Answer:
Area of the border is 142.80 ft²
Step-by-step explanation:
The given figure consist of three figures = 2× semicircles + 1 square.
We will calculate area of the figure including border
Area of one semicircle = (1/2)π×r²= (1/2)×π×(12/2)² = (1/2)π×(6)² = 18π ft²
Area of square = side² = 12² = 144 ft²
Total area = 144 + 18π + 18π = (144 + 36π) ft²
Now we will calculate area without border.
Area of the semicircle = (1/2)π×r² =(1/2)π×[(12-4)/2]²=(1/2)π×(4)² = 8π ft²
area of square = side²= (12-4)²= 8² = 64 ft²
Total area = 64 + 8π + 8π = (64 + 16π) ft²
Now the area of the border = Area with border - Area without border
= (144 + 36π) - (64 + 16π) = 20π + (144 - 64) = 20π + 80
= 20×3.14 + 80 = 142.80 ft²
Area of the border = 142.80 ft²
The area of the flower border surrounding the heart-shaped pond is approximately 142.80 square feet.
The given figure consists of three parts: two semicircles and one square. Let's calculate the area of the border step by step:
1. Area of the Semicircles:
- The semicircles form the rounded top of the heart shape.
- Each semicircle has a radius of half the width of the pond, which is [tex]\(12 \, \text{ft}\)[/tex].
- Area of one semicircle = [tex]\(\frac{1}{2} \pi r^2\)[/tex]
[tex]\[ = \frac{1}{2} \pi (6)^2 = 18\pi \, \text{ft}^2\][/tex]
- Total area contributed by both semicircles = [tex]\(2 \times 18\pi = 36\pi \, \text{ft}^2\)[/tex]
2. Area of the Square:
- The square section of the pond has sides of [tex]\(10 \, \text{ft}\)[/tex] each.
- Area of the square = side squared
[tex]\[ = 10^2 = 100 \, \text{ft}^2\][/tex]
3. Total Area Including Border:
- Total area = Area of semicircles + Area of square
[tex]\[ = 144 + 36\pi \, \text{ft}^2\][/tex]
4. Area Without Border:
- To find the area without the border, we subtract the area of the pond from the total area:
[tex]\[ = 100 + 16\pi \, \text{ft}^2\][/tex]
5. Area of the Border:
- The area of the border is the difference between the total area and the area without the border:
[tex]\[ = (144 + 36\pi) - (100 + 16\pi) = 20\pi + 80 = 20 \times 3.14 + 80 = 142.80 \, \text{ft}^2\][/tex]
Therefore, the area of the flower border surrounding the heart-shaped pond is approximately 142.80 square feet.
In an equilateral hexagon, four of the exterior angles each have a measure of x degrees. The other two exterior angles each have a measure of twice the sum of x and 48. Find the measure of each exterior angle. (Show work!!)
Final answer:
The measure of each of the four exterior angles of the hexagon is 21 degrees, and the measure of the remaining two exterior angles is 138 degrees each. This was determined by setting up an equation based on the sum of exterior angles of a polygon, which is always 360 degrees, and solving for x.
Explanation:
To solve this problem, we start by understanding that the sum of the exterior angles of any polygon is always 360 degrees. For a hexagon, this sum is divided among six exterior angles. According to the problem, four of these angles are each x degrees, and the remaining two are each twice the sum of x and 48.
Let's set up the equation reflecting this information:
4x + 2(2x + 96) = 360.
Simplifying this equation, we get:
4x + 4x + 192 = 360,
which combines to:
8x + 192 = 360.
Now, we'll solve for x:
8x = 360 - 192,
8x = 168,
x = 21.
Therefore, each of the four exterior angles is 21 degrees, and each of the remaining two exterior angles is twice the sum of 21 and 48, which is:
2(21 + 48) = 2(69) = 138 degrees.
The figure consists of two quarter circles and a
square. What is the perimeter of this figure?
Use 3.14 for π .
82.24 in.
