Hudson worked two jobs last summer to start saving for a car. He mowed lawns during the day and worked at a pizza place in the evenings. In one month, Hudson earned a total of $1,400. If he earned $360 more at the pizza place than mowing lawns how much did he earn at each job?

Answers

Answer 1
mowing lawns he earned 520 and at the pizza place he earned 880 
hope this helps!
Answer 2

Hudson earned $880 at pizza deliveries and $520 at mowing the lawn.

What is a system of linear equation?

A System of Linear Equations is when we have two or more linear equations working together.

Given that, Hudson mowed lawns during the day and worked at a pizza place in the evenings. Hudson earned a total of $1,400. also he earned $360 more at the pizza place than mowing lawns

Let he earn x at deliveries and y at mowing,

Therefore, establishing a system of equations,

x+y = 1400

x-y = 360

Adding both the equations,

2x = 1760

x = 880

y = 1400-880

y = 520

Hence, Hudson earned $880 at pizza deliveries and $520 at mowing the lawn.

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Related Questions

The perimeter of a quilt is 34 ft. If the quilt is 8 ft long, what is the area

Answers

2l + 2w = 34 (l = 8) (Problem)
2 x 8 = 16 (Finding out the length)
16 + 2w = 34 (Problem with the length)
-16           -16 (Using the subtraction property of equality to isolate the variable)
       2w = 18 (New problem)
       /2      /2 (Using division property of equality)
         w = 9. (Width is found)

9 x 8 = 72. The area is 72 squared feet.
34-(8x2)=18
18÷2=9
8x9=72

1.Write equatios to represent the distances the family drove on the given days.

2. construct a math argument to explain why your answer to 5 is correct.

3. How can you check that your answer is reasonable?

Answers

        equations are (174+106) (112+165) (121+168) (172+113)
i think this is correct because you need morning and evening combined to know a exact answer.  
you can check this by calculating you equations and u will end up with Wednesday as the longest amount of miles
  

Find geometric mean of the pair of number 6 and 10

Answers

1st step: multiply the numbers
6 x 10 = 60

2nd step find the square root 

sqrt(60) = 7.745

 round the answer as needed.

The Geometric mean of the pair of number 6 and 10 is [tex]7.74[/tex]

Geometric mean :

The geometric mean of two number m and n is given as,

                       [tex]G.M=\sqrt{m*n}[/tex]

Geometric mean of the pair of number 6 and 10 is,

                    [tex]G.M=\sqrt{6*10} =\sqrt{60} \\\\G.M=7.74[/tex]

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You track fuel accounts for q shipping line. One vessel consumes 2 1/2 tons of fuel per day during transport. About how many fuel in tons should the vessel consume during 15-day transport?

Answers

For this case, the first thing we must do is rewrite the expression:
 2 1/2
 Rewriting we have:
 2.5 ton / day
 The total amount after 15 days is:
 (2.5) * (15) = 37.5 Ton
 Rewriting we have:
 37 1/2 Ton
 Answer:
 the vessel should consume 37 1/2 Ton during 15-day transport

what is the probabilaty getting a sum of 7 if you rolled a pair of dice?

Answers

There are 36 possible outcomes when we throw a pair of fair six-sided dice.
Out of these, six {(1,6),(2,5),(3,4),(4,3),(5,2),(6,1)} give a sum of 7.
Therefore the probability of rolling a sum of 7 is 6/36=1/6

Which shows how the distributive property can be used to evaluate 7×84/5?

Answers

Well you have nothing here, so I'll take a guess.
84/5 gives 16 4/5. I don't know how much saving in work there is in doing this but you could do this.

7 ( 16 + 4/5)
You still have to do something with 28/5 when you get done, but it is one way to do it.

If you take out a loan that costs $130.50 over nine years at an interest rate of 10%, how much was the loan for?

Answers

Final answer:

The original loan amount for which the final amount payable is $130.50 over nine years at an interest rate of 10% was approximately $55.39.

