\mathrm s}-18.5\,\frac{\mathrm m}{\mathrm s}}{2.4\,\mathrm s}=11.5\,\dfrac{\mathrm m}{\mathrm s^2}[/tex]

The car's position over time would be given by

[tex]x=v_0t+\dfrac12at^2[/tex]

so that after 2.4 seconds, the car will have traveled a distance of

[tex]x=\left(18.5\,\dfrac{\mathrm m}{\mathrm s}\right)(2.4\,\mathrm s)+\dfrac12\left(11.5\,\dfrac{\mathrm m}{\mathrm s^2}\right)(2.4\,\mathrm s)^2[/tex]

[tex]\implies x=77.5\,\mathrm m[/tex]

Hello!

A race car accelerates uniformly from 18.5 m/s to 46.1 m/s in 2.47 seconds. Determine the acceleration of the car and the distance traveled.

* Determine the acceleration of the car....

We have the following data:

V (final velocity) = 46.1 m/s

Vo (initial velocity) = 18.5 m/s

ΔV  (speed interval)  = V - Vo → ΔV  = 46.1 - 18.5 → ΔV  = 27.6 m/s

ΔT (time interval) = 2.4 s

a (average acceleration) = ? (in m/s²)

Formula:

[tex]\boxed{a = \dfrac{\Delta{V}}{\Delta{T^}}}[/tex]

Solving:  

[tex]a = \dfrac{\Delta{V}}{\Delta{T^}}[/tex]

[tex]a = \dfrac{27.6\:\dfrac{m}{s}}{2.4\:s}[/tex]

[tex]\boxed{\boxed{a \approx 11.5\:m/s^2}}\longleftarrow(acceleration)\:\:\:\:\:\:\bf\green{\checkmark}[/tex]

* The distance traveled ?

We have the following data:

Vi (initial velocity) = 18.5 m/s

t (time) = 2.47 s

a (average acceleration) = 11.5 m/s²

d (distance interval) = ? (in m)

By the formula of the space of the Uniformly Varied Movement, it is:

[tex]d = v_i * t + \dfrac{a*t^{2}}{2}[/tex]

[tex]d = 18.5 * 2.4 + \dfrac{11.5*(2.4)^{2}}{2}[/tex]

[tex]d = 44.4 + \dfrac{11.5*5.76}{2}[/tex]

[tex]d = 44.4 + \dfrac{66.24}{2}[/tex]

[tex]d = 44.4 + 33.12[/tex]

[tex]\boxed{\boxed{d = 77.52\:m}}\longleftarrow(distance)\:\:\:\:\:\:\bf\green{\checkmark}[/tex]

________________________________  

[tex]\bf\red{I\:Hope\:this\:helps,\:greetings ...\:Dexteright02!}[/tex]

m = mass of the car = 1500 kg

we know that 1 mph = 0.45 m/s

hence

v = speed gained by the car = 40 mph = 40 x 0.45 m/s = 18 m/s

since the car is gaining speed here , hence the energy need is same as the kinetic energy gained by the car

kinetic energy is given as

KE = (0.5) m v²                     where m = mass , v = speed

inserting the above values in the formula

KE = (0.5) (1500) (18)²

KE = 2.43 x 10⁵ J

we know that , 1 J = 2.78 x 10⁻⁷ kwh

hence

KE = (2.43 x 10⁵) (2.78 x 10⁻⁷)

KE = 0.068 kwh

hence the energy needed is 0.068 kwh

Answer

The answer to this question is [tex]30 ms^{-1}[/tex]

Explanation

As we know that accelartion is the rate of change of velocity. So, it can be write as

[tex]a = (V_f -V_i) /t[/tex]

where

[tex]V_f[/tex] is the final velocity

[tex]V_i[/tex] is the initial velocity

t is the time

a is the accelartion

as we konw

[tex]a = 3 ms^{-2}[/tex]

t = 10 s

From rest So,

[tex]V_i[/tex] = 0

[tex]V_f[/tex] = ?

Putting values

[tex]3 = (V_f - 0)/10[/tex]

[tex]3 * 10 = V_f[/tex]

[tex]30 = V_f[/tex]

[tex]V_f = 30 ms^{-1}[/tex]

So, the right answe is [tex]30 ms^{-1}[/tex]

(3 m/s²) x (10 s) = 30 m/s

His speed at the end of 10 sec is 30 m/s.  We can't describe his velocity, because we have no information about the direction he's moving.

The answer would be A or D. The most appropriate answer would be D. Hope I helped :)

Given:

s(distance)= 20 meters

F(force)=200N

Now we know that

work done= Force applied x distance

Substituting the given values in the above formula we get

Work done= 20 x 200= 4000J

The work done by an elephant while moving a circus wagon 20 meters with a pulling force of 200N is calculated using the formula: Work = Force x Distance. Plugging the values into the formula gives us 4000 Joules.

The work done by the elephant pulling the circus wagon can be calculated using the formula for work, which is Work = Force x Distance. In this situation, the Force applied by the elephant is 200N and the Distance moved by the wagon is 20 meters.

So, the Work done would be: 200N x 20m = 4000 Joules.

This means the work done by the elephant is 4000 Joules.

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As Potential energy =mgh

m= 0.95kg

h=3 meter

g = 9.8 m/sec^2. ( acceleration due to gravity)

So P.E =(0.95)(9.8)(3)kgm^2/s^2

P.E =27.93 joules

The force he applies on himself is balanced force.

Answer:a balanced force

Explanation:

Explanation:

In this question, a position time graph is shown. We need to find the corresponding velocity time graph.

In position time graph, till 1 second the object is in uniform motion and reaches a distance of 30 meters. Then the object is at till 3 seconds. After 3 seconds, the object again reaches a distance of 40 meters uniformly.

Corresponding velocity-time graph is shown in figure (3). The object is moving initially with a speed of 30 m/s. After 1 second, it comes to rest till 3 seconds then it again moves. So, the correct option is (c). Hence, this is the required solution.

Option C is the velocity-time graph matches the position-time graph

A velocity-time graph, also known as a v-t graph, is a graphical representation that shows how an object's velocity changes over time. It uses the vertical axis to represent velocity (with direction indicated by sign) and the horizontal axis for time.

The graph's slope indicates acceleration or deceleration, flat segments represent constant velocity, and zero velocity points indicate moments of rest.

Velocity-time graphs are essential tools for analyzing an object's motion, including its acceleration, deceleration, periods of rest, and changes in direction.

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