114.24 in.
132.48 in.
164.48 in.
(A square with sides measuring 16 in and has two quarter circles attached with with the same measurements.)
Answer:
The perimeter of the figure is [tex]114.24\ in[/tex]
Step-by-step explanation:
we know that
The perimeter of the figure is equivalent to the perimeter of a square plus the perimeter of a semicircle
step 1
Find the perimeter of square
The perimeter of square is equal to
[tex]P=4b[/tex]
where
b is the length side of the square
we have
[tex]b=16\ in[/tex]
substitute
[tex]P=4(16)=64\ in[/tex]
step 2
Find the circumference of a semicircle
The circumference of a semicircle is equal to
[tex]C=\pi r[/tex]
we have
[tex]r=16\ in[/tex]
[tex]\pi=3.14[/tex]
substitute
[tex]C=3.14(16)=50.24\ in[/tex]
step 3
Find the perimeter of the figure
[tex]64\ in+50.24\ in=114.24\ in[/tex]
In one hour 3/4 pint of a chemical can be filtered how long in HOURS will it take to filter 2 1/2 pints of chemical
half of a number decreased by 6
The answer is: " [tex]\frac{1}{2}[/tex] x − 6 " .
_______________________________________________
→ in which "x" represents the "unknown number" .
_______________________________________________
The expression written for: "Half of a number decreased by 6" is:
→ " [tex]\frac{1}{2}[/tex] x − 6 " ;
_____________________________________________
→ in which "x" represents the "unknown number" .
________________________________________
Explanation:
Let "x" represent the "unknown number".
→ "One-half" of a number , decreased by "6" ;
→ is written as: "1/2 of "x" , minus "6" .
Note that: " 1/2 of x " = " [tex]\frac{1}{2}[/tex] * x " = " [tex]\frac{1}{2}[/tex] x " .
Then, we subtract "6" ; from that value; to write the expression:
________________________________________
The expression written for: "Half of a number decreased by 6" is:
" [tex]\frac{1}{2}[/tex] x − 6 " ;
→ in which "x" represents the "unknown number" .
________________________________________
Hope this helps!
Best wishes in your academic endeavors — and within the "Brainly" community!
________________________________________
Three people become infected with a virus that spreads quickly. Each day that passes, the number of infected people doubles. How can the number of infected people be determined from the number of days that have passed?
Final answer:
The number of infected people can be determined by doubling the number of infected people for each day that passes.
Explanation:
The number of infected people can be determined by doubling the number of infected people for each day that passes. Let's say that on the first day, there is 1 infected person. On the second day, the number of infected people doubles to 2. On the third day, it doubles again to 4, and so on. We can represent this pattern with an exponential equation: y = 2ˣ, where y is the number of infected people and x is the number of days that have passed.
For example, if 5 days have passed, we can plug in x = 5 into the equation: y = 2⁵ = 32. So, there would be 32 infected people.
Which unit of measurement is best to measure the amount of water in a swimming pool?
a. mililiter
b. kiloliter
c. centiliter
d. kilometer
experts only please.......................
what is the place value of 7 in 3.567
Chris wrote a 5 digit number. One digit has the value of 3. One digit has a value of 4000. One has value that is 10 times the value of the digit in the ones place. One has a value that is 10 times the value of the digit in the tens place. One has the value that is 10 times the value of the thousands place. What number did chris write?
Final answer:
The number Chris wrote, considering the values and conditions provided for each digit, is 40353.