Explanation:

To find out the original amount of the loan for which the final amount payable is $130.50 over nine years at an interest rate of 10%, we will use the formula for the present value of a loan.

The formula given is P = A / (1 + r/n)^nt, where P is the principal (initial loan amount), A is the final amount, r is the annual interest rate (expressed as a decimal), n is the number of times that interest is compounded per year, and t is the time the money is borrowed for in years.

As the question doesn't specify how many times the interest is compounded per year, we will assume it is compounded once a year (n=1).

We have:

A = $130.50,r = 10% or 0.10,n = 1,t = 9 years.

Plugging these values into the formula:

P = $130.50 / (1 + 0.10/1)^(1*9)

P = $130.50 / (1 + 0.10)^9

P = $130.50 / (1.10)^9

P = $130.50 / 2.35794769

P = $55.39 approximately

Therefore, the original loan amount was approximately $55.39.

Suppose that the probabilities of a customer purchasing​ 0, 1, or 2 books at a book store are 0.20.2​, 0.30.3​, and 0.50.5​, respectively. what is the standard deviation of this​ customer's book​ purchases?

Answers

E [x] = Expected value of X
 μ = average
 σ = standard deviation
 V (X) = Variance
 σ = (V(X)) ^ 0.5
 E [X] = X * P (x)
Assuming that the number of books purchased is a discrete random variable with mean μ = E [X]
 Then the variance of X can be written as V (X) = E [X-μ]^2
 We started finding the average μ
 μ = 0 * 0.20 + 1 * 0.30 + 2 * 0.50
 μ = 1.3
 Once the average is found, we can calculate the value of the variance
 V (X) = 0.20 * (0-1.3) ^ 2 + 0.30 * (1-1.3) ^ 2 + 0.50 * (2-1.3) ^ 2
 V (X) = 0.61
 Now we know that from the variance the standard deviation can be obtained by doing:
 σ = (V (X)) ^ 0.5
 Finally
 σ = 0.781

The standard deviation of the customer's book purchases is 0.72.

The standard deviation of a discrete probability distribution can be calculated using the following formula:

σ = √(p[tex](x - \mu)^2[/tex])

where:

σ is the standard deviation

p(x) is the probability of the event x

μ is the mean of the distribution

In this case, the probabilities of the customer purchasing 0, 1, or 2 books are 0.2, 0.3, and 0.5, respectively. So, the mean of the distribution is:

μ = (0 * 0.2) + (1 * 0.3) + (2 * 0.5) = 1.2

The standard deviation is then:

σ = √([tex](0 - 1.2)^2 (0.3)^2[/tex] + [tex](1 - 1.2)^2 (0.3)^2[/tex] + [tex](2 - 1.2)^2 (0.5)^2)[/tex] = 0.72

So, the standard deviation of the customer's book purchases is 0.72.

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HELP PLEASE
Translate the answer, T2 = A3, into words:

The BLANK of the orbital period, T, of a
planet is equal to the BLANK of the average distance, A, of the planet from the Sun.

Square
Square Root
Cube

Answers

SQUARE and CUBE are the answers i just did it.

Answer:  The square of the orbital period, T, of a  planet is equal to the cube of the average distance, A, of the planet from the Sun.

Step-by-step explanation:

In mathematics, A number or variable 'a' to its second power is said to be square of 'a' i.e. [tex]\ a^2[/tex] is the square of a.

A number or variable 'b' to its third power is said to be cube of 'b' i.e. [tex]\ b^3[/tex] is the cube of b.

In the given equation: [tex]T^2 = A^3[/tex]

Here,  [tex]T^2 [/tex] is square of T.

And  [tex]A^3[/tex] is cube of A.

Therefore, The square of the orbital period, T, of a  planet is equal to the cube of the average distance, A, of the planet from the Sun.

