Answer:
2nd, 4th and last one are correct answers
Step-by-step explanation:
[tex] {16}^{ \frac{5}{2} } \\ = ( {4}^{2} )^{ \frac{5}{2} } \\ = {4}^{{2} \times \frac{5}{2} } \\ = {4}^{5} \\ [/tex]
Options: 2nd, 4th and last one are correct answers
Find the given percent of 7% of 98
Answer:
Hello! 7% of 98 is 6.86.
Step-by-step explanation:
98 x 0.07 = 6.86
If you move the percentage mark of the 7% two times to the left, you get 7% as a decimal, which is 0.07. You then take 0.07 and multiply it by 98 to get 6.86.
Suppose that the distribution for total amounts spent by students vacationing for a week in Florida is normally distributed with a mean of 650 and a standard deviation of 120 . Suppose you take a simple random sample (SRS) of 25 students from this distribution. What is the probability that a SRS of 25 students will spend an average of between 600 and 700 dollars
Answer:
96.24% probability that a SRS of 25 students will spend an average of between 600 and 700 dollars
Step-by-step explanation:
To solve this question, we need to understand the normal probability distribution and the central limit theorem.
Normal probability distribution
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
Central Limit Theorem
The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
In this problem, we have that:
[tex]\mu = 650, \sigma = 120, n = 25, s = \frac{120}{\sqrt{25}} = 24[/tex]
What is the probability that a SRS of 25 students will spend an average of between 600 and 700 dollars
This is the pvalue of Z when X = 700 subtracted by the pvalue of Z when X = 600. So
X = 700
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
By the Central Limit Theorem
[tex]Z = \frac{X - \mu}{s}[/tex]
[tex]Z = \frac{700 - 650}{24}[/tex]
[tex]Z = 2.08[/tex]
[tex]Z = 2.08[/tex] has a pvalue of 0.9812
X = 600
[tex]Z = \frac{X - \mu}{s}[/tex]
[tex]Z = \frac{600 - 650}{24}[/tex]
[tex]Z = -2.08[/tex]
[tex]Z = -2.08[/tex] has a pvalue of 0.0188
0.9812 - 0.0188 = 0.9624
96.24% probability that a SRS of 25 students will spend an average of between 600 and 700 dollars
This table represents a quadratic function. X 0, 1,2,3,4,5 Y 14, 10.5,8,6.5,6,6.5 what is the value ofa in the function's equation?
Answer:
1/2
Thats about it
What does the median represent in a set of numbers?
A whatever number is in the middle of the list, regardless of the value of the numbers
B the number that represents the middle value in the set of numbers
Final answer:
Option B: the number that represents the middle value in the set of numbers
Explanation:
The median is a statistical measure that represents the middle value in a set of numbers.
To find the median, first, the numbers must be arranged in ascending order. If the number of values (n) in the dataset is odd, the median is the middle value directly.
If n is even, the median is the average of the two middle values. It effectively separates the dataset into two halves, where half of the values are equal to or less than the median, and the other half are equal to or greater than the median value.
For example, in the data set {3, 4, 5, 9, 11}, the median is 5, as it is the middle value of the ordered set.
In another set with an even number of values, for instance, {3, 4, 7, 10}, the median would be the average of 4 and 7, which is 5.5.
This concept is important especially when dealing with outliers, or extreme values, as the median is not affected by them like the mean (average) would be.
The National Institute of Standards and Technology (NIST) offers Standard Reference Materials to aid in the calibration of measurement instruments and verify the accuracy of measurements. Suppose a medical researcher wants to verify that the distances he measures with his computed tomography machine are not too large, so he orders a Dimensional Standard for Medical Computed Tomography from NIST.This standard consists of 18 plastic balls held in place by a plastic support structure. The certified distance between the balls numbered 1 and 2 is 15.96 mm, and NIST determines that measurement errors are normally distributed with a standard deviation of 0.05 mm. Upon receiving the Standard Reference Material, the researcher measured the distance between balls 1 and 2 five times. Take these five measurements to be a simple random sample of all measurements made on this device under carefully controlled conditions. The researcher then calculated the summary statistics, where ???? is the mean distance between balls 1 and 2, as measured by his computed tomography machine.Test of ????=15.96 vs ????>15.96The assumed standard deviation=0.05Samplesize Samplemean Standarderror???? x⎯⎯⎯ SE5 16.02 0.02236(1). Complete the analysis by calculating the value of the one-sample z-statistic, the p-value, and making the decision. First, calculate z to at least two decimal places.z=(2).Use software or a table of standard normal critical values to determine the p‑value. Give your answer precise to at least four decimal places.p=(3). Should the researcher reject his null hypothesis if his significance level is ????=0.05?A. Yes, there is enough evidence (p<0.05) that the mean distance between balls 1 and 2, as measured by his computed tomography machine, is greater than 16.02 mm.B. No, there is not enough evidence (p>0.05) that the mean distance between balls 1 and 2, as measured by his computed tomography machine, is greater than 16.02 mm.C. No, there is not enough evidence (p<0.05) that the mean distance between balls 1 and 2, as measured by his computed tomography machine, is greater than 16.02 mm.D. Yes, there is enough evidence (p>0.05) that the mean distance between balls 1 and 2, as measured by his computed tomography machine, is greater than 16.02 mm.