Explanation:
To solve this problem, let's identify each digit based on the clues provided:
One digit has the value of 3. This could be in the ones, tens, hundreds, thousands, or ten-thousands place, but we will determine its position later.One digit has a value of 4000, meaning the digit in the thousands place must be 4.One digit is 10 times the value of the ones place. Let's call the ones place 'x', so this digit would be '10x'.One digit is 10 times the value of the tens place. If the tens place is 'y', then this digit is '10y'.Finally, one digit is 10 times the value of the thousands place, which we know is 4, so this digit is 40, and it must be in the ten-thousands place.Now we start assigning values:
The ten-thousands place must be 40, so the first digit is 4.The digit 3 can't be in the thousands place since 4 is already there. It also can't be in the ten-thousands place (which is 40) nor in the hundreds place (which would make it 300, but that is not asked for). Hence, the 3 must be in the tens or ones place.If 3 were in the tens place, then the digit in the thousands place '10y' would be 30, which is incorrect. Therefore, 3 must be in the ones place and 'x' equals 3.So, 10 times the value of the ones place (which is 3) would make the hundreds place 30, but since we can only have a single digit in each place, this is invalid.Since the only sensible option left is for the tens place 'y' to be equal to 3 (making the digit 3 have the value of 30), the digit 10 times the tens place (300) then goes in the hundreds place, and the ones place is left as 'x', which equals 3.So the number Chris wrote is 40353.
The number Chris wrote appears to be 43031.
To determine the 5-digit number that Chris wrote, we need to analyze the values of each digit based on the clues given.
One digit has the value of 3:
This means one of the digits is 3.One digit has a value of 4000:
This means one of the digits represents the thousands place, specifically 4.One digit has a value that is 10 times the digit in the ones place:
Let’s denote the digit in the ones place as [tex]x[/tex]. Therefore, this digit is [tex]10x[/tex], which must be a valid digit (0-9). This means [tex]x[/tex] can be either 0 or 1 (for [tex]10x[/tex] to be a single digit).One digit has a value that is 10 times the digit in the tens place:
Let’s denote the digit in the tens place as [tex]y[/tex]. Thus, this digit is [tex]10y[/tex]. For it to be a valid digit, [tex]y[/tex] can also be 0 or 1.One digit has a value that is 10 times the thousands place:
The thousands place as previously established has a digit 4. Therefore, the digit in question must be [tex]10 \times 4 = 40[/tex], which would also need to be valid as a single digit. However, since this goes beyond the single-digit representation allowed (0-9), we will not use this assumption for any digit.Based on the second and first clues:
If we take 4 for the thousands place, we are left with 0 (from the thousands) plus additional digits accounting for tens.If we choose [tex]x = 1[/tex], we see the ones place becomes 1, giving 10 when multiplied by 10 times the once value.Following the same thought for this representation yields that:So, we could set:
Thousands place as [tex]4[/tex]Hundreds place could be modeled as 0.Tens place can have a digit such 3.Ones as set previously to 1.Therefore the representation of the number combining these values might just happen to yield:
[tex]40000 + 300 + 10 + 1 = 43031[/tex]
Which measure of central tendency is preferred for this data set? Why?
56, 40, 58, 41, 53, 55, 46, 45, 60, 47, 51, 56, 43, 44, 48, 54, 60, 50, 57, 40,46, 47, 49, 59, 44, 50, 42, 53, 95, 41
Answer:
median; The outlier has a large effect on the sum.
Step-by-step explanation:
Final answer:
The median is the preferred measure of central tendency for the given data set due to the presence of outliers, which can skew the mean.
Explanation:
For the given data set, we should consider the presence of outliers in determining the preferred measure of central tendency. This data set contains values such as 95, which is considerably higher than the rest of the values. This can skew the mean to a higher value, making it less representative of the data set. The median is the middle value when all the numbers are arranged in order, which makes it robust to the effect of outliers. In contrast, the mode represents the most frequently occurring number in the data set, which might not be the best central value in this case. Given the outlier's effect on the mean, the median would be a more accurate reflection of the central tendency for this data set.
Han and Clare walk towards each other a constant rate, meet up, and then continue past each other in opposite direction. We will call the position where they meet up 0 feet and the time when they meet up 0 seconds - Han’s velocity is 4 feet per second. -Clare’s velocity is -5 feet per second. -where is each person 10 second before they meet up? - where is each person at the position -10 feet from the meeting place?