PLEASE HELP FAST!!!!!!!!!!!! WILL GIVE BRAINILST OR WHATEVER :)))))))))))

let f(x)=4x+3 and g(x)=-2+5. find (fog) (5)

Answers

the correct question is
let f(x)=4x+3 and g(x)=-2x+5. find (fog) (5)

we have that
f(x)=4x+3
g(x)=-2x+5
(fog) (x)---------> f(g(x))------> 4*[-2x+5]+3---------> f(g(x))=-8x+20+3
f(g(x))=-8x+23
then 
(fog) (5)=-8*5+23---------> (fog) (5)=-40+23
(fog) (5)=-17

the answer is (fog) (5)=-17


If the test scores of a class of 34 students have a mean of 73.1 and the test scores of another class of 26 students have a mean of 66.4, then the mean of the combined group is

Answers

Combined mean
= (73.1 * 34 + 66.4 * 26) / (34 + 26)
= (2485.4 + 1726.4) / 60
= 70.2 (rounded)

The Mean of the combined class is 70.19.

Mean

Mean is the average of a set of two or more numbers. The arithmetic and geometric mean are the types of mean that can be calculated.

Mean formula

[tex]\rm Mean = \dfrac{sum\ of\ the\ term}{total\ number\ of\ term}[/tex]

Given

The test scores of a class of 34 students have a mean of 73.1 and

The test scores of another class of 26 students have a mean of 66.4.

To find

The mean of the combined group.

How to get the mean of the combined group?

The sum of the total of the test score = Total number of students x Mean

Class 1 sum will be

The sum of the total test score = 34 x 73.1

The sum of the total test score = 2485.4

Class 2 sum will be

The sum of the total test score = 26 x 66.4

The sum of the total test score = 1726.4

Than Mean for the combine will be

[tex]\rm Mean = \dfrac{sum\ of\ the\ term}{total\ number\ of\ term}\\\\Mean = \dfrac{2485.4+1726.4}{34+26} \\\\Mean = \dfrac{4211.8}{60} \\\\Mean = 70.19[/tex]

Thus the Mean of the combined class is 70.19.

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which of the following is equivalent to the polynomial below

Answers

Try this solution:
1. to find the roots of the equation (D=-36):
[tex] \left[\begin{array}{ccc}x=5+6i\\ x=5-6i\end{array}\right[/tex]
2. to simplify the polinom:
x²-10x+61=(x-(5-6i))(x+(5+6i))
Answer: 1

Solve the equation by completing the square. Round to the nearest hundredth if necessary. x2 – 4x = 5

Answers

Solve for x over the real numbers:
x^2 - 4 x = 5

Subtract 5 from both sides:
x^2 - 4 x - 5 = 0

x = (4 ± sqrt((-4)^2 - 4 (-5)))/2 = (4 ± sqrt(16 + 20))/2 = (4 ± sqrt(36))/2:
x = (4 + sqrt(36))/2 or x = (4 - sqrt(36))/2

sqrt(36) = sqrt(4×9) = sqrt(2^2×3^2) = 2×3 = 6:
x = (4 + 6)/2 or x = (4 - 6)/2

(4 + 6)/2 = 10/2 = 5:
x = 5 or x = (4 - 6)/2

(4 - 6)/2 = -2/2 = -1:

Answer:  x = 5 or x = -1

Answer:

  x = 5 or x = -1

Step-by-step explanation:

x^2 – 4x = 5

Solve it by completing the square method

In completing the square method, we take the coefficient of x that is -4, divide it by 2 and then square it

-4/2 = -2  

square it (-2)^2 = 4

Now add 4 on both sides

x^2 – 4x +4 = 5+4

x^2 – 4x +4 = 9

Now factor the left hand side

(x-2)(x-2)=9

(x-2)^2 = 9

Take square root on both sides

x-2 = +-3

x-2 = 3 , so x= 5

x-2 = -3, so x= -1

A bank runs a contest to encourage new customers to open accounts. In the contest, each contestant draws a slip representing a different reward—$5, $3, or $x—from a jar. At the beginning of the contest the jar contains 60 slips for $5, 40 slips for $3, and 50 slips for $x.
If the expected value of the first draw from the jar is $5.8, the value of x is__
At one point in the contest, the jar contains 3 slips for $5, 7 slips for $3, and y slips for $x. If the expected value on the next draw is $6, the value of y is __

Answers

Part 2:


We'll use x = 9 from part 1.