Answer:
A. There is enough evidence that p < 0.05 that the mean distance between ball one and two as measured by his computed tomography machine is greater than 16.02mm.
Step-by-step explanation:
n= 5
x bar= 16.02
Standard Error= 0.02236
NB:
The null hypothesis is referred to as a characteristic arithmetic theory that gives a statement that suggests that no statistical relationship and significance exists in a set of given observed variables between two sets of observed data and also, measured phenomena. The hypotheses play a crucial role in testing the significance of differences in experiments and between observations. H o represents the null hypothesis of no difference.
The alternative hypothesis is generally represented as H1. It makes a statement that suggests a potential result or an outcome that a researcher may expect.
Standard error measures how far the sample mean of the data is most likely to be from the true population mean.
We want to test the null and alternative hypothesis
H o : μ = 15.96 vs H1 : μ > 15.96
1. Test statistics
Z= xbar - μ / Standard error
Z= 16.02 - 15.96 / 0.002236
Z= 2.6834
2. P value= 0.0036
3. Yes, there is enough evidence that p < 0.05 that the mean distance between ball one and two as measured by his computed tomography machine is greater than 16.02mm.
Therefore, option A is the correct answer.
A circle has a circumference of \blue{8}8start color #6495ed, 8, end color #6495ed. It has an arc of length \dfrac{32}{5} 5 32 start fraction, 32, divided by, 5, end fraction. What is the central angle of the arc, in degrees? 18 ^\circ ∘
Answer:
The central angle of the arc is 288 degrees
Step-by-step explanation:
The correct question is
A circle has a circumference of 8. It has an arc of length 32/5 . What is the central angle of the arc,in the degrees?
we know that
The circumference of the circle subtend a central angle of 360 degrees
so
uing a proportion
Find out the central angle for an arc of length 32/5
[tex]\frac{8}{360^o}=\frac{(32/5)}{x}\\\\x=360(32/5)/8\\\\x=288^o[/tex]
Answer:
288
Step-by-step explanation:
Use the convolution theorem to find the inverse Laplace transform of the given function. StartFraction 5 Over s cubed (s squared plus 25 )EndFraction 5 s3s2+25 laplace transform Superscript negative 1 Baseline StartSet StartFraction 5 Over s cubed (s squared plus 25 )EndFraction EndSet (t )ℒ−1 5 s3s2+25(t)
Answer:
[tex]\frac{1}{2}[/tex][tex]t^{2}Sin5t[/tex]
Step-by-step explanation:
using the Convolution theorem to find the inverse of :
[tex]\frac{5}{s^{3}(s^{2}+25 ) }[/tex]
[tex]L^{-1}[/tex] [tex]\frac{5}{s^{3}(s^{2}+25 ) }[/tex] = [tex]\frac{1}{s^{3} }[/tex] × [tex]\frac{5}{s^{2}+25}[/tex]
we know from derivation that
Sin(at) = [tex]\frac{a}{s^{2}+a^{2} }[/tex]
Hence: [tex]\frac{5}{s^{2}+25}[/tex] = Sin5t
Also: [tex]L^{-1}[/tex] [tex]\frac{n!}{s^{n+1} }[/tex] = [tex]t^{n}[/tex]
[tex]L^{-1}[/tex] [tex]\frac{1}{s^{3} }[/tex] = [tex]\frac{1}{2}[/tex] [tex]L^{-1}[/tex] ([tex]\frac{2!}{s^{3} }[/tex])
= [tex]\frac{1}{2}[/tex][tex]t^{2}[/tex]
therefore [tex]L^{-1}[/tex] [tex]\frac{5}{s^{3}(s^{2}+25 ) }[/tex] = [tex]\frac{1}{2}[/tex][tex]t^{2}Sin5t[/tex]
"Cyber Monday is a huge online shopping day. In 2017, approximately 21% of Cyber Monday shoppers used their mobile device to make a purchase. If a person used a mobile device to make a purchase, the probability of making a purchase from Amazon was .55. Suppose a Cyber Monday purchase is selected at random. What is the probability that the purchase was made with a mobile device and was from Amazon."