Han is around a distance of 40 feet away from Clare, Clare is around -50 feet away from Han and both would be -10 feet far away from the meeting point.
What are Arithmetic operations?Arithmetic operations can also be specified by adding, subtracting, dividing, and multiplying built-in functions.
* Multiplication operation: Multiplies values on either side of the operator
For example 4*2 = 8
Given that Han's velocity is 4 feet per second, and their meeting point is 0 feet and 0 seconds. Clare's speed is -5 feet per second.
We can calculate their distance in 10 seconds by multiplying their velocity.
Han is around (10× 4)40 feet away from Clare.
Clare is around (10× -5)-50 feet away from Han.
Han and Clare would be -10 feet faraway from the meeting point.
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In Mr.Martinez's sixth period class, there are 8 boys and 12 girls. what is the probability of randomly selecting a girl?
What is the measure of each base angle on an isosceles triangle it it's vertex angle measures 28 degrees and it's 2 congruent sides measure 12 units
Final answer:
The measure of each base angle in an isosceles triangle with a 28-degree vertex angle is 76 degrees, which is the result of subtracting the vertex angle from 180 and dividing by 2.
Explanation:
To find the measure of each base angle of an isosceles triangle when the vertex angle is given, you can use the fact that the sum of all angles in a triangle is 180 degrees. Since in an isosceles triangle the two base angles are congruent (equal in measure), you can subtract the vertex angle from 180 degrees and then divide the result by 2 to find the measure of each base angle.
For the given triangle with a vertex angle of 28 degrees:
Subtract the vertex angle from 180 degrees: 180 - 28 = 152 degrees.Divide the result by 2 to find each base angle: 152 / 2 = 76 degrees.Thus, the measure of each base angle in the given isosceles triangle is 76 degrees.
Can you help me pleas now?
To arrange the six numbers into three pairs so that the sum of each pair is equal, you could create the pairings of 4 and -2, -1 and 5, and 6 and 8. Each of these pairs has a sum of 2, 4, and 14 respectively.
Explanation:The six number cards provided are 4, -2, -1, 5, 6 and 8. The task is to arrange these into three pairs, such that the sum of each pair is equal. Based on these conditions, our possible pairs are:
4 and -2-1 and 56 and 8These pairs are obtained by adding the numbers together. For example, the pair 4 and -2 results in a sum of 2 (4 + -2 = 2). Similarly, -1 and 5 also results in a sum of 4 (-1 + 5 = 4), and 6 and 8 results in a sum of 14 (6 + 8 = 14). Two pairs have the same sum of 4 while one pair has the sum of 14.
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Therefore, the complete question is
Here are six number cards
-4, -2, -1, 5, 6, 8
Arrange the cards into three pairs with the same total.
• Please write each pair on separate lines and use the word 'and' between the numbers (eg. 7 and -3)
Given: p: x – 5 =10 q: 4x + 1 = 61 Which is the inverse of p → q? If x – 5 ≠ 10, then 4x + 1 ≠ 61. If 4x + 1 ≠ 61, then x – 5 ≠ 10. If x – 5 = 10, then 4x + 1 = 61. If 4x + 1 = 61, then x – 5 = 10.
Answer:If
x – 5 ≠ 10, then 4x + 1 ≠ 61.
Step-by-step explanation:
I just completed the test
complete this complex math problem
200/20×5+20-20
Can someone figure out the area ?
in a recent survey of middle school students about pizza toppings it was found that 25 students liked pepperoni pizza 31 like banana peppers pizza and 5 liked both pepperoni and banana peppers on their Pizza if 66 students where surveyed how many students do not like banana peppers on their Pizza
Using the principle of inclusion-exclusion, it was determined that out of 66 surveyed students, 15 do not like banana peppers on their pizza.