Again let,
A = event that the $5 reward is drawn
B = event that the $3 reward is drawn
C = event that the $x reward is drawn (x is some positive number)

We can update event C to say
C = event that the $9 reward is drawn


The probabilities change to
P(A) = 3/(10+y)
P(B) = 7/(10+y)
P(C) = y/(10+y)
where y is some positive whole number. It represents the number of slips in jar C


The net values are
V(A) = 5
V(B) = 3
V(C) = x = 9


Like before, multiply the probabilities and net values to get
P(A)*V(A) = (3/(10+y))*5 = 15/(10+y)
P(B)*V(B) = (7/(10+y))*3 = 21/(10+y)
P(C)*V(C) = (y/(10+y))*9 = (9y)/(10+y)


The results add up to
[ 15/(10+y) ] + [ 21/(10+y) ] + [ (9y)/(10+y) ]
(15+21+9y)/(10+y)
(36+9y)/(10+y)


That last expression is the expected value. The expected value is also given to be 6, so set the two expressions equal to each other and solve for y.
(36+9y)/(10+y) = 6
36+9y = 6(10+y)
36+9y = 6(10)+6(y)
36+9y = 60+6y
9y-6y = 60-36
3y = 24
3y/3 = 24/3
y = 8


The statement "y slips of $x" turns into "8 slips of $9" since x = 9 and y = 8.
x=9                                                                                                                     and                                                                                                                         y =8.......................................

Can you answer this one for my plz I need before Monday ty

Answers

Since you need the vertex, and knowing the vertex will tell you the axis of symmetry, it is convenient to put the equation in vertex form.
.. -x^2 -4x +1
.. = -(x^2 +4x) +1
.. = -(x^2 +4x +(4/2)^2) +1 -(-(4/2)^2) . . . . complete the square
.. = -(x +2)^2 +5

The vertex is (-2, 5).
The axis of symmetry is x = -2.

A gardener plants a bed of flowers such that he plants twenty day lilies in the first row, twenty-six day lilies in the second row, and thirty-two day lilies in the third row. He continues to plant lilies in the bed with this pattern for a total of twelve rows. How many day lilies did he plant?

Answers

he planted 92 of those because 12 times 6 is 72 and 72 plus 20 is 92 therefore the answer is 92

There are 86 lilies he did plant in 12th row of the garden.

What is Arithmetic Sequence?

Arithmetic Progression (AP) is a sequence of numbers in order, in which the difference between any two consecutive numbers is a constant value. It is also called Arithmetic Sequence.

Here, The number of lilies plants in first, second third,..., and last row are respectively.

20,26,32,........

the number of rows of lilies plants is 12.

The sequence 20,26,32,........ is an A.P. with first term a =20, common difference d = 6 and n =12

formula for nth term.

aₙ = a+(n−1)d

aₙ=20+ (12-1).6

aₙ = 20 + 11 X 6

aₙ = 86

Thus, there are 86 lilies he did plant in 12th row of the garden.

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What is the following product? 3 sqrt d x 3 sqrt d x 3 sqrt d

Answers

[tex]\bf 3\sqrt{d}\times 3\sqrt{d}\times 3\sqrt{d}\implies (3)(3)(3)\sqrt{d\times d\times d}\\\\\\ 27\sqrt{d^2d}\implies 27d\sqrt{d}[/tex]

Answer: the first option, d.