Answer:
11.55% probability that the purchase was made with a mobile device and was from Amazon.
Step-by-step explanation:
We have these following probabilities:
21% probability that a Cyber Monday shopper used their mobile device to make a purchase.
55% probability that a purchase made with a mobile device is from Amazon.
What is the probability that the purchase was made with a mobile device and was from Amazon."
55% of 21%
So
P = 0.21*0.55 = 0.1155
11.55% probability that the purchase was made with a mobile device and was from Amazon.
An ordinary (fair) coin is tossed 3 times. Outcomes are thus triples of "heads" (An ordinary (fair) coin is tossed 3 times. Ou) and "tails" () which we write , , etc. For each outcome, let be the random variable counting the number of tails in each outcome. For example, if the outcome is , then . Suppose that the random variable is defined in terms of as follows: . The values of are thus:Outcome Value of Calculate the probability distribution function of , i.e. the function . First, fill in the first row with the values of . Then fill in thevalue x of X Px(X)
The probability distribution function of X, filled in:
X P(X)
0 1/8
1 3/8
2 3/8
3 1/8
Possible outcomes: There are 2^3 = 8 possible outcomes when a fair coin is tossed 3 times (HHH, HHT, HTH, THH, HTT, THT, TTH, TTT).
Counting tails: We count the number of tails in each outcome to determine the values of X.
Probability of each X: We calculate the probability of each value of X by counting the outcomes that correspond to that value and dividing by the total number of outcomes (8).
Detailed breakdown:
X = 0: Only one outcome has 0 tails (HHH), so P(X=0) = 1/8.
X = 1: Three outcomes have 1 tail (HHT, HTH, THH), so P(X=1) = 3/8.
X = 2: Three outcomes have 2 tails (HTT, THT, TTH), so P(X=2) = 3/8.
X = 3: Only one outcome has 3 tails (TTT), so P(X=3) = 1/8.
Two planes are 1530 mi apart and are traveling toward each other. One plane is traveling 100 mph faster than the other plane. The planes meet in 1.5 h. Find the speed of each plane.
Answer: The speed of one plane is 560 mph and the speed of the other is 460 mph.
Step-by-step explanation: Please see the attachments below
ΔABC undergoes a dilation by a scale factor. Using the coordinates of ΔABC and ΔA'B'C', prove that the triangles are similar by AA.
Given:
ΔABC undergoes a dilation by a scale factor and comes as ΔA'B'C'.
To show that both the triangles are similar.
Formula
By the condition of similarity we get,If two triangles have three pairs of sides in the same ratio, then the triangles are similar.
By Pythagoras theorem we get,[tex]Hypotenuse^2 = Base^2+Height^2[/tex]
Now,
In ΔABC,
AB = 18 unit
BC = 10 unit
So, [tex]AC^2 = AB^2+BC^2[/tex]
or, [tex]AC^2 = 18^2+10^2[/tex]
or, [tex]AC = \sqrt{424}[/tex]
Again,
In ΔA'B'C'
A'B' = 9 unit
B'C' = 5 unit
So, [tex]A'C' ^2 = A'B'^2+B'C'^2[/tex]
or, [tex]A'C'^2 = 9^2+5^2[/tex]
or, [tex]A'C' = \sqrt{106}[/tex]
Now,
[tex]\frac{AB}{A'B'} = \frac{18}{9} = 2[/tex]
[tex]\frac{BC}{B'C'} = \frac{10}{5} = 2[/tex]
[tex]\frac{AC}{A'C'} = \frac{\sqrt{424} }{\sqrt{106} } = 2[/tex]
Hence,
All the ratios are equal.
Therefore, we can conclude that,
ΔABC and ΔA'B'C' are similar.
Geophysicists determine the age of a zircon by counting the number ofuranium fission tracks on a polished surface. A particular zircon is of such anage that the average number of tracks per square centimeter is five. What is the probability that a 2cm^2 sample of this zircon will reveal at most three tracks,thus leading to an underestimation of the age of the material?