The number of students who do not like banana peppers on their pizza can be calculated as follows:
Students who like pepperoni pizza only = 25 - 5 = 20
Students who like banana peppers pizza only = 31 - 5 = 26
Students who do not like banana peppers = Total students surveyed - Students who like banana peppers - Students who like only pepperoni = 66 - 31 - 20 = 15 students
A tennis star was hired at a convention. She was paid $3000 plus 2% of all admission fees collected at the door. The total amount she received for the day was $3440. Find the total amount collected at the door.
The value of a is -3
What is the range of: 21, 35, 17, 27, 32, 12 and 30
Find 2/9 of 36
write in simplest form 12:3
jamal runs 1 2/5 miles a day to train a race. If he runs the same distance for 3 days a week, what is the distance he runs in one week?
Which equation can be used to find the unknown length, a, in this triangle?
The unknown length, a, in this triangle can be found using the formula in the first option, a² + 15² = 17².
What is Pythagoras Theorem?Pythagoras theorem states that for a right angled triangle, the square of the hypotenuse is the sum of the squares of base and altitude.
Given is a right angled triangle.
We know the Pythagoras Theorem which states that,
Hypotenuse² = Base² + Altitude²
Hypotenuse is the side opposite to the right angle.
Here length of hypotenuse = 17 m
Length of base = 15 m
Length of altitude = a
Using the theorem,
17² = 15² + a²
Or,
a² + 15² = 17²
Hence the correct formula is a² + 15² = 17².
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Ken got 7 hamsters and 3 mice today. If he does not want to put more than 3 hamsters or mice in a cage, how many cages does he need?
Mark as Brainliest
Answer:
yup 4 cages
Step-by-step explanation:
A study was done to investigate the relationship between outdoor temperature and the amount of fluids an outdoor athlete drinks per day. The correlating linear model is shown below, where x represents the number of degrees over 80°F, and y represents the amount of fluids drank (in liters). Interpret the y-intercept. y = 3.85 + 0.55x A. An athlete drinks 7 L per day when the temperature is 80°F. B. An athlete drinks 4.4 L per day when the temperature is 80°F. C. An athlete drinks 3.85 L per day when the temperature is 80°F. D. An athlete drinks 0.55 L per day when the temperature is 80°F.
Answer:
C. An athlete drinks 3.85 L per day when the temperature is 80°F
Step-by-step explanation:
Y-intercept of a linear model, equation or a straight line refers the point at which a line crosses the y-axis of a graph. It generally indicates a point on the graph where x equals 0.
For the equation y = 3.85 + 0.55x
At y-intercept, x = 0. Substitute x into the equation, we have:
y = 3.85 + 0.55 (0)
y = 3.85 + 0
y = 3.85
This implies that the value of fluid drank by an athlete at the starting temperature of 80°F (at x=0) is 3.85 L per day
Ellen wishes to mix candy worth $1.45 per pound with candy worth $3.74 per pound to form 27 pounds of a mixture worth
$3.06 per pound. How many pounds of the more expensive candy should she use?r.
Final answer:
Ellen should use approximately 18.98 pounds of the more expensive candy worth $3.74 per pound to achieve a 27-pound mixture worth $3.06 per pound when mixed with candy worth $1.45 per pound.
Explanation:
To solve the problem of mixing candies to achieve a specific price per pound, we can use the method of weighted averages. Ellen wants to mix candy worth $1.45 per pound with candy worth $3.74 per pound to create a 27-pound mixture that will be worth $3.06 per pound. Let's denote the amount of the more expensive candy as x pounds and the amount of the less expensive candy as 27 - x pounds.
The total value of the expensive candy is x times $3.74, and the total value of the less expensive candy is (27 - x) times $1.45. The total value of the mixture should equal 27 times $3.06, which gives us the equation:
(x × $3.74) + ((27 - x) × $1.45) = 27 × $3.06
Expanding the equation:
$3.74x + $1.45 × 27 - $1.45x = $82.62
Combining like terms:
$3.74x - $1.45x = $82.62 - $1.45 × 27
$2.29x = $82.62 - $39.15
$2.29x = $43.47
Dividing both sides by $2.29 gives us the amount of the more expensive candy:
x = $43.47 / $2.29
x ≈ 18.98 pounds
Ellen should use approximately 18.98 pounds of the more expensive candy to achieve the desired mixture.