Step-by-step explanation:

A triangle has one 60 degree angle and one 20 degree angle. The third angle in the triangle must be
a.acute
b.obtuse
c.commplementary
d.straight

Answers

The 3rd angle has to be b. obtuse because a triangle's angles must add to 180°. 20° and 60° add to 80, and you must have a 100° for them to add to 180°. Any angle above 90° is known as an obtuse angle, so that's your answer.

Evaluate g(n-5) if g(x)=x^2-6/2x

Answers

g(x) = (x^2-6) / 2x 

g( n-5) = ( [n-5]^2 -6) / 2(n-5) 

= ( n^2 -10n +25 -6 ) / 2(n-5) or ( n^2 -10n +25 -6 ) / (2n-10) 
Your Answer 

I did foil first and got n^2-10n+25 
then did 25-6 to get 19. 
so n^2-10n+25 is on top.////// should have been n^2 -10n +19 
and the bottom is 2(n-5) so I distributed the 2 and got 2n-10 

so n^2-10n+25 
2n-10 
= (n^2 -10n +19) / 2(n-5)

Answer: We want to evaluate g(x) in x = n -5, where g(x) = (x^2-6)/2x

then, doing it step by step: [tex]g( n- 5)= \frac{(n-5)^{2} - 6 }{2*(n-5)}= \frac{(n^{2} - 2*5*n + 25) - 6 }{2n - 10} = \frac{n^{2} - 10n + 19 }{2n - 10}[/tex]

where i used that (a - b)^2 = a^2 -2ab + b^2

So the correct option is C.

How many bits are required to represent the decimal numbers in the range from 0 to 999 in straight binary code?

Answers

Note that powers of 2 can be written in binary as

[tex]2^0=1_2[/tex]
[tex]2^1=10_2[/tex]
[tex]2^2=100_2[/tex]

and so on. Observe that [tex]n+1[/tex] digits are required to represent the [tex]n[/tex]-th power of 2 in binary.

Also observe that

[tex]\log_2(2^n)=n\log_22=n[/tex]

so we need only add 1 to the logarithm to find the number of binary digits needed to represent powers of 2. For any other number (non-power-of-2), we would need to round down the logarithm to the nearest integer, since for example,

[tex]2_{10}=10_2\iff\log_2(2^1)=\log_22=1[/tex]
[tex]3_{10}=11_2\iff\log_23=1+(\text{some number between 0 and 1})[/tex]
[tex]4_{10}=100_2\iff\log_24=2[/tex]

That is, both 2 and 3 require only two binary digits, so we don't care about the decimal part of [tex]\log_23[/tex]. We only need the integer part, [tex]\lfloor\log_23\rfloor[/tex], then we add 1.

Now, [tex]2^9=512<1024=2^{10}[/tex], and 999 falls between these consecutive powers of 2. That means

[tex]\log_2999=9+\text{(some number between 0 and 1})[/tex]

which means 999 requires [tex]\lfloor\log_2999\rfloor+1=9+1=10[/tex] binary digits.

Your question seems to ask how many binary digits in total you need to represent all of the numbers 0-999. That would depend on how you encode numbers that requires less than 10 digits, like 1. Do you simply write [tex]1_2[/tex]? Or do you pad this number with 0s to get 10 digits, i.e. [tex]0000000001_2[/tex]? In the latter case, the answer is obvious; [tex]1000\times10=10^4[/tex] total binary digits are needed.

In the latter case, there's a bit more work involved, but really it's just a matter of finding how many number lie between successive powers of 2. For instance, 0 and 1 both require one digit, 2 and 3 require two, while 4-7 require three, while 8-15 require four, and so on.

Final answer:

To represent the decimal numbers from 0 to 999 in binary code, we require 10 bits. This is determined by finding the binary equivalent of the largest number, 999, which necessitates at least 10 powers of 2 (from [tex]2^0 \ to \ 2^9[/tex]).