Answer:
p(x = 3, λ = 5) = 0.14044
Step-by-step explanation:
Given
λ = 5 (the average number of tracks per square centimeter)
ε = 2.718 (constant value)
x = 3 (the variable that denotes the number of successes that we want to occur)
p(x,λ) = probability of x successes, when the average number of occurrences of them is λ
We can use the equation
p(x,λ) = λˣ*ε∧(-λ)/x!
⇒ p(x = 3, λ = 5) = (5)³*(2.718)⁻⁵/3!
⇒ p(x = 3, λ = 5) = 0.14044
Answer:
0.0108
Step-by-step explanation:
Let X denote the number of uranium fission tracks occurring on the average 5 per square centimetre.We need to find the probability that a 2cm² sample of this zircon will reveal at most three tracks. X follows Poisson distribution, λ = 5 and s = 2.
k = λs = 5×2 = 10
Since we need to reveal at most three tracks the required probability is:
P (X≤3) = P (X =0) + P (X =1) + P (X =2) + P (X =3)
P (X≤3) = (((e^-10) × (10)⁰)/0!) + (((e^-10) × (10)¹)/1! + (((e^-10) × (10)²)/2! + (((e^-10) × (10)3)/3!
P (X≤3) = 0.0004 + 0.0005 +0.0023 +0.0076
P (X≤3) = 0.0108
Therefore, the probability that a 2cm² sample of this zircon will reveal at most three tracks is 0.0108
Assume that XY=MN . Which of the following statements are true? (Assume that X, Y, M, N, and F are nonzero real numbers, and assume that all expressions have nonzero denominators.) Create an answer using the numbers associated with the true statements. For example, if only 1, 2, and 5 are true, then the answer is 125; if only 3 and 5 are true, then the answer is 35, etc.
Answer:
123
Step-by-step explanation:
The complete question is Assume that X/Y=M/N . Which of the following statements are true? (Assume that X, Y, M, N, and F are nonzero real numbers, and assume that all expressions have nonzero denominators.) Create an answer using the numbers associated with the true statements. For example, if only 1, 2, and 5 are true, then the answer is 125; if only 3 and 5 are true, then the answer is 35, etc
The statements are given in 1st attachment and answer choices are given in 2nd attachment
Let's start by verifying statements 3 and 4 as these are easy to verify
To verify statement 3,
(X+Y)/Y= (M+N)/N
X/Y + 1= M/N + 1
since X/Y=M/N
X/Y + 1= X/Y +1
So statement 3 is true
To verify statement 4,
(X+F)/Y= (M+F)/N
X/Y + F/Y = M/N + F/N
Statement 4 is false
Look at the answer choices, statement 3 is mentioned in option c,d and e. Statement 4 is mentioned in c and d. Since statement 4 is incorrect our answer is option e
250 students out of 3,000 have found that math is their favorite subject among 10 subjects they are studying. If the choice of favorite subjects was truly random, one out of 10 students would choose math as his/her favorite subject, so p=0.1p=0.1. We are looking to see if pp is less than the expected value of 0.1. Where will the randomization distribution be centerered?
Answer:
The randomization distribution is created under the assumption that H₀: p = 0.1
The randomization distribution will also be centred at 0.1
Step-by-step explanation:
If the distribution was truly random, 1 out of 10 students will choose math as his/her favorite subject.
This means that the randomization will have the null hypothesis saying that the proportion of students who will choose maths as their favourite subject = 0.1
Mathematically, it'll be written as
The null hypothesis is given as
H₀: p = 0.1
And the randomization distribution will be centred at 0.1 too.
The alternative hypothesis will now prove the theory they're looking to see in the question that
Hₐ: p < 0.1
Hope this Helps!!!
Two negative integers are 5 units apart on the number line, and their product is 126. What is the sum of the two integers?
A. -23
B. -5
C. 9
D. 14
One major reason that the two-sample t procedures are widely used is that they are quite robust. What does this mean? t procedures do not require that we know the standard deviations of the populations. Confidence levels and P-values from the t procedures are quite accurate even if the population distribution is not exactly Normal. t procedures compare population means, a comparison that answers many practical questions.
