When a stable diatomic molecule spontaneously forms from its atoms, what are the signs of δh°, δs°, and δg°?

Answer:

blank, 2, blank, 2

The correct answer is: 6.173 seconds.

Explanation:

The formula for half life (of reaction) is:

Half-life = [tex]\frac{1}{K*I}[/tex] --- (A)

Where,

K = Rate constant = 0.54 [tex]\frac{1}{ms}[/tex]

I = Initial concentration = 0.30 m

Plug in the values in equation (A):

Half-life = [tex]\frac{1}{0.54*0.30} = 6.173[/tex]

Hence, the half life is 6.173 seconds.

The half-life of a second-order reaction is [tex]\boxed{{\text{6}}{\text{.173 seconds}}}[/tex]  

Further explanation:

Second-order reaction:

A reaction is said to be of second-order if its rate is proportional to the square of the concentration of one reactant. The general example of second-order reaction is,

[tex]2{\text{A}}\to{\text{P}}[/tex]

Here,

A is the reactant.

P is the product.

The rate is calculated by using the following equation:

[tex]{\text{Rate}}={\text{k}}{\left[{\text{A}}\right]^2}[/tex]

Another form of second-order reaction is as follows:

[tex]{\text{A}}+{\text{B}}\to{\text{P}}[/tex]

Here,

A and B are the two different reactants.

P is the product.

The rate is calculated by using the following equation:

[tex]{\text{Rate}}={\text{k}}\left[{\text{A}}\right]\left[{\text{B}}\right][/tex]

Half-life:

Half-life is defined as the time required to reduce the concentration of reactant to half of its initial value. It is denoted by [tex]{{\text{t}}_{1/2}}[/tex] . The general expression to calculate [tex]{{\text{t}}_{1/2}}[/tex]  of second-order reaction is,

[tex]{{\text{t}}_{1/2}}=\frac{1}{{{\text{k}}{{\left[{\text{A}}\right]}_{\text{0}}}}}[/tex]                                                              …… (1)

Here,

[tex]{{\text{t}}_{1/2}}[/tex]  is the half-life of the reaction.

k is the rate constant for the reaction.

[tex]{\left[ {\text{A}}\right]_{\text{0}}}[/tex]  is the initial concentration of the reactant.

The rate constant for the given reaction is [tex]0.54\;{{\text{M}}^{-1}}{{\text{s}}^{-1}}[/tex] .

The initial concentration of the given reaction is 0.30 M.

Substitute these values in equation (1).

[tex]\begin{aligned}{{\text{t}}_{1/2}}&=\frac{1}{{\left({0.54\;{{\text{M}}^{ - 1}}{{\text{s}}^{ - 1}}}\right)\left( {{\text{0}}{\text{.30 M}}}\right)}}\\&=\frac{1}{{0.162\;{{\text{s}}^{ - 1}}}}\\&=6.1728\;{\text{s}}\\&\approx 6.173\;{\text{s}}\\\end{aligned}[/tex]

So, the half-life of a second-order reaction is 6.173 seconds.

Learn more:

1. Calculate the moles of chlorine in 8 moles of carbon tetrachloride: https://brainly.com/question/3064603

2. Calculate the moles of ions in the solution: https://brainly.com/question/5950133

Answer details:

Grade: Senior School

Subject: Chemistry

Chapter: Chemical Kinetics

Keywords: second-order reaction, half-life, initial, half, 6.173 seconds, 0.30 m, k, A0, A, B, P, 2A, reactant, product, t1/2.

Answer : The formula for the compound aluminum sulfate is [tex]Al_2(SO_4)_3[/tex]

Explanation :

For formation of a neutral ionic compound, the charges on cation and anion must be balanced.

The cation is formed by loss of electrons by metals and anions are formed by gain of electrons by non-metals.

In the given question, the aluminum metal forms an ionic compound with polyatomic anion (sulfate) [tex]SO_4^{2-}[/tex].

Here, aluminum is having an oxidation state of +3 called as [tex]Al^{3+}[/tex] cation and sulfate [tex]SO_4^{2-}[/tex] is an anion with oxidation state of -2. The charges are not balanced. So, the charges are balanced by the cris-cross method. Thus, the compound formed will be, [tex]Al_2(SO_4)_3[/tex]

Hence, the formula for the compound aluminum sulfate is [tex]Al_2(SO_4)_3[/tex]

The formula for aluminum sulfate is Al₂(SO₄)₃. This is because two Al³+ ions balance three SO₄²⁻ ions to achieve electrical neutrality.

The compound aluminum sulfate is formed when an aluminum cation (Al³+) combines with a sulfate ion (SO₄²⁻). Given that atoms strive to reach electrical neutrality, the formula for this ionic compound reflects the simplest ratio that can balance the positive and negative charges. In this case, two aluminum ions (2 x +3 for a total charge of +6) are needed to balance three sulfate ions (3 x -2 for a total charge of -6), resulting in the chemical formula Al₂(SO₄)₃.

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Answer:

The half-life (in seconds) of a zero-order reaction is 8.15 seconds.

Explanation:

Initial concentration of the of the reactant = [tex][A_o]=0.884 M[/tex]

The value of rate constant = [tex]k=5.42\times 10^{-2} M/s[/tex]

The half life for zero order reaction is given as:

[tex]t-{\frac{1}{2}}=\frac{[A_o]}{2k}=\frac{0.884 M}{2\times 5.42\times 10^{-2} M/s}=8.15 s[/tex]

The half-life (in seconds) of a zero-order reaction is 8.15 seconds.

Answer:

D. Fe2(SO4)3

is the answer

Explanation:

Answer:

The answer is 450 g

Explanation:

When the solid sublimes, it gives the same mass of gas because sublimation is a physical change, and it is valid the energy and mass conservation law (mass cannot be destroyed or created in a chemical or physical process). If sublimation is complete, all the molecules changes its physical state from solid to gas.

Sublimation is the process where a solid changes directly into a gas without passing through the liquid phase. The mass of the substance remains unchanged, so a solid with a mass of 450 g will yield a gas with a mass of 450 g.

The process that changes a solid directly into a gas is called sublimation. In this process, a solid transitions to a gas phase without passing through the liquid phase. Importantly, the mass of the substance remains constant during this phase change. Therefore, if you start with a solid that has a mass of 450 g, the resulting gas will also have a mass of 450 g. This is in accordance with the law of conservation of mass which suggests that mass can neither be created nor be destroyed.

An example of sublimation occurs with dry ice (solid CO₂), which transitions directly from a solid to a gas at standard temperature and pressure.

The two chair conformations of cis 1 chloro 2 methylcyclohexane are shown in the image attached.

Due to the cyclohexane ring's capacity for ring flipping, isopropyl chloro-2-methylcyclohexane displays two chair conformations. The methyl group is positioned equatorially in the first conformation, while the chlorine atom is located in the axial position.

The chlorine atom is in the equatorial position and the methyl group is in the axial position in the second conformation, which has the substituents arranged in reverse order. These conformations show the dynamic character of cyclohexane rings, where substituents can be positioned in either an axial or an equatorial orientation to minimize steric hindrance between them by ring flipping.