Explanation:

To determine how many bits are required to represent the decimal numbers in the range from 0 to 999 in straight binary code, we need to find the binary equivalent of the largest number in that range, which is 999. In binary, this would require the highest power of 2 that is less than or equal to 999. The largest power of 2 less than 999 is 512 (29), and we continue to add powers of 2 to represent the number:


 512 (29)
 256 (28)
 128 (27)
 64 (26)
 32 (25)
 16 (24)
 8 (23)
 4 (22)
 2 (21)
 1 (20)

Adding these up, we see that we need at least 10 bits to represent the number 999 in binary, because adding powers of 2 from 20 to 29 will give us the required range. Therefore, we need 10 bits to represent any number from 0 to 999 in binary.

What is the mean of the values in the stem-and-leaf plot? Enter your answer in the box.Key: 2|5 means 25





Enter your answer in the box.



Key: 2|5 means 25

A stem-and-leaf plot with a stem value of 1 with leaf values of 5 and 8, a stem value of 2, a stem value of 3, a stem value of 4 with a leaf value of 6, a stem value of 5 with leaf values of 0, 0, 0, 0, 7, a stem value of 6, a stem value of 7, a stem value of 8, and a stem value of 9.

Answers

The stem and leaf plot represents the numbers 15, 18, 46, 50, 50, 50, 50, 57. To find the mean, add these up (336) and divide by the number of data points (8). The mean is 42.

The mean of the values in the stem-and-leaf plot is 42.

To find the mean of the values in the stem-and-leaf plot, we first need to interpret the plot correctly. Here's the stem-and-leaf plot description:

Stem | Leaves

 1  | 5, 8

 2  |

 3  |

 4  | 6

 5  | 0, 0, 0, 0, 7

 6  |

 7  |

 8  |

 9  |

Let's list the individual values from the plot:

- From stem 1: Leaves are 5 and 8

- From stem 4: Leaf is 6

- From stem 5: Leaves are 0, 0, 0, 0, 7

Now, we calculate the mean (average) of these values.

Step-by-step calculation:

1. List of values:

  - Values from stem 1: 15, 18

  - Values from stem 4: 46

  - Values from stem 5: 50, 50, 50, 57

2. Count the number of values:

  - There are 2 values from stem 1, 1 value from stem 4, and 5 values from stem 5.

  - Total count = 2 + 1 + 5 = 8

3. Calculate the sum of all values:

  - Sum = 15 + 18 + 46 + 50 + 50 + 50 + 50 + 57

  - Sum = 336

4. Calculate the mean:

  - Mean = Sum / Count

  - Mean = 336 / 8

  - Mean = 42

Therefore, the mean of the values in the stem-and-leaf plot is [tex]{42} \).[/tex]

A triangle on a coordinate plane is translated according to the rule T–3, 5(x, y). Which is another way to write this rule?

(x, y) → (x – 3, y + 5)
(x, y) → (x – 3, y – 5)
(x, y) → (x + 3, y – 5)
(x, y) → (x + 3, y + 5)

Answers

we have that

 the original (x,y) coordinates are being moved to the left by 3 units and up by 5 units.

therefore 
the answer is the option 
(x, y) → (x – 3, y + 5)

Another way to write the given rule is (x, y) → (x – 3, y + 5).

Given that,

There are the original x and y coordinates that are being moved to the left-hand side by 3 units and go up by 5 units.

Based on the information, we can conclude that another way to write the given rule is (x, y) → (x – 3, y + 5).

Hence, the other options are incorrect.

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a paragraph of; compare savings and investments

Answers

Your "savings" are usually put into the safest places or products that allow you access to your money at any time. Examples include savings accounts, checking accounts, and certificates of deposit. At some banks and savings and loan associations your deposits may be insured by the Federal Deposit Insurance Corporation. When you "invest," you have a greater chance of losing your money than when you "save." Unlike the Federal Deposit Insurance Corporation; insured deposits, the money you invest in securities, mutual funds, and other similar investments is not federally insured. You could lose your "principal," which is the amount you've invested. Which is true, even if you purchase your investments through a bank. But when you invest, you also have the opportunity to earn more money than when you save.  There is a tradeoff between the higher risk of investing and the potential for greater rewards.

factor, x^4y+8x^3y-6x^2y^2-48xy^2

Answers

Hey there Ruben!