To solve this problem, set up a system of equations using the weight and price information. Then solve the system of equations to find the number of pounds of the more expensive candy. Ellen should use 19 pounds of the more expensive candy, which is worth $3.74 per pound.
Explanation:To solve this problem, we can set up a system of equations. Let x represent the number of pounds of candy worth $1.45 per pound and y represent the number of pounds of candy worth $3.74 per pound. We know that the total weight of the mixture is 27 pounds, so we have the equation x + y = 27. We also know that the average price of the mixture is $3.06 per pound, so we can set up the equation (1.45x + 3.74y)/27 = 3.06.
We can solve this system of equations using substitution or elimination methods. Let's use substitution.
From the first equation, we can solve for x in terms of y: x = 27 - y.Substitute this expression for x in the second equation: (1.45(27 - y) + 3.74y)/27 = 3.06.Simplify and solve for y: 39.15 - 1.45y + 3.74y = 82.62.Combine like terms: 2.29y = 43.47.Divide both sides by 2.29: y = 19.So, Ellen should use 19 pounds of the more expensive candy, which is worth $3.74 per pound.
In triangle FGH, mF is 94°, mG is 49°, and mH is 37°. The exterior angles of triangle FGH are J, K, and L, and they are adjacent to F, G, and H, respectively.
What is mK?
A. 86°
B. 49°
C. 143°
D. 131°
Using the property of exterior angles, mK is found by adding the measures of the non-adjacent interior angles mF and mH, resulting in mK being equal to 131°.
Explanation:The student is asking to find the measure of exterior angle mK in triangle FGH. To find mK, which is the exterior angle adjacent to G, we need to use the property of exterior angles in a triangle. This property states that the measure of an exterior angle is equal to the sum of the measures of the two non-adjacent interior angles.
To find mK we add the measures of angles mF and mH:
mK = mF + mH
mK = 94° + 37°
mK = 131°
Therefore, the measure of the exterior angle K is 131°, which corresponds to answer choice D.
What is the median value of the data set shown on the line plot? Enter your answer in the box. A line plot with twenty-two data values. Labels are at zero, three, six, nine, and twelve. Tick marks are every one unit. Values appear as x marks above the line. Plot data values are one x mark above one, one x mark above two, two x marks above three, two x marks above four, three x marks above five, four x marks above six, three x marks above seven, three x marks above eight, two x marks above nine, and one x mark above eleven.
The median is 6.
This median is easy to find-- you place all your numbers in numerical order and choose the number(s) in the middle-- for this question the median is 6.
I believe your line plot looks like this [Screenshot was taken on K12]:
Please forgive me if this is wrong, and please tell me the correct answer if this incorrect.
((5x−16)^3−4)^3=216,000
Final answer:
To solve the equation ((5x−16)^3−4)^3=216,000, one must apply the rules of exponents and algebraic manipulation step by step, isolating x and using mathematical operations to simplify the expression.
Explanation:
Solving an Equation with Powers
The problem ((5x−16)^3−4)^3=216,000 involves understanding the rules of exponents and algebraic manipulation. When you're dealing with expressions raised to a power, it's important to remember that the power affects everything inside the parentheses, including the number. This is evident in expressions like (5³)* which is equivalent to 5⅜⅓ and results in 5 multiplied by itself 12 times, giving 5⁼.
When approaching the given equation, you would first look to isolate the base of the cube on one side, leading to the cube root to undo the cube power. You would continue simplifying step by step until you isolate x, the variable in question. The key here is to perform operations that counteract the powers and other mathematical operations presented.
In some cases, you might encounter a polynomial long division such as dividing S=9x⁵ +4x⁴ - 5x³ +6x² + 2x - 3 by another polynomial. This requires knowledge of the long division algorithm adapted for polynomials. Each term is divided individually to find the quotient.