Answer:
Confidence levels and P-values from the t procedures are quite accurate even if the population distribution is not exactly Normal
Step-by-step explanation:
Confidence levels and P-values from the t procedures are quite accurate even if the population distribution is not exactly Normal
there is a general rule that depicts that T is okay to use when n >30. also when the sampling method for each sample is simple random sampling and samples are independent.
A study is being conducted to compare the average training time for two groups of airport security personnel: those who work for the federal government and those employed by private security companies. From a random sample of 12 government-employed security personnel, average training time was 72 hours, with a sample standard deviation of 8 hours. In a random sample of 16 privately employed security personnel, training time was 65.4 hours, with a sample standard deviation of 12.3 hours. Assume that training time for each group is normally distributed. Use the following notations:
μ1: The mean training time for the population of airport security personnel
employed by the federal government.
μ2: The mean training time for the population of airport security personnel
employed by private security companies.
The goal of the statistical analysis is to determine whether the sample data support the hypothesis that average training time for government-employed security personnel is higher than those employed by private security companies.
1. What is the null hypothesis H0?
Select one:
a. μ1- μ2 <= 0
b. μ1- μ2 < 0
c. μ1- μ2 =/ 0
d. μ1- μ2 > 0
2. What is the alternative hypothesis Ha?
Select one:
a. μ1- μ2 > 0
b. μ1- μ2 <= 0
c. μ1- μ2 = 0
d. μ1- μ2 >= 0
Answer:
1.a. H₀: μ₁ - μ₂ ≤ 0
2.b. H₁: μ₁ - μ₂ > 0
Step-by-step explanation:
Hello!
The objective is to compare the average training time for two groups of airport security personnel.
Group 1: Security personnel that works for the federal government
n= 12
X[bar]= 72 hs
S= 8hs
Group 2: Security personnel from private companies
n= 16
X[bar]= 65.4 hs
S= 12.3 hs
The goal of the analysis is to test if the average training time for government-employed security personnel is higher than those employed by private security companies, symbolically: μ₁ > μ₂
The null and alternative hypotheses are complementary and exhaustive.
The null hypothesis always represents the "no change situation" and therefore always carries the = symbol. Generally, the researcher's claim is stated in the alternative hypothesis.
With all this in consideration, the hypotheses for this experiment are:
H₀: μ₁ ≤ μ₂
H₁: μ₁ > μ₂
I hope this helps!
Can someone help me plz
2. Researchers are designing an experiment to compare two diferenst types of running shoes, A and B, to investigate which type is better for minimizing running time for a one-mile run. The experiment will consist of distributing design is planned, with blocking by classification of runner. Random samples of 50 professional runners and wear either the type A shoe or the type B shoe, and their running times will be recorded for a one-mile run. (a) What is a statistical advantage of blocking by the classification of runner? the shoes to runners who are classified as either professional or recreational. A randomized block unners will be selected. Each runner within each classification will be randomly assigned to Blocana by the classi (b) Why is it important to randomize the type of shoe the runner will wear instead of allowing the runner to choose the shoe? GO ON TO THE NEXT PAGE. EER Describe the shape of a histogram created from the data of the two s of students combined. With no ndicaion oF ourliers A crnitr berwen 96-10 s. The data nas a epiend of tom veseun 35-15 avou 80. (e) Consider the pogulation of all tudents in honors biokogy classes in the high school's state who are given the times has a shape similar to the combined histogram of students at the high school, with mean 70 minutes and standard deviation 26.5 minutes. For random samples of 50 students taken from the population, describe the sampling distribution of the sample mean completion time. task of using the spreadsheet program to investigate the topic in genetics. The distribution of the completion GO ON TO THE NEXT PAGE eny part of this page egat 7-
Answer:
2 a) In Randomized Block design there are two variables one is a blocking variable the other one will be the treatment variable. Here type of shoes is the treatment variable and the type of runner is the blocking variable. Blocking is the arrangement of subjects similar in certain characteristics in to a group. Here professional runners are different from recreational runners . Blocking is done to reduce variability within groups so that variability within blocks is less than the variability between blocks. Then, subjects within each block are randomly assigned one of the shoes.
b) Randomization is the process of assigning participants a specific treatment so that each participant has an equal chance of being assigned a shoe A or B. Randomization is done using random number generation and assignment is made according to the random numbers The main purpose of randomization is to eliminate biases. If the person in a group are allowed to choose the shoes they may choose their preferred one based on their past experience of using it or one variety will be preferred by most of the subjects in the group spoiling the entire purpose of the study. for e.g a group of professionals coming from a particular region prefers type A . If randomization is employed in such a situation almost half of the professionals coming from a particular region gets type A and the other half may get type B thus eliminating the personal biases in choice. This way we can eliminate any possible biases that may arise in the experiment. So randomization and blocking are important for a randomized block design in order to minimize bias in the responses.