[tex]\boxed{\boxed{((((x^4)*y)+((8*(x^3))*y))-((6*(x^2))*(y^2)))-(24*3xy^2)}} \\ \\ (let's \ simplify \ some \ number's \ down) \\ \\ \boxed{\boxed{ ((((x4)*y)+((8*(x3))*y))-((2*3x2) *y2))-(24*3xy2)}} \\ \\ \\ Pull \ out \ like \ factors : \\ \\ \boxed{\boxed{ x4y + 8x^3y - 6x2y^2 - 48xy^2 = xy * (x3 + 8x^2 - 6xy - 48^y) }} \\ \\ \\ (TAKE \ NOTICE) \swarrow\swarrow\swarrow\swarrow \swarrow\swarrow\swarrow\swarrow\swarrow\swarrow \\ \\ \\ [/tex]

[tex]\boxed{\boxed{\boxed{ (((((x^4)*y)+(23x^3*y))-(2*3x2y2))}}} \\ \\ \\ \boxed{\boxed{\boxed{-(24*3xy2))-xy*(x3+8x2-6xy-48y) = \boxed{0}}}}}[/tex]

I hope this helps you!
the answer is xy(x+8)(x^2-6y)

see attached picture for steps:

With a short time remaining in the day a delivery driver has to make deliveries at 5 locations among the 6 locations remaining. How many different routes are possible

Answers

The delivery driver has to make deliveries at 5 locations among the 6 locations. This means the order of the probability is important because the route he will take from A to B is different with A to C.
So, you need to use permutation for this problem. The calculation would be:
6P5= 6!/ (6-5)!= 720 different routes
Final answer:

To find the number of different routes the delivery driver can take to make the deliveries at 5 out of 6 locations, we can use the concept of permutations.

Explanation:

To find the number of different routes the delivery driver can take, we can use the concept of permutations. Since the delivery driver has to make deliveries at 5 out of the remaining 6 locations, we need to calculate the number of ways to arrange these locations.

We can use the formula for permutations to find the number of different routes:

nPr = n! / (n - r)!

Using this formula, we can calculate the number of different routes as:

6P5 = 6! / (6 - 5)! = 6! / 1! = 6 × 5 × 4 × 3 × 2 × 1 / 1 = 720

Therefore, there are 720 different routes the delivery driver can take to make the deliveries.

Which triangle is it ?

Answers

the answer in attached figure

we know that
sin(30°)=0.5    cos(30°)=√3/2
sin(60°)=√3/2  cos(60°)=0.5

sin(60)=BC/AC=5√3/10=√3/2-------------- is ok
cos (60)=AB/AC=5/10=0.5---- is ok

sin(30)=BA/AC=5/10=0.5-------------- is ok
cos (30)=BC/AC=5√3/10=√3/2-------------- is ok

if angle B is 90°
then
AB²+BC²=AC²------------> 5²+(5√3)²=10²=(25+75)=100------------- > is ok



the solution in the attached figure

How to start the problem off. (substitution)

Answers

Do you have to use substitution? 

describe the graph of y=3/4x-12 as compared to the graph of y=1/x

Answers

Answer:

Parent function is compressed by a factor of 3/4 and shifted to right by 3 units.

Step-by-step explanation:

We are asked to describe the transformation of function [tex]y=\frac{3}{4x-12}[/tex] as compared to the graph of [tex]y=\frac{1}{x}[/tex].

We can write our transformed function as:

[tex]y=\frac{3}{4(x-3)}[/tex]

[tex]y=\frac{3}{4}*\frac{1}{(x-3)}[/tex]

Now let us compare our transformed function with parent function.

