Which equation could be used to find m∠J in △JKL? x = cos–1 x = cos–1 x = sin–1 x = sin–1

Answer:

w + 2w = 60

Step-by-step explanation:

w + 2w = 60

This equation will not give you the correct value for W because W is the siez or represents the size of the smaller side, since you have 4 sides, 2 small and 2 big, the sum of this 4 sides will be the perimeter, or the total meters of fence needed, since the total meter of fence need is 60 and in the equation you just have 2 sides, the value for W will be double than the real.

Answer:

74,088 cm³

Step-by-step explanation:

[tex]whl = V \\ \\ [4,2]^{3} = 74,088[/tex]

I am joyous to assist you anytime.

Noel is more likely to draw two cards with a sum that is greater than 13.

To determine which outcome is more likely, let's count the number of combinations that meet each criterion.

1. **Sum that is a multiple of 3**:

  - Possible sums: 3, 6, 9, 12

  - Counting the combinations:

    - 3: 1 combination

    - 6: 2 combinations

    - 9: 3 combinations

    - 12: 4 combinations

  - Total combinations: 1 + 2 + 3 + 4 = 10 combinations.

2. **Sum greater than 13**:

  - Possible sums: 14, 15, 16, 17, 18, 19, 20, 21, 22, 23

  - Counting the combinations:

    - 14: 1 combination

    - 15: 2 combinations

    - 16: 2 combinations

    - 17: 3 combinations

    - 18: 2 combinations

    - 19: 3 combinations

    - 20: 2 combinations

    - 21: 3 combinations

    - 22: 1 combination

    - 23: 1 combination

  - Total combinations: 1 + 2 + 2 + 3 + 2 + 3 + 2 + 3 + 1 + 1 = 20 combinations.

Comparing the total combinations, we see that there are more combinations with a sum greater than 13 (20 combinations) than there are combinations with a sum that is a multiple of 3 (10 combinations). Therefore, Noel is more likely to draw two cards with a sum that is greater than 13.

The probable question may be:

Noel is playing a game where he draws one playing card each out of two stacks of 5 cards. The table below shows all possible sums for the two numbers on the cards.

3, 6, 7, 9, 1

1 = 4, 7, 8, 10, 12

4 = 7, 10, 11, 13, 15

6 = 9, 12, 13, 15, 17

8 = 11, 14, 15, 17, 19

12 = 15, 18, 19, 21, 23

Is Noel more likely to draw two cards with a sum that is a multiple of 3 or two cards with a sum that is greater than 13?

Noel is more likely to draw two cards with a sum greater than 13, as there are 37 combinations compared to 11 combinations for multiples of 3.

To determine whether Noel is more likely to draw two cards with a sum that is a multiple of 3 or two cards with a sum that is greater than 13, we can analyze the table provided.

1. Sum that is a multiple of 3:

  - There are several combinations of card values that result in a sum that is a multiple of 3. We can count these combinations from the table:

    - (3, 4), (3, 7), (3, 9), (3, 12)

    - (6, 7), (6, 10), (6, 12)

    - (7, 8), (7, 11)

    - (9, 10), (9, 13)

    - (11, 12)

2. Sum greater than 13:

  - We need to count the combinations of card values that result in a sum greater than 13:

    - (6, 8), (6, 10), (6, 11), (6, 12), (6, 13), (6, 15), (6, 17)

    - (7, 8), (7, 9), (7, 10), (7, 11), (7, 12), (7, 13), (7, 15), (7, 17), (7, 19)

    - (9, 10), (9, 11), (9, 12), (9, 13), (9, 15), (9, 17), (9, 19)

    - (11, 12), (11, 13), (11, 15), (11, 17), (11, 19)

    - (12, 13), (12, 15), (12, 17), (12, 19)

    - (13, 15), (13, 17), (13, 19)

    - (15, 17), (15, 19)

    - (17, 19)

After counting the combinations, we can compare the number of combinations in each category:

1. Sum that is a multiple of 3:

  - Total combinations: 11

2. Sum greater than 13:

  - Total combinations: 37

Comparing the totals, we can see that Noel is more likely to draw two cards with a sum that is greater than 13, as there are more combinations resulting in this outcome.

Complete Question:

Angle a and angle b are pairs of angles called the alternate angles. Alternate angles are pair of angles that is formed by two parallel lines. These two angles are not adjacent to each other. They are located on the opposite sides of the line that intersects the parallel lines.