Step-by-step explanation:
A method currently used by doctors to screen women for possible breast cancer fails to detect cancer in 15% of women who actually have the disease. A new method has been developed that researchers hope will be able to detect cancer more accurately. A random sample of 70 women known to have breast cancer were screened using the new method. Of these, the new method failed to detect cancer in 8. Calculate the test statistic used by the researchers for the corresponding test of hypothesis.
Answer:
The statistic is z=-0.674.
The null hypothesis failed to be rejected.
Step-by-step explanation:
To make conclusions about the effectiveness of the new method, they should perform an hypothesis test on the proportion of failed cancer detection.
The actual method has a proportion of failed cancer detection of p=0.15. If the new method is better, it should have enough evidence that its actual proportion is below 0.15. This claim, that the new method proportion is below 0.15, will be stated in the alternative hypothesis.
The null and alternative hypothesis are:
[tex]H_0: \pi=0.15\\\\H_a:\pi<0.15[/tex]
The sample size is n=70.
The sample proportion is p=8/70=0.114.
The standard error is calculated as:
[tex]\sigma_p=\sqrt{\dfrac{\pi(1-\pi)}{n}}=\sqrt{\dfrac{0.15*0.85}{70}}=\sqrt{0.0018}=0.043[/tex]
Then, the z-statistic for this sample is:
[tex]z=\dfrac{p-\pi+0.5/n}{\sigma_p}=\dfrac{0.114-0.15+0.5/70}{0.043}=\dfrac{-0.029}{0.043} =-0.674[/tex]
The P-value for this statistic is:
[tex]P-value=P(z<-0.674)=0.25[/tex]
At a significance level of 0.1, the P-value is bigger, so the effect is not significant. The null hypothesis failed to be rejected.
Answer:
[tex]z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}[/tex] (1)
[tex]z=\frac{0.114 -0.15}{\sqrt{\frac{0.15(1-0.15)}{70}}}=-0.844[/tex]
Step-by-step explanation:
Data given and notation
n=70 represent the random sample taken
X=8 represent the number of the new method failed to detect cancer
[tex]\hat p=\frac{8}{70}=0.114[/tex] estimated proportion of number of the new method failed to detect cancer
[tex]p_o=0.15[/tex] is the value that we want to test
[tex]\alpha[/tex] represent the significance level
z would represent the statistic (variable of interest)
[tex]p_v[/tex] represent the p value (variable of interest)
Concepts and formulas to use
We need to conduct a hypothesis in order to test the claim that the new method is able to detect cancer more accurately than the currently method (that means a lower rate of the proportion of interest) .:
Null hypothesis:[tex]p \geq 0.15[/tex]
Alternative hypothesis:[tex]p < 0.15[/tex]
When we conduct a proportion test we need to use the z statistic, and the is given by:
[tex]z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}[/tex] (1)
The One-Sample Proportion Test is used to assess whether a population proportion [tex]\hat p[/tex] is significantly different from a hypothesized value [tex]p_o[/tex].
Calculate the statistic
Since we have all the info requires we can replace in formula (1) like this:
[tex]z=\frac{0.114 -0.15}{\sqrt{\frac{0.15(1-0.15)}{70}}}=-0.844[/tex]
HURRY PLSSSSS
Lines Line D E and Line A B are parallel.
Which angles are congruent?
angles A and E
angles B and C
angles C, D, and E
angles A and C
Answer:
Angles A and E are congruent.
Step-by-step explanation:
Angles A and E are congruent because they are alternate interior angles.
Angle A and E are congruent angles. Option A is correct.
In given figure, Line D E and Line A B are parallel.
Which angles are congruent to be determined?
In congruent geometry, the shapes that are so identical. can be superimposed to themselves.
Parallel lines are defined as the lines in which every point is equidistant from the corresponding point on the other line and the parallel line met it infinity.
By property of the parallel line, when a line intersect numbers of parallel line the alternate opposite angles are equal.
By property and clear observatin Angle, A is congruent with Angle E. and Angle D is congruent with Angle B, Hence Option A is correct and all the option can be omitted.
Thus, Angle A and E are congruent angles. Option A is correct.