Let us see rules of transformation.  

[tex]f(x-a)\rightarrow\text{Graph shifted to the right by a units}[/tex],

[tex]f(x+a)\rightarrow\text{Graph shifted to the left by a units}[/tex],

Scaling of a function: [tex]a*f(x)[/tex]

If a>1 , so function is stretched vertically.

If 0<a<1 , so function is compressed vertically.

As our parent function is multiplied by a scale factor of 3/4 and 3/4 is less than 1, so our parent function is compressed vertically by a factor of 3/4.

As 3 is being subtracted from x, so our parent function is shifted to right by 3 units or a horizontal shift to right by 3 units.

Therefore, our parent graph is compressed by a factor of 3/4 and shifted to right by 3 units to get our new graph.

Final answer:

The equation y=3/4x-12 represents a linear function with a straight line graph, while y=1/x depicts a rectangular hyperbola with a curved graph showcasing an inverse relationship. These graphs exhibit fundamentally different behaviors, one being constant and the other varying.

Explanation:

The student's question involves comparing the graph of y=3/4x-12 to the graph of y=1/x. The first equation, y=3/4x-12, describes a linear function with a slope of 3/4 and a y-intercept of -12. This means it is a straight line that increases as x increases, crossing the y-axis at (0, -12).

On the other hand, the graph of y=1/x is a rectangular hyperbola. This curve approaches the x-axis and y-axis but never touches them, known as asymptotes. The hyperbola is divided into two parts, one in the first quadrant where both x and y are positive, and another in the third quadrant where both x and y are negative. This graph does not resemble a straight line at any part.

Comparatively, the key difference lies in the nature of their graphs - one is a straight line and the other a curved hyperbola, showcasing completely different behaviors. The linear equation reflects constant change, whereas the hyperbola’s rate of change varies with x, indicating an inverse relationship.

What is the measure of angle z in this figure?

Enter your answer in the box.

z = ___°

Answers

Hello!

I've attached a photo for reference.

Lines A and B form straight angles, which  measure 180 degrees. That means that - 

m∠x + m∠y = 180°
m∠y + m∠z = 180°
m∠z + 43° = 180°
43° + m∠x = 180°

Since you're trying to find z, use the solvable equation with z in it:

m∠z + 43° = 180°
180 = z + 43
137 = z

Answer:
m∠z = 137°


8. The U.S. population was 309 million in 2010. If the U.S. had had the same firearm death rate as Australia in 2010, how many firearm deaths would the U.S. have expected to have that year? Australia’s population was 22.3 million people in 2010. Australia had 236 firearm deaths in 2010. (round to the nearest person)

Answers

To answer this question I would use ratios . I would set this up as 236 deaths/22.3 million people = x number of deaths/ 309 million people. You could use cross products to solve for x. 309 x 236= 22.3x. 72924= 22.3x. Divide both sides by 22.3 to solve for X, or the number of deaths in the US. X = 3270 deaths. Another way to figure this out would be to figure out how many groups of 22.3 million Australian people there are in 309 million Americans. This factor would then be multiplied by 236 to get the number of deaths in the United States. The answer would be the same.

As per linear equation, in 2010 the expected firearm death U.S. had is 3270.

What is a linear equation?

A linear equation represents an equation that has one or multiple variables with the highest power of the variable is 1.

Australia’s population was 22.3 million people in 2010.

Australia had 236 firearm deaths in 2010.

Therefore, portion of Australian population had firearm deaths is

[tex]= \frac{236}{22.3(10)^{6} } \\= 0.000011[/tex]

The U.S. population was 309 million in 2010.

Therefore, the expected firearm deaths in U.S. in 2010 was

[tex]= (309) (10^{6}) (0.000011)\\= 3270.13\\= 3270[/tex]

Learn more about linear equation here: https://brainly.com/question/5280825

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