We know that [tex] \boldsymbol{A^2}=\boldsymbol{A\times A} [/tex]

We also know that [tex] \boldsymbol{I}=\begin{bmatrix}
1 &0 \\
0&1
\end{bmatrix} [/tex]

Now, it has been given to us that [tex] \boldsymbol{A^2}=\boldsymbol{I} [/tex]

Therefore, we will have to find the correct [tex] \boldsymbol{A} [/tex] from the given options and we find that when:

[tex] \boldsymbol{A}=\begin{bmatrix}
3 &-2 \\
4&-3
\end{bmatrix} [/tex]

then [tex] \boldsymbol{A^2}=\boldsymbol{A\times A}=\begin{bmatrix}
3 &-2 \\
4&-3
\end{bmatrix}\times \begin{bmatrix}
3 &-2 \\
4&-3
\end{bmatrix}=\begin{bmatrix}
1 & 0\\
0 & 1
\end{bmatrix} [/tex]

Therefore, from the above given options, Option C is the correct option.

Therefore, [tex] \boldsymbol{A}=\begin{bmatrix}
3 & -2\\
4 & -3
\end{bmatrix} [/tex] is the correct answer.

Answer:

C. [3, -2]

    [4, -3]

Step-by-step explanation:

PLATOOOO

There are 9000 possible 4-sequences that do not begin with the digit 0.

The question asks how many 4-sequences on the set {0..9} do not begin with 0. To solve this, we need to consider the number of possible options for each of the four positions in the sequence, knowing that the first digit cannot be 0.

For the first position, there are 9 options (1-9), since 0 is not allowed. For the next three positions, each can be any of the 10 digits (0-9), since there are no restrictions. Thus, the total number of such sequences is the product of the number of options for each position.

9 options (1st position) x 10 options (2nd position) x 10 options (3rd position) x 10 options (4th position) = 9 x 10 x 10 x 10 = 9000.

So, to find how many 4-sequences do not begin with 0, multiply the number of choices for each position: 9 (first position, cannot be 0) x 10 (second position) x 10 (third position) x 10 (fourth position), resulting in 9000 such sequences.

Answer: C. 4, 1, 2, 3.

I hope this helps :)

Answer: Third option is correct.

Step-by-step explanation:

Since there are four steps in solving one's personal financial challenges:

1) First he needs to assessing the needs and wants .

2) Then, he will consider opportunity costs, i.e. next best alternative.

3) Then, he will assessing the risks and returns associated with the opportunity costs.

4) Last, but not the least, he will be setting short and long term goals.

So, The correct order of these steps is 4,1,2,3.

Hence, Third option is correct.

To write the decimal number 0.8(repeating) as a fraction, use the concept of an infinite geometric series and convert it to an equation. Multiply both sides of the equation by 10 to eliminate the decimal point and subtract the original equation to eliminate the repeating part. Finally, divide by 9 to get the equivalent fraction form.

To write the decimal number 0.8(repeating) as a fraction, we can use the concept of an infinite geometric series. Let's assume the repeating decimal as x: x = 0.8(repeating). Now, multiply both sides of the equation by 10 to remove the decimal point: 10x = 8(repeating). Next, subtract the original equation from this new equation to eliminate the repeating part: 10x - x = 8(repeating) - 0.8(repeating). Simplifying these expressions gives us: 9x = 7.2. Finally, divide both sides of the equation by 9: x = 7.2/9. Therefore, the equivalent fraction form of 0.8(repeating) is 7.2/9.

Answer:

36 cm^2

Step-by-step explanation:

The differential of the function v = 2y cos(xy) is found using the product rule and the chain rule, yielding dv = 2 cos(xy) dy - 2y sin(xy) (xdy + ydx), which accounts for changes with respect to both x and y.

To find the differential of the function v = 2y cos(xy), we'll need to apply the product rule and the chain rule. The product rule states that the differential of a product of two functions is d(uv) = u dv + v du. The chain rule is used when differentiating composite functions, and it implies that d/dx (f(g(x))) = f'(g(x)) * g'(x).

Applying the product rule, we get:

Combining these, the differential dv becomes:

dv = 2 cos(xy) dy - 2y sin(xy) (xdy + ydx).

This equation represents the total differential of the function v with respect to both x and y.

For implicit differentiation examples like in equation In(xy) = x2y3 or systems of differential equations, understanding and applying the product rule, chain rule, and implicit differentiation are essential to calculate derivatives and solve the equations.