Learn more about congruent geometry here:
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What is the equation of the line:
* parallel to the line 3x + 2y - 6 = 0 and * passing through the point (4, 5)?
Answer:
y = -1.5x + 11
Step-by-step explanation:
Because the line is parallel, the equation will have the same slope. To find the slope, convert the given equation to y=mx+b form. The equation you get should be y = -1.5x + 3. The slope will be -1.5.
Now using the y=mx+b form, plug in the points given and the slope we found and solve for b.
5 = -1.5(4) + b
b = 11
Now, with the slope and b, you should get the equation y = -1.5x + 11.
The percentage of titanium in an alloy used in aerospace castings is measured in 51 randomly selected parts. The sample standard deviation is s 0.37. (a) Test the hypothesis versus using 0.05. State any necessary assumptions about the underlying distribution of the data. (b) Find the P-value for this test. (c) Construct a 95% two-sided CI for . (d) Use the CI in part (c) to test the hypothesis.
Answer:
attached
Step-by-step explanation:
attached
Suppose 20 donors come to a blood drive. Assume that the blood donors are not related in any way, so that we can consider them to be independent. The probability that a donor has type "O" blood is 0.06. What is the probability that 1 or more donors have type O blood? A. 0.370 B. 0.290 C. 0.630 D. 0.710
Given Information:
Probability of success = p = 0.06
Number of trials = n = 20
Required Information:
Probability of 1 or more donors of "O" blood group = ?
Answer:
P( x ≥ 1 ) = 0.710
Step-by-step explanation:
We are given the probability that a donor has type "O" blood group.
We want to find out the probability of having 1 or more donors who has type "O" blood group out of 20 donors.
P( x ≥ 1 ) = 1 - P( x = 0)
So we will first find the probability that none of the donors has type "O" blood group then we will subtract that from 1 to get the probability of having 1 or more donors with "O" blood group.
P( x = 0) = (p⁰)(1 - p)²⁰
P( x = 0) = (0.06⁰)(1 - 0.06)²⁰
P( x = 0) = (1)(0.94)²⁰
P( x = 0) = 0.290
So the probability of having 1 or more donors with "O" blood group is
P( x ≥ 1 ) = 1 - P( x = 0)
P( x ≥ 1 ) = 1 - 0.290
P( x ≥ 1 ) = 0.710
P( x ≥ 1 ) = 71%
Therefore, the correct answer is D. 0.710
Final answer:
The probability that 1 or more donors have type O blood is approximately 0.370.
Explanation:
The probability that 1 or more donors have type O blood can be found using the complement rule. The complement of the event that 0 donors have type O blood is the event that 1 or more donors have type O blood.
The probability that a donor has type O blood is 0.06. The probability that a donor does not have type O blood is 1 - 0.06 = 0.94. Let's calculate the complement probability:
P(1 or more donors have type O blood) = 1 - P(0 donors have type O blood)
= 1 - (0.94)^{20} (since the donors are independent)
Using a calculator, we get P(1 or more donors have type O blood) ≈ 0.370
Latisha determined the approximate amount of time each student in her homeroom class spent outside on a sunny day and on a rainy day. The dot plots below show her results.
Which measures of center and variability can be used to most accurately compare the two data sets?
A.mean and MAD
B.mean and IQR
C.median and MAD
D.median and IQR
Answer:
THE ANSWER IS A. I HAD THE SAME QUESTION
Step-by-step explanation:
Answer:
A
Step-by-step explanation:
The measure of an angle is forty-four times the measure of its supplementary angle. What is the measure of each angle?
Answer: 176 degrees and 4 degrees.
Step-by-step explanation: To find the measure of the angles, all you have to do is create an equation. Let's call the supplementary angle x and the other angle 44x, because the other angle is 44*the supplementary angle. Now, we structure the equation 44x + x = 180. The reason we say the sum of the angles is 180 is because any angle plus its supplementary angle equals 180 degrees. From there it's just algebra:
44x + x = 180
45x = 180
x = 180/45
x = 4
We can check our work by substituting x for 4 in the equation:
44*4 + 4 = 180
174 + 4 = 180
180 = 180
Thus, the first angle is 176 degrees and the second is 4 degrees.
Please help! 3 − |-4| − |2| =
Answer:
-3
Step-by-step explanation:
3 - |-4| - |2|
= 3 - 4 - |2|
= -1 - |2|
= 1 - 2
= -3
(Hope this helps)
Most hard drives are divided into sectors of 512 bytes each. Our disk has a size of 16 GB. Calculate how many sectors the disk has.
