A series RL circuit contains two resistors and two inductors. The resistors are 27Ω and 47Ω. The inductors have inductive reactances of 50 Ω and 40 Ω. The applied voltage is 120 V. What is the voltage drop on the inductor that has 40 Ω of reactance?

Answers

Answer 1

Answer:

voltage drop across 40Ω inductor is 41.2V

Step-by-step explanation:

We are given that a series RL circuit contains two resistors 27Ω, 47Ω and two inductors which have reactances 50Ω,40Ω.

Hence total resistance in the circuit =27+47=74Ω

Total reactance=50+40=90Ω

Since all of these elements are in series, same current goes through all the elements.

And that current I=[tex]\frac{E_{T}} {Z}[/tex]

Given Applied voltage,[tex]E_{T}=120V[/tex]

Hence [tex]I=\frac{120}{\sqrt{74^{2}+90^{2}}} =\frac{120}{\sqrt{13576}} =1.03A[/tex]

Therefore voltage drop on the inductor that has 40Ω of reactance=40X1.03

                                                                           =41.196≈41.2V

Answer 2

Final answer:

The voltage drop on the inductor in a series RL circuit with a 40 Ω reactance is calculated using the total impedance and Ohm's Law to find the circuit current, which is then multiplied by the inductor's reactance. The calculated voltage drop is 41.2 V.

Explanation:

The student is dealing with an RL circuit and needs to calculate the voltage drop on an inductor with a given reactance in that circuit. In an RL circuit, the total impedance (Z) is found by combining the resistive (R) and inductive reactance (XL) components together, where R is the sum of individual resistances and XL is the sum of individual reactances. Since the components are in series, the total resistance would be R = 27 Ω + 47 Ω = 74 Ω and the total reactance would be

XL = 50 Ω + 40 Ω = 90 Ω.

The total impedance (Z) can be calculated using the Pythagorean theorem for the right triangle formed by R and XL:

=  [tex]\sqrt{(74^2 + 90^2)[/tex]

= √(5476 + 8100)

= √(13576) ≈ 116.52 Ω.

With the total impedance known, we can find the current in the circuit (I) using Ohm's Law:

I = V/Z

= 120 V / 116.52 Ω

≈ 1.03 A.

The voltage drop across an individual inductor can be found by ∗ V = I * XL, where XL is the inductive reactance of the inductor in question. Therefore, the voltage drop for the inductor with a 40 Ω reactance is:

V = 1.03 A * 40 Ω

= 41.2 V.

This is the voltage drop on the inductor with a 40 Ω reactance.


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Answer:

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Step-by-step explanation:

Final answer:

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Answers

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-Mabel <3

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Answers

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Explanation:

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Answers

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Explanation:

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Answers

Hi, there

Question:Ms. Lynch has 21 coins in nickels and dimes. Their total value is $1. 65. How many of each coin does she have?

Explanation:

1.65 x 21

Answer 34.65

Hi!

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Answers

Assist

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Answer:

Step-by-step explanation:

assist

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Answers

Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Answers

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