Answer:
33,554,432 sectors
Step-by-step explanation:
-We first convert both sizes to a uniform measure(both to be in bytes or gigabytes).
-We convert the drive size into Bytes:
[tex]1GB=1,073,741,824 \ Bytes\\\\\therefore 16GB=16\times1,073,741,824=1.717986918\times10^{10}\ Bytes[/tex]
#We then divide the Drive size by the sector size to get the number of sectors.
-Let X be the number of sectors:
[tex]X=\frac{Drive \ Size}{Sector \ Size}\\\\=\frac{1.717986918\times10^{10}}{512}\\\\=33,554,432[/tex]
Hence, the disk has 33,554,432 sectors.
To calculate the number of sectors in a 16GB disk, you first convert the disk size from GB to bytes. Then, you divide the total bytes by the size in bytes of one sector. So, a 16GB disk has 33,554,432 sectors.
Explanation:The disk size is provided in gigabytes (GB), but first, we need to convert it into bytes, as sectors are measured in bytes. There are 1,073,741,824 bytes in 1 GB. Therefore, a 16 GB disk has 16 * 1,073,741,824 = 17,179,869,184 bytes.
Since each sector is 512 bytes, we can find the number of sectors by dividing the total number of bytes by the size of one sector: 17,179,869,184 / 512 = 33,554,432 sectors.
Learn more about Disk Sectors here:https://brainly.com/question/33313245
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A student at a Midwest college is interested in whether Psychology majors spend more or less time studying than English majors. She randomly selects 8 Psychology majors and 8 English majors and determines their weekly studying time. The following are the scores. Note one person dropped out of the study.
Psychology Majors 16 12 13 10 9 10 8
English Majors 10 25 15 17 23 14 19 18
An analysis is being conducted using the Mann-Whitney U test. If a = 0.052 tail, Ucrit =
A) 07
B) 49
C) 10
D) 46
C.10
Explanation
From table critical value of U when n1 is 7 and n2 is 8 and symbol alpha is 0.05 then Ucrit=10
The Mann-Whitney U test was used to compare study times between Psychology and English majors. The U value computed was 0.5, which is less than the critical value of 46. Therefore, the correct answer is A) 07.
To determine if there is a difference in the studying time between Psychology and English majors, the student is using the Mann-Whitney U test. The Mann-Whitney U test is a non-parametric test used to compare differences between two independent groups when the dependent variable is either ordinal or continuous, but not normally distributed.
Here are the given study times:
Psychology Majors: 16, 12, 13, 10, 9, 10, 8English Majors: 10, 25, 15, 17, 23, 14, 19, 18First, we need to rank all the study times from both groups combined, from lowest to highest, and then sum the ranks for each group.
Ranks:
Psychology Majors: 16 (10.5), 12 (7), 13 (8), 10 (4), 9 (3), 10 (4), 8 (2)
English Majors: 10 (4), 25 (16), 15 (9), 17 (13), 23 (15), 14 (8), 19 (14), 18 (12)
Sum of ranks:
Psychology Majors: 49.5
English Majors: 91.5
Using these ranks and sums, we calculate the U values:
U1 (Psychology) = n1 × n2 + (n1 × (n1 + 1)) ÷ 2 - R1 = 7 × 8 + (7 × (7 + 1)) ÷ 2 - 49.5 = 56 + 28 - 49.5 = 34.5U2 (English) = n1 × n2 + (n2 × (n2 + 1)) ÷ 2 - R2 = 7 × 8 + (8 × (8 + 1)) ÷ 2 - 91.5 = 56 + 36 - 91.5 = 0.5The Mann-Whitney U value is the smaller of U1 and U2, so U = 0.5. Given that Ucrit = 46 at α = 0.05, 2-tailed, we compare our U value to Ucrit.
Because 0.5 < 46, we reject the null hypothesis.
The correct answer choice is A) 07.
Determining the Difference in Means
2 dot plots. The highlands have a mean rainfall of 15.27 millimeters, and the Lowlands have a mean rainfall of 12.05 millimeters.
Analyze the dot plots. What is the approximate difference between the means of the two data sets to the nearest whole number?
Answer:
its 3mm i promise its right pls make me brainliest
Step-by-step explanation:
Answer:
the answer is 3mm
Step-by-step explanation:
got it right on edge trust me the other guy is right to.